flask-admin incorrect relative url - flask

I am trying to create a simple admin for editing a mongo collection. I have posted the code below. It all works perfectly locally or as a docker container. However when I deploy this in our micro-service architecture the app lives at: SERVER_NAME/TEAM_NAME/APP_NAME/.
Flask routes set with #app.route work correctly. However the urls in the admin templates are not correct and always start directly at SERVER_NAME ignoring team-name and app-name. The actual pages and resources are located at the correct urls but the urls for the static resources are not found. How do I make sure the urls generated within flask-admin also take into account the relative url?
The code:
import os
import flask_admin
from wtforms import form, fields
from flask_admin.contrib.pymongo import ModelView, filters
# User admin
class WordPairsForm(form.Form):
text = fields.StringField("Text")
language = fields.SelectField("Language", choices=[("de", "german"), ("en", "english"), ("pl", "polish")])
label = fields.SelectField("Label", choices=[("badword", "bad word"), ("no_stay", "no overnight stay")])
active = fields.BooleanField("Active", default="checked")
class WordPairsView(ModelView):
column_list = ("text", "language", "label", "active")
column_sortable_list = ("text", "language", "label", "active")
column_searchable_list = ("text",)
column_filters = (
filters.FilterLike("text", "Text"),
filters.FilterNotLike("text", "Text"),
filters.FilterEqual("language", "Language", options=[("de", "german"), ("en", "english"), ("pl", "polish")]),
filters.FilterEqual("label", "Label", options=[("badword", "bad word"), ("no_stay", "no overnight stay")]),
filters.BooleanEqualFilter("active", "Active")
)
form = WordPairsForm
def create_form(self):
_form = super(WordPairsView, self).create_form()
return _form
def edit_form(self, obj):
_form = super(WordPairsView, self).edit_form(obj)
return _form
def get_list(self, *args, **kwargs):
count, data = super(WordPairsView, self).get_list(*args, **kwargs)
return count, data
def get_url
def add_admin(app):
admin = flask_admin.Admin(
app,
name="CQAS Admin",
url=os.getenv(
"F_ADMIN_URL",
"/admin"
),
static_url_path=os.getenv("F_ADMIN_STATIC_URL", None),
subdomain=os.getenv("F_ADMIN_SUBDOMAIN", None),
endpoint=os.getenv("F_ADMIN_ENDPOINT", None)
)
admin.add_view(WordPairsView(app.data.data, "WordPairs"))

Related

Flask Admin - is there a way to store current url (with custom filters applied) of table view?

I am working on ticketing system in Flask Admin. The Flask Admin enviroment will be the main one for all the users. For creating or editing tickets I go out from Flask-Admin and use wtforms to implement backend logic. After creation or editing the ticket (validate_on_submit) I want to redirect back to Flask Admin, so I use redirect(url_for(ticket.index_view)). It works fine.
Is there a way to redirect to flask admin, but also with specific filters which were applied before user left Flask admin enviroment? (it is basiccaly GET parameters of url - but in FLASK)
I was trying to use:
referrer = request.referrer
get_url()
But I am probably missing something crucial and don´t know how to implement it (where to put it so I can call the arguments)
Thank you so much.
EDIT : adding more context:
I have a flask admin customized to different roles of users. The main ModelView is the one showing the TICKETS : the specifics of the Class are not vital to my current problem but here its how it looks:
class TicketModelView(ModelView):
column_list = ['id', 'title', 'osoba', 'content', 'povod_vmc_kom', 'dateVMC','zodpovedni', 'deadline', 'odpoved', 'solution', 'is_finished']
column_searchable_list = ['osoba']
column_filters = [ 'povod_vmc_kom', 'dateVMC', 'osoba', 'zodpovedni']
column_labels = dict(povod_vmc_kom='VMČ / Komisia', dateVMC='Dátum VMČ / komisie', zodpovedni = "Zodpovední")
column_display_actions = True
column_filters = [
FilterEqual(column=Ticket.povod_vmc_kom, name='Výbor/komisia', options=(('VMČ Juh','VMČ Juh'), ('UM','UM'), ('Kom dopravy','Kom dopravy'))),
'zodpovedni', 'is_finished',
'dateVMC', 'osoba'
]
def is_accessible(self):
#práva pre vedenie mesta - môže len nazerať
if current_user.is_authenticated and current_user.role == 0:
self.can_export=True
self.can_delete = False
self.can_edit = False
self.can_create = False
self._refresh_form_rules_cache()
self._refresh_forms_cache()
return True
#práva pre super admina (ostatné práva sú defaultne zapnuté)
if current_user.is_authenticated and current_user.role == 1:
self.can_export=True
self.can_delete=True
self.form_edit_rules = ('zodpovedni', 'is_finished' )
self.column_editable_list = ['is_finished']
self._refresh_form_rules_cache()
self._refresh_forms_cache()
return True
#práva pre garantov
if current_user.is_authenticated and current_user.role == 2:
self.can_delete = False
self.can_create = False
self.can_edit = False
self.can_export=True
self.column_searchable_list = ['title']
self._refresh_form_rules_cache()
self._refresh_forms_cache()
return True
#práva pre veducich utvarov
if current_user.is_authenticated and current_user.role == 3:
self.can_create = False
self.can_delete = False
self.can_export=True
self.column_searchable_list = ['title']
self.column_editable_list = ['odpoved', 'date_odpoved', 'solution', 'date_solution' ]
self.form_edit_rules = ('odpoved', 'date_odpoved', 'solution', 'date_solution')
self._refresh_form_rules_cache()
self._refresh_forms_cache()
return True
return False
def _solution_formatter(view, context, model, name):
# Format your string here e.g show first 20 characters
# can return any valid HTML e.g. a link to another view to show the detail or a popup window
if model.solution:
return model.solution[:50]
pass
def _content_formatter(view, context, model, name):
# Format your string here e.g show first 20 characters
# can return any valid HTML e.g. a link to another view to show the detail or a popup window
if len(model.content) > 100:
markupstring = "<a href= '%s'>%s</a>" % (url_for('ticket', ticket_id=model.id), "...")
return model.content[:100] + Markup(markupstring)
return model.content
def _user_formatter(view, context, model, name):
if model.id:
markupstring = "<a href= '%s'>%s</a>" % (url_for('ticket', ticket_id=model.id), model.id)
return Markup(markupstring)
else:
return ""
column_formatters = {
'content': _content_formatter,
'solution': _solution_formatter,
'id': _user_formatter
}
When user viewing the TicketView in Flask Admin, he can apply various filters which is vital to the user experience of the whole web app. The filters work fine and they are stored in URL as GET arguments. When he wants to create or edit a ticket, I am not allowing him to do it in Flask Admin (I edited Flask-Admin layout.html template and added a button to navbar which redirects to my new_ticket url with wtforms.) because of backend logic I want to be applied. For example when he edits field "solution" : I want the value in field "date_of_solution" be generated automatically (date.today()). So I am using wtforms and flask routing : example is bellow:
#app.route("/ticket/<int:ticket_id>/solution", methods = ['GET', 'POST'])
#login_required
def solution(ticket_id):
if current_user.role != 3:
flash("Pre zadanie riešenia alebo odpovede musíte byť prihlásený ako vedúci útvaru", "danger")
return redirect(url_for('ticket', ticket_id=ticket_id))
ticket = Ticket.query.get_or_404(ticket_id)
form = AdminPanelForm()
if form.validate_on_submit():
print("1")
if not ticket.date_solution:
print("2")
ticket.date_solution= datetime.now()
if not ticket.date_odpoved:
print("3")
if form.odpoved.data != ticket.odpoved:
print("4")
ticket.date_odpoved= datetime.now()
ticket.solution = form.solution.data
ticket.odpoved = form.odpoved.data
ticket.is_finished = True
db.session.commit()
flash("Ticket bol updatenutý", "success")
**return redirect(url_for('ticketmod.index_view'))**
elif request.method == 'GET':
form.solution.data = ticket.solution
form.odpoved.data = ticket.odpoved
return render_template("admin_ticket.html", form=form, ticket = ticket)
Now you can see that after succesful updating the ticket, user is redirected to Ticket model View where he came from, return redirect(url_for('ticketmod.index_view')) but without filters applied. I am looking for the solution, how can you store the url GET parameters (the filters) and then use them when redirecting back to ModelView. I tried function get_url() or request.referrer but I wasn´t succesful.
As I said in my original post, maybe I am missing something crucial in web architecture - if you have in mind some learning material I shoul be looking at : thanks for any advice.
Within the formatter method you can get a view's url including the applied filters/sorting criteria using the following:
_view_url = view.get_url('.index_view', **request.args)
Now pass this along to route request, either as a parameter or some other means. For example:
class TicketModelView(ModelView):
# blah blah
def _user_formatter(view, context, model, name):
if model.id:
# This is the current url of the view including filters
_view_url = view.get_url('.index_view', **request.args)
# Pass this as a parameter to your route
markupstring = "<a href= '%s'>%s</a>" % (url_for('ticket', ticket_id=model.id, return_url=_view_url), model.id)
return Markup(markupstring)
At the route you can now pull out the return_url from the request arg and add it as a hidden field in the form. Then in the post back retrieve the value from the form and redirect.
#app.route("/ticket/<int:ticket_id>/solution", methods = ['GET', 'POST'])
#login_required
def solution(ticket_id):
# Get the return_url from the request
_return_url = request.args.get('return_url'):
# Add the return_url to the form as a hidden field
form.return_url.data = _return_url
# blah blah
if form.validate_on_submit():
# get return value from form
_return_url = form.return_url.data
return redirect(_return_url) if _return_url else redirect(url_for('ticketmod.index_view'))

Limit Amount Of Files A User Can Upload

I have a multi-file upload and want to limit users to 3 uploads each. My problem is that I need to know how many files a user has already created in the DB and how many they are currently uploading (they can upload multiple files at once, and can upload multiple times).
I have attempted many things, including:
Creating a validator (the validator was passed the actual file being added, not a model, so I couldn't access the model to get it's id to call if StudentUploadedFile.objects.filter(student_lesson_data=data.id).count() >= 4:).
Doing the validation in clean(self): (clean was only passed one instance at a time and the DB isn't updated till all files are cleaned, so I could count the files already in the DB but couldn't count how many were currently being uploaded).
Using a pre-save method (If the DB was updated between each file being passed to my pre-save method it would work, but the DB is only updated after all the files being uploaded have passed through my pre-save method).
My post-save attempt:
#receiver(pre_save, sender=StudentUploadedFile)
def upload_file_pre_save(sender, instance, **kwargs):
if StudentUploadedFile.objects.filter(student_lesson_data=instance.data.id).count() >= 4:
raise ValidationError('Sorry, you cannot upload more than three files')
edit:
models.py
class StudentUploadedFile(models.Model):
student_lesson_data = models.ForeignKey(StudentLessonData, related_name='student_uploaded_file', on_delete=models.CASCADE)
student_file = models.FileField(upload_to='module_student_files/', default=None)
views.py
class StudentUploadView(View):
def get(self, request):
files_list = StudentUploadedFile.objects.all()
return render(self.request, 'users/modules.html', {'student_files': files_list})
def post(self, request, *args, **kwargs):
form = StudentUploadedFileForm(self.request.POST, self.request.FILES)
form.instance.student_lesson_data_id = self.request.POST['student_lesson_data_id']
if form.is_valid():
uploaded_file = form.save()
# pass uploaded_file data and username so new file can be added to students file list using ajax
# lesson_id is used to output newly added file to corresponding newly_added_files div
data = {'is_valid': True, 'username': request.user.username, 'file_id': uploaded_file.id, 'file_name': uploaded_file.filename(),
'lesson_id': uploaded_file.student_lesson_data_id, 'file_path': str(uploaded_file.student_file)}
else:
data = {'is_valid': False}
return JsonResponse(data)
template.py
<form id='student_uploaded_file{{ item.instance.id }}'>
{% csrf_token %}
<a href="{% url 'download_student_uploaded_file' username=request.user.username file_path=item.instance.student_file %}" target='_blank'>{{ item.instance.filename }}</a>
<a href="{% url 'delete_student_uploaded_file' username=request.user.username file_id=item.instance.id %}" class='delete' id='{{ item.instance.id }}'>Delete</a>
</form>
js
$(function () {
// open file explorer window
$(".js-upload-photos").on('click', function(){
// concatenates the id from the button pressed onto the end of fileupload class to call correct input element
$("#fileupload" + this.id).click();
});
$('.fileupload_input').each(function() {
$(this).fileupload({
dataType: 'json',
done: function(e, data) { // process response from server
// add newly added files to students uploaded files list
if (data.result.is_valid) {
$("#newly_added_files" + data.result.lesson_id).prepend("<form id='student_uploaded_file" + data.result.file_id +
"'><a href='/student_hub/" + data.result.username + "/download_student_uploaded_file/" +
data.result.file_path + "' target='_blank'>" + data.result.file_name + "</a><a href='/student_hub/" + data.result.username +
"/delete_student_uploaded_file/" + data.result.file_id + "/' class='delete' id=" + data.result.file_id + ">Delete</a></form>")
}
}
});
});
UPDATE:
forms.py
class StudentUploadedFileForm(forms.ModelForm):
student_file = forms.FileField(widget=forms.ClearableFileInput(attrs={'multiple': True}))
view.py
class StudentUploadView(View):
model = StudentUploadedFile
max_files_per_lesson = 3
def post(self, request, *args, **kwargs):
lesson_data_id = request.POST['student_lesson_data_id']
current_files_count = self.model.objects.filter(
student_lesson_data_id=lesson_data_id
).count()
avail = self.max_files_per_lesson - current_files_count
file_list = request.FILES.getlist('student_file')
print(len(file_list))
if avail - len(file_list) < 0:
return JsonResponse(data={
'is_valid': False,
'reason': f'Too many files: you can only upload {avail}.'
})
else:
for f in file_list:
print(f)
data = {'test': True}
return JsonResponse(data)
Thank you.
I've tried using a PyPi package and it works flawlessly. I'm gonna go out on a limb here and assume that you are open to editing the package code to fix any errors you encounter due to compatibility issues since most of the packages that haven't been updated in quite a while might face them.
To solve the problem of limiting the number of files a user can upload, django-multiuploader package would be of enormous help and would honestly do more than you ask for. And yes, it uses JQuery form for uploading multiple files.
How to use it?
Installation and pre-usage steps
Installation
pip install django-multiuploader
python3 manage.py syncdb
python3 manage.py migrate multiuploader
In your settings.py file :
MULTIUPLOADER_FILES_FOLDER = ‘multiuploader’ # - media location where to store files
MULTIUPLOADER_FILE_EXPIRATION_TIME = 3600 # - time, when the file is expired (and it can be cleaned with clean_files command).
MULTIUPLOADER_FORMS_SETTINGS =
{
'default': {
'FILE_TYPES' : ["txt","zip","jpg","jpeg","flv","png"],
'CONTENT_TYPES' : [
'image/jpeg',
'image/png',
'application/msword',
'application/vnd.openxmlformats-officedocument.wordprocessingml.document',
'application/vnd.ms-excel',
'application/vnd.openxmlformats-officedocument.spreadsheetml.sheet',
'application/vnd.ms-powerpoint',
'application/vnd.openxmlformats-officedocument.presentationml.presentation',
'application/vnd.oasis.opendocument.text',
'application/vnd.oasis.opendocument.spreadsheet',
'application/vnd.oasis.opendocument.presentation',
'text/plain',
'text/rtf',
],
'MAX_FILE_SIZE': 10485760,
'MAX_FILE_NUMBER':5,
'AUTO_UPLOAD': True,
},
'images':{
'FILE_TYPES' : ['jpg', 'jpeg', 'png', 'gif', 'svg', 'bmp', 'tiff', 'ico' ],
'CONTENT_TYPES' : [
'image/gif',
'image/jpeg',
'image/pjpeg',
'image/png',
'image/svg+xml',
'image/tiff',
'image/vnd.microsoft.icon',
'image/vnd.wap.wbmp',
],
'MAX_FILE_SIZE': 10485760,
'MAX_FILE_NUMBER':5,
'AUTO_UPLOAD': True,
},
'video':{
'FILE_TYPES' : ['flv', 'mpg', 'mpeg', 'mp4' ,'avi', 'mkv', 'ogg', 'wmv', 'mov', 'webm' ],
'CONTENT_TYPES' : [
'video/mpeg',
'video/mp4',
'video/ogg',
'video/quicktime',
'video/webm',
'video/x-ms-wmv',
'video/x-flv',
],
'MAX_FILE_SIZE': 10485760,
'MAX_FILE_NUMBER':5,
'AUTO_UPLOAD': True,
},
'audio':{
'FILE_TYPES' : ['mp3', 'mp4', 'ogg', 'wma', 'wax', 'wav', 'webm' ],
'CONTENT_TYPES' : [
'audio/basic',
'audio/L24',
'audio/mp4',
'audio/mpeg',
'audio/ogg',
'audio/vorbis',
'audio/x-ms-wma',
'audio/x-ms-wax',
'audio/vnd.rn-realaudio',
'audio/vnd.wave',
'audio/webm'
],
'MAX_FILE_SIZE': 10485760,
'MAX_FILE_NUMBER':5,
'AUTO_UPLOAD': True,
}}
Take note of that MAX_FILE_NUMBER, right within their lies the answer to your question. Have a look at the source once you install this and try implementing it on your own if you want. It might be fun.
Refer for further instructions :
django-multiuploader package on pypi
I guess that you can use multi file upload in Django hasn't trickled to the community yet. Excerpt:
If you want to upload multiple files using one form field, set the multiple HTML attribute of field’s widget:
# forms.py
from django import forms
class FileFieldForm(forms.Form):
file_field = forms.FileField(widget=forms.ClearableFileInput(attrs={'multiple': True}))
Your form and view structure is also very contrived, excluding fields from a form and then setting values injected via HTML form on the model instance. However, with the code shown, the model instance would never exist as the form has no pk field.
Anyway - to focus on the problem that needs fixing...
In the form, request.FILES is now an array:
class StudentUploadView(View):
model = StudentUploadedFile
max_files_per_lesson = 3
def post(request, *args, **kwargs):
lesson_data_id = request.POST['student_lesson_data_id']
current_files_count = self.model.objects.filter(
student_lesson_data_id=lesson_data_id
).count()
avail = self.max_files_per_lesson - current_files_count
file_list = request.FILES.get_list('student_file')
if avail - len(file_list) < 0:
return JsonResponse(data={
'is_valid': False,
'reason': f'Too many files: you can only upload {avail}.'
})
else:
# create one new instance of self.model for each file
...
Addressing comments:
From an aesthetic perspective, you can do a lot with styling...
However, uploading async (separate POST requests), complicates validation and user experience a lot:
The first file can finish after the 2nd, so which are you going to deny if the count is >3.
Frontend validation is hackable, so you can't rely on it, but backend validation is partitioned into several requests, which from the user's point of view is one action.
But with files arriving out of order, some succeeding and some failing, how are you going to provide feedback to the user?
If 1, 3 and 4 arrive, but user cares more about 1, 2, 3 - user has to
take several actions to correct the situation.
One post request:
There are no out of order arrivals
You can use a "everything fails or everything succeeds" approach, which is transparent to the end user and easy to correct.
It's likely that file array order is user preferred order, so even if you allow partial success, you're likely to do the right thing.
So the gist of it is that you are using jQuery .each to upload images via AJAX. Each POST request to your Django view is a single file upload, but there might be multiple requests at the same time.
Try this:
forms.py:
class StudentUploadedFileForm(forms.ModelForm):
class Meta:
model = StudentUploadedFile
fields = ('student_file', )
def __init__(self, *args, **kwargs):
"""Accept a 'student_lesson_data' parameter."""
self._student_lesson_data = kwargs.pop('student_lesson_data', None)
super(StudentUploadedFileForm, self).__init__(*args, **kwargs)
def clean(self):
"""
Ensure that the total number of student_uploaded_file instances that
are linked to the student_lesson_data parameter are within limits."""
cleaned_data = super().clean()
filecount = self._student_lesson_data.student_uploaded_file.count()
if filecount >= 3:
raise forms.ValidationError("Sorry, you cannot upload more than three files")
return cleaned_data
views.py:
class StudentUploadView(View):
def get(self, request):
# stuff ...
def post(self, request, *args, **kwargs):
sld_id = request.POST.get('student_lesson_data_id', None)
student_lesson_data = StudentLessonData.objects.get(id=sld_id)
form = StudentUploadedFileForm(
request.POST,
request.FILES,
student_lesson_data=student_lesson_data
)
if form.is_valid():
uploaded_file = form.save()
# other stuff ...

Django rest framework: How to reuse an app using different settings?

I have an application that has it's own urls and uses specific settings to access another api.
I would like to use this same app again within the same project, but with different urls and using a seperate endpoint.
So just setup new urls, and point to the same views from the original app but inject different settings.
For example one of my views is:
class SummaryVMsList(ListAPIView):
'''
VM Summary
'''
def list(self, request, *args, **kwargs):
'''
Return a list of processed vm's
'''
v_token = settings.VTOKEN
base_url = settings.VURL
v_password = settings.VPASSWORD
v_username = settings.VUSERNAME
session = Session()
session.headers.update({
'v_token': v_token
})
client = VClient(
url=base_url,
v_username=v_username,
v_password=v_password,
session=session
)
try:
repos = client.get_summary_vms()
return Response(data=repos, status=status.HTTP_200_OK)
except VError as err:
return Response(
data={'error': str(err)},
status=status.HTTP_500_INTERNAL_SERVER_ERROR
)
# log the error
finally:
client.logout()
How would I be able to change the setting values: settings.VTOKEN, settings.VURL, settings.VPASSWORD and settings.VUSERNAME
Based on whick url is used:
In urls-site1.py
app_name = 'v_site1'
urlpatterns = [
path('vm-summary', views.SummaryVMsList.as_view(), name='vms_list'),
]
In urls-site2.py:
app_name = 'v_site2'
urlpatterns = [
path('vm-summary', views.SummaryVMsList.as_view(), name='vms_list'),
]
In this case, a better idea would be to store such params in constants instead of settings. The settings in Django used for different environments, in the end, it can be hard to work with it.
Also, take note that there are two exactly the same URL vm-summary and it could cause a name collision.

Django show object count on admin interface

I have modified my dashboard with the help of dashboard.py file. There in I have added a custom module/widget called 'My Widget' (haven't created myself but rather just appended as a child referring to a specific django app). Code is as follows:
# append an app list module for "Administration"
self.children.append(modules.AppList(
_('Administration'),
models=('django.contrib.*',),
))
self.children.append(modules.AppList(
_('My widget'),
models=('flights.*',),
children=[
]
))
flights is my django app which has three models. Dashboard looks like following:
On this widget I want to show the count of users who did log in today.
The count itself I was able to get (not on admin interface but through a view accessible via url for testing purpose) with following code snippet:
User.objects.filter(last_login__startswith=timezone.now().date()).count()
How can I show such a count on this widget?
The entire dashboard.py:
"""
This file was generated with the customdashboard management command, it
contains the two classes for the main dashboard and app index dashboard.
You can customize these classes as you want.
To activate your index dashboard add the following to your settings.py::
ADMIN_TOOLS_INDEX_DASHBOARD = 'api.dashboard.CustomIndexDashboard'
And to activate the app index dashboard::
ADMIN_TOOLS_APP_INDEX_DASHBOARD = 'api.dashboard.CustomAppIndexDashboard'
"""
from django.utils.translation import ugettext_lazy as _
from django.core.urlresolvers import reverse
from admin_tools.dashboard import modules, Dashboard, AppIndexDashboard
from admin_tools.utils import get_admin_site_name
from admin_tools_stats.modules import DashboardCharts, get_active_graph
class CustomIndexDashboard(Dashboard):
"""
Custom index dashboard for api.
"""
columns = 3
def init_with_context(self, context):
site_name = get_admin_site_name(context)
# append a link list module for "quick links"
self.children.append(modules.LinkList(
_('Quick links'),
layout='inline',
draggable=False,
deletable=False,
collapsible=False,
children=[
[_('Return to site'), '/'],
[_('Change password'),
reverse('%s:password_change' % site_name)],
[_('Log out'), reverse('%s:logout' % site_name)],
]
))
graph_list = get_active_graph()
for i in graph_list:
kwargs = {}
kwargs['require_chart_jscss'] = True
kwargs['graph_key'] = i.graph_key
if context['request'].POST.get('select_box_' + i.graph_key):
kwargs['select_box_' + i.graph_key] = context['request'].POST['select_box_' + i.graph_key]
self.children.append(DashboardCharts(**kwargs))
# append an app list module for "Applications"
self.children.append(modules.AppList(
_('All Applications'),
exclude=('django.contrib.*',),
))
# append an app list module
self.children.append(modules.AppList(
_('Dashboard Stats Settings'),
models=('admin_tools_stats.*', ),
))
# append an app list module for "Administration"
self.children.append(modules.AppList(
_('Administration'),
models=('django.contrib.*',),
))
self.children.append(modules.AppList(
_('My widget'),
models=('flights.*',),
content='test content',
children=[
]
))
# append a recent actions module
self.children.append(modules.RecentActions(_('Recent Actions'), 4))
# append another link list module for "support".
self.children.append(modules.LinkList(
_('Support'),
children=[
{
'title': _('Django documentation'),
'url': 'http://docs.djangoproject.com/',
'external': True,
},
{
'title': _('Django "django-users" mailing list'),
'url': 'http://groups.google.com/group/django-users',
'external': True,
},
{
'title': _('Django irc channel'),
'url': 'irc://irc.freenode.net/django',
'external': True,
},
]
))
class CustomAppIndexDashboard(AppIndexDashboard):
"""
Custom app index dashboard for api.
"""
# we disable title because its redundant with the model list module
title = ''
def __init__(self, *args, **kwargs):
AppIndexDashboard.__init__(self, *args, **kwargs)
# append a model list module and a recent actions module
self.children += [
modules.ModelList(self.app_title, self.models),
modules.RecentActions(
_('Recent Actions'),
include_list=self.get_app_content_types(),
limit=5
)
]
def init_with_context(self, context):
"""
Use this method if you need to access the request context.
"""
return super(CustomAppIndexDashboard, self).init_with_context(context)

django social auth limiting user data

I have configured django social auth's to take from google only e-mail, but google shows this screen alerting app user that gender, date of birth, picture, language will be collect:
My django-social-auth config is as follow:
WHITE_LISTED_DOMAINS = [ 'some_domain', ]
GOOGLE_WHITE_LISTED_DOMAINS = WHITE_LISTED_DOMAINS
SOCIAL_AUTH_EXTRA_DATA = False
#LOGIN_ERROR_URL = '/login-error/' Not set
#SOCIAL_AUTH_DEFAULT_USERNAME = 'new_social_auth_user' Not set
#GOOGLE_CONSUMER_KEY = '' Not set
#GOOGLE_CONSUMER_SECRET = '' Not set
#GOOGLE_OAUTH2_CLIENT_ID = '' Not set
#GOOGLE_OAUTH2_CLIENT_SECRET = '' Not set
SOCIAL_AUTH_USERNAME_IS_FULL_EMAIL = False
SOCIAL_AUTH_PROTECTED_USER_FIELDS = ['email',]
INSTALLED_APPS = (
'django.contrib.auth',
...
'social_auth',
)
How can I do to avoid this google message?
EDITED
I have move to GoogleOauth2 auth and inherit and change google backend:
from social_auth.backends.google import *
GOOGLE_OAUTH2_SCOPE = ['https://www.googleapis.com/auth/userinfo.email',]
class GoogleOAuth2(BaseOAuth2):
"""Google OAuth2 support"""
AUTH_BACKEND = GoogleOAuth2Backend
AUTHORIZATION_URL = 'https://accounts.google.com/o/oauth2/auth'
ACCESS_TOKEN_URL = 'https://accounts.google.com/o/oauth2/token'
REVOKE_TOKEN_URL = 'https://accounts.google.com/o/oauth2/revoke'
REVOKE_TOKEN_METHOD = 'GET'
SETTINGS_SECRET_NAME = 'GOOGLE_OAUTH2_CLIENT_SECRET'
SCOPE_VAR_NAME = 'GOOGLE_OAUTH_EXTRA_SCOPE'
DEFAULT_SCOPE = GOOGLE_OAUTH2_SCOPE
REDIRECT_STATE = False
print DEFAULT_SCOPE #<------ to be sure
def user_data(self, access_token, *args, **kwargs):
"""Return user data from Google API"""
return googleapis_profile(GOOGLEAPIS_PROFILE, access_token)
#classmethod
def revoke_token_params(cls, token, uid):
return {'token': token}
#classmethod
def revoke_token_headers(cls, token, uid):
return {'Content-type': 'application/json'}
But google still ask for profile data, profile is still in scope:
https://accounts.google.com/o/oauth2/auth?response_type=code&scope=https://www.googleapis.com/auth/userinfo.email+https://www.googleapis.com/auth/userinfo.profile&redirect_uri=...
Runs fine if I modify by hand social-auth code instead inherit:
def get_scope(self):
return ['https://www.googleapis.com/auth/userinfo.email',]
What is wrong with my code?
That's because the default scope used on google backend is set to that (email and profile information), it's defined here. In order to avoid that you can create your own google backend which just sets the desired scope, then use that backend instead of the built in one. Example:
from social_auth.backends.google import GoogleOAuth2
class SimplerGoogleOAuth2(GoogleOAuth2):
DEFAULT_SCOPE = ['https://www.googleapis.com/auth/userinfo.email']
Those who don't know how to add in AUTHENTICATION_BACKENDS, if using the way Omab suggested you need to add newly defined backend in your setting.py file:
AUTHENTICATION_BACKENDS = (
'app_name.file_name.class_name', #ex: google_auth.views.SimplerGoogleOAuth2
# 'social_core.backends.google.GoogleOAuth2', # comment this as no longer used
'django.contrib.auth.backends.ModelBackend',
)
To know how to create the class SimplerGoogleOAuth2 check Omab's answer.