Difficulty in a menu oriented program for C++ - c++

Question

I am having an issue when trying to use a getline command where a user can enter in a movie and then add to the collection of movies (stored in "movies.txt")
My code is compiling, but it starts out with the 3rd case automatically. When I press "q" to quit that case, it reverts to the menu, yet when I try and write out the file or print the collection, no movie titles have been saved. Where I should go from here? I feel like I'm on the cusp of understanding this.
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
const int ARRAY_SIZE = 200;
string movieTitle [ARRAY_SIZE];
int loadData (string pathname);
int writeData (string pathname);
int getTitle (string movieTitle[]);
void showAll (int count);
int main()
{
loadData("movies.txt");
char userInput;
string movieTitle[ARRAY_SIZE];
int count = getTitle(movieTitle);
bool endOfProgram = false;
while (endOfProgram ==false)
{
cout << "1. Read in Collection" << endl;
cout << "2. Print Collection" << endl;
cout << "3. Add a Movie to the Collection" << endl;
cout << "4. Write out Collection" << endl;
cout << "5. Quit the Program" <<endl;
cin >> userInput;
switch(userInput)
{
case('1'):
{
loadData("movies.txt");
break;
}
case('2'):
{
showAll(loadData("movies.txt"));
break;
}
case('3'):
{
cout << getTitle(movieTitle);
break;
}
case('4'):
{
cout <<"Write out Collection" << endl;
writeData("movies.txt");
break;
case('5'):
{
endOfProgram=true;
cout << "Have a nice day" <<endl;
break;
}
}
}
}
}
int loadData (string pathname)
{
int count = 0;
ifstream inFile;
inFile.open(pathname.c_str());
if (!inFile)
return -1;
else
{
while(!inFile.eof())
{
getline(inFile, movieTitle[count]);
count++;
}
}
return count;
}
int writeData (string pathname)
{
ofstream outfile;
outfile.open("movies.txt");
if(!outfile.is_open())
{
cout << "Cannot open movies.txt" << endl;
return -1;
}
outfile.close();
return 0;
}
void showAll (int count)
{
cout << "\n";
for (int i=0; i< count; i++)
{
cout << movieTitle[i] << endl;
}
cout << "\n";
}
int getTitle (string movieTitle[])
{
string movie;
int count = 0;
while(true)
{
cout <<"Enter Movie Titles (Type 'q' to quit)" <<endl;
cin >> movie;
if (movie == "q")
{
break;
}
movieTitle [count] = movie;
count++;
}
return count;
}

Answer 1

I believe cin reads until eol is found, i.e. the user presses return.
So look for integer in the userInput variable, and pass that to your switch statement
int nr = atoi(userInput.c_str())
switch(nr){
case 1:
case 2: etc ...

Answer 2

In your codes it is not clear why it directly goes to case '3'. It should wait for a user input first. Seems like something already available in buffer. Just put one cout statement in case '3': and check what it print. If possible put break point there and run the application in debug mode and check the value. Hope this will help you.
case('3'):
{
cout<<"Value of userInput is: "<<userInput<<endl;
cout << getTitle(movieTitle);
break;
}
Alternately you can add the below line of code just before cin like below
std::cin.clear();
cin >> userInput;

Answer 3

I recommend inputting an integer instead of a character for your input.
You will need to change the case values too:
int selection = 0;
//...
cin >> selection;
switch (selection)
{
case 1:
//...
}
You won't have to worry about characters in the buffer. The stream will fail if an integer is not read.