How IF statement works with AND and OR? - if-statement

Question

Suppose that I have the following code in a generic language:
a = 1
b = 2
IF a == 3 AND b == 2:
do something
ELSE:
do something
If a == 3 is false the program wouldn't need to check the second part because always results false for any value of n.
In the same way with or:
a = 1
b = 2
IF a == 1 OR b == 3:
do something
ELSE:
do something
if a == 1 is true the program wouldn't need to check if b == 3 because is always true.
I want to know if the program stops in the first part in these cases.

Answer 1

It could very well depend on the language. I know that in C/C++ it would indeed only check b==2 if a==3 in the case of an and statement. I wasn't positive about the or statement, but I just checked by running this and the output I got indicates only the first part of the or statement executes. I'd recommend going through the effort of just writing your own sample to test such questions in the future.
#include <stdio.h>
int call_false()
{
printf("CALL FALSE \n\r");
return 0;
}
int call_true()
{
printf("CALL TRUE \n\r");
return 1;
}
int main()
{
printf("Hello World");
int a = 1;
int b = 2;
if( a == call_true() || b == call_false())
{
printf("TRUE \n\r");
}else
{
printf("FALSE");
}
return 0;
}
Gives the following output:
Hello WorldCALL TRUE
TRUE
...Program finished with exit code 0
Press ENTER to exit console.