Why Django ORM failing on simple foreign key relation? - django

Question

I'm trying to simply create one to many relation model of categories using Django amazing ORM.
SQL:
create table categories(
id serial primary key not null,
parent_id int
);
insert into categories values(default,default,default);
update categories set parent_id = 1 where id > 1;
select * from categories;
id | parent_id
----+-----------
2 | 1
3 | 1
1 |
(3 rows)
Django amazing orm model:
class Categories(models.Model):
id = models.AutoField(primary_key=True)
parent_id = models.ForeignKey('self')
class Meta:
managed = False
db_table = 'categories'
Django Query:
Categories.objects.get(id=1)
OUTPUT:
django.db.utils.ProgrammingError: column categories.parent_id_id does not exist
LINE 1: SELECT "categories"."id", "categories"."parent_id_id" FROM "...
^
HINT: Perhaps you meant to reference the column "categories.parent_id".
Why it uses parent_id_id column instead of parent_id and how I can force it to use parent_id?
EDIT
I just changed parent_id field to parent.
EDIT 2
tatlar answer is not in my case becouse i already have database schema.
So after digging more deeper in documentation and other questions on stackoverflow there is what i have in result. This model contains reference to parent and children categories for each row. It could be inherited for all graph alike data models (comments, categories etc).
class Categories(models.Model):
id = models.AutoField(primary_key=True)
parent = models.ForeignKey('self', on_delete=None, parent_link=True, related_name='children')
class Meta:
managed = False
db_table = 'categories'
Get all children for category 1:
from myapp.models import Categories
ch = Categories.objects.get(id=1).children print (ch)
# <QuerySet [<Categories: Categories object (2)>, <Categories: Categories object (3)>]>
Get parent for category 2:
from myapp.models import Categories
ch = Categories.objects.get(id=1).parent
print (ch)
# <Categories: Categories object (1)>

Answer 1

Sorry to hear that you are having trouble with Django. In time you may grow to love the Django ORM and how it abstracts all the SQL code for you :)
You need to dig a little deeper into how the ORM works -- it's not a 1:1 replacement for SQL code. Check out the Model docs.
In your specific case, you need to create a new class called Parent and reference that class (via a ForeignKey) from your Categories class (you might also like to rename your Categories class to Category -- the ORM also handles plurals).
Try the code below (where I have already renamed Categories to Category for you):
from django.db import models
class Category(models.Model):
id = models.AutoField(primary_key=True)
parent = models.ForeignKey(Parent)
# ... Extra model attributes
class Meta:
verbose_name_plural = "categories"
class Parent(models.Model):
id = models.AutoField(primary_key=True)
# ... Extra model attributes
Then add all the extra attributes you need. This will create all the database tables, and their relationships, without you ever writing any SQL. If you are used to writing SQL it is a change, but it makes sense as you work more with the ORM and understand how good it is actually architected.
Good luck!

Answer 2

tatlar answer is not in my case becouse i already have database schema.
So after digging more deeper in documentation and other questions on stackoverflow there is what i have in result. This model contains reference to parent and children categories for each row. It could be inherited for all graph alike data models (comments, categories etc).
class Categories(models.Model):
id = models.AutoField(primary_key=True)
parent = models.ForeignKey('self', on_delete=None, parent_link=True, related_name='children')
class Meta:
managed = False
db_table = 'categories'
Get all children for category 1:
from myapp.models import Categories
ch = Categories.objects.get(id=1).children
print (ch)
# <QuerySet [<Categories: Categories object (2)>, <Categories: Categories object (3)>]>
Get parent for category 2:
from myapp.models import Categories
ch = Categories.objects.get(id=1).parent
print (ch)
# <Categories: Categories object (1)>