XSLT and numbers in attributes - templates

Question

I have an xml-fragment like this:
<p rend="noIndent">eget <seg type="comStart" n="com123"/>kunde<seg type="comEnd" n="com123"/> der i Anledning af disse <seg type="comStart" n="com13"/>kunde<seg type="comEnd" n="com13"/> Smaadigte være at s</p>
I want to change the numbers in the n-attribut and make the numbers starts with 1. The values in the n-attribut shold be the same for each pair of comStat and comEnd in the type-attribute, ending up with this result:
<p rend="noIndent">eget <seg type="comStart" n="com1"/>havde<seg type="comEnd" n="com1"/> der i Anledning af disse <seg type="comStart" n="com2"/>kunde<seg type="comEnd" n="com2"/> Smaadigte være at s</p>
How do I match the corresponding n-attributs in xslt?
KSR

Answer 1

If there are always pairs you can simply create the number using xsl:number for the comStart element:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="3.0">
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="*[#type = ('comStart', 'comEnd')]/#n">
<xsl:attribute name="{name()}">n<xsl:number level="any" count="*[#type = 'comStart']"/></xsl:attribute>
</xsl:template>
</xsl:stylesheet>
http://xsltfiddle.liberty-development.net/eiQZDbm
respectively
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[#type = 'comStart' or #type = 'comEnd']/#n">
<xsl:attribute name="{name()}">n<xsl:number level="any" count="*[#type = 'comStart']"/></xsl:attribute>
</xsl:template>
</xsl:stylesheet>
for XSLT 1 (http://xsltfiddle.liberty-development.net/eiQZDbm/1).