How to add signal method for my view? - django

Question

I want to count how may files the user has uploaded.
I have added signals.py
from django.dispatch import Signal
upload_completed = Signal(providing_args=['upload'])
And summary.py
from django.dispatch import receiver
from .signals import upload_completed
#receiver(charge_completed)
def increment_total_uploads(sender, total, **kwargs):
total_u += total
to my project.
My views upload
#login_required
def upload(request):
# Handle file upload
user = request.user
if request.method == 'POST':
form = DocumentForm(request.POST, request.FILES)
if form.is_valid():
newdoc = Document(docfile=request.FILES['docfile'])
newdoc.uploaded_by = request.user.profile
upload_completed.send(sender=self.__class__, 'upload')
#send signal to summary
newdoc.save()
# Redirect to the document list after POST
return HttpResponseRedirect(reverse('upload'))
else:
form = DocumentForm() # A empty, unbound form
# Load documents for the upload page
documents = Document.objects.all()
# Render list page with the documents and the form
return render(request,'upload.html',{'documents': documents, 'form': form})
This effort does not work.I got
upload_completed.send(sender=self.__class__, 'upload')
^
SyntaxError: positional argument follows keyword argument
I found signal example testing-django-signals
from .signals import charge_completed
#classmethod
def process_charge(cls, total):
# Process charge…
if success:
charge_completed.send_robust(
sender=cls,
total=total,
)
But it seems to me that classmethod would not work in my case
How to fix my method?

Answer 1

You don't need the 'uploads' argument for the send() method.
But a tip, if you're planning on a persistent count of the number of file uploads (which I assume you most likely are), then I think you should create a new model so that you can save it in your database.Then you can update that model every time a Document model is saved.
And I suggest you have a look at post_save. Have a nice day coding!