render multiple template from a single view in django - django

I want to send context data to one html and want to render different html.
After login user is redirected to this dashboard view. Here I want to render two html file, the context value will be sent to one html let say temp1.html file, but user can see temp2.html file. In temp2.html and other html file, I will include temp1.html file. Is there any way to do so?
views.py
def dashboard(request):
print('in dashboard view')
object = UserSelection.objects.get(user=request.user)
if object.user_type == 'candidate':
val_cand = CandidateDetail.objects.filter(candidate_username=request.user)
if val_cand:
print('Candidate filled data') #Already filled data
data = CandidateDetail.objects.get(candidate_username=request.user)
return render(request, 'dashboard.html',{'obj':object.user_type, 'data':data})
else:
print('new user') #Registered but not filled data
return render(request, 'dashboard.html', {'obj':object.user_type})
else:
val_emp = EmployerDetail.objects.filter(name=request.user)
if val_emp:
print('Employer filled data') #Already filled data
data = EmployerDetail.objects.get(name=request.user)
return render(request, 'dashboard.html',{'obj':object.user_type, 'data':data})
else:
print('new user') #Registered but not filled data
return render(request, 'dashboard.html', {'obj':object.user_type})

You can't render two html file in single view. Please use the Django template language for the desired behaivour.
i.e) If your passing obj to dashboard.html and inside html files can also access obj.
dashboard.html
{{ obj }}
{% include 'test1.html' %}
{% include 'test2.html' %}
You can pass additional context to the template using keyword arguments:
{% include 'test1.html' with obj=obj additional_context='blah' %}
test1.html
{{ obj }}

Related

Why is my ModelForm not showing the right settings?

I have two Model Forms, one for notification types and one for privacy settings. Both show the defaults and not what is saved in the database. How can I make the form show the choice that's stored in the database instead of the defaults? Example: Say the user chose a Direct Message privacy of "Friends and Followers". When they visit the privacy options page again after having saved the changes, it shows "Open" instead of reflecting what is in the database. I tried assigning the values saved in the database directly to the form when rendering the page when the request is GET but that didn't do anything, even though the debug print shows that the value of form.dm_privacy is indeed what's in the database, it still shows "Open".
Both forms work fine, the changes get saved and everything. I don't understand why it's not reflecting the changes though, is this just something that Model Forms do and not something I can change?
privacy_options.html
{% extends "accbase.html" %}
{% block content %}
<h1>Privacy Options</h1>
<form method="post">
{% csrf_token %}
{{form.as_p}}
<button type="submit">Save</button>
</form>
{% endblock %}
views.py
#login_required
def privacy_options(request):
"""
Holds all privacy options such as.. open/closed DMs, who can see profile/posts on profile
"""
if request.method == "POST":
form = PrivacyOptionForm(request.POST)
if form.is_valid():
print("Before saving:",request.user.dm_privacy, request.user.profile_privacy, request.user.included_in_find_friends)
user = request.user.username
request.user.dm_privacy = form.cleaned_data['dm_privacy']
request.user.profile_privacy = form.cleaned_data['profile_privacy']
request.user.included_in_find_friends = form.cleaned_data['included_in_find_friends']
request.user.save()
print("After save:",request.user.dm_privacy, request.user.profile_privacy, request.user.included_in_find_friends)
return render(request, 'acc_manage/acc_nav.html', {'username':user})
else:
form = PrivacyOptionForm()
form.included_in_find_friends = request.user.included_in_find_friends
form.profile_privacy = request.user.profile_privacy
form.dm_privacy = request.user.dm_privacy
print("\n\n",form.dm_privacy, "\n\n")
return render(request, 'acc_manage/privacy_options.html', {'form': form})
Fixed it by changing form = PrivacyOptionForm() to form = PrivacyOptionForm(instance=request.user)

django, views direct to a another html page

I am using Django for develop a website. The website is intended to use to search information stored in a MySQL database.
This is the current basic flow of the web site.
1) index.html - this has a form to select an option
2) according the option, users will redirect to search.html (include a form)
3) once the user provides the criteria, the result will be displayed in reply.html
In my views.py , I have two functions.
from django.shortcuts import render
from website.models import WebsiteRepository
from .forms import SearchForm
from .forms import SelectTypeForm
def Search(request):
if request.method == 'POST':
#do something
return render(request, 'reply.html', {'env_dict':env_dict})
else:
#do something
return render(request, 'search.html', context = context)
def index(request):
if request.method =='POST':
#do something
return render(request, 'search.html', context = context)
else:
#do something
return render(request, 'index.html', context= context)
When I go to index.html page, I can select a option and it will direct me to search.html. After, I fill the form there and submit, it wont give me the reply.html page.
I have a feeling that, I could make this work by changing urls.py.
from django.urls import path
from website import views
urlpatterns = [
path('', views.index, name='index'),
#path('search/', view.Search, name ='Search')
]
I tried to google it. But its too much details and Iam kind of lost.
Do any of you guys know how to achieve this?
Thanks
search.html
{% extends "base_generic.html" %}
{% block content %}
<h3>Welcome to search information Repository</h3>
<form method="post">
{% csrf_token %}
{{form.as_p}}
<button type = 'submit'>submit</button>
</form>
{% endblock %}
index.html
{% block content %}
<h3>Welcome to information Repository</h3>
<form method="post">
{% csrf_token %}
{{form.as_p}}
<button type = 'submit'>submit</button>
</form>
just for clarify things more, ill add the forms.py too
from django import forms
from .models import WebsiteRepository
class SearchForm(forms.Form):
websiterepository = WebsiteRepository
env_indicators = websiterepository.objects.filter (key_aspect='Environmental').values_list('repo_id','indicator')
indicator = forms.ChoiceField(choices=env_indicators,label = 'Indicator' )
OPTIONS = (('2000','2000'),('2001','2001'),('2002','2002'), ('2003','2003'),('0000','0000'),)
year = forms.ChoiceField(choices=OPTIONS)
class SelectTypeForm(forms.Form):
OPTIONS = (('1', 'Envirnmental Indicators'),('2','Economic Indicators'),('3','Social Indicators'),)
types = forms.ChoiceField(choices=OPTIONS)
Your code is wrong on many points.
First thing first: for a search, you want a GET request, not a POST (POST is for updating the server's state - adding or updating your database mostly). This is the semantically correct method (since you want to GET data), and it will allow a user to bookmark the url.
Second point: you don't want to submit the search form to the index view but to the search view. No need for redirects etc, just use the {% url %} templatetag to fill the action attribute of your form (you of course need to have a 'Search' url in your urls.py):
<form method="get" action="{% url 'Search' %}">
{% csrf_token %}
{{form.as_p}}
<button type = 'submit'>submit</button>
</form>
if you want to have this form on more than one page (which is often the case for search forms), use an inclusion tag tha will take care of creating an unbound SearchForm and render the template fragment.
Then in your search view, you only want GET requests, and do not use two different templates, this will only lead to useless duplication.
def Search(request):
form = SearchForm(request.GET)
# use the form's data - if any - to get search results
# and put those results (even if empty) in you context
return render(request, 'reply.html', {'env_dict':env_dict})
And finally, your search form is totally broken:
class SearchForm(forms.Form):
# this is totally useless
websiterepository = WebsiteRepository
# this will only be evaluated once at process startup, so you will
# get stale data in production - and probably different data
# per process, in a totally unpredictable way.
# You need to either put this in the form's __init__ or wrap it
# in a callable and pass this callable
env_indicators = websiterepository.objects.filter (key_aspect='Environmental').values_list('repo_id','indicator')
indicator = forms.ChoiceField(choices=env_indicators,label = 'Indicator' )
# are you going to manually add a new year choice every year ???
OPTIONS = (('2000','2000'),('2001','2001'),('2002','2002'), ('2003','2003'),('0000','0000'),)
year = forms.ChoiceField(choices=OPTIONS)
For the "indicators" ChoiceField you want something like:
def get_indicators_choices():
return Websiterepository.objects.filter (key_aspect='Environmental').values_list('repo_id','indicator')
class SearchForm(forms.Form):
# IMPORTANT : we are NOT calling the function here, just
# passing it (python functions are objects) to the field, which
# will call it everytime the form is instanciated, so you don't
# have stale data
indicator = forms.ChoiceField(
choices=get_indicator_choices,
label='Indicator')
As a last note: be consistent with your namings (ie why name one view in all lower (index) and capitalize the other (Search) ? Whichever convention you choose (I strongly suggest respecting pep8 here), at least stick to it for the whole project.
The problem is that code is not redirecting to /search, instead rendering search.html after post from index.html.
Try doing like-
views.py-
#your code
def index(request):
#do something
if request.method == 'POST':
return redirect('Search')
else:
#render index.html
def search(request):
#do something
if request.method == 'POST':
#render reply.html
else:
#render search.html
Another way to achieve this is if you specify action in your form so that form posts on /search.
search.html
<form method="post" action="/search">
{% csrf_token %}
{{form.as_p}}
<button type = 'submit'>submit</button>
</form>

Add filename to formset for display purpose only

I have a model which contains a number of user uploaded files that other than the file itself also contain a description and some other meta information.
class ArchiveFile(models.Model):
archive_file = models.FileField(upload_to=grab_archive_folder, default=None, blank=False)
description = models.CharField(max_length=255)
What I want is for a user to (1) upload new files. And (2) be able to edit the descriptions of all files associated with the user, including the recently uploaded. The uploading of new files is done via AJAX / JQuery and new forms (as part of a formset) are generated dynamically.
In order to do be able to edit the descriptions in an efficient matter, it would help for a user to know of what file it is changing the description, and so I would like the filename to be displayed.
My initial solution was the following:
forms.py
class ArchiveDataForm(ModelForm):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self.fields['archive_file'].widget.attrs['disabled'] = True
class Meta:
model = ArchiveFile
fields = ['archive_file','description']
views
def archive_data_update(request):
if request.method == 'GET':
ArchiveDataFormSet=modelformset_factory(ArchiveFile, form=ArchiveDataForm, extra=0)
archive_formset = ArchiveDataFormSet(queryset=ArchiveFile.objects.filter(user_id=request.user.id)
template = 'archive_data_edit.html'
template_context = {
'archive_formset': archive_formset,
...
}
return render(request, template, template_context)
if request.method == 'POST':
ArchiveDataFormSet=modelformset_factory(ArchiveFile, form=ArchiveDataForm, extra=0)
archive_formset = ArchiveDataFormSet(request.POST, queryset=ArchiveFile.objects.filter(user_id=request.user.id)
if archive_formset.is_valid():
for archive_form in archive_formset:
archive_form.save()
return HttpRespone('ok')
template
{% for archive_form in archive_formset %}
{{ archive_form.archive_file.value }}
{{ archive_form.description }}
{% endfor %}
My issue is that I am getting validation errors on the dynamically created forms, saying that no file is present. Which I suppose is correct since all I do is inject the filename to the dynamically created form via my AJAX/JQuery. Is there a way I can ignore this validation for the purpose of this form only? or is there an easier/different way to display the filenames?
Some comments:
If you only want to edit the descriptions you should not include as a form field the archive_file field.
You could instead pass in your view the instance of the form to the context of the request. And then interpolate the title of the file in the template.
If you could provide your view code, we can discuss an actual implementation.
UPDATE:
Looking at the source code of model form, you hava always available the instance of the object of the form. why don't you try using that?
As in:
# template
{% for archive_form in archive_formset %}
{{ archive_form.instance.archive_file.filename }}
{{ archive_form.description }}
{% endfor %}

django adding quotes on subsequent submits

Here's the goal: when the user submits the form, use one view to send the submitted data to the database, then redirect back to the form, but with the data pre-populated. This is mostly working, but something about my implementation is wrapping extra quotes around the string. For now, I'm just using a super-simple form, btw. I enter Billy, and the pre-pop is: "Billy", if I click submit again, it comes back as: "\"Billy\"", then "\"\\\"Billy\\\"\"", and so on (as far as I have tested, anyways.
relevant views are:
def editUsers(request):
if request.method == 'POST':
# create a form instance and populate it with data from the request:
form = usersForm(request.POST)
# check whether it's valid:
# process the data in form.cleaned_data as required
# redirect to a new URL:
name = json.dumps(form.data['user_name'])
request.session['editUserName'] = name
# call out to limboLogic.py to update values
test = name
return redirect('../users')
# if a GET (or any other method) we'll create a blank form
else:
return redirect('../users')
from .forms import *
def users(request):
form = None
if 'editUserName' not in request.session:
# create a blank form
form = usersForm()
else:
# form = equipmentForm(initial='jim') - used to make sure I was branching the if/else correctly
form = usersForm(initial={'user_name':request.session['editUserName']}, auto_id=False) #limboLogic.GetUserInfo(name))
return render(request, 'limboHtml/UserManagement.html', {'form': form})
form is simply:
class usersForm(forms.Form):
user_name = forms.CharField(label='New User\'s name', max_length=100)
and the template is:
{% extends "base.html" %}
{% block content %}
<div class="row">
<p>This is the user management page</p><br>
<form action="/edit/users.html" method="post">
{% csrf_token %}
{{ form }}
<input type="submit" value="OK">
</form>
<br><p class="bold">This is below the form</p>
</div>
{% endblock %}
thoughts?
I can't quite say what the intracies are here, but the problem involves the fact that I was using a json class. I used this site as a guide and managed to fix the problem. note that the key aspect is inside the second if:
name = form.cleaned_data['user_name'] works fine,
name = json.dumps(form.data['user_name']) does not
the whole function as it now stands:
def editUsers(request):
if request.method == 'POST':
# create a form instance and populate it with data from the request:
form = usersForm(request.POST)
# check whether it's valid:
# process the data in form.cleaned_data as required
# redirect to a new URL:
if form.is_valid():
name = form.cleaned_data['user_name']
# name = json.dumps(form.data['user_name'])
request.session['editUserName'] = name
# call out to limboLogic.py to update values
test = name
return redirect('../users')
# if a GET (or any other method) we'll create a blank form
return redirect('../users')

How do I input two views in a template

I am trying to create a template that contains a form that creates something and a list of those somethings.If I have the views
def list_of_something(request):
list1=something.objects.all()
return render(request , 'index.html' ,{'list1':list1})
def post_something(request):
form_class=SomethingForm
if request.method="POST":
form=form_class(request.POST)
if form.is_valid():
.........
........
........
return render(request, 'post_something.html', {'form': form,})
This is what I have done.
I have tried the include putting {% include "post_something.html" %} into index.html, it loads the post_something.html but when it gets to {{form.as_p}}it doesnt load it?
I have checked out Class-based view,but i dont know how to use it to do the above.
UPDATE
Thanks to the answers below.What I did was add {% include "post_something.html" %} to index.html.and pass the name of the form to the view return render(request,'index.html,{'list1':list1,'form':SomethingForm()}) .
And additionally,point your form action attribute to post_something view and it should work.
post_something.html is just the name of the template, you still need to pass in the form. I'm assuming you're trying to show the list_of_something view so you need to include the form in the context data of that view.
return render(request , 'index.html',{'list1':list1, 'form': SomethingForm()})
Assume that the contents of post_something.html will be merged to index.html when you use {% include %} tag. Now you need to pass all the variables in the merged template from your view. It should be like this:
return render(request,
'index.html',
{'list1':list1, 'form': form})
You can define the form based on your business use case.