I have this XML below and I'm trying to print the content of the MyField element using XSLT. Unfortunately I can't make it work. Can you help me fix my XSLT?
XML
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="my_xsl.xsl"?>
<ns:Collection>
<Load>
<Item>
<MyField>Please Print Me</MyField>
XSLT
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:value-of select="ns:Collection/Load/Item/MyField" />
Your XML is not namespace well formed because the namespace prefix "ns" has not been bound to any namespace URI.
XSLT cannot process XML input unless it is namespace well formed.
Use namespace for ns: in the root element
Related
I'm trying to figure out how to pass XML into a XSLT document and parse it as you would on any node.
XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:param name="xmlparam"></xsl:param>
<xsl:template match="/">
<xsl:value-of select="node()"></xsl:value-of>
<xsl:value-of select="$xmlparam/coll"></xsl:value-of>
</xsl:template>
</xsl:stylesheet>
xmlparam:
<?xml version="1.0" encoding="UTF-8"?>
<coll>
<title>Test</title>
<text>Some text</text>
</coll>
Input:
<?xml version="1.0" encoding="UTF-8"?>
<coll>
Root doc
</coll>
Output:
<?xml version="1.0" encoding="UTF-8"?>
Root doc
XPTY0019: Required item type of first operand of '/' is node(); supplied value has item type xs:untypedAtomic
Does anyone know how to parse XML passed in as a parameter to XSLT? Due to certain restraints, I cannot read in a file, it needs to be a parameter.
You could get your XML input to be parsed by the style sheet by using the document function, e.g. like (from memory, so maybe not completely accurate)
<xsl:variable name="myData" select="document('myData')"/>
AND registering a custom URIResolver with the with your Transformer. This custom URIResolver will get "myData" as value of the parameter href of its resolve method and could then obtain the content of the document from e.g. a String. This would give you roughly the same flexibility as adding the content as a parameter.
Code sketch (assuming the obvious implementation of MyURIResolver):
Transformer myTransformer = getMyTransformer();
String myXmlDocument = getMyXmlDocumetAsString();
URIResolver myURIResolver = new MyURIResolver();
myURIResolver.put("myData", myXmlDocument);
myTransformer.setURIResolver(myURIResolver);
myTransformer.transform(source, result);
I working with a project in BizTalk where use xslt to convert from and edifact file to an UBL file.
The edifact file contains price values of ###.0 and that do not work. I want to change it to ###.00 using format-number. But I cannot make it work.
This is what I have made so far:
<cbc:Value>
<xsl:variable name="SumOfNodes" select="edi:PRI/edi:C509/C50902"/>
<xsl:value-of select="format-number($SumOfNodes, '0.00')"/>
</cbc:Value>
I am using this stylesheet:
<?xml version="1.0" encoding="utf-16"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:edi="http://schemas.microsoft.com/BizTalk/EDI/EDIFACT/2006/MEDIAMARKT"
xmlns:ubl="urn:oasis:names:specification:ubl:schema:xsd:Order-2"
xmlns:cac="urn:oasis:names:specification:ubl:schema:xsd:CommonAggregateComponents-2"
xmlns:cbc="urn:oasis:names:specification:ubl:schema:xsd:CommonBasicComponents-2"
exclude-result-prefixes="msxsl edi">
Any ideas on how to solve this??
This may be due to undeclared namespace in your XSLT. Please check whether namespaces are declared correctly in your XSLT. Unless you show the full XSLT coding with XML coding, we cannot able to provide solution. However please refer the below Sample XML and XSLT with the output
XSLT:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="chapter">
<Value>
<xsl:variable name="num" select="number"/>
<xsl:value-of select="format-number($num,'00.00')"/>
</Value>
</xsl:template>
</xsl:stylesheet>
Sample XML
<?xml version="1.0"?>
<chapter>
<number>45</number>
</chapter>
Output
<?xml version='1.0' ?>
<Value>45.00</Value>
I have this simple xml document:
<?xml version='1.0' encoding='UTF-8'?>
<registry xmlns="http://www.iana.org/assignments" id="character-sets">
<registry id="character-sets-1">
<record>
<name>ANSI_X3.4-1968</name>
</record>
</registry>
</registry>
When I use this xsl I can extract the name:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="http://www.iana.org/assignments" version="1.0">
<xsl:template match="/my:registry">
<xsl:copy-of select="//my:record/my:name"/>
</xsl:template>
</xsl:stylesheet>
However, If I omit the namespace in the xsl xpath-selectors, I get no output:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="http://www.iana.org/assignments" xpath-default-namespace="http://www.iana.org/assignments" version="1.0">
<xsl:template match="/registry">
<xsl:copy-of select="//record/name"/>
</xsl:template>
</xsl:stylesheet>
I thought xpath-default-namespace is meant to do the trick. What am I missing?
In case library versions are important I have
libexpat1 (>= 1.95.8)
libxerces-c3.1
libxml2 (>= 2.7.4)
libxslt1.1 (>= 1.1.25)
Unfortunately xpath-default-namespace is an XSLT 2.0 feature. You'll need to repeat the namespace or alias it in your xpath in xslt 1.0
Reference : Jenni Tennison and IBM
I'm new to xsl and am trying to write a template to transform xml to html.
I have an xml document that begins
<?xml version="1.0" encoding="UTF-8"?>
<data xmlns:autn="http://schemas.com/aci/"
xmlns="http://iptc.org/std/nar/2006-10-01/">
<name>Bob</name>
and my xsl template begins
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:autn="http://schemas.autonomy.com/aci/">
<xsl:output method="html" omit-xml-declaration="yes"/>
<xsl:template match="/">
...
<body>
<p>user name:</p>
<p><xsl:value-of select="data/name"/></p>
The problem is, if I do
I don't get anything back for the value-of select.
If I do
I get 'Bob' but I lose all my html.
What am I missing?
You are missing the default namespace of the XML document:
xmlns="http://iptc.org/std/nar/2006-10-01/"
Add it to the XSLT as well:
<xsl:stylesheet version="1.0"
xmlns:mynamespace="http://iptc.org/std/nar/2006-10-01/"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:autn="http://schemas.autonomy.com/aci/">
And use that namespace in the xsl:value-of:
<xsl:value-of select="mynamespace:data/mynamespace:name" />
I have a specific problem getting values for width and height out of some XML that has namespace prefixes defined. I can get other values such as SomeText from RelatedMaterial quite easily using normal xpath with namespace "n:" but unable to get values for width and height.
Sample XML:
<Description>
<Information>
<GroupInformation xml:lang="en">
<BasicDescription>
<RelatedMaterial>
<SomeText>Hello</SomeText>
<t:ContentProperties>
<t:ContentAttributes>
<t:Width>555</t:Width>
<t:Height>444</t:Height>
</t:ContentAttributes>
</t:ContentProperties>
</RelatedMaterial>
</BasicDescription>
</GroupInformation>
</Information>
</Description>
Here is an extract from the XSLT:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:n="urn:t:myfoo:2010" xmlns:tva2="urn:t:myfoo:extended:2008"
<xsl:apply-templates select="n:Description/n:Information/n:GroupInformation"/>
<xsl:template match="n:GroupInformation">
<width>
<xsl:value-of select="n:BasicDescription/n:RelatedMaterial/t:ContentProperties/t:ContentAttributes/t:Width"/>
</width>
</xsl:template>
The above XSLT does not work for getting the width. Any ideas?
I'm not sure you have realised that both your input and XSLT is invalid, it's always better to provide working examples.
Anyway, if we look at the XPath expression n:BasicDescription/n:RelatedMaterial/t:ContentProperties/t:ContentAttributes/t:Width you're using a prefix n which is mapped to urn:t:myfoo:2010 but when the data infact is in the default namespace. The same goes for the t prefix which isn't defined at all in neither the input data nor XSLT.
You need to define the namespaces on "both sides", in the XML data and the XSLT transformation and they need to be the same, not the prefixes, but the URI.
Somebody else could probably explain this better than me.
I've corrected your example and added a few things to make this work.
Input:
<?xml version="1.0" encoding="UTF-8"?>
<Description
xmlns="urn:t:myfoo:2010"
xmlns:t="something...">
<Information>
<GroupInformation xml:lang="en">
<BasicDescription>
<RelatedMaterial>
<SomeText>Hello</SomeText>
<t:ContentProperties>
<t:ContentAttributes>
<t:Width>555</t:Width>
<t:Height>444</t:Height>
</t:ContentAttributes>
</t:ContentProperties>
</RelatedMaterial>
</BasicDescription>
</GroupInformation>
</Information>
</Description>
XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"
xmlns:n="urn:t:myfoo:2010"
xmlns:t="something...">
<xsl:template match="/">
<xsl:apply-templates select="n:Description/n:Information/n:GroupInformation"/>
</xsl:template>
<xsl:template match="n:GroupInformation">
<xsl:element name="width">
<xsl:value-of select="n:BasicDescription/n:RelatedMaterial/t:ContentProperties/t:ContentAttributes/t:Width"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<width>555</width>