Calling a macro several times - sas

I have a pretty large macro that I want to call several times. (I'm using replicate weights to calculate my error.) I want to call the process for different variables, say VAR1-VAR99. In the past I've used a DATA NULL step and CALL EXECUTE like so:
data _null_;
do i=1 to 99;
call execute(compress("%mymacro(VAR" || i || ")") );
end;
run;
This isn't working for me this time, though. There might be something I'm missing about the scope of macro variables? I'd like to call:
%mymacro(VAR1)
%mymacro(VAR2)
...
%mymacro(VAR99)
and of course I'd like to do this without 99 lines of code. Why might my method be suddenly failing me? What are other ways to do this?

Here is an example of generating macro calls with call execute. I added %NRSTR, as it prevents macro timing issues. It makes the call execute generate the macro call, without actually executing the macro. If your macro generates macro variables from data, without the %NRSTR you can end up with timing issues and scope issues.
%macro mymacro(var) ;
%put var=&var ;
%mend mymacro ;
data _null_;
do i=1 to 5;
call execute(cats('%nrstr(%mymacro(var',i,"))")) ;
end;
run;
Or it could be as simple as changing your code to use single quotes instead of double quotes. Single quotes will prevent the macro from executing when the data step compiles. If your macro does not generate macro variables from data, this may be enough. But I always use %NRSTR.
data _null_;
do i=1 to 5;
call execute(compress('%mymacro(VAR' || i || ")") );
end;
run;

Don't use call execute, try to call macro program in macro program.
%macro repeat(n);
%do i=1 %to &n;
%mymacro(VAR&i);
%end;
%mend;

Large is probably the key word in that question. Let me explain.
You are pushing the macro calls onto the stack using call execute(). But what actually is getting placed on the stack is the code generated by the macro and not the call. Look at the lines with + at the beginning in the SAS log.
If the macro generates just a few lines of code then not much is stacked up to run after the data step. But if it is large then you might overload the stack.
Also if the macro uses the lines of SAS code it generates to create macro variables (using call symputx() or SQL's into clause) that later drive the macro's logic there will be a timing issue. Again that is more likely to happen with a large macro than a small (simple) macro.
Wrap the macro call (or at least the macro's name) in %nrstr() will prevent SAS from running the macro during the call exucute() call. Instead the macro call will placed onto the stack to be run after the data step finishes.
Consider this simple macro definition.
%macro mymacro(varname);
proc means data=sashelp.class ;
var &varname ;
run;
%mend mymacro;
If I use call execute() to generate calls to it like this:
data _null_;
call execute('%mymacro(age)');
call execute('%mymacro(height)');
call execute('%mymacro(weight)');
run;
Then you will see lines like this in the SAS log
1 + proc means data=sashelp.class ; var age ; run;
2 + proc means data=sashelp.class ; var height ; run;
3 + proc means data=sashelp.class ; var weight ; run;
But if instead you add %nrstr() like this:
data _null_;
call execute('%nrstr(%mymacro)(age)');
call execute('%nrstr(%mymacro)(height)');
call execute('%nrstr(%mymacro)(weight)');
run;
Then the lines in the SAS log look like this.
1 + %mymacro(age)
2 + %mymacro(height)
3 + %mymacro(weight)

Related

What will be the output of this %macro function in SAS and how to display the output in sas studio

%macro segm1;
data _null_;
%do i=0 %to 8;
call symput("yyyymm_i",put(intnx('month',today(),-1,'b'),yymmn6.));
%end;
%mend;
%segm1;
run;
What will be the output and how to get/dispaly/view output of this macro code in sas studio?
Since a macro is used to generate SAS code to view the output of macro set the MPRINT option before running it. You will see that the macro generates a data statement and 8 call symput statements.
There are a lot of problems with that code.
Uses %DO loop where it should be using a DO loop.
Creates the same macro variable over and over.
Starts a data step, but does not end it. Was this on purpose? Why?
Creates LOCAL macro variables that will disappear when the macro finishes.
Uses older less functional call symput() function instead of call symputx().
If you want to create 8 macro variables just use a normal DO loop. No need for a macro. Use the value of the loop variable to change the name of the macro variable generated and the month the result represents.
data _null_;
do i=0 to 8;
call symputx(cats('yyyymm_',i),put(intnx('month',today(),-i,'b'),yymmn6.));
end;
run;
Which will create a series of macro variables named YYYYMM_0 to YYYYMM_8 with six digit strings like 202204 , 202203 , ... representing the current month back to eight months ago
If you did want to run that inside a macro and have the macro variables it creates available after the macro ends then set the optional third parameter to call symputx() to the string 'G' so that they are defined in the global symbol table instead of the local symbol table.
You can print individual macro variables to the log with the %put statement, like %put &yyyymm_i;
You can print all macro variable with %put _all_;, or if you are only interested in variables you created yourself: %put _user_; (or within a macro %put _local_;)
By the way, your code is wrong, try this
%macro segm1;
data _null_;
%do i=0 %to 8;
call symput("yyyymm_&i", put(intnx('month',today(),-1,'b'),yymmn6.));
%end;
%mend;
%segm1;
run;
%put _user_;

SAS macro modification

I have two values which represent dates:
a=101 and b=103
Below is first macro saved in separate file one.sas:
%global time nmall;
%let nmall =;
%macro pmall;
%do i=&a. %to &b;
%if &i =&a. then %do;
%let nmall=&nmall.&i;
%end;
%else %let nmall=&nmall.,&i;
end;
%put (&nmall);
%mend;
%pmall;
So above pmall give me values 101,102,103.
Below is second macro:
%include “one.as”;
%macro c(a=,b=);
%let m=;
%let m1=;
%do i =&a %to &b;
%let o=&i;
proc sql;
create table new&o as select * from data where nb in(&o.);quit;
%let m =&m.date&o;
data date&o.;
set date&o.;
if pass =&o.;
run;
proc sort data=date&o.;
by flag;
end;
data output &a._&b.;
set &m;
%mend;
The above macro creates three datasets date101 date102 and date 103, then append it to output101_103.
I am trying to modify above macros in such a way that I will not use %macro and %mend approach. Below is the modified macro code:
data a_to_c;
do o=&a to &c;
output;
end;
run;
so above code will have values 101 102 103 in variable o for dataset a_to_c.
data _null_;
set a_to_c;
call execute ('create table new’||strip(o)||' as select * from data
where nb in(’||strip(o)||' );quit;’);
run;
I want to know how to do below things.
Create pmall values in a macro variable in my modified macro inside the data step data a_to_c, so that I can use it further.
How to proceed from %let m macro in the first macro code to new code which I am developing above.
Geetha:
I think you will find the macro-ization of the process to be far easier if you go from a data-centric explicit solution and proceed abstracting the salient features into macro symbols (aka variables)
The end run solution appears to be:
data output_101_to_103;
set original_data;
where nb between 101 and 103;
run;
proc sort data=output_101_to_103;
by nb flag;
run;
In which case you could code a macro that abstracts 101 to FIRST and 103 to LAST. The data sets could also be abstracted. The abstracted parts are specified as the macro parameters.
%macro subsetter(DATA=, FIRST=, LAST, OUTPREFIX=OUTPUT);
%local out;
%let out = &OUTPREFIX._&FIRST._&LAST.;
data &out;
set &DATA.;
where nb between &FIRST. and &LAST.;
* condition = "between &FIRST. and &LAST."; * uncomment if you want to carry along the condition into your output data set;
run;
proc sort data=&out;
by nb flag;
run;
%mend;
And use as
%subsetter (data=original_data, first=101, last=103, outprefix=output)
Note: If you did keep the condition variable in the output data, you WOULD NOT be able to use it directly as a source code statement in a future data step, as in if nb condition then ...
I suppose you could also pass the NB and FLAG as parameters -- but you approach a point of diminishing returns on the utility of the macro.
Macro-izing the specific example I showed doesn't make too much sense unless you need to perform a lot of different variations of FIRST and LAST in a well documented framework. Sometimes it is just better to not abstract the code and work with the specific cases. Why? Because when there are too many abstracted pieces the macro invocation is almost as long as the specific code you are generating and the abstraction just gets in the way of understanding.
If the macro is simply chopping up data and reassembling data, you might be better served rethinking the flow using where, by, and class statements and abstracting around that.
Pmall is macro variable which will have list of values separated by
commas. In my modify macro, i want to create pmall as macro variable
in the datastep data a_to_c; do o=&a to &c; output; end; run; – geetha
anand 1 min ago
To create a macro variable from within a data step using the CALL SYMPUTX() function.
data a_to_c;
length pmall $200 ;
do o=&a to &c;
pmall=catx(',',pmall,o);
output;
end;
call symputx('pmall',pmall);
drop pmall;
run;
If you really want to generate code without a SAS macro you can use CALL EXECUTE() or write the code to a file and use %INCLUDE to run it. Or for small pieces of code you could try putting the code in a macro variable, but macro variables can only contain 64K bytes.
It is really hard to tell from what you posted what code you want to generate. Let's assume that you want to generate an new dataset for each value in the sequence and then append that to some aggregate dataset. So for the first pass through the loop your code might be as simple as these two steps. First to create the proper subset in the right order and the second to append the result to the aggregate dataset.
proc sort data=nb out=date101 ;
where nb=101 ;
by flag ;
run;
proc append base=date101_103 data=date101 force;
run;
Then next two times through the loop will look the same only the "101" will be replaced by the current value in the sequence.
So using CALL EXECUTE your program might look like:
%let a=101;
%let c=103;
proc delete data=date&a._&c ;
run;
data _null_;
do nb=&a to &c;
call execute(catx(' ','proc sort data=nb out=',cats('date',nb,'),';'));
call execute(cats('where nb=',nb,';')) ;
call execute('by flag; run;');
call execute("proc append base=date&a._&c data=");
call execute(cats('date',nb));
call execute(' force; run;');
end;
run;
Writing it to a file to run via %INCLUDE would look like this:
filename code temp ;
data _null_;
file code ;
do nb=&a to &c;
put 'proc sort data=nb out=date' nb ';'
/ ' where ' nb= ';'
/ ' by flag;'
/ ';'
/ "proc append base=date&a._&c data=date" nb 'force;'
/ 'run;'
;
end;
run;
proc delete data=date&a._&c ;
run;
%include code / source2;
If the goal is to just create the aggregate dataset and you do not need to keep the smaller intermediate datasets then you could just use the same name for the intermediate dataset on each pass through the loop. That will make the code generation easier as then there is only only place that needs to change based on the current value. Also that way you only need to have two dataset names even for a sequence of 10 or 20 values. It will take less space and reduce clutter in the work library.

SAS execute macro conditionally

I want to execute a macro conditionally, based on some loop variable in the dataset.
data alldat;
do i=1 to 5;
* here, a macro should be called ;
* that is accessing some array variable of the dataset ;
* e.g. %my_macro(my_array(i));
%put hello;
output;
end;
run;
proc print; run;
How is this possible?
If I execute this example code above, hello is only output once, while alldat contains 5 values, as one would expect. I want 5 hellos in my output.
Thank you!
If you want your data step loop to output hello 5 times then use a PUT statement instead of a %PUT statement.
In general macros are used to generate SAS code that is then executed. It really depends on what type of code your macro generates. If it only generates statements than can be used inside of a data step then call it once inside of your DO loop and the generated statements will run 5 times. So if your macro generates data step statements that could update the variable whose name is passed to it then your code might look like this.
data alldata;
array my_array var1-var5 ;
do i=1 to dim(my_array);
%my_macro(my_array(i));
put 'hello';
output;
end;
run;
Otherwise you could use CALL EXECUTE to generate the macro calls so that they can then run and generate their code after the data step stops. This data step will read values from an existing array and pass the values to the macro. So it will generate 5 calls to the macro for every observation in the input data. The generated macro calls will run after the data step stops.
data _null_;
set mydata;
array my_array var1-var5 ;
do i=1 to dim(my_array);
call execute(cats('%nrstr(%my_macro)(',my_array(i),');'));
call execute('%nrstr(%put hello;)');
end;
run;

SAS - How to return a value from a SAS macro?

I would like to return a value from a SAS macro I created but I'm not sure how. The macro computes the number of observations in a dataset. I want the number of observations to be returned.
%macro nobs(library_name, table_name);
proc sql noprint;
select nlobs into :nobs
from dictionary.tables
where libname = UPCASE(&library_name)
and memname = UPCASE(&table_name);
quit;
*return nobs macro variable;
&nobs
%mend;
%let num_of_observations = %nobs('work', 'patients');
Also, I would like the &nobs macro variable that is used within the macro to be local to that macro and not global. How can I do that?
I'll answer the core question Bambi asked in comments:
My main concern here is how to return a value from a macro.
I'm going to quibble with Dirk here in an important way. He says:
A SAS macro inserts code. It can never return a value, though in some cases you can mimic functions
I disagree. A SAS macro returns text that is inserted into the processing stream. Returns is absolutely an appropriate term for that. And when the text happens to be a single numeric, then it's fine to say that it returns a value.
However, the macro can only return a single value if it only has macro statements in addition to that value. Meaning, every line has to start with a %. Anything that doesn't start with % is going to be returned (and some things that do start with % might also be returned).
So the important question is, How do I return only a value from a macro.
In some cases, like this one, it's entirely possible with only macro code. In fact, in many cases this is technically possible - although in many cases it's more work than you should do.
Jack Hamilton's linked paper includes an example that's appropriate here. He dismisses this example, but that's largely because his paper is about counting observations in cases where NOBS is wrong - either with a WHERE clause, or in certain other cases where datasets have been modified without the NOBS metadata being updated.
In your case, you seem perfectly happy to trust NOBS - so this example will do.
A macro that returns a value must have exactly one statement that either is not a macro syntax statement, or is a macro syntax statement that returns a value into the processing stream. %sysfunc is an example of a statement that does so. Things like %let, %put, %if, etc. are syntax statements that don't return anything (by themselves); so you can have as many of those as you want.
You also have to have one statement that puts a value in the processing stream: otherwise you won't get anything out of your macro at all.
Here is a stripped down version of Jack's macro at the end of page 3, simplified to remove the nlobsf that he is showing is wrong:
%macro check;
%let dsid = %sysfunc(open(sashelp.class, IS));
%if &DSID = 0 %then
%put %sysfunc(sysmsg());
%let nlobs = %sysfunc(attrn(&dsid, NLOBS));
%put &nlobs;
%let rc = %sysfunc(close(&dsid));
%mend;
That macro is not a function style macro. It doesn't return anything to the processing stream! It's useful for looking at the log, but not useful for giving you a value you can program with. However, it's a good start for a function style macro, because what you really want is that &nlobs, right?
%macro check;
%let dsid = %sysfunc(open(sashelp.class, IS));
%if &DSID = 0 %then
%put %sysfunc(sysmsg());
%let nlobs = %sysfunc(attrn(&dsid, NLOBS));
&nlobs
%let rc = %sysfunc(close(&dsid));
%mend;
Now this is a function style macro: it has one statement that is not a macro syntax statement, &nlobs. on a plain line all by itself.
It's actually more than you need by one statement; remember how I said that %sysfunc returns a value to the processing stream? You could remove the %let part of that statement, leaving you with
%sysfunc(attrn(&dsid, NLOBS))
And then the value will be placed directly in the processing stream itself - allowing you to use it directly. Of course, it isn't as easy to debug if something goes wrong, but I'm sure you can work around that if you need to. Also note the absence of a semi-colon at the end of the statement - this is because semicolons aren't required for macro functions to execute, and we don't want to return any extraneous semicolons.
Let's be well behaved and add a few %locals to get this nice and safe, and make the name of the dataset a parameter, because nature abhors a macro without parameters:
%macro check(dsetname=);
%local dsid nlobs rc;
%let dsid = %sysfunc(open(&dsetname., IS));
%if &DSID = 0 %then
%put %sysfunc(sysmsg());
%let nlobs = %sysfunc(attrn(&dsid, NLOBS));
&nlobs
%let rc = %sysfunc(close(&dsid));
%mend;
%let classobs= %check(dsetname=sashelp.class);
%put &=classobs;
There you have it: a function style macro that uses the nlobs function to find out how many rows are in any particular dataset.
What is the Problem writing function-like macros?
i.e. macros you can use as%let myVar = %myMacro(myArgument)
You can use your user written macro as if it were a function if all you do is
calling some %doSomething(withSometing) like macro functions
assign values to macro variables with a %let someVar = statement
"return" your result, typically by writing &myResult. on the last line before your %mend
As soon as you include a proc or data step in your macro, this does not work any more
Luckily, %sysFunc() comes to the rescue, so we can use any data step function
This includes low level functions like open, fetch and close which can even access your data
nerdy people can do quite a lot with it, but even if you are nerdy, your boss will seldom give you the time to do so.
How do we solve this?, i.e. which building blocks do I use to solve this?
proc fcmp allows packaging some data step statements in a subroutine or function
This function, meant for use in a data step, can be used within %sysfunc()
Within this function you can call run_macro to execute any macro IN BACKGROUND IMMEDIATELY
Now we are ready for the practical solution
Step 1: write a helper macro
with no parameters,
using some global macro variables
"returning" its result in a global macro variable
I know that is bad coding habit, but to mitigate the risk, we qualify those variables with a prefix. Applied to the example in the question
** macro nobsHelper retrieves the number of observations in a dataset
Uses global macro variables:
nobsHelper_lib: the library in which the dataset resides, enclosed in quotes
nobsHelper_mem: the name of the dataset, enclosed in quotes
Writes global macro variable:
nobsHelper_obs: the number of observations in the dataset
Take care nobsHelper exists before calling this macro, or it will be ost
**;
%macro nobsHelper();
** Make sure nobsHelper_obs is a global macro variable**;
%global nobsHelper_obs;
proc sql noprint;
select nobs
into :nobsHelper_obs
from sashelp.vtable
where libname = %UPCASE(&nobsHelper_lib)
and memname = %UPCASE(&nobsHelper_mem);
quit;
%* uncomment these put statements to debug **;
%*put NOTE: inside nobsHelper, the following macro variables are known;
%*put _user_;
%mend;
Step 2: write a helper function;
**Functions need to be stored in a compilation library;
options cmplib=sasuser.funcs;
** function nobsHelper, retrieves the number of observations in a dataset
Writes global macro variables:
nobsHelper_lib: the library in which the dataset resides, enclosed in quotes
nobsHelper_mem: the name of the dataset, enclosed in quotes
Calls the macro nobsHelper
Uses macro variable:
nobsHelper_obs: the number of observations in the dataset
**;
proc fcmp outlib=sasuser.funcs.trial;
** Define the function and specity it should be called with two character vriables **;
function nobsHelper(nobsHelper_lib $, nobsHelper_mem $);
** Call the macro and pass the variables as global macro variables
** The macro variables will be magically qouted **;
rc = run_macro('nobsHelper', nobsHelper_lib, nobsHelper_mem);
if rc then put 'ERROR: calling nobsHelper gave ' rc=;
** Retreive the result and pass it on **;
return (symget('nobsHelper_obs'));
endsub;
quit;
Step 3: write a convenience macro to use the helpers;
** macro nobs retrieves the number of observations in a dataset
Parameters:
library_name: the library in which the dataset resides
member_name: the name of the dataset
Inserts in your code:
the number of observations in the dataset
Use as a function
**;
%macro nobs(library_name, member_name);
%sysfunc(nobsHelper(&library_name, &member_name));
%* Uncomment this to debug **;
%*put _user_;
%mend;
Finally use it;
%let num_carrs = %nobs(sasHelp, cars);
%put There are &num_carrs cars in sasHelp.Cars;
Data aboutClass;
libname = 'SASHELP';
memname = 'CLASS';
numerOfStudents = %nobs(sasHelp, class);
run;
I know this is complex but at least all the nerdy work is done.
You can copy, paste and modify this in a time your boss will accept.
;
A SAS macro inserts code. It can never return a value, though in some cases you can mimic functions, usually you need a work around like
%nobs(work, patients, toReturn=num_of_observations )
** To help you understand what happens, I advice printing the code inserted by the macro in your log: ;
options mprint;
We pass the name of the macro variable to fill in to the macro, I find it most practical to
not require the user of my macro to put quotes around the libary and member names
make the name of the variable a named macro variable, so we can give it a default;
%macro nobs(library_name, table_name, toReturn=nobs);
Make sure the variable to return exists
If it exists it is known outside of this macro.
Otherwisse if we create it here, it wil by default be local and lost when we leave the macro;
%if not %symexist(&toReturn.) %then %global &toReturn.;
In the SQL, I
use the SASHELP.VTABLE, a view provided by SAS on its meta data
add the quotes I omitted in the macro call ("", not '': macro variables are not substituted in single qoutes)
use the macro %upcase function instead of the SAS upcase function, as it sometimes improves performance;
proc sql noprint;
select nobs
into :&toReturn.
from sashelp.vtable
where libname = %UPCASE("&library_name.")
and memname = %UPCASE("&table_name.");
quit;
%mend;
Pay attention if you call a macro within a macro, Run this code and read the log to understand why;
%macro test_nobs();
%nobs(sashelp, class); ** will return the results in nobs **;
%nobs(sashelp, shoes, toReturn=num_of_shoes);
%let num_of_cars = ;
%nobs(sashelp, cars, toReturn=num_of_cars);
%put NOTE: inside test_nobs, the following macro variables are known;
%put _user_;
%mend;
%test_nobs;
%put NOTE: outside test_nobs, the following macro variables are known;
%put _user_;
You can't 'return' a value from a function-style macro unless you have written it using only macro statements. Quentin's link provides an example of how to do this.
For example, you cannot use your macro like so, because proc sql cannot execute in the middle of a %put statement (this is possible with other more complex workarounds, e.g. dosubl, but not the way you've written it).
%put %nobs(mylib,mydata);
The best you can do without significant changes is to create a global macro variable and use that in subsequent statements.
To create a macro variable that is local to the originating macro, you have to first declare it via a %local statement within the macro definition.
I know I am very late to this discussion, but thought of commenting since I came across this. This is another way of doing this I think:
%macro get_something_back(input1, input2, output);
&output = &input1 + &input2;
%mend;
data _test_;
invar1 = 1; invar2 = 2;
%get_something_back(invar1, invar2, outvar);
end;
This will also work outside a datastep.
%global sum;
%macro get_something_back(input1, input2, outvar);
%let &outvar = &sysevalf(&input1 + &input2);
%mend;
%get_something(1, 2, sum);

Using a dynamic macro variable in a call symput statement

I posted a question a while back about trimming a macro variable down that I am using to download a CSV from Yahoo Finance that contains variable information on each pass to the site. The code that was suggested to me to achieve this was as follows:
data _null_;
a = "&testvar.";
call symputx('svar',trim(input(a,$8.)));
run;
That worked great, however I have since needed to redesign the code so that I am declaring multiple macro variables and submitting multiple ones at the same time.
To declare multiple macros at the same time I have used the following lines of code:
%let svar&e. = &svar.;
%put stock_ticker = &&svar&e.;
The varible &e. is an iterative variable that goes up by one everytime. This declares what looks to be an identical macro to the one called &svar. everytime they are put into the log, however the new dynamic macro is now throwing up the original warning message of:
WARNING: The quoted string currently being processed has become more than 262 characters long. You
may have unbalanced quotation marks.
That i was getting before i started using the symputx option suggested in my original problem.
The full code for this particular nested macro is listed below:
%macro symbol_var;
/*here the start row and end row created in the macro above are passed to this nested macro and then passed through the*/
/*source dataset. at the end of the loop each ticker macro variable is defined in turn for use in the following nested*/
/*macro, symbol by metric.*/
%do e = &beg_point. %to &end_point. %by 1;
%put stock row in dataset nasdaq ticker = &e.;
%global svar&e;
proc sql noprint;
select symbol
into :testvar
from nasdaq_ticker
where monotonic() = &e.;
quit;
/*convert value to string here*/
data _null_;
a = "&testvar.";
call symputx('svar',trim(input(a,$8.)));
run;
%let svar&e. = &svar.;
%put stock_ticker = &&svar&e.;
%end;
%mend;
%symbol_var;
Anyone have any suggestions how I could declare the macro &&svar&e. directly into the call synputx step? It currently throws up an error saying that the macro variable being created cannot contain any special characters. Ive tried using &QUOTE, %NRQUOTE and %NRBQUOTE but either I have used the function in an invalid context or I haven't got the syntax exactly right.
Thanks
Isn't this as simple as the following two line data step?
%macro symbol_var;
/*here the start row and end row created in the macro above are passed to this nested macro and then passed through the*/
/*source dataset. at the end of the loop each ticker macro variable is defined in turn for use in the following nested*/
/*macro, symbol by metric.*/
data _null_;
set nasdaq_ticker(firstobs=&beg_point. obs=&end_point.);
call symputx('svar' || strip(_n_), symbol);
run;
%mend;
%symbol_var;
Or the following (which includes debugging output)
%macro symbol_var;
/*here the start row and end row created in the macro above are passed to this nested macro and then passed through the*/
/*source dataset. at the end of the loop each ticker macro variable is defined in turn for use in the following nested*/
/*macro, symbol by metric.*/
data _null_;
set nasdaq_ticker(firstobs=&beg_point. obs=&end_point.);
length varname $ 32;
varname = 'svar' || strip(_n_);
call symputx(varname, symbol);
put varname '= ' symbol;
run;
%mend;
%symbol_var;
When manipulating macro variables and desiring bullet-proof code I often find myself reverting to using a data null step. The original post included the problem about a quoted string warning. This happens because the SAS macro parser does not hide the value of your macro variables from the syntax scanner. This means that your data (stored in macro vars) can create syntax errors in your program because SAS attempts to interpret it as code (shudder!). It really makes the hair on the back of my neck stand up to risk my program at the hands of what might be in the data. Using the data step and functions protects you from this completely. You will note that my code never uses an ampersand character other than the observation window points. This makes my code bullet proof regarding what dirty data there may be in the nasdaq_ticker data set.
Also, it is important to point out that both Dom and I wrote code that makes one pass over the nasdaq_ticker data set. Not to bash the original posted code, but looping in that way causes a proc sql invocation for every observation in the result set. This will create very poor performance for large result sets. I recommend developing an awareness of how many times a macro loop is going to cause you to read a data set. I have been bitten by this many times in my own code.
Try
call symputx("svar&e",trim(input(a,$8.)));
You need double quotes ("") to resolve the e macro.
As an aside, I am not sure you need the input statement if $testvar is a string and not a number.
I would have written this as
%macro whatever();
proc sql noprint;
select count(*)
into :n
from nasdaq_ticker;
select strip(symbol)
into :svar1 - :svar%left(&n)
from nasdaq_ticker;
quit;
%do i=1 %to &n;
%put stock_ticker = &&svar&i;
%end;
%mend;