Partially rename an XML node - xslt

Question

Given the XML snippet:
<rng:define name="starting_limits">
<rng:element name="limits">
<rng:ref name="Limits"/>
</rng:element>
</rng:define>
I want this:
<rng:define name="limits">
<rng:element name="limits">
<rng:ref name="Limits"/>
</rng:element>
</rng:define>
For all define elements. So I just want to remove the "starting_" prefix for all define element name attributes in the infoset.

Answer 1

you can use this:
<xsl:template match="#*[starts-with(., 'starting_')]">
<xsl:attribute name="{name()}" select="replace(., 'starting_', '')"/>
</xsl:template>
it matched all attribute start-with 'starting_' and remove it from output

Answer 2

In your XML the attribute is called name and has a value of starting_xxxx, so to match it, you would do this...
<xsl:template match="#name[starts-with(., 'starting_')]">
Or maybe this, in XSLT 2.0 and above
<xsl:template match="#name[matches(., 'starting_.*')]">
To remove the starting_attribute you can do one of the following, for example
<xsl:value-of select="substring-after(., 'starting_')"/>
<xsl:value-of select="substring(., 10)"/>
So, for example, your template may look like this
<xsl:template match="#name[starts-with(., 'starting_')]">
<xsl:attribute name="name">
<xsl:value-of select="substring(., 10)"/>
</xsl:attribute>
</xsl:template>
If you wanted to make it more generic, and match any attribute, not just one called name, you could change it to this
<xsl:template match="#*[starts-with(., 'starting_')]">
<xsl:attribute name="{name()}">
<xsl:value-of select="substring(., 10)"/>
</xsl:attribute>
</xsl:template>