I would like to get the distinct values inside of a for loop, or within some group. Since the xsl:key can only be declared at the top level, how would I be able to make a xsl:key for each group? In the example below, the group would be the most outer fruit tags. Note that there's also a xsl:sort. If there is a way to accomplish this by just xpaths (preceding-sibling), I would love to know this solution as well. I'm not sure if I would need to use the Muenchian method to accomplish this, but this is what I have:
Input.xml
<root>
<fruits>
<fruit>
<fruit id="2">
<banana><taste>Yummy</taste></banana>
<banana><taste>Disgusting</taste></banana>
</fruit>
<fruit id="1">
<banana><taste>Eh</taste></banana>
<banana><taste>Disgusting</taste></banana>
</fruit>
</fruit>
<fruit>
<fruit id="2">
<banana><taste>Yummy</taste></banana>
<banana><taste>Disgusting</taste></banana>
</fruit>
<fruit id="1">
<banana><taste>Amazing</taste></banana>
<banana><taste>Disgusting</taste></banana>
</fruit>
</fruit>
</fruits>
</root>
Transform.xsl
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:key name="taste" use="." match="taste" />
<xsl:template match="root">
<xsl:apply-templates select="fruits" />
</xsl:template>
<xsl:template match="fruits">
<xsl:element name="newFruits">
<xsl:call-template name="test" />
</xsl:element>
</xsl:template>
<xsl:template name="test">
<xsl:for-each select="fruit">
<xsl:sort select="fruit/#id" />
<xsl:element name="newFruit">
<!-- xsl:for-each select="fruit/banana/taste[not(.=preceding::taste)]/.." /> -->
<xsl:for-each select="fruit/banana/taste[generate-id() = generate-id(key('taste',.)[1])]/..">
<xsl:element name="fruit">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Output (comments in the output is the desired tags that should appear)
<?xml version="1.0" encoding="UTF-8"?>
<newFruits>
<newFruit>
<fruit>Yummy</fruit>
<fruit>Disgusting</fruit>
<fruit>Eh</fruit>
</newFruit>
<newFruit>
<!-- <fruit>Yummy</fruit> -->
<!-- <fruit>Disgusting</fruit> -->
<fruit>Amazing</fruit>
</newFruit>
</newFruits>
The issue is that you want your taste elements to be distinct per each top-level fruit element. Your current grouping is getting the distinct elements for the whole document.
If you can't update to XSLT 2.0 then shed a tear, as you have to then use a concatenated key in XSLT 1.0, to include a unique identifier for the relevant fruit element, which can be achieved by using generate-id()
<xsl:key name="taste" use="concat(generate-id(../../..), '|', .)" match="taste" />
Then, in your "test" template, define a variable to hold the id for the relevant fruit...
<xsl:variable name="id" select="generate-id()" />
And your expression to get the distinct tastes becomes this...
<xsl:for-each select="fruit/banana/taste[generate-id() = generate-id(key('taste', concat($id, '|', .))[1])]">
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output method="xml" indent="yes" />
<xsl:key name="taste" use="concat(generate-id(../../..), '|', .)" match="taste" />
<xsl:template match="root">
<xsl:apply-templates select="fruits" />
</xsl:template>
<xsl:template match="fruits">
<newFruits>
<xsl:call-template name="test" />
</newFruits>
</xsl:template>
<xsl:template name="test">
<xsl:for-each select="fruit">
<xsl:variable name="id" select="generate-id()" />
<newFruit>
<!-- xsl:for-each select="fruit/banana/taste[not(.=preceding::taste)]/.." /> -->
<xsl:for-each select="fruit/banana/taste[generate-id() = generate-id(key('taste', concat($id, '|', .))[1])]">
<fruit>
<xsl:value-of select="."/>
</fruit>
</xsl:for-each>
</newFruit>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Note, you don't really need the first template, and I can't see the point of a named template, so you can simplify the above XSLT to this...
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output method="xml" indent="yes" />
<xsl:key name="taste" use="concat(generate-id(../../..), '|', .)" match="taste" />
<xsl:template match="fruits">
<newFruits>
<xsl:apply-templates select="fruit" />
</newFruits>
</xsl:template>
<xsl:template match="fruit">
<xsl:variable name="id" select="generate-id()" />
<newFruit>
<!-- xsl:for-each select="fruit/banana/taste[not(.=preceding::taste)]/.." /> -->
<xsl:for-each select="fruit/banana/taste[generate-id() = generate-id(key('taste', concat($id, '|', .))[1])]">
<fruit>
<xsl:value-of select="."/>
</fruit>
</xsl:for-each>
</newFruit>
</xsl:template>
</xsl:stylesheet>
Related
I'm new on XSLT and have a requirement to use XSLT to select values from an XML file of this form :
<?xml version="1.0" encoding="utf-8"?>
<deviceInstallation>
<order>
<orderID>296</orderID>
<orderPosID>1</orderPosID>
<action rvcd="2">unInstall</action>
</order>
<deviceInfo>
<actionInfo rvcd="1">Software Install</actionInfo>
<device>
<deviceID>1436</deviceID>
</device>
</deviceInfo>
<deviceInfo>
<actionInfo rvcd="2">Software Uninstall</actionInfo>
<device>
<deviceID>4112</deviceID>
</device>
</deviceInfo>
</deviceInstallation>
I need to filter the elements deviceinfo based on the attribute rvcd = 2 because this is what is defined on the same attribute of child element action of the order element.
I tried to write and xslt and used a var to get the value to filter but don't know how to use it :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<xsl:output method="text" />
<xsl:variable name="separator" select="';'" />
<xsl:variable name="newline" select="'
'" />
<xsl:variable name="actionFilter" select="/deviceInstallation/order/action[]/#rvcd" />
<xsl:template match="/">
<xsl:text>orderID;DeviceID</xsl:text>
<xsl:value-of select="$newline" />
<xsl:for-each select="/deviceInstallation">
<!--OrderID-->
<xsl:value-of select="/deviceInstallation/order/orderID"/>
<xsl:value-of select="$separator"/>
<!--DeviceID-->
<xsl:value-of select="/deviceInstallation/deviceInfo/device/deviceID"/> <!-- here want to filter on rvcd-->
<xsl:value-of select="$separator"/>
<xsl:value-of select="$newline" />
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Any help appreciated
IIUC, you want to do:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />
<xsl:template match="/deviceInstallation">
<xsl:variable name="orderID" select="order/orderID" />
<xsl:variable name="actionFilter" select="order/action/#rvcd" />
<xsl:text>orderID;DeviceID
</xsl:text>
<xsl:for-each select="deviceInfo[actionInfo/#rvcd=$actionFilter]">
<xsl:value-of select="$orderID" />
<xsl:text>;</xsl:text>
<xsl:value-of select="device/deviceID" />
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
or perhaps a bit more elegantly:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />
<xsl:key name="dev" match="deviceInfo" use="actionInfo/#rvcd" />
<xsl:template match="/deviceInstallation">
<xsl:variable name="orderID" select="order/orderID" />
<xsl:text>orderID;DeviceID
</xsl:text>
<xsl:for-each select="key('dev', order/action/#rvcd)">
<xsl:value-of select="$orderID" />
<xsl:text>;</xsl:text>
<xsl:value-of select="device/deviceID" />
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I am facing an xslt/xpath problem and hope someone could help, in a few words here is what I try to achieve.
I have to transform an XML document where some nodes may be missing, these missing nodes are mandatory in the final result. I have the set of mandatory node names available in an xsl:param.
The base document is:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="TRANSFORM.xslt"?>
<BEGIN>
<CLIENT>
<NUMBER>0021732561</NUMBER>
<NAME1>John</NAME1>
<NAME2>Connor</NAME2>
</CLIENT>
<PRODUCTS>
<PRODUCT_ID>12</PRODUCT_ID>
<DESCRIPTION>blah blah</DESCRIPTION>
</PRODUCTS>
<PRODUCTS>
<PRODUCT_ID>13</PRODUCT_ID>
<DESCRIPTION>description ...</DESCRIPTION>
</PRODUCTS>
<OPTIONS>
<OPTION_ID>1</OPTION_ID>
<DESCRIPTION>blah blah blah ...</DESCRIPTION>
</OPTIONS>
<PROMOTIONS>
<PROMOTION_ID>1</PROMOTION_ID>
<DESCRIPTION>blah blah blah ...</DESCRIPTION>
</PROMOTIONS>
</BEGIN>
Here is the stylesheet so far:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:param name="mandatoryNodes" as="xs:string*" select=" 'PRODUCTS', 'OPTIONS', 'PROMOTIONS' "/>
<xsl:template match="/">
<xsl:apply-templates select="child::node()"/>
</xsl:template>
<xsl:template match="node()">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="BEGIN">
<xsl:element name="BEGIN">
<xsl:for-each select="$mandatoryNodes">
<!-- If there is no node with this name -->
<xsl:if test="count(*[name() = 'current()']) = 0">
<xsl:element name="{current()}" />
</xsl:if>
</xsl:for-each>
<xsl:apply-templates select="child::node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I tried the transformation in XML Spy, the xsl:iftest failed saying that 'current item is PRODUCTS of type xs:string.
I've tried the same xsl:if outside of a for-each and it seems to work ... what am I missing ?
Inside of <xsl:for-each select="$mandatoryNodes"> the context item is a string but you want to access the primary input document and its nodes so you need to store that document or the template's context node in a variable and use that e.g.
<xsl:template match="BEGIN">
<xsl:variable name="this" select="."/>
<xsl:element name="BEGIN">
<xsl:for-each select="$mandatoryNodes">
<!-- If there is no child node of `BEGIN` with this name -->
<xsl:if test="count($this/*[name() = current()]) = 0">
<xsl:element name="{current()}" />
</xsl:if>
</xsl:for-each>
<xsl:apply-templates select="child::node()"/>
</xsl:element>
</xsl:template>
Input:
<persons>
<person name="John" role="Writer"/>
<person name="John" role="Poet"/>
<person name="Jacob" role="Writer"/>
<person name="Jacob" role="Poet"/>
<person name="Joe" role="Poet"/>
</persons>
Expected Output:
<groups>
<group roles="Wriet, Poet" persons="John, Jacob"/>
<group roles="Poet" persons="Joe"/>
</groups>
As in the above example, I first need to group on person names and find everyone's roles. If more than one person is found to have the same set of roles (e.g. both John and Jacob are both Writer and Poet), then I need to group on each set of roles and list the person names.
I can do this for the first level of grouping using Muenchian method or EXSLT set:distinct etc.
<groups>
<group roles="Wriet, Poet" persons="John"/>
<group roles="Wriet, Poet" persons="Jacob"/>
<group roles="Poet" persons="Joe"/>
</groups>
The above was transformed using XSLT 1.0 and EXSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:sets="http://exslt.org/sets" extension-element-prefixes="sets">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:key name="persons-by-name" match="person" use="#name"/>
<xsl:template match="persons">
<groups>
<xsl:for-each select="sets:distinct(person/#name)">
<group>
<xsl:attribute name="persons"><xsl:value-of select="."/></xsl:attribute>
<xsl:attribute name="roles">
<xsl:for-each select="key('persons-by-name', .)">
<xsl:value-of select="#role"/>
<xsl:if test="position()!=last()"><xsl:text>, </xsl:text></xsl:if>
</xsl:for-each>
</xsl:attribute>
</group>
</xsl:for-each>
</groups>
</xsl:template>
</xsl:stylesheet>
However, I need help to understand how to group on the grouped roles.
If XSLT 1.0 solution is not available, please feel free to recommend XSLT 2.0 approach.
Try it this way?
XSLT 1.0
(using EXSLT node-set() and distinct() functions)
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:exsl="http://exslt.org/common"
xmlns:set="http://exslt.org/sets"
extension-element-prefixes="exsl set">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:key name="person-by-name" match="person" use="#name" />
<xsl:key name="person-by-roles" match="person" use="#roles" />
<xsl:variable name="distinct-persons">
<xsl:for-each select="set:distinct(/persons/person/#name)">
<person name="{.}">
<xsl:attribute name="roles">
<xsl:for-each select="key('person-by-name', .)/#role">
<xsl:sort/>
<xsl:value-of select="." />
<xsl:if test="position()!=last()">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:attribute>
</person>
</xsl:for-each>
</xsl:variable>
<xsl:template match="/">
<groups>
<xsl:for-each select="set:distinct(exsl:node-set($distinct-persons)/person/#roles)">
<group roles="{.}">
<xsl:attribute name="names">
<xsl:for-each select="key('person-by-roles', .)/#name">
<xsl:value-of select="." />
<xsl:if test="position()!=last()">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:attribute>
</group>
</xsl:for-each>
</groups>
</xsl:template>
</xsl:stylesheet>
Result:
<?xml version="1.0" encoding="UTF-8"?>
<groups>
<group roles="Poet, Writer" names="John, Jacob"/>
<group roles="Poet" names="Joe"/>
</groups>
I did exactly the same thing as you already did and then went a step further and grouped again. Now I get the following output with your input:
<?xml version="1.0" encoding="UTF-8"?>
<groups>
<group roles="Writer,Poet" persons="John,Jacob"/>
<group roles="Poet" persons="Joe"/>
</groups>
This is the XSLT 2.0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns="" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:avintis="http://www.avintis.com/esb" exclude-result-prefixes="#all" version="2.0">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:template match="/persons">
<groups>
<xsl:variable name="persons" select="."/>
<!-- create a temporary variable containing all roles of a person -->
<xsl:variable name="roles">
<xsl:for-each select="distinct-values(person/#name)">
<xsl:sort select="."/>
<xsl:variable name="name" select="."/>
<xsl:element name="group">
<xsl:attribute name="roles">
<!-- sort the roles of each person -->
<xsl:variable name="rolesSorted">
<xsl:for-each select="$persons/person[#name=$name]">
<xsl:sort select="#role"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="string-join($rolesSorted/person/#role,',')"/>
</xsl:attribute>
<xsl:attribute name="persons" select="."/>
</xsl:element>
</xsl:for-each>
</xsl:variable>
<!-- now loop again over all roles of the persons and group persons having the same roles -->
<xsl:for-each select="distinct-values($roles/group/#roles)">
<xsl:element name="group">
<xsl:variable name="name" select="."/>
<xsl:attribute name="roles" select="$name"/>
<xsl:attribute name="persons">
<xsl:value-of select="string-join($roles/group[#roles=$name]/#persons,',')"/>
</xsl:attribute>
</xsl:element>
</xsl:for-each>
</groups>
</xsl:template>
<xsl:template match="*|text()|#*">
<xsl:copy>
<xsl:apply-templates select="*|text()|#*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
The roles get also sorted - so independent from the input order of the roles and persons.
I have list of elements in variable
|ELEMENT1|ELEMENT2|ELEMENT3|ELEMENT4|ELEMENT5|
If any of request elements matches this , I should display local name and its value.
Request XML :
<Root>
<element1>Test1</element1>
<child>
<element2>222</element2>
</child>
<secondChild>
<element2>234</element2>
</secondChild>
<thirdchild>
<element3>5w2</element3>
</thirdchild>
</Root>
XSL:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="text"/>
<xsl:variable name="lower" select="'abcdefghijklmnopqrstuvwxyz'"/>
<xsl:variable name="upper" select="'ABCDEFGHIJKLMNOPQRSTUVWXYZ'"></xsl:variable>
<xsl:variable name="list"><xsl:value-of select="'|ELEMENT1|ELEMENT2|ELEMENT3|ELEMENT4|ELEMENT5|'"/></xsl:variable>
<xsl:template match="/">
<xsl:for-each select="//*[contains(translate($list,$lower,$upper),concat('|',translate(local-name(),$lower,$upper),'|'))]">
<xsl:value-of select="concat(local-name(),':',.,'|')"></xsl:value-of>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Expected Output :
element1:Test1|element2:222|element3:5w2|
But I am getting
element1:Test1|element2:222|element2:234|element3:5w2|
This is because I have element2 in two places in XML. I should not read second element2 while processing.
Can you please help on this
Filter out any elements that have a preceding element of the same name.
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text"/>
<xsl:variable name="lower" select="'abcdefghijklmnopqrstuvwxyz'" />
<xsl:variable name="upper" select="'ABCDEFGHIJKLMNOPQRSTUVWXYZ'" />
<xsl:variable name="list" select="'|ELEMENT1|ELEMENT2|ELEMENT3|ELEMENT4|ELEMENT5|'" />
<xsl:template match="/">
<xsl:for-each select="//*[
contains(
concat('|', translate($list, $lower, $upper), '|'),
concat('|', translate(local-name(), $lower, $upper), '|')
)
]">
<xsl:if test="not(preceding::*[local-name() = local-name(current())])">
<xsl:value-of select="concat(local-name(), ':', ., '|')" />
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
You can define a key
<xsl:key name="name" match="*" use="local-name()"/>
and then in your condition you check
<xsl:for-each select="//*[generate-id() = generate-id(key('name', local-name())[1])][contains(translate($list,$lower,$upper),concat('|',translate(local-name(),$lower,$upper),'|'))]">
I have a scenario where I need to convert the input XML to a CSV file. The output should have values for every attribute with their respective XPATH.
For example: If my input is
<School>
<Class>
<Student name="" class="" rollno="" />
<Teacher name="" qualification="" Employeeno="" />
</Class>
</School>
The expected output would be:
School/Class/Student/name, School/Class/Student/class, School/Class/Student/rollno,
School/Class/Teacher/name, School/Class/Teacher/qualification, School/Class/Teacher/Employeeno
An example does not always embody a rule. Assuming you want a row for each element that has any attributes, no matter where in the document it is, and a column for each attribute of an element, try:
Edit:
This is an improved version, corrected to work properly with nested elements.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="UTF-8"/>
<xsl:template match="*">
<xsl:param name="path" />
<xsl:variable name="newpath" select="concat($path, '/', name())" />
<xsl:apply-templates select="#*">
<xsl:with-param name="path" select="$newpath"/>
</xsl:apply-templates>
<xsl:if test="#*">
<xsl:text>
</xsl:text>
</xsl:if>
<xsl:apply-templates select="*">
<xsl:with-param name="path" select="$newpath"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="#*">
<xsl:param name="path" />
<xsl:value-of select="substring(concat($path, '/', name()), 2)"/>
<xsl:if test="position()!=last()">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
When applied to the following test input:
<Root>
<Parent parent="1" parent2="1b">
<Son son="11" son2="11b"/>
<Daughter daughter="12" daughter2="12b">
<Grandson grandson="121" grandson2="121b"/>
<Granddaughter granddaughter="122" granddaughter2="122b"/>
</Daughter>
<Sibling/>
</Parent>
</Root>
the result is:
Root/Parent/parent, Root/Parent/parent2
Root/Parent/Son/son, Root/Parent/Son/son2
Root/Parent/Daughter/daughter, Root/Parent/Daughter/daughter2
Root/Parent/Daughter/Grandson/grandson, Root/Parent/Daughter/Grandson/grandson2
Root/Parent/Daughter/Granddaughter/granddaughter, Root/Parent/Daughter/Granddaughter/granddaughter2
Note that the number of columns in each row can vary - this is often unacceptable in a CSV document.