extracting a word between brackets using regex pattern - regex

Am using this tutorial to create regular expression for one of my task with input string as:
[Begin] { (GetLatestCode)
Trying to extract string between brackets i.e. trying to extract GetLatestCode for which I made the following:
(?<=\[Begin\]\s{\s\()\w+(?=\)) //returns GetLatestCode
But this solution does not seem to work when I have multiple spaces around the curly brace.
[Begin] { (GetLatestCode) //does not work

If you need to account for 0 or more spaces, add a * after each space:
(?<=\[Begin\]\s*{\s*\()\w+(?=\))
If you need to account for 1 or more, use a +:
(?<=\[Begin\]\s+{\s+\()\w+(?=\))

Related

Writing using Regular Expressions in Google Cloud query

I currently have a regular expression: REGEXP_EXTRACT_ALL(data, r'\"createdAt\"\:(.*?)\}')
Which finds "createAt":" and outputs anything past that text and up until the next "}".
Example output: {"_seconds":1620327345,"_nanoseconds":155071000
This works BUT I need the last } to be included in the output.
Preferred Output: {"_seconds":1620327345,"_nanoseconds":155071000}
How will I need to change my regular expression so that the } is included in the output?
You need to include the } into the capturing group:
REGEXP_EXTRACT_ALL(data, r'"createdAt":(.*?})')
Besides, you can make it a bit more efficient with a negated character class:
REGEXP_EXTRACT_ALL(data, r'"createdAt":([^}]*})')
With [^}]*, you match any zero or more chars other than } as many times as possible.
Also, if you chose single quotation marks as a string literal delimiter char, you need not escape double quotation marks (they are not special regex metacharacters.) Note } is not a special character if there is no paired { with a number (or {<number>,<number>) in front of it.

Regex for not including the contain of a closed curly braces in Java

Please help me to solve this in java.
input string = <V2>UTM_Source:google|UTM_Medium:cpc|UTM_Campaign:{Core|IN|Desktop|BMM|Top Cities|TS}|
UTM_Content:{Compare Car Insurance}|UTM_Term:
I want to split with "|" but not the inside contain of curly braces
So the output will be:
<V2>UTM_Source:google
UTM_Medium:cpc
UTM_Campaign:{Core|IN|Desktop|BMM|Top Cities|TS}
UTM_Content:{Compare Car Insurance}
UTM_Term:
Thanks in advance.
So basically, you want to match the entire {...} sequences all at the same time, or in other words, treat them as a single character within your regular expression: \{.*?\} Using this fragment as the first choice in an alternation with a single "regular non pipe" character, and then letting that whole thing repeat, we avoid spurious matches inside the curly brackets:
((?:\{.*?\}|[^|])+)\|
or as Sven points out, you don't even need that last | or the capturing group:
(?:\{.*?\}|[^|])+
demo

Not able to find all groups using a pattern regex in matlab

I am trying to parse a regular expression in matlab. I am trying to extract all the number between '[]' for all the groups. Here are the details:
pat = '(\[\d,\d,\d,\d\])';
s1 = 'frame_1:[1,2,3,5],[11,22,33,44],[23,12,12,33],'
[matched_string] = regexp(s1,pat,'match');
>> matched_string{:}
ans =
'[1,2,3,5]'
I want to get all the boxes, i.e [1,2,3,5],[11,22,33,44] and [23,12,12,33].
Can someone help me figure out what I am doing wrong?
Your pattern only matches single digits inside square brackets. To match one or more, add + after each:
'(\[\d+,\d+,\d+,\d+\])'
If you do not care of the format inside the square brackets, and just need to extract square brackets with digits and commas inside, you may use a simpler
'\[[\d,]+]'
Note that ] at the end of the regular expression is not a special char here, since there is no corresponding [ that opens a character class, thus, no need escaping it.

How to generate a regex to capture everything but curly brace contents

I'm trying to match strings of any size NOT surrounded with { and } as in foo{bar} the regex should match foo but not {bar}.
The regexes I originally came up with were ^([^${].*[}$]) and ^(?=[{]).+(?<=[}]) but they don't seem to do what I expected them to do.
If you want to fetch all the characters that is not within {} then you can attempt an split operation using regex.
Split the string by this regex by using your preferred language:
{.*?}
The returned array should consist the segments that was found outside each {}
The following java example returns an array (arr):
String abc="19{22}33{44}55{66}7";
String[] arr=abc.split("\\{.*?\\}");
which contains:
["19","33","55","7"]

Regular expression to place number pair in square brackets

I have a large data file with sequences of numbers bearing the form
6.06038475036627,50.0646896362306\r\n
6.0563435554505,50.0635681152345\r\n
6.05446767807018,50.0632934570313\r\n
which I am trying to modify in Notepad++ so it reads
[6.06038475036627,50.0646896362306]\r\n
[6.0563435554505,50.0635681152345]\r\n
[6.05446767807018,50.0632934570313]\r\n
I can count the number of instances of these occurrences with a relatively simple regex \d{1,2}\.\d+\,\d{1,2}\.\d+. However, there my own regex skills hit the buffers. I am dimly aware that it is possible to go a step further and perform the actual modifications but I have no idea how that should be done.
You would simply need to do as follows:
Find what: (\d+\.\d+,\d+\.\d+)
Replace with: [\1]
Make sure that Regular Expression is checked.
Given this, it will transform this:
6.06038475036627,50.0646896362306\r\n
6.0563435554505,50.0635681152345\r\n
6.05446767807018,50.0632934570313\r\n
Into this:
[6.06038475036627,50.0646896362306]\r\n
[6.0563435554505,50.0635681152345]\r\n
[6.05446767807018,50.0632934570313]\r\n
The expression above will match the comma seperated numbers and throw them in a group. The replace will inject a [, followed by the matched group (denoted by \1) and it will inject another ].
Try the following regexp(with substitution):
\b(\d{1,2}\.\d+,\d{1,2}\.\d+)\b
https://regex101.com/r/VkHppp/1