Nested IF AND OR in Excel - if-statement

How do I write the formula for the following:
if B2 = "SF" and D2 = "1"
then H2 = E2 + .75
else if B2 = "SF" and D2 = ".25"
then H2 = E2 + .625
else if B2 = "CW" and D2 = "1"
then H2 = E2 + 1
I want my answers to be in H2, with data being entered into B2, D2 and E2.

=if(AND(B2="SF",D2=1)=TRUE,E2+0.75,if(AND(B2="SF",D2=0.25)=TRUE,E2+0.625,if(AND(B2="CW",D2=1)=TRUE,E2+1,0)))
Regards

Related

Wrong field names on Postgresql with ADO

I'm trying to get data from a PostgreSQL database using ADO and official PostgreSQL ODBC driver. In some cases I get wrong field names when using NextRecordset(). It looks like a bug in a driver. Is there any workaround for this?
Here is a small example. It prints 'g1' for the last field of the second recordset, but it must be 'g2'.
SQL
Create Table Test ("Field" int);
C++
_bstr_t strCnn("Provider='MSDASQL';Driver=PostgreSQL Unicode;uid=postgres;Server=127.0.0.1;port=5432;database=MyDB;pwd=password;");
_RecordsetPtr pRstCompound = NULL;
TESTHR(pRstCompound.CreateInstance(__uuidof(Recordset)));
auto Statement =
"Select '1' a1, '2' b1, '3' c1, '4' d1, '5' e1, '6' f1, \"Field\" g1 From Test;\n"
"Select '1' a2, '2' b2, '3' c2, '4' d2, '5' e2, \"Field\" f2, '7' g2 From Test;\n";
pRstCompound->Open(Statement, strCnn, adOpenForwardOnly, adLockReadOnly, adCmdText);
int intCount = 1;
while (!(pRstCompound == NULL)) {
printf("\n\nContents of recordset #%d\n", intCount++);
auto Fields = pRstCompound->Fields;
long const nFields = Fields->Count;
for (long nField = 0; nField < nFields; ++nField)
printf("%s%s",
(LPCSTR)(_bstr_t)Fields->GetItem(nField)->Name,
nField + 1 == nFields ? "\n" : "\t");
pRstCompound = pRstCompound->NextRecordset(nullptr);
}
Output:
Contents of recordset #1
a1 b1 c1 d1 e1 f1 g1
Contents of recordset #2
a2 b2 c2 d2 e2 f2 g1
Expected output:
Contents of recordset #1
a1 b1 c1 d1 e1 f1 g1
Contents of recordset #2
a2 b2 c2 d2 e2 f2 g2

How do I make the canonical PROC CALIS LINEQS example work?

I'm trying out the PROC CALIS LINEQS example outlined here (it works when I use the PATH and RAM examples) using the Wheaton dataset (I've renamed the headers to match the code below) with this code:
proc calis nobs=932 data=Wheaton;
lineqs
Anomie67 = 1.0 * f_Alien67 + E1,
Powerless67 = 0.833 * f_Alien67 + E2,
Anomie71 = 1.0 * f_Alien71 + E3,
Powerless71 = 0.833 * f_Alien71 + E4,
Education = 1.0 * f_SES + E5,
SEI = lambda * f_SES + E6,
f_Alien67 = gamma1 * f_SES + D1,
f_Alien71 = gamma2 * f_SES + beta * Alien67 + D2;
std
E1 = theta1,
E2 = theta2,
E3 = theta1,
E4 = theta2,
E5 = theta3,
E6 = theta4,
D1 = psi1,
D2 = psi2,
f_SES = phi;
cov
E1 E3 = theta5,
E2 E4 = theta5;
run;
but I get this error:
"Predictor variable Alien67 in the equation with outcome variable f_Alien71 is neither a manifest, an F, an E, nor a D variable."
What am I doing wrong?
okay, I found the error - I had to consult page 450 of the SAS OnlineDoc™: Version 8 to find the solution which is basically to change this line of code:
f_Alien71 = gamma2 * f_SES + beta * Alien67 + D2;
to
f_Alien71 = gamma2 * f_SES + beta * f_Alien67 + D2;
I got a clue when I was reading page 450 because V5 in the book which corresponds to SEI in the code was using F3 (which was f_SES) as an input and then I noticed that the input to F2 in the book (which was f_Alien71 in the code) was F1 (which was f_Alien67 in the code) and I found that there was a mismatch.

Reading csv with several subgroups

I have a csv-file that contains "pivot-like" data that I would like to store into a pandas DataFrame. The original data file is divided using different number of whitespaces to differentiate between the level in the pivot-data like so:
Text that I do not want to include,,
,Text that I do not want to include,Text that I do not want to include
,header A,header B
Total,100,100
A,,2.15
a1,,2.15
B,,0.22
b1,,0.22
" slightly longer name"...,,0.22
b3,,0.22
C,71.08,91.01
c1,57.34,73.31
c2,5.34,6.76
c3,1.33,1.67
x1,0.26,0.33
x2,0.26,0.34
x3,0.48,0.58
x4,0.33,0.42
c4,3.52,4.33
x5,0.27,0.35
x6,0.21,0.27
x7,0.49,0.56
x8,0.44,0.47
x9,0.15,0.19
x10,,0.11
x11,0.18,0.23
x12,0.18,0.23
x13,0.67,0.85
x14,0.24,0.2
x15,0.68,0.87
c5,0.48,0.76
x16,,0.15
x17,0.3,0.38
x18,0.18,0.23
d2,6.75,8.68
d3,0.81,1.06
x19,0.3,0.38
x20,0.51,0.68
Others,24.23,0
N/A,,
"Text that I do not want to include(""at all"") ",,
(It looks aweful, but you should be able to paste in e.g. Notepad to see it a bit clearer)
Basically, there are only two columns a and b, but the rows are indented using 0, 3, 6, 9, ... etc whitespaces to differentiate between the levels. So for instance,
zero level, the main group, A has 0 spaces,
first level a1 has 3 spaces,
second level a2 has 6 spaces,
third level a3 has 9 spaces and
fourth and final level has 12 spaces with the corresponding values for columns a and b respectively.
I would now like to be able to read and group this data on these levels in order to create a new summarizing DataFrame, with columns corresponding to these different levels, looking like:
Level 4 Diff(a,b) Level 0 Level 1 Level 2 Level 3
x7 525 C c1 c2 c3
x5 -0.03 A a1 a22 NaN
x4 -0.04 A a1 a22 NaN
x8 -0.08 C c1 c2 c3
…
Any clue on how to do this?
Thanks
Easiest is to split this into different functions
read the file
parse the lines
generate the 'tree'
construct the DataFrame
Parse the lines
def parse_file(file):
import ast
import re
pat = re.compile(r'^( *)(\w+),([\d.]+),([\d.]+)$')
for line in file:
r = pat.match(line)
if r:
spaces, label, a, b = r.groups()
diff = ast.literal_eval(a) - ast.literal_eval(b)
yield len(spaces)//3, label, diff
Reads each line, yields the level, 'label' and diff using a regular expression. I use ast to convert the string to int or float
Generate the tree
def parse_lines(lines):
previous_label = list(range(5))
for level, label, diff in lines:
previous_label[level] = label
if level == 4:
yield tuple(previous_label), diff
Initiates a list of length 5, and then overwrites the level this node is on.
Construct the DataFrame
with StringIO(file_content) as file:
lines = parse_file(file)
index, data = zip(*parse_lines(lines))
idx = pd.MultiIndex.from_tuples(index, names=[f'level_{i}' for i in range(len(index[0]))])
df = pd.DataFrame(data={'Diff(a,b)': list(data)}, index=idx)
Opens the file, constructs the index and generates the DataFrame with the different levels in the index. If you don't want this, you can add a .reset_index() or construct the DataFrame slightly different
df
level_0 level_1 level_2 level_3 level_4 Diff(a,b)
A a1 a2 a3 x1 -0.07
A a1 a2 a3 x2 -0.08000000000000002
A a1 a22 a3 x3 -0.04999999999999999
A a1 a22 a3 x4 -0.04000000000000001
A a1 a22 a3 x5 -0.03
A a1 a22 a3 x6 -0.06999999999999998
C c1 c2 c3 x7 525.0
C c1 c2 c3 x8 -0.08000000000000002
alternative for missing levels
def parse_lines(lines):
labels = [None] * 5
previous_level = None
for level, label, diff in lines:
labels[level] = label
if level == 4:
if previous_level < 3:
labels = labels[:previous_level + 1] + [None] * (5 - previous_level)
labels[level] = label
yield tuple(labels), diff
previous_level = level
the items under a22 don't seem to have a level_3, so it copies that from the previous. If this is unwanted, you can take this variation
df
level_0 level_1 level_2 level_3 level_4 Diff(a,b)
C c1 c2 c3 x1 -0.07
C c1 c2 c3 x2 -0.08000000000000002
C c1 c2 c3 x3 -0.09999999999999998
C c1 c2 c3 x4 -0.08999999999999997
C c1 c2 c4 x5 -0.07999999999999996
C c1 c2 c4 x6 -0.060000000000000026
C c1 c2 c4 x7 -0.07000000000000006
C c1 c2 c4 x8 -0.02999999999999997
C c1 c2 c4 x9 -0.04000000000000001
C c1 c2 c4 x11 -0.05000000000000002
C c1 c2 c4 x12 -0.05000000000000002
C c1 c2 c4 x13 -0.17999999999999994
C c1 c2 c4 x14 0.03999999999999998
C c1 c2 c4 x15 -0.18999999999999995
C c1 c2 c5 x17 -0.08000000000000002
C c1 c2 c5 x18 -0.05000000000000002
C c1 d2 d3 x19 -0.08000000000000002
C c1 d2 d3 x20 -0.17000000000000004

Python Pandas Dataframe merge and pick only few columns

I have a basic question on dataframe merge. After I merge two dataframe , is there a way to pick only few columns in the result.
Taking an example from documentation
https://pandas.pydata.org/pandas-docs/stable/merging.html#
left = pd.DataFrame({'key1': ['K0', 'K0', 'K1', 'K2'],
'key2': ['K0', 'K1', 'K0', 'K1'],
'A': ['A0', 'A1', 'A2', 'A3'],
'B': ['B0', 'B1', 'B2', 'B3']})
right = pd.DataFrame({'key1': ['K0', 'K1', 'K1', 'K2'],
'key2': ['K0', 'K0', 'K0', 'K0'],
'C': ['C0', 'C1', 'C2', 'C3'],
'D': ['D0', 'D1', 'D2', 'D3']})
result = pd.merge(left, right, on=['key1', 'key2'])
Result comes as :
A B key1 key2 C D
0 A0 B0 K0 K0 C0 D0
1 A2 B2 K1 K0 C1 D1
2 A2 B2 K1 K0 C2 D2
None
Is there a way I can chose only column 'C' from 'right' dataframe? For example, I would like my result to be like:
A B key1 key2 C
0 A0 B0 K0 K0 C0
1 A2 B2 K1 K0 C1
2 A2 B2 K1 K0 C2
None
result = pd.merge(left, right[['key1','key2','C']], on=['key1', 'key2'])
OR
right.merge(left, on=['key1','key2'])[['A','B','C','key1','key2']]

Extract "Red" "Blue" "Circle" "Black" from "RedBlueCircleBlack" using capital as delimiter?

Is this a RegEx problem?
To note: there will always be only four items, each starts with a capital letter, each will be in order (color,color,shape,color):
"BlackWhiteTriangleGreen" etc.
So,
a="BlackWhiteTriangleGreen"
yields:
c1 = "Black"
c2 = "White"
S = "Triangle"
c3 = "Green"
EDIT: referencing the post suggested by Alex K., an AS3 solution as follows works:
private function UpperCaseArray(input:String):void {
var result:String = input.replace(/([A-Z]+)/g, ",$1").replace(/^,/, "");
var b:Array=result.split(",");
c1 = b[0];
c2 = b[1];
S = b[2];
c3 = b[3];
}
referencing the post suggested by Alex K., an AS3 solution as follows works:
private function UpperCaseArray(input:String):void {
var result:String = input.replace(/([A-Z]+)/g, ",$1").replace(/^,/, "");
var b:Array=result.split(",");
c1 = b[0];
c2 = b[1];
S = b[2];
c3 = b[3];
}