I am trying to solve the yodaness problem, but my code is not outputting anything when i run my program. I am not sure where my mistake is, because my code is compiling and running just with no output. I am trying to count the number of inversions in a string of characters, but I am not sure that I am going about it the correct way. Any help would be appreciated, thanks
#include <iostream>
#include <sstream>
#include <limits>
#include <map>
#include <string>
using namespace std;
const int MAX = 30000, LEN = 33;
int total = 0;
map<string, int> index_words(const string &line)
{
map<string, int> result;
istringstream in(line);
string word;
int index = 0;
while (in >> word)
{
if (result.find(word) == result.end())
result[word] = index++;
}
return result;
}
void merge(int *a, int p, int q, int r) {
int i, j, k, n1 = (q-p+1), n2 = (r-q);
int L[n1], R[n2];
for(i=0;i<n1;i++) L[i] = a[p+i];
for(j=0;j<n2;j++) R[j] = a[q+j+q];
for(k=p, i=j=0; k<=r; k++) {
if(j>=n2 || (i<n1 && L[i] <=R[j])) a[k] = L[i++];
else {
total += n1-i;
a[i] = R[j++];
}
}
}
void mergesort(int *a, int p, int r) {
if(p<r) {
int q = (p+r)/2;
mergesort(a,p,q);
mergesort(a,q+1,r);
merge(a,p,q,r);
total++;
}
}
char word[MAX][LEN];
int a[MAX];
int main()
{
cin >> instances;
char temp[LEN];
for (int i = 0; i < instances; ++i)
{
int numwords;
cin >> numwords;
cin.ignore(numeric_limits<streamsize>::max(), '\n';
string yoda_line, english_line;
getline(std::cin, yoda_line);
getline(std::cin, english_line);
auto yoda_idx = index_words(yoda_line);
auto english_idx = index_words(english_line);
for(int i = 0; i < instances; i++) a[i] = yoda_idx[word[i]];
mergesort(a,0, instances-1);
cout << total;
}
}
Related
It is good array only if gcd(val[i],val[j])>1
Here,
gcd(a,b) = Greatest common divisor of two numbers.
Split the array has one parameter
Val: A integer array of n integer
Here are two examples.
Sample Input 0:
5 // no of value in an integer
2
3
2
3
3
Sample Output 0:
2
Sample Input 1:
5 //no of value in an integer
3
5
7
11
2
Sample Output 1:
5
example of sample input 0
subarray[1..3] ={2,3,2} here gcd(2,2)>1
subarray[4..5]={3,3} gcd(3,3)>1
#include <bits/stdc++.h>
using namespace std;
string ltrim(const string &);
string rtrim(const string &);
Now how to impelement the splitTheArray() function?
You need to find the minimum number of subarrays such that in each sub-array, first and last elements' gcd > 1. You can do it easily by O(Nˆ2) complexity.
int splitTheArray(vector<int> val) {
// implement this function
int sz = val.size();
if(sz == 0) return 0;
int ind = sz - 1;
int subarray = 0;
while(ind >= 0) {
for(int i = 0; i <= ind; i++) {
if(__gcd(val[ind], val[i]) > 1) {
subarray++;
ind = i-1;
break;
}
}
}
return subarray;
}
#include <iostream>
#include <vector>
#include <fstream>
#include <string>
using namespace std;
int gcd(int a, int b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
int max(int a, int b)
{
return (a > b) ? a : b;
}
int min(int a, int b)
{
return (a < b) ? a : b;
}
int solve(vector<int> vec)
{
int n = gcd(vec[0], vec[vec.size() - 1]);
if (n > 1)
return 0;
int con = 0 , flag = 0 , j=0 , i=0 , flag2=0;
for (i = j; i < vec.size()/2; i++)
{
i = j;
if (i >= vec.size())
break;
int f = vec[i];
flag = 0;
for (j = i+1; j < vec.size(); j++)
{
int l = vec[j];
int ma = max(f, l);
int mi = min(f, l);
n = gcd(ma, mi);
if (flag)
{
if (n > 1)
con++;
else
break;
}
if (n > 1)
{
flag = 1;
flag2 = 1;
con++;
}
}
}
if (!flag2)
return vec.size();
return con;
}
int main()
{
int n;
cin >> n;
vector<int> vec;
for (int i = 0; i < n; i++)
{
int tm;
cin >> tm;
vec.emplace_back(tm);
}
cout<<solve(vec);
return 0;
}
#include <bits/stdc++.h>
using namespace std;
#define int long long int
#define boost ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
void solve()
{
int n,i,j;
cin>>n;
int A[n+1],DP[n+1];
for(i=1;i<=n;i++)
cin>>A[i];
memset(DP,0,sizeof(DP));
unordered_map<int,int> M;
for(i=1;i<=n;i++)
{
vector<int> Fact;
Fact.push_back(A[i]);
for(j=2;j*j<=A[i];j++)
{
if(A[i]%j==0)
{
if(j*j==A[i])
{
Fact.push_back(j);
}
else
{
Fact.push_back(j);
Fact.push_back(A[i]/j);
}
}
}
int ans=DP[i-1]+1;
for(j=0;j<Fact.size();j++)
{
if(M.find(Fact[j])==M.end())
{
M[Fact[j]]=DP[i-1];
}
else
{
ans=min(ans,M[Fact[j]]+1);
}
}
DP[i]=ans;
}
cout<<DP[n]<<endl;
}
int32_t main()
{
boost;
int t=1;
// cin>>t;
for(int i=1;i<=t;i++)
{
//cout<<"Case #"<<i<<": ";
solve();
}
}
Time Complexity: N*Sqrt(max(A[i]))
P.S There can be a optimization of calculation of factor using the sieve instead of calculating factor every time for every number.
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
vector<int>a(n);
for(int i=0;i<n;i++){
cin>>a[i];
}
vector<int>dp(n+1,0);
dp[n-1]=1;
for(int i=n-2;i>=0;i--){
dp[i]=1+dp[i+1];
for(int j=i+1;j<n;j++){
if(__gcd(a[i],a[j])>1)
dp[i]=min(dp[i],1+dp[j+1]);
}
}
cout<<dp[0];
return 0;
}
I keep getting the segmentation fault (core dumped) on the code below. Any ideas on why this is happening. The code is designed to read numbers from a text document, convert them to integers, perform radix sort, and print out the array.
#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
#include <time.h>
#include <sstream>
using namespace std;
int getMax(int arr[], int n)
{
int max = arr[0];
for (int i = 1; i < n; i++)
if (arr[i] > max)
max = arr[i];
return max;
}
void countSort(int arr[], int n, int exp)
{
int output[n];
int i, count[10] = {0};
for (i = 0; i < n; i++)
count[(arr[i] / exp) % 10]++;
for (i = 1; i < 10; i++)
count[i] += count[i - 1];
for (i = n - 1; i >= 0; i--)
{
output[count[(arr[i] / exp) % 10] - 1] = arr[i];
count[(arr[i] / exp) % 10]--;
}
for (i = 0; i < n; i++)
arr[i] = output[i];
}
void radixsort(int arr[], int n)
{
clock_t clockStart;
clockStart = clock();
int m = getMax(arr, n);
for (int exp = 1; m / exp > 0; exp *= 10)
countSort(arr, n, exp);
cout << "\nTime taken by radix sort: " << (double)(clock() - clockStart) / CLOCKS_PER_SEC << endl;
}
int StrToInt(string sti)
{
int f;
stringstream ss(sti); //turn the string into a stream
ss >> f;
return f;
}
int main()
{
int arr[10000];
int i = 0;
int result;
string line = "";
ifstream myfile;
myfile.open("integers2.txt");
if(myfile.is_open())
{
while(!myfile.eof())
{
getline(myfile, line);
result = StrToInt(line);
arr[i] = result;
//cout<< arr[i] <<"\n";
i++;
}
}
int n = sizeof(arr)/sizeof(arr[0]);
radixsort(arr, n);
for (int i = 0; i < n; i++)
{
cout << arr[i] << "\n";
}
return 0;
}
Contents of the text file I am using for input:
1244
3455
6565
55
765
8768
687
879
Your program has undefined behavior, because it uses more entries of the array than you initialized with data. You pass the length of the entire array for n even though only a small portion of it, from 0 to i, has been initialized.
Change the code to use n in place of i in the reading loop, and pass that n unmodified to the sort function. This is going to fix the problem (demo).
int n = 0;
myfile.open("integers2.txt");
if(myfile.is_open()) {
while (myfile >> arr[n]) {
n++;
}
}
radixsort(arr, n);
Here's your working code:
#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
#include <time.h>
#include <sstream>
using namespace std;
int getMax(int arr[], int n)
{
int max = arr[0];
for (int i = 1; i < n; i++)
if (arr[i] > max)
max = arr[i];
return max;
}
void countSort(int arr[], int n, int exp)
{
int output[n];
int i, count[10] = {0};
for (i = 0; i < n; i++)
count[(arr[i] / exp) % 10]++;
for (i = 1; i < 10; i++)
count[i] += count[i - 1];
for (i = n - 1; i >= 0; i--)
{
output[count[(arr[i] / exp) % 10] - 1] = arr[i];
count[(arr[i] / exp) % 10]--;
}
for (i = 0; i < n; i++)
arr[i] = output[i];
}
void radixsort(int arr[], int n)
{
clock_t clockStart;
clockStart = clock();
int m = getMax(arr, n);
for (int exp = 1; m / exp > 0; exp *= 10)
countSort(arr, n, exp);
cout << "\nTime taken by radix sort: " << (double)(clock() - clockStart) / CLOCKS_PER_SEC << endl;
}
int StrToInt(string sti)
{
int f;
stringstream ss(sti); //turn the string into a stream
ss >> f;
return f;
}
int main()
{
const int MAX_SIZE = 10;
int arr[ MAX_SIZE ] = { 0 };
//int i = 0;
//int result = 0;
string line = "";
ifstream myfile;
myfile.open("integers2.txt");
if(!myfile.is_open())
{
cerr << "Could not open file!\n";
return -1;
}
cout << "Reading integers...\n";
int index = 0;
//while ( index < SIZE && getline( myfile, line ) )
while ( index < MAX_SIZE && myfile >> arr[ index ] )
{
//getline( myfile, line );
//result = StrToInt( line );
//arr[index] = std::stoi( line );
cout << arr[index] <<"\n";
index++;
}
cout << "Sorting integers...\n";
//int n = sizeof(arr) / sizeof(arr[0]);
radixsort( arr, index );
for ( int i = 0; i < index; i++ )
{
cout << arr[i] << "\n";
}
return 0;
}
Some points:
Check std::stoi for string to integer conversion; BTW, you don't need to do that. Just read it directly like this: while ( file >> integer ).
Need to check if the file is open; return ERROR otherwise; in your case, the rest of the code was executing anyway even if the file was not open i.e. code after if ( myfile.open() ) { ... }
while( !myfile.eof() ) is bad practice. See: Why is iostream::eof inside a loop condition considered wrong?
You don't need to calculate the size like int n = sizeof(arr) / sizeof(arr[0]); because you already know the size. Just use a const for this.
While reading from file, you also need to validate the maximum size of your array. You should read what the size allows you. Take care of out-of-bounds read / write errors.
Use <ctime> instead of <time.h>.
I am trying to convert this code that works for '0' - '3' strings to integer so that it will work for higher numbers
#include <string>
#include <iostream>
using namespace std;
void permutate(char[], int );
bool recurse(char[], int );
int main()
{
int strLength;
cout << "Enter your desired length: ";
cin >> strLength;
char strArray[strLength];
for (int i = 0; i<strLength; i++)
strArray[i] = '0';
permutate(strArray, sizeof(strArray));
return 0;
}
void permutate(char charArray[], int length)
{
string wait;
length--;
bool done = false;
while(!done)
{
for (int i = 0; i <= length; i++)
cout << charArray[i];
cout << endl;
if (charArray[length] == '3')
done = recurse(charArray, length);
else
charArray[length] = (char)(charArray[length]+1);
}
}
bool recurse(char charArray[], int length)
{
bool done = false;
int temp = length;
if (temp > 1)
{
charArray[temp] = '0';
if (charArray[temp-1] == '3')
{
temp--;
done = recurse(charArray, temp);
}
else
(charArray[temp-1] = (char)(charArray[temp-1] + 1));
}
else
{
charArray[temp] = '0';
if (charArray[temp-1] == '3')
done = true;
else
charArray[temp-1] = (char)(charArray[temp-1]+1);
}
return done;
}
I changed every char to int,
every '0' = 0, '3' = 3
every (charArray[temp-1] = (char)(charArray[temp-1] + 1)); to charArray[temp-1]++;
I tried to debug but I still can`t make it work :(
Manged to fix it( works for high numbers):
#include <string>
#include <iostream>
using namespace std;
void permutate(int[], int, int );
bool recurse(int[], int, int );
int main()
{
int strLength, nrElem;
cout << "Enter your desired length: ";
cin >> strLength;
cout << "Enter nr elem: ";
cin >> nrElem;
int strArray[strLength];
for (int i = 0; i<strLength; i++)
strArray[i] = 0;
permutate(strArray, strLength, nrElem );
cout << "\nSTOP";
return 0;
}
void permutate(int charArray[], int length, int nrElem)
{
// length--;
bool done = false;
while(!done)
{
for (int i = 0; i < length; i++)
cout << charArray[i] << " ";
cout << endl;
if (charArray[length - 1] == nrElem)
//done = true;
done = recurse(charArray, length, nrElem);
else
charArray[length - 1]++;
}
}
bool recurse(int charArray[], int length, int nrElem)
{
bool done = false;
int temp = length ;
if (temp > 1)
{
charArray[temp] = 0;
if (charArray[temp-1] == nrElem)
{
temp--;
done = recurse(charArray, temp, nrElem);
}
else
charArray[temp-1]++;
}
else
{
charArray[temp] = 0;
if (charArray[temp-1] == nrElem)
done = true;
else
charArray[temp-1]++;
}
return done;
}
In your permutate function, you're incrementing charArray[length] but checking to see if charArray[length - 1] is equal to nrElem, so you never end up calling recurse.
Here is a short piece of code to do the same (not an answer, however it did not look right in a comment field), not sure if you need the recursion, if you do not this code may be of interest:
#include <iostream>
#include <sstream>
using namespace std;
string output(int firstIntSize, int secondIntSize)
{
std::ostringstream oss;
for (int i = 0; i<firstIntSize; i++)
{
for (int j = 0; j< secondIntSize; j++)
{
oss << i << j << " ";
}
}
return oss.str();
}
int main()
{
cout << output(2,3);
return 0;
}
hmmm... Why not simply make a Permutations algorithm and then use a generic function to print whatever you are permutating. Here's how I would do it for strings:
#include <iostream>
#include <string>
template<class T>
void print(T * A, unsigned n){ //for printing purposes
for(unsigned i=0;i<n;i++){
std::cout<<A[i]<<" ";
}
std::cout<<std::endl;
}
void generate_permutations(unsigned k, std::string str, char *A, bool *U){
// k is the position that we need to fill, starts from 0 and goes to the end.
if(k<str.size()) //if k==str.size() then we will print it
for(unsigned i=0;i<str.size();i++){
if(U[i]==0){
A[k]=str[i]; U[i]=1;
generate_permutations(k+1, str, A,U);
U[i]=0; //after the recursion is finished and printed, we can release the letter.
}
}
else
print(A,str.size());
}
int main(){
std::string str;
std::cout<<"Enter the string to be permutated: \n";
std::cin>>str;
int n;
n = str.length(); // You don't really need to ask the user the size of the string he/she wants to enter.
bool *U; // we will keep track of the used letters with the help of this boolean vector
char *A; // we will copy the contents of str here, so that we keep the str intact
U = new bool[n];
for (int i=0;i<n;i++) U[i]=false;
A = new char[n];
for (int i=0;i<n;i++) A[i]=str[i];
generate_permutations(0,str,A,U);
return 0;
}
Now if you want to convert to numbers (ints), it's almost the same:
#include <iostream>
template<class T>
void print(T * A, int n){
for(int i=0;i<n;i++){
std::cout<<A[i]<<" ";
}
std::cout<<std::endl;
}
void generate_permutations(int k, int *A, bool *U, int n){
if(k==n)
print(A,n);
else {
for(int i=0;i<n;i++){
if(U[i]==0){
A[k]=i; U[i]=1;
generate_permutations(k+1,A,U,n);
U[i]=0;
}
}
}
}
int main(){
int n;
std::cout<<"Permutations of how many objects? \n";
std::cin>>n;
int * A;
bool *U;
A = new int[n];
U = new bool[n];
for (int i=0;i<n;i++) U[i]=false;
print(U, n);
generate_permutations(0,A,U,n);
return 0;
}
I have an array, and the user can insert a string.
And I have this code:
int main(){
char anagrama[13];
cin >> anagrama;
for(int j = 0; j < strlen(anagrama); j++){
cout << anagrama[j];
for(int k = 0; k < strlen(anagrama); k++){
if(j != k)
cout << anagrama[k];
}
cout << endl;
}
}
The problem is that I need all permutations of the string in sorted order.
For example if the user write: abc, the output must to be:
abc
acb
bac
bca
cab
cba
and my code doesn't show all permutations, and not sorted
Can you help me?
I need do the implementation without a function already implemented.
I think with a recursive function, but I do not know how.
This is an example:
http://www.disfrutalasmatematicas.com/combinatoria/combinaciones-permutaciones-calculadora.html without repetition and sorted
In C++ you can use std::next_permutation to go through permutations one by one. You need to sort the characters alphabetically before calling std::next_permutation for the first time:
cin>>anagrama;
int len = strlen(anagrama);
sort(anagrama, anagrama+len);
do {
cout << anagrama << endl;
} while (next_permutation(anagrama, anagrama+len));
Here is a demo on ideone.
If you must implement permutations yourself, you could borrow the source code of next_permutation, or choose a simpler way of implementing a permutation algorithm recursively.
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
void permute(string select, string remain){
if(remain == ""){
cout << select << endl;
return;
}
for(int i=0;remain[i];++i){
string wk(remain);
permute(select + remain[i], wk.erase(i, 1));
}
}
int main(){
string anagrama;
cout << "input character set >";
cin >> anagrama;
sort(anagrama.begin(), anagrama.end());
permute("", anagrama);
}
Another version
#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>
using namespace std;
void permute(string& list, int level, vector<string>& v){
if(level == list.size()){
v.push_back(list);
return;
}
for(int i=level;list[i];++i){
swap(list[level], list[i]);
permute(list, level + 1, v);
swap(list[level], list[i]);
}
}
int main(){
string anagrama;
vector<string> v;
cout << "input character set >";
cin >> anagrama;
permute(anagrama, 0, v);
sort(v.begin(), v.end());
copy(v.begin(), v.end(), ostream_iterator<string>(cout, "\n"));
}
#alexander the output of this programme is in exact order as requested by you:
HERE, is a simplest code for generating all combination/permutations of a given array without including some special libraries (only iostream.h and string are included) and without using some special namespaces than usual ( only namespace std is used).
void shuffle_string_algo( string ark )
{
//generating multi-dimentional array:
char** alpha = new char*[ark.length()];
for (int i = 0; i < ark.length(); i++)
alpha[i] = new char[ark.length()];
//populating given string combinations over multi-dimentional array
for (int i = 0; i < ark.length(); i++)
for (int j = 0; j < ark.length(); j++)
for (int n = 0; n < ark.length(); n++)
if( (j+n) <= 2 * (ark.length() -1) )
if( i == j-n)
alpha[i][j] = ark[n];
else if( (i-n)== j)
alpha[i][j] = ark[ ark.length() - n];
if(ark.length()>=2)
{
for(int i=0; i<ark.length() ; i++)
{
char* shuffle_this_also = new char(ark.length());
int j=0;
//storing first digit in golobal array ma
ma[v] = alpha[i][j];
//getting the remaning string
for (; j < ark.length(); j++)
if( (j+1)<ark.length())
shuffle_this_also[j] = alpha[i][j+1];
else
break;
shuffle_this_also[j]='\0';
//converting to string
string send_this(shuffle_this_also);
//checking if further combinations exist or not
if(send_this.length()>=2)
{
//review the logic to get the working idea of v++ and v--
v++;
shuffle_string_algo( send_this);
v--;
}
else
{
//if, further combinations are not possiable print these combinations
ma[v] = alpha[i][0];
ma[++v] = alpha[i][1];
ma[++v] = '\0';
v=v-2;
string disply(ma);
cout<<++permutaioning<<":\t"<<disply<<endl;
}
}
}
}
and main:
int main()
{
string a;
int ch;
do
{
system("CLS");
cout<<"PERMUNATING BY ARK's ALGORITH"<<endl;
cout<<"Enter string: ";
fflush(stdin);
getline(cin, a);
ma = new char[a.length()];
shuffle_string_algo(a);
cout<<"Do you want another Permutation?? (1/0): ";
cin>>ch;
} while (ch!=0);
return 0;
}
HOPE! it helps you! if you are having problem with understanding logic just comment below and i will edit.
/*Think of this as a tree. The depth of the tree is same as the length of string.
In this code, I am starting from root node " " with level -1. It has as many children as the characters in string. From there onwards, I am pushing all the string characters in stack.
Algo is like this:
1. Put root node in stack.
2. Loop till stack is empty
2.a If backtracking
2.a.1 loop from last of the string character to present depth or level and reconfigure datastruture.
2.b Enter the present char from stack into output char
2.c If this is leaf node, print output and continue with backtracking on.
2.d Else find all the neighbors or children of this node and put it them on stack. */
class StringEnumerator
{
char* m_string;
int m_length;
int m_nextItr;
public:
StringEnumerator(char* str, int length): m_string(new char[length + 1]), m_length(length) , m_Complete(m_length, false)
{
memcpy(m_string, str, length);
m_string[length] = 0;
}
StringEnumerator(const char* str, int length): m_string(new char[length + 1]), m_length(length) , m_Complete(m_length, false)
{
memcpy(m_string, str, length);
m_string[length] = 0;
}
~StringEnumerator()
{
delete []m_string;
}
void Enumerate();
};
const int MAX_STR_LEN = 1024;
const int BEGIN_CHAR = 0;
struct StackElem
{
char Elem;
int Level;
StackElem(): Level(0), Elem(0){}
StackElem(char elem, int level): Elem(elem), Level(level){}
};
struct CharNode
{
int Max;
int Curr;
int Itr;
CharNode(int max = 0): Max(max), Curr(0), Itr(0){}
bool IsAvailable(){return (Max > Curr);}
void Increase()
{
if(Curr < Max)
Curr++;
}
void Decrease()
{
if(Curr > 0)
Curr--;
}
void PrepareItr()
{
Itr = Curr;
}
};
void StringEnumerator::Enumerate()
{
stack<StackElem> CStack;
int count = 0;
CStack.push(StackElem(BEGIN_CHAR,-1));
char answerStr[MAX_STR_LEN];
memset(answerStr, 0, MAX_STR_LEN);
bool forwardPath = true;
typedef std::map<char, CharNode> CharMap;
typedef CharMap::iterator CharItr;
typedef std::pair<char, CharNode> CharPair;
CharMap mCharMap;
CharItr itr;
//Prepare Char Map
for(int i = 0; i < m_length; i++)
{
itr = mCharMap.find(m_string[i]);
if(itr != mCharMap.end())
{
itr->second.Max++;
}
else
{
mCharMap.insert(CharPair(m_string[i], CharNode(1)));
}
}
while(CStack.size() > 0)
{
StackElem elem = CStack.top();
CStack.pop();
if(elem.Level != -1) // No root node
{
int currl = m_length - 1;
if(!forwardPath)
{
while(currl >= elem.Level)
{
itr = mCharMap.find(answerStr[currl]);
if((itr != mCharMap.end()))
{
itr->second.Decrease();
}
currl--;
}
forwardPath = true;
}
answerStr[elem.Level] = elem.Elem;
itr = mCharMap.find(elem.Elem);
if((itr != mCharMap.end()))
{
itr->second.Increase();
}
}
//If leaf node
if(elem.Level == (m_length - 1))
{
count++;
cout<<count<<endl;
cout<<answerStr<<endl;
forwardPath = false;
continue;
}
itr = mCharMap.begin();
while(itr != mCharMap.end())
{
itr->second.PrepareItr();
itr++;
}
//Find neighbors of this elem
for(int i = 0; i < m_length; i++)
{
itr = mCharMap.find(m_string[i]);
if(/*(itr != mCharMap.end()) &&*/ (itr->second.Itr < itr->second.Max))
{
CStack.push(StackElem(m_string[i], elem.Level + 1));
itr->second.Itr++;
}
}
}
}
I wrote one without a function already implemented even any templates and containers. actually it was written in C first, but has been transform to C++.
easy to understand but poor efficiency, and its output is what you want, sorted.
#include <iostream>
#define N 4
using namespace std;
char ch[] = "abcd";
int func(int n) {
int i,j;
char temp;
if(n==0) {
for(j=N-1;j>=0;j--)
cout<<ch[j];
cout<<endl;
return 0;
}
for(i=0;i<n;i++){
temp = ch[i];
for(j=i+1;j<n;j++)
ch[j-1] = ch[j];
ch[n-1] = temp;
//shift
func(n-1);
for(j=n-1;j>i;j--)
ch[j] = ch[j-1];
ch[i] = temp;
//and shift back agian
}
return 1;
}
int main(void)
{
func(N);
return 0;
}
In case you have std::vector of strings then you can 'permute' the vector items as below.
C++14 Code
#include <iostream>
#include <algorithm>
#include <iostream>
#include <string>
#include <vector>
#include <boost/algorithm/string/join.hpp>
using namespace std;
int main() {
// your code goes here
std::vector<std::string> s;
s.push_back("abc");
s.push_back("def");
s.push_back("ghi");
std::sort(s.begin(), s.end());
do
{
std::cout << boost::algorithm::join(s,"_") << std::endl ;
} while(std::next_permutation(s.begin(), s.end()));
return 0;
}
Output:
abc_def_ghi
abc_ghi_def
def_abc_ghi
def_ghi_abc
ghi_abc_def
ghi_def_abc
I have an array, and the user can insert a string.
And I have this code:
int main(){
char anagrama[13];
cin >> anagrama;
for(int j = 0; j < strlen(anagrama); j++){
cout << anagrama[j];
for(int k = 0; k < strlen(anagrama); k++){
if(j != k)
cout << anagrama[k];
}
cout << endl;
}
}
The problem is that I need all permutations of the string in sorted order.
For example if the user write: abc, the output must to be:
abc
acb
bac
bca
cab
cba
and my code doesn't show all permutations, and not sorted
Can you help me?
I need do the implementation without a function already implemented.
I think with a recursive function, but I do not know how.
This is an example:
http://www.disfrutalasmatematicas.com/combinatoria/combinaciones-permutaciones-calculadora.html without repetition and sorted
In C++ you can use std::next_permutation to go through permutations one by one. You need to sort the characters alphabetically before calling std::next_permutation for the first time:
cin>>anagrama;
int len = strlen(anagrama);
sort(anagrama, anagrama+len);
do {
cout << anagrama << endl;
} while (next_permutation(anagrama, anagrama+len));
Here is a demo on ideone.
If you must implement permutations yourself, you could borrow the source code of next_permutation, or choose a simpler way of implementing a permutation algorithm recursively.
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
void permute(string select, string remain){
if(remain == ""){
cout << select << endl;
return;
}
for(int i=0;remain[i];++i){
string wk(remain);
permute(select + remain[i], wk.erase(i, 1));
}
}
int main(){
string anagrama;
cout << "input character set >";
cin >> anagrama;
sort(anagrama.begin(), anagrama.end());
permute("", anagrama);
}
Another version
#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>
using namespace std;
void permute(string& list, int level, vector<string>& v){
if(level == list.size()){
v.push_back(list);
return;
}
for(int i=level;list[i];++i){
swap(list[level], list[i]);
permute(list, level + 1, v);
swap(list[level], list[i]);
}
}
int main(){
string anagrama;
vector<string> v;
cout << "input character set >";
cin >> anagrama;
permute(anagrama, 0, v);
sort(v.begin(), v.end());
copy(v.begin(), v.end(), ostream_iterator<string>(cout, "\n"));
}
#alexander the output of this programme is in exact order as requested by you:
HERE, is a simplest code for generating all combination/permutations of a given array without including some special libraries (only iostream.h and string are included) and without using some special namespaces than usual ( only namespace std is used).
void shuffle_string_algo( string ark )
{
//generating multi-dimentional array:
char** alpha = new char*[ark.length()];
for (int i = 0; i < ark.length(); i++)
alpha[i] = new char[ark.length()];
//populating given string combinations over multi-dimentional array
for (int i = 0; i < ark.length(); i++)
for (int j = 0; j < ark.length(); j++)
for (int n = 0; n < ark.length(); n++)
if( (j+n) <= 2 * (ark.length() -1) )
if( i == j-n)
alpha[i][j] = ark[n];
else if( (i-n)== j)
alpha[i][j] = ark[ ark.length() - n];
if(ark.length()>=2)
{
for(int i=0; i<ark.length() ; i++)
{
char* shuffle_this_also = new char(ark.length());
int j=0;
//storing first digit in golobal array ma
ma[v] = alpha[i][j];
//getting the remaning string
for (; j < ark.length(); j++)
if( (j+1)<ark.length())
shuffle_this_also[j] = alpha[i][j+1];
else
break;
shuffle_this_also[j]='\0';
//converting to string
string send_this(shuffle_this_also);
//checking if further combinations exist or not
if(send_this.length()>=2)
{
//review the logic to get the working idea of v++ and v--
v++;
shuffle_string_algo( send_this);
v--;
}
else
{
//if, further combinations are not possiable print these combinations
ma[v] = alpha[i][0];
ma[++v] = alpha[i][1];
ma[++v] = '\0';
v=v-2;
string disply(ma);
cout<<++permutaioning<<":\t"<<disply<<endl;
}
}
}
}
and main:
int main()
{
string a;
int ch;
do
{
system("CLS");
cout<<"PERMUNATING BY ARK's ALGORITH"<<endl;
cout<<"Enter string: ";
fflush(stdin);
getline(cin, a);
ma = new char[a.length()];
shuffle_string_algo(a);
cout<<"Do you want another Permutation?? (1/0): ";
cin>>ch;
} while (ch!=0);
return 0;
}
HOPE! it helps you! if you are having problem with understanding logic just comment below and i will edit.
/*Think of this as a tree. The depth of the tree is same as the length of string.
In this code, I am starting from root node " " with level -1. It has as many children as the characters in string. From there onwards, I am pushing all the string characters in stack.
Algo is like this:
1. Put root node in stack.
2. Loop till stack is empty
2.a If backtracking
2.a.1 loop from last of the string character to present depth or level and reconfigure datastruture.
2.b Enter the present char from stack into output char
2.c If this is leaf node, print output and continue with backtracking on.
2.d Else find all the neighbors or children of this node and put it them on stack. */
class StringEnumerator
{
char* m_string;
int m_length;
int m_nextItr;
public:
StringEnumerator(char* str, int length): m_string(new char[length + 1]), m_length(length) , m_Complete(m_length, false)
{
memcpy(m_string, str, length);
m_string[length] = 0;
}
StringEnumerator(const char* str, int length): m_string(new char[length + 1]), m_length(length) , m_Complete(m_length, false)
{
memcpy(m_string, str, length);
m_string[length] = 0;
}
~StringEnumerator()
{
delete []m_string;
}
void Enumerate();
};
const int MAX_STR_LEN = 1024;
const int BEGIN_CHAR = 0;
struct StackElem
{
char Elem;
int Level;
StackElem(): Level(0), Elem(0){}
StackElem(char elem, int level): Elem(elem), Level(level){}
};
struct CharNode
{
int Max;
int Curr;
int Itr;
CharNode(int max = 0): Max(max), Curr(0), Itr(0){}
bool IsAvailable(){return (Max > Curr);}
void Increase()
{
if(Curr < Max)
Curr++;
}
void Decrease()
{
if(Curr > 0)
Curr--;
}
void PrepareItr()
{
Itr = Curr;
}
};
void StringEnumerator::Enumerate()
{
stack<StackElem> CStack;
int count = 0;
CStack.push(StackElem(BEGIN_CHAR,-1));
char answerStr[MAX_STR_LEN];
memset(answerStr, 0, MAX_STR_LEN);
bool forwardPath = true;
typedef std::map<char, CharNode> CharMap;
typedef CharMap::iterator CharItr;
typedef std::pair<char, CharNode> CharPair;
CharMap mCharMap;
CharItr itr;
//Prepare Char Map
for(int i = 0; i < m_length; i++)
{
itr = mCharMap.find(m_string[i]);
if(itr != mCharMap.end())
{
itr->second.Max++;
}
else
{
mCharMap.insert(CharPair(m_string[i], CharNode(1)));
}
}
while(CStack.size() > 0)
{
StackElem elem = CStack.top();
CStack.pop();
if(elem.Level != -1) // No root node
{
int currl = m_length - 1;
if(!forwardPath)
{
while(currl >= elem.Level)
{
itr = mCharMap.find(answerStr[currl]);
if((itr != mCharMap.end()))
{
itr->second.Decrease();
}
currl--;
}
forwardPath = true;
}
answerStr[elem.Level] = elem.Elem;
itr = mCharMap.find(elem.Elem);
if((itr != mCharMap.end()))
{
itr->second.Increase();
}
}
//If leaf node
if(elem.Level == (m_length - 1))
{
count++;
cout<<count<<endl;
cout<<answerStr<<endl;
forwardPath = false;
continue;
}
itr = mCharMap.begin();
while(itr != mCharMap.end())
{
itr->second.PrepareItr();
itr++;
}
//Find neighbors of this elem
for(int i = 0; i < m_length; i++)
{
itr = mCharMap.find(m_string[i]);
if(/*(itr != mCharMap.end()) &&*/ (itr->second.Itr < itr->second.Max))
{
CStack.push(StackElem(m_string[i], elem.Level + 1));
itr->second.Itr++;
}
}
}
}
I wrote one without a function already implemented even any templates and containers. actually it was written in C first, but has been transform to C++.
easy to understand but poor efficiency, and its output is what you want, sorted.
#include <iostream>
#define N 4
using namespace std;
char ch[] = "abcd";
int func(int n) {
int i,j;
char temp;
if(n==0) {
for(j=N-1;j>=0;j--)
cout<<ch[j];
cout<<endl;
return 0;
}
for(i=0;i<n;i++){
temp = ch[i];
for(j=i+1;j<n;j++)
ch[j-1] = ch[j];
ch[n-1] = temp;
//shift
func(n-1);
for(j=n-1;j>i;j--)
ch[j] = ch[j-1];
ch[i] = temp;
//and shift back agian
}
return 1;
}
int main(void)
{
func(N);
return 0;
}
In case you have std::vector of strings then you can 'permute' the vector items as below.
C++14 Code
#include <iostream>
#include <algorithm>
#include <iostream>
#include <string>
#include <vector>
#include <boost/algorithm/string/join.hpp>
using namespace std;
int main() {
// your code goes here
std::vector<std::string> s;
s.push_back("abc");
s.push_back("def");
s.push_back("ghi");
std::sort(s.begin(), s.end());
do
{
std::cout << boost::algorithm::join(s,"_") << std::endl ;
} while(std::next_permutation(s.begin(), s.end()));
return 0;
}
Output:
abc_def_ghi
abc_ghi_def
def_abc_ghi
def_ghi_abc
ghi_abc_def
ghi_def_abc