error converting const char* to char - c++

Question

I am trying to convert one char variable to a const char variable but I have the below error . Content of variable char is ok, in this case is a "H" and "e" but when I convert to const char* I have the letter + something else after. Can you guys please tell me where I did something wrong ?
Please see the picture from link !
#include <iostream>
#include <Windows.h>
#include <lmcons.h>
#include <stdio.h>
#include <stdlib.h>
char Body[] = { 'H', 'e', 'l', 'l', 'o' }; // elements of char array
int size = sizeof(Body); // get size of Body array
char Line;
std::cout << "Size : " << size << "\n"; // view the size of Body array
for(int i=0; i<=size; i++) // for statement : from first element to the last element of array
{ // beginning of for statement
Line = Body[i]; // get each element from Body array and put to char variable
std::cout << "Char : " << Line << "\n"; // view the content of char variable
const char *Line2 = &Line ; // convert from from char to const char*
std::cout << "Const char : " << Line2 << "\n"; // view the content of const char* variable
} // end of for statement
enter image description here

Answer 1

const char *Line2 = &Line ;
Doesn't magically create a string from your character; as a string must be Null (or 0) terminated you can't pass this pointer to cout as it's expecting multiple characters to be processed. If you were to change it to be
char Line[2] = {0}; // 0 initialise all the chars
Line[0] = Body[i];
Line[1] = 0; // completely not required, but just making the point
char* Line2 = &Line[0]; // there are other cleaner ways, but this shows explicitly what is happening
std::cout << Line2;
You would not have UB.

Answer 2

The problem is that you are not terminating Body with a null char(\0). And the second problem is your loop you are trying to access something that is out of range. The code should be like this:
char Body[] = { 'H', 'e', 'l', 'l', 'o', '\0' }; // elements of char array
int size = sizeof(Body); // get size of Body array
char Line;
std::cout << "Size : " << size << "\n"; // view the size of Body array
for(int i=0; i<size; i++) // for statement : from first element to the last element of array
{ // beginning of for statement
Line = Body[i]; // get each element from Body array and put to char variable
std::cout << "Char : " << Line << "\n"; // view the content of char variable
const char *Line2 = &Line ; // convert from from char to const char*
std::cout << "Const char : " << Line2 << "\n"; // view the content of const char* variable
} // end of for statement
You need null char at the end of the any raw string in c/c++ language because this helps it understand the ending of the string.

Answer 3

The problem is that you are accessing Body[5], when running the loop as
for(int t=0;t<=sizeof(Body);t++){}
if you remove that = sign it will be okay.
for(int t=0;t<sizeof(Body);t++){}
Also, try to convert
std::const char *Line2 = const_cast<const char *>(&Line );
Use std::const_cast<>() to convert non constant to constant data types.
Also to remove those extra things from console you need to dereference the const char *, if you directly use it. std::cout tries to print everything until null is encountered in case you pass it const char *
So,
std::cout << "Const char : " << *Line2;