How to define the function composition in c++17? - c++

I would like to compute the function composition -- f ( g (param) ). Here is what I tried:
auto fComposition(auto&& f, auto&& g, auto&&... params)
{
/* some stuff */
auto result = std::forward<decltype(f)>(f)(
std::forward<decltype(g)>(g)(
std::forward<decltype(params)>(param)
)
);
/* other stuff */
return result;
};
Compiling with
g++ -std=c++17 src.cpp
basic test
#include <random>
#include <math.h>
int main()
{
std::random_device rd;
std::mt19937 gen(rd());
std::uniform_real_distribution<double> distr(-1.0, 1.0);
auto xx = fComposition(round, distr, gen);
return 0;
}
I've got the message that it doesn't recognize the type of first function .

BTW, is this really your code? You're not expanding params so it should not compile.
I. The way you define composition, it is indistinguishable from a simple invocation: your fComposition(f, g, arg) is the same as f(g(arg)) except for extra characters typing. The real composition is usually a combinator that accepts two functions and returns a closure that, when invoked on actual arguments, applies them in succession. Something like:
template<class F, class G> auto comp(F f, G g) {
return [f, g](auto &&... args) {
return f(g(std::forward<decltype(args)>(args)...));
};
}
(Note by-values bindings. In C++17, they are more advanced than twenty years ago. :) You can add std::moves and std::forwards by taste.)
This way you compose two functions:
auto fg = comp(f, g);
and later invoke the result on arguments:
auto x = fg(arg1, arg2);
II. But really, why limit ourselves with two operands? In Haskell, (.) is a single binary function. In C++, we can have a whole tree of overloads:
template<class Root, class... Branches> auto comp(Root &&root, Branches &&... branches) {
return [root, branches...](auto &&...args) {
return root(branches(std::forward<decltype(args)>(args)...)...);
};
}
Now you can encapsulate any AST in a single callable:
int f(int x, int y) { return x + y; }
int g(int x) { return x * 19; }
int h(int x) { return x + 2; }
#include <iostream>
int main() {
auto fgh = comp(f, g, h);
std::cout << fgh(2) << '\n';
}
A similar technique was the only way known to me to have anonymous closures in C++ prior to 11 standard.
III. But wait, is there a library solution? In fact, yes. From std::bind's description
If the stored argument arg is of type T for which std::is_bind_expression<T>::value == true (for example, another bind expression was passed directly into the initial call to bind), then bind performs function composition: instead of passing the function object that the bind subexpression would return, the subexpression is invoked eagerly, and its return value is passed to the outer invokable object. If the bind subexpression has any placeholder arguments, they are shared with the outer bind (picked out of u1, u2, ...). Specifically, the argument vn in the std::invoke call above is arg(std::forward<Uj>(uj)...) and the type Vn in the same call is std::result_of_t<T cv &(Uj&&...)>&& (cv qualification is the same as that of g).
Sorry, no examples here at this moment. >_<
P.S. And yes, std::round is an overloaded function so you should typecast it to specify which exactly overload you need to be composed.

The include of random includes cmath, which in libstdc++ also defines several of the math operators (including round) in the default namespace as well as in the std namespace. (See this answer for the rationale.) And C++'s round has multiple overloads. As a result, you have several versions of round available, and your function doesn't know which round you want to use, thus the error message about ambiguity. The correct solution is to disambiguate which round you mean. You can do this with a static cast:
static_cast<double(*)(double)>(round)
Since you have to go through the trouble anyway, you may as well also use the cmath header instead of math.h and use std::round instead. At least then you know that it's going to be overloaded up front.

Related

Is there a way to "return" multiple values to call inside another function? C++ [duplicate]

Is there a preferred way to return multiple values from a C++ function? For example, imagine a function that divides two integers and returns both the quotient and the remainder. One way I commonly see is to use reference parameters:
void divide(int dividend, int divisor, int& quotient, int& remainder);
A variation is to return one value and pass the other through a reference parameter:
int divide(int dividend, int divisor, int& remainder);
Another way would be to declare a struct to contain all of the results and return that:
struct divide_result {
int quotient;
int remainder;
};
divide_result divide(int dividend, int divisor);
Is one of these ways generally preferred, or are there other suggestions?
Edit: In the real-world code, there may be more than two results. They may also be of different types.
In C++11 you can:
#include <tuple>
std::tuple<int, int> divide(int dividend, int divisor) {
return std::make_tuple(dividend / divisor, dividend % divisor);
}
#include <iostream>
int main() {
using namespace std;
int quotient, remainder;
tie(quotient, remainder) = divide(14, 3);
cout << quotient << ',' << remainder << endl;
}
In C++17:
#include <tuple>
std::tuple<int, int> divide(int dividend, int divisor) {
return {dividend / divisor, dividend % divisor};
}
#include <iostream>
int main() {
using namespace std;
auto [quotient, remainder] = divide(14, 3);
cout << quotient << ',' << remainder << endl;
}
or with structs:
auto divide(int dividend, int divisor) {
struct result {int quotient; int remainder;};
return result {dividend / divisor, dividend % divisor};
}
#include <iostream>
int main() {
using namespace std;
auto result = divide(14, 3);
cout << result.quotient << ',' << result.remainder << endl;
// or
auto [quotient, remainder] = divide(14, 3);
cout << quotient << ',' << remainder << endl;
}
For returning two values I use a std::pair (usually typedef'd). You should look at boost::tuple (in C++11 and newer, there's std::tuple) for more than two return results.
With introduction of structured binding in C++ 17, returning std::tuple should probably become accepted standard.
Personally, I generally dislike return parameters for a number of reasons:
it is not always obvious in the invocation which parameters are ins and which are outs
you generally have to create a local variable to catch the result, while return values can be used inline (which may or may not be a good idea, but at least you have the option)
it seems cleaner to me to have an "in door" and an "out door" to a function -- all the inputs go in here, all the outputs come out there
I like to keep my argument lists as short as possible
I also have some reservations about the pair/tuple technique. Mainly, there is often no natural order to the return values. How is the reader of the code to know whether result.first is the quotient or the remainder? And the implementer could change the order, which would break existing code. This is especially insidious if the values are the same type so that no compiler error or warning would be generated. Actually, these arguments apply to return parameters as well.
Here's another code example, this one a bit less trivial:
pair<double,double> calculateResultingVelocity(double windSpeed, double windAzimuth,
double planeAirspeed, double planeCourse);
pair<double,double> result = calculateResultingVelocity(25, 320, 280, 90);
cout << result.first << endl;
cout << result.second << endl;
Does this print groundspeed and course, or course and groundspeed? It's not obvious.
Compare to this:
struct Velocity {
double speed;
double azimuth;
};
Velocity calculateResultingVelocity(double windSpeed, double windAzimuth,
double planeAirspeed, double planeCourse);
Velocity result = calculateResultingVelocity(25, 320, 280, 90);
cout << result.speed << endl;
cout << result.azimuth << endl;
I think this is clearer.
So I think my first choice, in general, is the struct technique. The pair/tuple idea is likely a great solution in certain cases. I'd like to avoid the return parameters when possible.
std::pair<int, int> divide(int dividend, int divisor)
{
// :
return std::make_pair(quotient, remainder);
}
std::pair<int, int> answer = divide(5,2);
// answer.first == quotient
// answer.second == remainder
std::pair is essentially your struct solution, but already defined for you, and ready to adapt to any two data types.
There are a bunch of ways to return multiple parameters. I'm going to be exhastive.
Use reference parameters:
void foo( int& result, int& other_result );
Use pointer parameters:
void foo( int* result, int* other_result );
which has the advantage that you have to do a & at the call-site, possibly alerting people it is an out-parameter.
Write an out<?> template and use it:
template<class T>
struct out {
std::function<void(T)> target;
out(T* t):target([t](T&& in){ if (t) *t = std::move(in); }) {}
out(std::optional<T>* t):target([t](T&& in){ if (t) t->emplace(std::move(in)); }) {}
out(std::aligned_storage_t<sizeof(T), alignof(T)>* t):
target([t](T&& in){ ::new( (void*)t ) T(std::move(in)); } ) {}
template<class...Args> // TODO: SFINAE enable_if test
void emplace(Args&&...args) {
target( T(std::forward<Args>(args)...) );
}
template<class X> // TODO: SFINAE enable_if test
void operator=(X&&x){ emplace(std::forward<X>(x)); }
template<class...Args> // TODO: SFINAE enable_if test
void operator()(Args...&&args){ emplace(std::forward<Args>(args)...); }
};
then we can do:
void foo( out<int> result, out<int> other_result )
and all is good. foo is no longer able to read any value passed in as a bonus.
Other ways of defining a spot you can put data can be used to construct out. A callback to emplace things somewhere, for example.
We can return a structure:
struct foo_r { int result; int other_result; };
foo_r foo();
whick works ok in every version of C++, and in c++17 this also permits:
auto&&[result, other_result]=foo();
at zero cost. Parameters can even not even be moved thanks to guaranteed elision.
We could return a std::tuple:
std::tuple<int, int> foo();
which has the downside that parameters are not named. This permits the c++17:
auto&&[result, other_result]=foo();
as well. Prior to c++17 we can instead do:
int result, other_result;
std::tie(result, other_result) = foo();
which is just a bit more awkward. Guaranteed elision doesn't work here, however.
Going into stranger territory (and this is after out<>!),
We can use continuation passing style:
void foo( std::function<void(int result, int other_result)> );
and now callers do:
foo( [&](int result, int other_result) {
/* code */
} );
a benefit of this style is you can return an arbitrary number of values (with uniform type) without having to manage memory:
void get_all_values( std::function<void(int)> value )
the value callback could be called 500 times when you get_all_values( [&](int value){} ).
For pure insanity, you could even use a continuation on the continuation.
void foo( std::function<void(int, std::function<void(int)>)> result );
whose use looks like:
foo( [&](int result, auto&& other){ other([&](int other){
/* code */
}) });
which would permit many-one relationships between result and other.
Again with uniforn values, we can do this:
void foo( std::function< void(span<int>) > results )
here, we call the callback with a span of results. We can even do this repeatedly.
Using this, you can have a function that efficiently passes megabytes of data without doing any allocation off the stack.
void foo( std::function< void(span<int>) > results ) {
int local_buffer[1024];
std::size_t used = 0;
auto send_data=[&]{
if (!used) return;
results({ local_buffer, used });
used = 0;
};
auto add_datum=[&](int x){
local_buffer[used] = x;
++used;
if (used == 1024) send_data();
};
auto add_data=[&](gsl::span<int const> xs) {
for (auto x:xs) add_datum(x);
};
for (int i = 0; i < 7+(1<<20); ++i) {
add_datum(i);
}
send_data(); // any leftover
}
Now, std::function is a bit heavy for this, as we would be doing this in zero-overhead no-allocation environments. So we'd want a function_view that never allocates.
Another solution is:
std::function<void(std::function<void(int result, int other_result)>)> foo(int input);
where instead of taking the callback and invoking it, foo instead returns a function which takes the callback.
foo(7)([&](int result, int other_result){ /* code */ });
this breaks the output parameters from the input parameters by having separate brackets.
Use a Generator:
With variant and c++20 coroutines, you could make foo a generator of a variant of the return types (or just the return type). The syntax is not yet fixed, so I won't give examples.
Use signals/slot style:
In the world of signals and slots, a function that exposes a set of signals:
template<class...Args>
struct broadcaster;
broadcaster<int, int> foo();
allows you to create a foo that does work async and broadcasts the result when it is finished.
Use pipelines:
Down this line we have a variety of pipeline techniques, where a function doesn't do something but rather arranges for data to be connected in some way, and the doing is relatively independant.
foo( int_source )( int_dest1, int_dest2 );
then this code doesn't do anything until int_source has integers to provide it. When it does, int_dest1 and int_dest2 start recieving the results.
It's entirely dependent upon the actual function and the meaning of the multiple values, and their sizes:
If they're related as in your fraction example, then I'd go with a struct or class instance.
If they're not really related and can't be grouped into a class/struct then perhaps you should refactor your method into two.
Depending upon the in-memory size of the values you're returning, you may want to return a pointer to a class instance or struct, or use reference parameters.
With C++17 you can also return one ore more unmovable/uncopyable values (in certain cases). The possibility to return unmovable types come via the new guaranteed return value optimization, and it composes nicely with aggregates, and what can be called templated constructors.
template<typename T1,typename T2,typename T3>
struct many {
T1 a;
T2 b;
T3 c;
};
// guide:
template<class T1, class T2, class T3>
many(T1, T2, T3) -> many<T1, T2, T3>;
auto f(){ return many{string(),5.7, unmovable()}; };
int main(){
// in place construct x,y,z with a string, 5.7 and unmovable.
auto [x,y,z] = f();
}
The pretty thing about this is that it is guaranteed to not cause any copying or moving. You can make the example many struct variadic too. More details:
Returning variadic aggregates (struct) and syntax for C++17 variadic template 'construction deduction guide'
The OO solution for this is to create a ratio class. It wouldn't take any extra code (would save some), would be significantly cleaner/clearer, and would give you some extra refactorings letting you clean up code outside this class as well.
Actually I think someone recommended returning a structure, which is close enough but hides the intent that this needs to be a fully thought-out class with constructor and a few methods, in fact, the "method" that you originally mentioned (as returning the pair) should most likely be a member of this class returning an instance of itself.
I know your example was just an "Example", but the fact is that unless your function is doing way more than any function should be doing, if you want it to return multiple values you are almost certainly missing an object.
Don't be afraid to create these tiny classes to do little pieces of work--that's the magic of OO--you end up breaking it down until every method is very small and simple and every class small and understandable.
Another thing that should have been an indicator that something was wrong: in OO you have essentially no data--OO isn't about passing around data, a class needs to manage and manipulate it's own data internally, any data passing (including accessors) is a sign that you may need to rethink something..
There is precedent for returning structures in the C (and hence C++) standard with the div, ldiv (and, in C99, lldiv) functions from <stdlib.h> (or <cstdlib>).
The 'mix of return value and return parameters' is usually the least clean.
Having a function return a status and return data via return parameters is sensible in C; it is less obviously sensible in C++ where you could use exceptions to relay failure information instead.
If there are more than two return values, then a structure-like mechanism is probably best.
C++17, using std::make_tuple, structured binding and as much auto as possible:
#include <tuple>
#include <string>
#include <cstring>
auto func() {
// ...
return std::make_tuple(1, 2.2, std::string("str"), "cstr");
}
int main() {
auto [i, f, s, cs] = func();
return i + f + s.length() + strlen(cs);
}
With -O1 this optimizes out completely: https://godbolt.org/z/133rT9Pcq
-O3 needed only to optimize out std::string: https://godbolt.org/z/Mqbez73Kf
And here: https://godbolt.org/z/WWKvE3osv you can see GCC storing all the returned values packed together in a single chunk of memory (rdi+N), POD-style, proving there is no performance penalty.
Use a struct or a class for the return value. Using std::pair may work for now, but
it's inflexible if you decide later you want more info returned;
it's not very clear from the function's declaration in the header what is being returned and in what order.
Returning a structure with self-documenting member variable names will likely be less bug-prone for anyone using your function. Putting my coworker hat on for a moment, your divide_result structure is easy for me, a potential user of your function, to immediately understand after 2 seconds. Messing around with ouput parameters or mysterious pairs and tuples would take more time to read through and may be used incorrectly. And most likely even after using the function a few times I still won't remember the correct order of the arguments.
If your function returns a value via reference, the compiler cannot store it in a register when calling other functions because, theoretically, the first function can save the address of the variable passed to it in a globally accessible variable, and any subsecuently called functions may change it, so the compiler will have (1) save the value from registers back to memory before calling other functions and (2) re-read it when it is needed from the memory again after any of such calls.
If you return by reference, optimization of your program will suffer
Here, i am writing a program that is returning multiple values(more than two values) in c++. This program is executable in c++14 (G++4.9.2). program is like a calculator.
# include <tuple>
# include <iostream>
using namespace std;
tuple < int,int,int,int,int > cal(int n1, int n2)
{
return make_tuple(n1/n2,n1%n2,n1+n2,n1-n2,n1*n2);
}
int main()
{
int qut,rer,add,sub,mul,a,b;
cin>>a>>b;
tie(qut,rer,add,sub,mul)=cal(a,b);
cout << "quotient= "<<qut<<endl;
cout << "remainder= "<<rer<<endl;
cout << "addition= "<<add<<endl;
cout << "subtraction= "<<sub<<endl;
cout << "multiplication= "<<mul<<endl;
return 0;
}
So, you can clearly understand that in this way you can return multiple values from a function. using std::pair only 2 values can be returned while std::tuple can return more than two values.
I tend to use out-vals in functions like this, because I stick to the paradigm of a function returning success/error codes and I like to keep things uniform.
Alternatives include arrays, generators, and inversion of control, but none is appropriate here.
Some (e.g. Microsoft in historical Win32) tend to use reference parameters for simplicity, because it's clear who allocates and how it will look on the stack, reduces the proliferation of structures, and allows a separate return value for success.
"Pure" programmers prefer the struct, assuming it is the function value (as is the case here), rather than something that's touched incidentally by the function. If you had a more complicated procedure, or something with state, you'd probably use references (assuming you have a reason for not using a class).
I'd say there is no preferred method, it all depends on what you're going to do with the response. If the results are going to be used together in further processing then structures make sense, if not I'd tend to pass then as individual references unless the function was going to be used in a composite statement:
x = divide( x, y, z ) + divide( a, b, c );
I often choose to pass 'out structures' by reference in the parameter list rather than having the pass by copy overhead of returning a new structure (but this is sweating the small stuff).
void divide(int dividend, int divisor, Answer &ans)
Are out parameters confusing? A parameter sent as reference suggests the value is going to change (as opposed to a const reference). Sensible naming also removes confusion.
Why do you insist on a function with multiple return values? With OOP you can use a class offering a regular function with a single return value, and any number of additional "return values" like below. The advantage is that the caller has a choice of looking at the extra data members, but is not required to do this. This is the preferred method for complicated data base or networking calls, where lots of additional return info may be needed in case errors occur.
To answer your original question, this example has a method to return the quotient, which is what most callers may need, and additionally, after the method call, you can get the remainder as a data member.
class div{
public:
int remainder;
int quotient(int dividend, int divisor){
remainder = ...;
return ...;
}
};
Boost tuple would be my preferred choice for a generalized system of returning more than one value from a function.
Possible example:
include "boost/tuple/tuple.hpp"
tuple <int,int> divide( int dividend,int divisor )
{
return make_tuple(dividend / divisor,dividend % divisor )
}
rather than returning multiple values,just return one of them and make a reference of others in the required function for eg:
int divide(int a,int b,int quo,int &rem)
Here is the link to the "core guidelines" (by Bjarne Stroustrup and Herb Sutter) on this topic.
https://isocpp.github.io/CppCoreGuidelines/CppCoreGuidelines#Rf-out-multi
Partial Quote:
F.21: To return multiple “out” values, prefer returning a struct or tuple
Reason A return value is self-documenting as an “output-only” value. Note that C++ does have multiple return values, by convention of using a tuple (including pair), possibly with the extra convenience of tie or structured bindings (C++17) at the call site. Prefer using a named struct where there are semantics to the returned value. Otherwise, a nameless tuple is useful in generic code.
We can declare the function such that, it returns a structure type user defined variable or a pointer to it . And by the property of a structure, we know that a structure in C can hold multiple values of asymmetrical types (i.e. one int variable, four char variables, two float variables and so on…)
I would just do it by reference if it's only a few return values but for more complex types you can also just do it like this :
static struct SomeReturnType {int a,b,c; string str;} SomeFunction()
{
return {1,2,3,string("hello world")}; // make sure you return values in the right order!
}
use "static" to limit the scope of the return type to this compilation unit if it's only meant to be a temporary return type.
SomeReturnType st = SomeFunction();
cout << "a " << st.a << endl;
cout << "b " << st.b << endl;
cout << "c " << st.c << endl;
cout << "str " << st.str << endl;
This is definitely not the prettiest way to do it but it will work.
Quick answer:
#include <iostream>
using namespace std;
// different values of [operate] can return different number.
int yourFunction(int a, int b, int operate)
{
a = 1;
b = 2;
if (operate== 1)
{
return a;
}
else
{
return b;
}
}
int main()
{
int a, b;
a = yourFunction(a, b, 1); // get return 1
b = yourFunction(a, b, 2); // get return 2
return 0;
}

Is there an existing name for this type and function?

There are 2 hard problems in computer science: cache invalidation, naming things and off-by-one errors.
This is about the 2nd problem: naming things.
I'm looking if this technique or type has been used somewhere else already and has a name. dichotomy is an ok name, but bools_at_compile_time is a horrible one.
using dichotomy_t = std::variant<std::false_type, std::true_type>;
// (or a struct that inherits from that, and overloads operator bool())
constexpr dichotomy_t dichotomy( bool b ) {
if (b) return std::true_type{};
return std::false_type{};
}
template<class F, class...Bools>
constexpr auto bools_at_compile_time( F&& f, Bools...bools ) {
static_assert( (std::is_same<Bools, bool>{} && ...) );
return std::visit( std::forward<F>(f), dichotomy(bools)... );
}
dichotomy_t is a variant between true and false. Its runtime representation is 0 or 1.
What this lets you do is:
auto foo( bool x, bool y ) { // <-- x and y are run-time bools here
auto func = [&](auto x, auto y) {
return some_template<x,y>(); // <-- x and y are compile-time bools here
};
return bools_at_compile_time( func, x, y ); // <-- converts runtime to compile time bools
}
Is there a name for dichotomy_t or the more general bools_at_compile_time technique? I'm looking for a name that is well known in any community (even a non-C++ one), even a verb that describes "taking a runtime value and creating a switch and a set of compile time value in generated code to pick between" better than a sentence.
Live example
A good answer would include the name, citations/quotes describing what that name means, examples of that named thing in use in the other context, and evidence that this name is equivalent to or inclusive of the above type/value and function.
(It may help to find a name the generalization of this would be an enum instead of a bool, which has a fixed number of known states, and a switch/case map that converts the runtime value into a compile-time constant in each case clause.)
I do not know of any existing names for this pattern, but if you take a good look at how the STL is naming things, you can use name close enough to make your code explicit.
I also liked the dispatcher_t idea from #Jarod42 , I think it is more generic than dichotomy_t or n_chotomy_t.
dichotomy() could be called make_variant(b). Since it will return the std::variant value of a boolean given in argument. Much like std::make_tuple makes a tuple from multiple arguments.
I would suggest to replace bools_at_compile_time by static_eval. Much like static_assert makes an assertion at compile time.
Not that if eval is not the correct adjective for your use case you can easily adapt it static_*.
#include <type_traits>
#include <variant>
#include <utility>
using dichotomy_t = std::variant<std::false_type, std::true_type>;
// (or a struct that inherits from that, and overloads operator bool())
constexpr dichotomy_t make_variant( bool b ) {
if (b) return std::true_type{};
return std::false_type{};
}
template<class F, class...Bools>
constexpr auto static_eval( F&& f, Bools...bools ) {
static_assert( (std::is_same<Bools, bool>{} && ...) );
return std::visit( std::forward<F>(f), make_variant(bools)... );
}
template<bool x, bool y>
auto some_template() {
return x || y;
}
auto foo( bool x, bool y ) { // <-- x and y are run-time bools here
auto func = [&](auto x, auto y) {
return some_template<x,y>(); // <-- x and y are compile-time bools here
};
return static_eval( func, x, y ); // <-- converts runtime to compile time bools
}
#include <iostream>
int main() {
std::cout << foo( true, true ) << "\n";
}
Generation of specialized version of a function is called cloning. (see Procedure Cloning). The term clone is used to name the specialized function generated by the optimizer during constant propagation (see gcc doc).
The set of specialized functions generated by std::visit could be named clone set.
This set is generated for all combinations of argument value. This term combination let us suppose that the set of possible value of each argument is finite.
So we could have a long name for the set of clones such as, set of clones for all combination of argument values. An other option more obscure but shorter could be combinatorial clone set.
As already pointed out, the action of selecting the right function to call in term of the argument could be called dispatch.
So I would propose combinatiorial_clone_set_dispatch or dispatch_in_combinatorial_clone_set ...
As I am unaware of a similar implementation, I'll just go type by type with bikeshed colors.
using boolean_t = std::variant<std::false_type, std::true_type>;
This is pretty self-explanatory, as it's a variant that can store one or the other of the std::integral_constants for true or false. It's kind of a bool, but bool_t is likely to cause confusion. An alternative is boolean_variant, but that may be too verbose.
constexpr boolean_t to_boolean_t( bool b ) {
if (b) return std::true_type{};
return std::false_type{};
}
I started with convert_bool, but that's a bit too generic. to_boolean_t is more expressive. make_boolean_t is also a possibility, as it is basically a boolean_t factory function. Note: I previously chose to_constexpr_boolean, but that's unnecessarily verbose.
template<class F, class...Bools>
constexpr auto static_eval( F&& f, Bools...bools ) {
static_assert( (std::is_same<Bools, bool>{} && ...) );
return std::visit( std::forward<F>(f), to_boolean_t(bools)... );
}
I chose static_eval here as I like Clonk's reasoning, but "static" has contextual meaning in C++, so alternatives are (in no order of importance):
boolean_visit
static_visit
constexpr_eval
constexpr_visit
You issue was: (bold mine)
I'm looking for a name that is well known in any community (even a
non-C++ one), even a verb that describes "taking a runtime value and
creating a switch and a set of compile time value in generated code to
pick between" better than a sentence.
There is, but only if you will adopt it from a related field of science:
The U.S. National Electrical Code (NEC) defines a switchboard as "a
large single panel, frame, or assembly of panels on which are mounted,
on the face, back, or both, switches, over-current and other
protective devices, buses, and usually instruments". The role of a
switchboard is to allow the division of the current supplied to the
switchboard into smaller currents for further distribution and to
provide switching, current protection and (possibly) metering for
those various currents. In general, switchboards may distribute power
to transformers, panelboards, control equipment, and, ultimately, to
individual system loads.
Adopting this thinking, you would simply call it switches.
I will also add that it is quite unusual to specify (ie. repeat) the storage type or cv-qualifier, etc. in type/variable names - even when not directly visible you would usually leave that as implicit - unless it really needs to be emphasized.
Maybe staticCastValue?
As in you are casting a dynamic(runtime) value to a static value.
Can be used with templates or overloads for different types.
Or maybe assertInmutable?
As in you are converting a mutable type into an inmutable one.
Or perhaps expressConstantly?
As in you are expressing the same value but in constant form.
A form similar to constexpr.
A wild one:
staticBifurcate?
As in theres two things to choose from, thus a bifurcation is there.
bifurcate
verb
/ˈbʌɪfəkeɪt/
1.
divide into two branches or forks.
"just below Cairo the river bifurcates"
Or finally convertToConstExpr?
Explicitly saying that the value will be converted to something akin or compatible with a constexpr.

Passing math expression to function

I need to make function in C++ to calculate integrals. I am using the simpsone rule to calculate value of the given integral. I know how to calculate that. I don't have any problem with math. I need to know how can I pass whole expression to make my program flexible.
I have 4 f(x) functions for which I should make calculations. For example:
f(x)=2e^x
f(x)=x^3e
etc.
I have two options to make it.
1)I can do separate function for each f(x) function.
double function1() {
...
calculations 2e^x
...
return resault;
}
double function2() {
...
calculations x^3e
...
return resault;
}
This way is easy and fast to write, but the code is not flexible at all. In this case I need to make new function for every new given f(x) function.
I would like to have one function to which I can pass selected f(x) function.
2) Second case I prefer is to make some kind of interpreter of expressions. I thought about putting the parts of expression into std::vector and then making calculations for each cell of vector.
I've seen already an idea to parse string to the expression, but I think at the end it will be almost the same as idea with vector. I can be wrong.
What is the best way to make my code flexible and easy to use for users(not programmers)?
Suppose you have a function that takes two expressions and returns sum of the results of them. You can pass the expressions to function using lambda expression which is supported since C++11 as follow:
template<typename Func, typename Func2>
int calculate(Func &lambda_expr1, int param1, Func2 &lambda_expr2, int param2)
{
return lambda_expr1(param1) + lambda_expr2(param2);
}
void main()
{
// case 1
auto f1 = [](int p) {return p*p; }; // expression 1
auto f2 = [](int p) {return p*p*p; }; // expression 2
int result = calculate(f1, 3, f2, 4);
// result = 73
// case 2
result = calculate([](int p) {return p*p/2; }, 4, [](int p) {return p*p*p/3; }, 3);
// result = 17
}

C++: newton raphson and overloading functions

I wrote a simple implementation of the newton raphson root finding algorithm which takes an initial guess init, a unary function f and the tolerance tol as arguments, as shown below:
bool newton_raphson(double& init,
double(*f)(double),
double tol){
const int max_iter = 10000;
double next_x, soln = init;
int i = 0;
while(++i < max_iter){
next_x = soln - f(soln)/fp_x(f, soln);
if(fabs(next_x - soln) < tol){
init = next_x;
return true;
}
soln = next_x;
}
return false;
}
double fp_x(double(*f)(double),
double x){
const double h = 0.000001;
return (f(x + h) - f(x - h))/2.0/h;
}
My question is: although this works perfectly fine for unary functions, I would like to change the implementation so that it works for functions f that have more than one parameter, but all except one parameter have constant values. To clarify: if I have a function f(x) = 3x + 2 as shown below
double f(double x){
return (3*x + 2);
}
Then my implementation works. However, I would also like it to work for any functions with any given number of arguments, but only the first argument is variable. So, if I have a function f(x,y) = 3x + 2y
double f(double x, double y){
return (3*x + 2*y);
}
I would like to find the root of f(x,2), or f(x,3) using the same function, and so on for n arguments, not just one or two (please ignore the idea that the functions I showed in the example are simple linear functions, this is just an example). Is there any way to implement the function for a varying number of arguments or do I have to write an implementation for every case?
Thanks,
NAX
NOTE
As you could tell by now, this question isn't really about newton-raphson, but it makes it easier if I use it as an example for the actual question, which is a single implementation for functions of different numbers of arguments.
UPDATE
A few answers below use std::bind and std::function to solve the problem, which actually better address my question than the selected answer; however, they are c++11 library classes/functions, (which, don't get me wrong, is something I strongly urge every c++ programmer to go ahead and learn) and at the time of this writing, I was facing some problems using them; Eclipse Juno using g++ 4.7 (which is c++11 compliant) still somehow failed to recognize std::function, and I therefore decided to go and stick with the checked answer below, which also works nicely.
I think you're asking for variadic functions:
A variadic function – a function declared with a parameter list ending
with ellipsis (...) – can accept a varying number of arguments of
differing types. Variadic functions are flexible, but they are also
hazardous. The compiler can't verify that a given call to a variadic
function passes an appropriate number of arguments or that those
arguments have appropriate types. Consequently, a runtime call to a
variadic function that passes inappropriate arguments yields undefined
behavior. Such undefined behavior could be exploited to run arbitrary
code.
From here:
https://www.securecoding.cert.org/confluence/display/cplusplus/DCL31-CPP.+Do+not+define+variadic+functions
However, as quoted above, there are a number of problems with them.
Most notably, it only works for compile time!
However, if you are interested in implementing one, here's an article with a nice example:
http://www.informit.com/guides/content.aspx?g=cplusplus&seqNum=138
UPDATE:
IMO, I think you're better off defining functions that take structure or object arguments (i.e. a general function object), and writing functions that work on those arguments explicitly.
The other option is to do some compile-time reflection - which would be useful, but is too much trouble to do in such an example as this. Plus, "reflection" in C++ isn't "true" reflection, but rather a bad and incomplete implementation of it.
For what you're trying to do here, what you're looking for is std::bind (or, if you're dealing with a C++03 compiler, std::bind1st and std::bnd2nd).
These will let you "bind" values to the other parameters, leaving you with a function (technically, a function object) that only requires a single parameter.
What you'd ideally like would be something like this:
double f(double x, double y) {
return 3*x + 2*y;
}
double init = 1.0;
newton_raphson(init, std::bind2nd(f, 3), 1e-4);
Unfortunately, in real use, it's not quite that simple -- to work with std::bind2nd, you can't use an actual function; you need to use a function object instead, and it has to derive from std::binary_function.
std::bind is quite a bit more flexible, so that's what you almost certainly want to use instead (if at all possible).
I used your question as a way to force myself to learn C++11 variadic template, here is a working example.
template< typename... Ts >
double f( Ts... Vs ) {
double array[] = { Vs... };
int numArg = sizeof...( Vs );
switch (numArg) {
case 1:
return 3 * array[0] + 2;
case 2:
return 3 * array[0] + 2 * array[1];
case 3:
return 3 * array[0] + 2 * array[1] + 1 * array[3];
....
default:
return 0.0;
}
}
template< typename... Ts >
double newton_raphson( double &init, double tol,
double (*func) ( Ts... Vs ), Ts... Vs ) {
return func( Vs... );
}
you can call it like
newton_raphson( &init, 1.0, f, 1.0, 2.0, 3.0, 4.0, 5.0 );
You can use std::bind and std::function. The type std::function<double(double)> represents a functional that takes in a double and returns a double. Similarly std::function<double(int,int)> is for a functional taking 2 ints and returns a double.
#include <functional>
bool newton_raphson(double& init,
std::function<double(double)>& f,
double tol){
const int max_iter = 10000;
double next_x, soln = init;
int i = 0;
while(++i < max_iter){
next_x = soln - f(soln)/fp_x(f, soln);
if(fabs(next_x - soln) < tol){
init = next_x;
return true;
}
soln = next_x;
}
return false;
}
double myfunction(double x, double y){
return (3*x + 2*y);
}
double fp_x(std::function<double(double)> f, double x) {
...
}
...
double d = 1.0;
// Here we set y=2.5 and we tell bind that 1st parameter is unbounded
// If we wanted to switch and set x=2.5 and let y be unbounded, then
// we would use (&myfunction, 2.5, std::placeholders::_1)
newton_raphson(d, std::bind(&myfunction, std::placeholders::_1, 2.5) , 1e-6);
...

c++ functions with variable and not known number of arguments [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Variable number of arguments in C++?
May I not set the number of arguments of a function with variable number of arguments? As an example: can the following interface be implemented?
int sum(...) { ... }
sum(1, 2, 3, 4); // return 10
Conventional variadic functions are messy and not type-safe, but in C++11 you can do this cleanly using variadic templates and (compile-time) recursion:
// Base case for recursion
template <typename T>
inline T sum(T n) {
return n;
}
// Recursive case
template <typename T, typename... Args>
inline T sum(T n, Args... args) {
return n + sum(args...);
}
Since it's a template, this'll work for any types that have an operator+ defined:
std::cout << sum(1, 2, 3) << std::endl; // Prints 6
std::cout << sum(3.14, 2.72) << std::endl; // Prints 5.86
However, because the return type of the recursive template function is taken from the first argument only, you can get suprising results if you mix different argument types in one call: sum(2.5, 2) returns 4.5 as expected, but sum(2, 2.5) returns 2 because the return type is int, not double. If you want to be fancy, you can use the new alternative function syntax to specify that the return type is whatever the natural type of n + sum(args...) would be:
// Recursive case
template <typename T, typename... Args>
inline auto sum(T n, Args... args) -> decltype(n + sum(args...)) {
return n + sum(args...);
}
Now sum(2.5, 2) and sum(2, 2.5) both return 4.5.
If your actual logic is more complex than summation, and you don't want it inlined, you can use the inline template functions to put all the values into some sort of container (such as a std::vector or std::array) and pass that into the non-inline function to do the real work at the end.
You probably want to do this by writing the function to take something like a vector<int>, which you'll construct on the fly with a braced initializer list:
int sum(std::vector<int> const &n) {
return std::accumulate(begin(n), end(n), 0);
}
If there's some possibility the numbers might be (for example) floating point instead, you probably want to write it as a template instead:
template <class T>
T sum(std::vector<T> const &n) {
return std::accumulate(begin(n), end(n), T());
}
Either way, you'd invoke this just marginally differently:
int x = sum({1,2,3,4});
Warning: this feature was added to C++ fairly recently, so some compilers (e.g., VC++) don't support it yet -- though others (e.g., g++ 4.7+), do.
No, you can't.
Just don't use variable arguments. They suck in every conceivable fashion and are completely not worth anybody's time.
A C++ variadic function must know how many (and what type) of arguments it was passed. For example, printf's format string tells it what extra arguments to expect.
Your sum has no way of knowing if it got 4 ints or 10. You could make the 1st argument a length:
int sum(int howmany, ...) { ... }
so the function knows how many ints follow. But really you should just pass an array (or vector if you're feeling C++'y)
There are multiple ways to solve your issue. I'll go over a few:
Method 1:
-Create a series of overloaded sum functions to suit your needs.
Cons
-code bloat
This can be implemented by making multiple functions with headers:
int sum(int a);
int sum(int a, int b);
int sum(int a, int b, int c);
etc...
Method 2:
-create a custom class with a linked list, and pass in a pointer to the head of the linked list. This is probably your best move in this case, assuming you don't know the amount of data to be passed in.
Function header:
int sum(LinkedList *headPointer);
Method 3:
-pass in an array of variables
Function header:
int sum(int input[]);
Method 4:
-create a function with auto-set variables
Function header:
int sum(int a=0, int b=0, int c=0, int d=0,... int n=0);