C++ : Create 3D array out of stacking 2D arrays - c++

In Python I normally use functions like vstack, stack, etc to easily create a 3D array by stacking 2D arrays one onto another.
Is there any way to do this in C++?
In particular, I have loaded a image into a Mat variable with OpenCV like:
cv::Mat im = cv::imread("image.png", 0);
I would like to make a 3D array/Mat of N layers by stacking copies of that Mat variable.
EDIT: This new 3D matrix has to be "travellable" by adding an integer to any of its components, such that if I am in the position (x1,y1,1) and I add +1 to the last component, I arrive to (x1,y1,2). Similarly for any of the coordinates/components of the 3D matrix.
SOLVED: Both answers from #Aram and #Nejc do exactly what expected. I set #Nejc 's answer as the correct one for his shorter code.

The Numpy function vstack returns a contiguous array. Any C++ solution that produces vectors or arrays of cv::Mat objects does not reflect the behaviour of vstack in this regard, becase separate "layers" belonging to individual cv::Mat objects will not be stored in contiguous buffer (unless a careful allocation of underlying buffers is done in advance of course).
I present the solution that copies all arrays into a three-dimensional cv::Mat object with a contiguous buffer. As far as the idea goes, this answer is similar to Aram's answer. But instead of assigning pixel values one by one, I take advantage of OpenCV functions. At the beginning I allocate the matrix which has a size N X ROWS X COLS, where N is the number of 2D images I want to "stack" and ROWS x COLS are dimensions of each of these images.
Then I make N steps. On every step, I obtain the pointer to the location of the first element along the "outer" dimension. I pass that pointer to the constructor of temporary Mat object that acts as a kind of wrapper around the memory chunk of size ROWS x COLS (but no copies are made) that begins at the address that is pointed-at by pointer. I then use copyTo method to copy i-th image into that memory chunk. Code for N = 2:
cv::Mat img0 = cv::imread("image0.png", CV_IMREAD_GRAYSCALE);
cv::Mat img1 = cv::imread("image1.png", CV_IMREAD_GRAYSCALE);
cv::Mat images[2] = {img0, img1}; // you can also use vector or some other container
int dims[3] = { 2, img0.rows, img0.cols }; // dimensions of new image
cv::Mat joined(3, dims, CV_8U); // same element type (CV_8U) as input images
for(int i = 0; i < 2; ++i)
{
uint8_t* ptr = &joined.at<uint8_t>(i, 0, 0); // pointer to first element of slice i
cv::Mat destination(img0.rows, img0.cols, CV_8U, (void*)ptr); // no data copy, see documentation
images[i].copyTo(destination);
}

This answer is in response to the question above of:
In Python I normally use functions like vstack, stack, etc to easily create a 3D array by stacking 2D arrays one onto another.
This is certainly possible, you can add matrices into a vector which would be your "stack"
For instance you could use a
std::vector<cv::Mat>>
This would give you a vector of mats, which would be one slice, and then you could "layer" those by adding more slices vector
If you then want to have multiple stacks you can add that vector into another vector:
std::vector<std::vector<cv::Mat>>
To add matrix to an array you do:
myVector.push_back(matrix);
Edit for question below
In such case, could I travel from one position (x1, y1, z1) to an immediately upper position doing (x1,y1,z1+1), such that my new position in the matrix would be (x1,y1,z2)?
You'll end up with something that looks a lot like this. If you have a matrix at element 1 in your vector, it doesn't really have any relationship to the element[2] except for the fact that you have added it into that point. If you want to build relationships then you will need to code that in yourself.

You can actually create a 3D or ND mat with opencv, you need to use the constructor that takes the dimensions as input. Then copy each matrix into (this case) the 3D array
#include <opencv2/opencv.hpp>
using namespace cv;
using namespace std;
int main() {
// Dimensions for the constructor... set dims[0..2] to what you want
int dims[] = {5, 5, 5}; // 5x5x5 3d mat
Mat m = Mat::zeros(5, 5, CV_8UC1);
for (size_t i = 0; i < 5; i++) {
for (size_t k = 0; k < 5; k++) {
m.at<uchar>(i, k) = i + k;
}
}
// Mat with constructor specifying 3 dimensions with dimensions sizes in dims.
Mat 3DMat = Mat(3, dims, CV_8UC1);
// We fill our 3d mat.
for (size_t i = 0; i < m2.size[0]; i++) {
for (size_t k = 0; k < m2.size[1]; k++) {
for (size_t j = 0; j < m2.size[2]; j++) {
3DMat.at<uchar>(i, k, j) = m.at<uchar>(k, j);
}
}
}
// We print it to show the 5x5x5 array.
for (size_t i = 0; i < m2.size[0]; i++) {
for (size_t k = 0; k < m2.size[1]; k++) {
for (size_t j = 0; j < m2.size[2]; j++) {
std::cout << (int) 3DMat.at<uchar>(i, k, j) << " ";
}
std::cout << endl;
}
std::cout << endl;
}
return 0;
}

Based on the question and comments, I think you are looking for something like this:
std::vector<cv::Mat> vec_im;
//In side for loop:
vec_im.push_back(im);
Then, you can access it by:
Scalar intensity_1 = vec_im[z1].at<uchar>(y, x);
Scalar intensity_2 = vec_im[z2].at<uchar>(y, x);
This assumes that the image is single channel.

Related

How can I reserve a fixed buffer size in OpenCV Mat?

I am rewriting some legacy code that does matrix operations on doubles using a raw C-style array. Since the code already has a dependency on OpenCV somewhere else, I want to use the cv::Mat class instead.
The specific code that bothers me works on square matrixes from size 1*1 to NN. It does so by allocating an NN buffer and uses a subset of it for smaller matrixes.
double* buf = new double[NxN];
for (int i = 1; i < N; ++i) {
// Reuse buf to create a i*i matrix and perform matrix operations
...
}
delete[] buf;
Basically, I want to replace that code to use cv::Mat objects in the loop instead. Problem is, the code requires a lot of loop iterations (there are nested loops and so on) and there are too many allocations/deallocations if I just use the naïve and clean approach. Therefore, I want to reserve the size of my matrix object beforehand and resize it for each iteration. This would ideally look like this:
cv::Mat m;
m.reserveBuffer(N * N * sizeof(double));
for (int i = 1; i < N; ++i) {
m = cv::Mat(i, i, CV_64F);
// Perform matrix operations on m
...
}
But in my understanding this would simply drop the previous instance of m and then allocate a i*i matrix. What would the right approach be?
You can create a submatix header for your buffer using cv::Mat::operator(). Pass a cv::Rect for ROI you want to process in current loop iteration ({0, 0, i, i} in your case) and it will return a view of your buffer region as another cv::Mat instance. It will not allocate new buffer but will refer to original buffer data instead.
cv::Mat m(N, N, CV_64FC1);
for (int i = 1; i < N; ++i) {
cv::Mat subM = m({0, 0, i*i});
// Perform matrix operations on "subM"
// Modifying "subM" will modify "m" buffer region that "subM" represents
}
Note that subM will not be continious, so you will need to process it row by row if you do any raw buffer processing.

How to convert vector<Mat> to vector<float>?

Suppose i have a vector<Mat> called regionFeaMatand regionFeaMat.size() == 81 .In other words, regionFeaMat have 81 equal size matrix, and regionFeaMat[0].rows==256 and regionFeaMat[0].cols==1. I want to convert reginFeaMat to vector<float> reginFeaVec. I tried with following code but i got wrong result:
vector<float> regionFeaVec;
regionFeaVec.assign((float*)regionFeaMat[0].datastart, (float*)regionFeaMat[80].dataend);
You seem to have made a few wrong assumptions.
std::vector does store its elements contiguously in memory, but cv::Mat is a header containing a pointer to its internal buffer, so only pointers in vector<Mat> are stored contiguously, not the Mat data itself. Because of that, the memory that lies in between (float*)regionFeaMat[0].dataend and (float*)regionFeaMat[80].datastart is some random garbage - if it does contain other Mat's data partially, it's pure luck.
Because of the above, you can't have a one-liner assigning vector to any other vector and you have to insert each mat separately instead. Try something like this:
// prevent vector reallocation after each Mat insertion:
regionFeaVec.reserve(regionFeaMat.size()*regionFeaMat[0].cols*regionFeaMat[0].rows);
for (int i = 0; i < regionFeaMat.size(); ++i)
{
if (regionFeaMat[i].isContinuous())
regionFeaVec.insert(
regionFeaVec.end(),
(float*)regionFeaMat[i].datastart,
(float*)regionFeaMat[i].dataend
);
else
{
for (int j = 0; j < regionFeaMat[i].rows; ++j)
{
const float* row = regionFeaMat[i].ptr<float>(j);
regionFeaVec.insert(regionFeaVec.end(), row, row + regionFeaMat[i].cols);
}
}
}
Note that I'm checking if a particular Mat object is continuous, because as per OpenCV docs, each row may contain gaps at the end in some cases, and in that case we have to read the matrix row by row.
This code can be simplified, because if matrix is continuous, we may treat it as a 1D vector as per the docs referenced above:
// prevent vector reallocation after each Mat insertion:
regionFeaVec.reserve(regionFeaMat.size()*regionFeaMat[0].cols*regionFeaMat[0].rows);
for (int i = 0; i < regionFeaMat.size(); ++i)
{
cv::Size size = regionFeaMat[i].size();
if (regionFeaMat[i].isContinuous())
{
size.width *= size.height;
size.height = 1;
}
for (int j = 0; j < size.height; ++j)
{
const float* row = regionFeaMat[i].ptr<float>(j);
regionFeaVec.insert(regionFeaVec.end(), row, row + size.width);
}
}
If you want to prevent vector reallocation in more general cases, you also have to change the method of calculating the number of elements passed to reserve(). The method I use assumes all the Mat objects have only two dimensions that are equal for all the objects since this is how you described your problem.
Also, if you want to assign it to vector<float>, be sure that the element type of regionFeaMat is CV_32F.

How does the return value "res" is updated? (ConcativeMat Con NN)

I have a questions about a for loop and its return value. This is C++ code, and I'm using openCV 2.4V.
Input to this function is max value of 600 images with pooling.
600 images << pooling << max value points.
The size of "res" matrix is 600x128 and vec.size() = 600.
For me, within the for loop, the res never get updated, however return value is not zeros.
I suspected
"ptmat.copyTo(subView)"
because, I thought that is not necessary line. However when I took that out, res did not get updated(being zero like initial Mat). Can anybody explain how does the res value get updated?
Also why does this function is called concatenate..?
Mat
concatenateMat(vector<vector<Mat> > &vec) {
int subFeatures = vec[0][0].rows * vec[0][0].cols;
int height = vec[0].size() * subFeatures;
int width = vec.size();
Mat res = Mat::zeros(height, width, CV_64FC1);
for (int i = 0; i<vec.size(); i++) {
for (int j = 0; j<vec[i].size(); j++) {
Rect roi = Rect(i, j * subFeatures, 1, subFeatures);
Mat subView = res(roi);
Mat ptmat = vec[i][j].reshape(0, subFeatures);
ptmat.copyTo(subView);
}
}
return res;
}
According to OpenCV documentation, the Mat::operator() does not make a copy of matrix data, thus any change to subView matrix object in the loop will be reflected in res matrix object as well. That's the line you've mentioned:
ptmat.copyTo(subView);
It's called concatenate because it concatenates 2D vector of Mat objects into a single one.

Opencv Mat vector assignment to a row of a matrix, fastest way?

What is the fastest way of assigning a vector to a matrix row in a loop? I want to fill a data matrix along its rows with vectors. These vectors are computed in a loop. This loop last until all the entries of data matrix is filled those vectors.
Currently I am using cv::Mat::at<>() method for accessing the elements of the matrix and fill them with the vector, however, it seems this process is quite slow. I have tried another way by using cv::Mat::X.row(index) = data_vector, it works fast but fill my matrix X with some garbage values which I can not understand, why.
I read that there exists another way of using pointers (fastest way), however, I can not able to understand. Can somebody explain how to use them or other different methods?
Here is a part of my code:
#define OFFSET 2
cv::Mat im = cv::imread("001.png", CV_LOAD_IMAGE_GRAYSCALE);
cv::Mat X = cv::Mat((im.rows - 2*OFFSET)*(im.cols - 2*OFFSET), 25, CV_64FC1); // Holds the training data. Data contains image patches
cv::Mat patch = cv::Mat(5, 5, im.type()); // Holds a cropped image patch
typedef cv::Vec<float, 25> Vec25f;
int ind = 0;
for (int row = 0; row < (im.rows - 2*OFFSET); row++){
for (int col = 0; col < (im.cols - 2*OFFSET); col++){
cv::Mat temp_patch = im(cv::Rect(col, row, 5, 5)); // crop an image patch (5x5) at each pixel
patch = temp_patch.clone(); // Needs to do this because temp_patch is not continuous in memory
patch.convertTo(patch, CV_64FC1);
Vec25f data_vector = patch.reshape(0, 1); // make it row vector (1X25).
for (int i = 0; i < 25; i++)
{
X.at<float>(ind, i) = data_vector[i]; // Currently I am using this way (quite slow).
}
//X_train.row(ind) = patch.reshape(0, 1); // Tried this but it assigns some garbage values to the data matrix!
ind += 1;
}
}
To do it the regular opencv way you could do :-
ImageMat.row(RowIndex) = RowMat.clone();
or
RowMat.copyTo(ImageMat.row(RowIndex));
Haven't tested for correctness or speed.
Just a couple of edits in your code
double * xBuffer = X.ptr<double>(0);
for (int row = 0; row < (im.rows - 2*OFFSET); row++){
for (int col = 0; col < (im.cols - 2*OFFSET); col++){
cv::Mat temp_patch = im(cv::Rect(col, row, 5, 5)); // crop an image patch (5x5) at each pixel
patch = temp_patch.clone(); // Needs to do this because temp_patch is not continuous in memory
patch.convertTo(patch, CV_64FC1);
memcpy(xBuffer, patch.data, 25*sizeof(double));
xBuffer += 25;
}
}
Also, you dont seem to do any computation in patch just extract grey level values, so you can create X with the same type as im, and convert it to double at the end. In this way, you could memcpy each row of your patch, the address in memory beeing `unsigned char* buffer = im.ptr(row) + col
According to the docs:
if you need to process a whole row of matrix, the most efficient way is to get the pointer to the row first, and then just use plain C operator []:
// compute sum of positive matrix elements
// (assuming that M is double-precision matrix)
double sum=0;
for(int i = 0; i < M.rows; i++)
{
const double* Mi = M.ptr<double>(i);
for(int j = 0; j < M.cols; j++)
sum += std::max(Mi[j], 0.);
}

How to improve sorting pixels in cvMat?

I am trying to sort pixel values of an image (example 80x20) from lowest to highest.
Below is the some code:
bool sortPixel(int first, int second)
{
return (first < second);
}
vector<int>vect_sortPixel;
for(int y=0; y<height; y++)
{
for(int x=0; x<width; x++)
{
vect_sortPixel.push_back(cvGetReal2D(srcImg, y, x));
sort(vect_sortPixel.begin(), vect_sortPixel.end(), sortPixel);
}
}
But it takes quite long time to compute. Any suggestion to reduce the processing time?
Thank you.
Don't use getReal2D. It's quite slow.
Convert image to cv::Mat or Mat. Use its data pointer to get the pixel values. Mat.data() will give you pointer to the original matrix. Use that.
And as far as sorting is concerned, I would advise you to first make an array of all the pixels, then sort it using Merge sort (time complexity O(n log n))
#include<opencv2/highgui/highgui.hpp>
#include<stdio.h>
using namespace cv;
using namespace std;
int main()
{
Mat img = imread("filename.jpg",CV_LOAD_IMAGE_COLOR);
unsigned char *input = (unsigned char*)(img.data);
int i,j,r,g,b;
for(int i = 0;i < img.cols;i++){
for(int j = 0;j < img.rows;j++){
b = input[img.cols * j + i] ;
g = input[img.cols * j+ i + 1];
r = input[img.cols *j + i +2];
}
}
return 0;
}
Using this you can access pixel values from the main matrix.
Warning: This is not how you compare it. I'm suggesting that by using something like this, you can access pixel values.
Mat.data() gives you pointer to the original matrix. This matrix is a 1 D matrix with all the given pixel values.
Image => (x,y,z),(x1,y1,z1), etc..
Mat(original matrix) => x,y,z,x1,y1,z1,...
If you still have some doubts regarding how to extract data from Mat, visit this link OpenCV get pixel channel value from Mat image
and here's a link regarding Merge Sort http://www.cplusplus.happycodings.com/Algorithms/code17.html
There are few problems in your code:
As Froyo already said you use cvGetReal2D which is actually not very fast. You have to convert your cvMat to cv::Mat. To do this there's cv::Mat constructor:
// converts old-style CvMat to the new matrix; the data is not copied by default
Mat(const CvMat* m, bool copyData=false);
And after this use direct pixels acces as mentioned in this SO question.
Another problem is that you use push_back which actually also not very fast. You know the size of array, so why don't you allocate needed memory at the beginning? Like this:
vector<int> vect_sortPixel(mat.cols*mat.rows);
And than just use vect_sortPixel[i] to get needed pixel.
Why do you call sort in the loop? You have to call it after loop, when array is already created! Default STL's sort should work fast:
Complexity
Approximately N*logN comparisons on average (where N is
last-first). In the worst case, up to N^2, depending on specific
sorting algorithm used by library implementation.