Django: Passing request to my modely.py - django

Question

in order to generate the full url in the email I send to the ticket purchaser, I have to access get_current_site in my models.py. To do so I pass request like this: get_absolute_url(request)
Is there anything wrong in doing it that way, or would you consider this as good code/approach?
def checkout_page(request):
[...]
#Send email
subject = render_to_string('checkout/email/your_ticket_subject.txt', {})
to_email = [transaction_profile.cleaned_data['email'],]
email_ticket_link = t.get_absolute_url(request, email=True)
content = render_to_string('checkout/email/your_ticket_message.txt', {'email_ticket_link': email_ticket_link,})
send_mail(subject, content, settings.DEFAULT_FROM_EMAIL, to_email)
ticket_link = t.get_absolute_url(request)
return redirect(ticket_link)
models.py
class TicketPurchase(models.Model):
order = models.ForeignKey(Order, on_delete=models.CASCADE) #change CASCADE
ticket = models.ForeignKey(Ticket, on_delete=models.CASCADE) #change CASCADE
ticketpurchase_id = models.CharField(max_length=10, unique=True)
refunded = models.BooleanField(default=False)
timestamp = models.DateTimeField(auto_now_add=True)
update = models.DateTimeField(auto_now=True)
def get_absolute_url(self, request, email=False):
ticket_link = reverse("ticketsgenerator:show_tickets",
kwargs={"order_id": self.order.order_id, "customer_key": self.order.customer_key}
)
if email:
current_site = get_current_site(request)
return 'https://{}{}'.format(current_site, ticket_link)
return ticket_link