How to save url of the image in database with Django - django

Question

i am new in Django, how to save url of the image in db using django. Thank you very much, sorry my english, i am learning too.
views.py
from django.shortcuts import render
from django.views.decorators.http import require_POST
from .models import Cad_component
from django import forms
from django.views.decorators.http import require_http_methods
class register_data(forms.ModelForm):
class Meta:
model = Cad_component
fields = ('title','slug','description','start_date','imagviewe')
def home(request):
imagesData = Cad_component.objects.all()
template_name = 'index.html'
context = {
'imagesData': imagesData
}
return render(request, template_name, context)
def register(request):
if request.method == "POST":
form = register_data(request.POST)
print (form)
if form.is_valid():
datas = form.save(commit=True)
#datas.image.save(request.read['title'],request.read['image'])
datas.save()
else:
form = register_data()
return render(request, 'register.html', {'form': form})
models.py
from django.db import models
import datetime
class ComponentManager(models.Manager):
def search(self, query):
return self.get_queryset().filter(
models.Q(name__icontains=query) | \
models.Q(description__icontains=query)
)
class Cad_component(models.Model):
title = models.CharField('Title', max_length=100)
slug = models.SlugField('Link')
description = models.TextField('Description', blank=True)
start_date = models.DateField('Data: ', null=True, blank=True)
image = models.ImageField(upload_to='img', verbose_name='Imagem', null=True, blank=True)
created_at = models.DateTimeField('Criado em ', auto_now_add=True)
updated_at = models.DateTimeField('Atualizado em', auto_now=True)
objects = ComponentManager()
def __str__(self):
return self.title

Answer 1

I was able to solve this problem, with a configuration that Django does in the HTML file. Just add: enctype = "multipart / form-data" in the FORM tag.
Follow:
<form class="needs-validation" method="post" enctype="multipart/form-data">
Any doubts I am available.

Answer 2

from django.core.files.storage import FileSystemStorage
//inside the view function
myfile = request.FILES['files']
f = FileSystemStorage()
filename = f.save(myfile.name, myfile)
url = f.url(filename)
Now you can store this url.
Give an up if it worked... I am new to stackoverflow.