I searched a bit, but didn't find a solution for this specific situation. I need to combine groups of non-blank lines into single lines, while preserving the blank lines. For example, the input:
Hi, My name is
Max
What are you
doing
Right now?
Hi
Hello
World
should be output as:
Hi, My name is Max
What are you doing Right now?
Hi
Hello World
Thanks in advance to all who respond.
You could try replacing
(?<![\n\r])[\n\r](?![\n\r])
With a space, as demonstrated here
Explanation -
(?<![\n\r]) is a negative look-behind which tells the regex that anything to be matched must not be preceded by a newline or by a carriage return (just take it as a newline)
[\n\r] is the newline or carriage return which is matched (and later replaced with a space)
(?![\n\r]) is a negative look-ahead that tells the regex that any newline to be matched should not be followed by another newline or carriage return.
In essence, this replaces the blank, new lines which are not followed by another newline - with a space.
You can try this too,
(?m)(?!^\s*$)(^[^\n]*)\n(?!^\s*$)
Demo,,, in which matches all lines which are not empty and not followed by empty line and remove all matched newline character (\n).
But, in notepad++, you must consider carrige return(\r) with newline(\n). Thus,
(?m)(?!^\s*$)(^[^\n]*)\r\n(?!^\s*$)
Related
Im using Notepad++ Find and replace and I have regex that looks for [^|]\r which will find the end of the line that starts with 8778.
8778|44523|0||TENNESSEE|ADMINISTRATION||ROLL 169 BATCH 8|1947-09-22|0|OnBase
See Also 15990TT|
I want to basically merge that line with the one below it, so it becomes this:
8778|44523|0||TENNESSEE|ADMINISTRATION||ROLL 169 BATCH 8|1947-09-22|0|OnBase See Also 15990TT|
Ive tried the replace being a blank space, but its grabbing the last character on that line (an e in this case) and replacing that with a space, so its making it
8778|44523|0||TENNESSEE|ADMINISTRATION||ROLL 169 BATCH 8|1947-09-22|0|OnBas
See Also 15990TT|
Is there any way to make it essentially merge the two lines?
\r only matches a carriage return symbol, to match a line break, you need \R that matches any line break sequence.
To keep a part of a pattern after replacement, capture that part with parentheses, and then use a backreference to that group.
So you may use
([^|\r])\R
Replace with $1. Or with $1 if you need to append a space.
Details
([^|\r]) - Capturing group 1 ($1 is the backreference that refers to the group value from the replacement pattern): any char other than | and CR
\R - any line break char sequence, LF, CR or CRLF.
See the regex demo and the Notepad++ demo with settings:
The issue is you're using [^|] to match anything that's not a pipe character before the carriage return, which, on replacement, will remove that character (hence why you're losing an e).
If it's imperative that you match only carriage returns that follow non-pipe characters, capture the preceding character ([^|])\r$ and then put it back in the replacement using $1.
You're also missing a \n in your regex, which is why the replacement isn't concatenating the two lines. So your search should be ([^|])\r\n$ and your replace should be $1.
Find
(\r\n)+
For "Replace" - don't put anything in (not even a space)
example text
example text
I was wondering if there was a way to match the line break in the middle of these two bits of text.
I was using \n but it would match at the end of "example text" and in the blank line
I am using this in a text to speech program called Voicedream to say out loud that it has progressed to a new line.
I suggest that you only match a newline that is preceded with another newline.
Use a positive lookbehind (?<=\n):
(?<=\n)\n
^^^^^^^
I'm trying to replace multiple spaces with a single one, but at the start of the line.
Example:
___abc___def__
___ghi___jkl__
should turn to
___abc_def__
___ghi_jkl__
Note that I've replaced space with underscore
A simple search using the following pattern:
([^\s])\s+
matches the space at the end of the first line up to the space at the beginning of the next one.
So, if I replace with \1_, I get the following:
___abc_def_ghi_jkl
And that is absolutely not what I expect and regex engines, e.g., PowerGREP or the one in Visual Studio, don't behave that way.
If you want to match only horizontal spaces, use \h:
Find what: (?<=\S)\h+(?=\S)
Replace with: (a space)
There are several possible interpretations of the question. For each of them the replacement will be a single space character.
If spaces is plural and means space characters but not tabs then use
a find string of (^ {2,})|( {2,}$).
If spaces is plural and should includes tabs then use a find string
of (^[ \t]{2,})|([ \t]{2,}$).
If any leading or trailing spaces and tabs (one or more) is to be
replaced with a space then use a find string of (^[ \t]+)|([ \t]+$).
The general form of each of these is (^...)|(...$). The | means an alternation so either the preceding or the following bracketed expression can match. Hence the find what text can match either at the beginning or the end of a line. The ... varies depending on exactly what needs to be matched. Specifying [ \t] means only the two characters space and tab, whereas \s includes the line-end characters.
Ok, so the intention was to replace this:
Hey diddle diddle, \n<br/>
The Cat and the fiddle,\n
with this:
Hey diddle diddle,\n<br/>
The Cat and the fiddle,\n
A slightly modified version of Toto's answer did the trick:
(?<=\S)\h+(?=\S)|\s+$
finding any space(s) between word-characters and trailing space at the end of the line.
Hello and thanks for reading. I am Once again playing and trying to learn more about regex. It's a regex question so dont please offer other solutions. I can easily do this with other VB methods. I love every time i improve my regex brain.
Take NEWLIne as a carriage return, i have a textbox in this format.
NEWLIne
NEWLIne
hello some text
NEWLIne
some more text
NEWLIne
NEWLIne
I would like to match the data
hello some text
NEWLIne
some more text
Ignore every newline until it matches a number or letter, plus a few special chars, ONE newline and proceeds match new text until it reaches a new line break.
Here is what i have (?i)(?<=\n+)[a-z0-9 :\-\n]+(?=\n+)
But it's still match every thing. I guess its because of the \n]+
With the assumption that a new line is specified by CR, try: (?im)^.+\n.+$
m in (?im) specifies multi-line mode, which should be useful for your needs.
I am trying to make simple regex that will check if a line is blank or not.
Case;
" some" // not blank
" " //blank
"" // blank
The pattern you want is something like this in multiline mode:
^\s*$
Explanation:
^ is the beginning of string anchor.
$ is the end of string anchor.
\s is the whitespace character class.
* is zero-or-more repetition of.
In multiline mode, ^ and $ also match the beginning and end of the line.
References:
regular-expressions.info/Anchors, Character Classes, and Repetition.
A non-regex alternative:
You can also check if a given string line is "blank" (i.e. containing only whitespaces) by trim()-ing it, then checking if the resulting string isEmpty().
In Java, this would be something like this:
if (line.trim().isEmpty()) {
// line is "blank"
}
The regex solution can also be simplified without anchors (because of how matches is defined in Java) as follows:
if (line.matches("\\s*")) {
// line is "blank"
}
API references
String String.trim()
Returns a copy of the string, with leading and trailing whitespace omitted.
boolean String.isEmpty()
Returns true if, and only if, length() is 0.
boolean String.matches(String regex)
Tells whether or not this (entire) string matches the given regular expression.
Actually in multiline mode a more correct answer is this:
/((\r\n|\n|\r)$)|(^(\r\n|\n|\r))|^\s*$/gm
The accepted answer: ^\s*$ does not match a scenario when the last line is blank (in multiline mode).
Try this:
^\s*$
Full credit to bchr02 for this answer. However, I had to modify it a bit to catch the scenario for lines that have */ (end of comment) followed by an empty line. The regex was matching the non empty line with */.
New: (^(\r\n|\n|\r)$)|(^(\r\n|\n|\r))|^\s*$/gm
All I did is add ^ as second character to signify the start of line.
The most portable regex would be ^[ \t\n]*$ to match an empty string (note that you would need to replace \t and \n with tab and newline accordingly) and [^ \n\t] to match a non-whitespace string.
Here Blank mean what you are meaning.
A line contains full of whitespaces or a line contains nothing.
If you want to match a line which contains nothing then use '/^$/'.
Somehow none of the answers from here worked for me when I had strings which were filled just with spaces and occasionally strings having no content (just the line terminator), so I used this instead:
if (str.trim().isEmpty()) {
doSomethingWhenWhiteSpace();
}
Well...I tinkered around (using notepadd++) and this is the solution I found
\n\s
\n for end of line (where you start matching) -- the caret would not be of help in my case as the beginning of the row is a string
\s takes any space till the next string
hope it helps
This regex will delete all empty spaces (blank) and empty lines and empty tabs from file
\n\s*