Django add form on every page - django

Question

In my application i need to add a form in base.html, which I've done. For this i used context_processors, now my problem is everytime i'm trying to post, i'm getting a blank page and this error: Method Not Allowed (POST)
In this form i want just to add a button where it will mark all current users notifications as read.
I know that you can use context_processors like this:
def my_context(request):
data = dict()
if request.user.is_authenticated:
data['notifications'] = Notification.objects.filter(user=request.user, read=False)
data['form'] = NotificationForm()
return data
But instead of adding the form i need these lines:
def my_context(request):
data = dict()
if request.user.is_authenticated:
data['notifications'] = Notification.objects.filter(user=request.user, read=False)
if request.method == 'POST':
if 'read-notifications' in request.POST:
for notification in data['notifications']:
notification.read = True
notification.save()
next = request.POST.get('next', '/')
return redirect(next)
return data
The form in base.html:
<form action="" method="POST">{% csrf_token %}
<input type="hidden" name="next" value="{{ request.path }}">
<button type="submit" class="btn m-btn--square btn-primary" name="read-notifications">Mark as read</button>
</form>
urls.py
url(r'^orders/create/$', views.admin_order_document, name='create_order'),
url(r'^orders/waiting/$', views.OrdersWaitingListView.as_view(), name='order_waiting_list'),
url(r'^orders/unallocated/$', views.OrdersUnallocatedListView.as_view(), name='order_unallocated_list'),
url(r'^orders/working/$', views.OrdersWorkingListView.as_view(), name='order_working_list'),
How can i show this form on every page without getting the above error?

Answer 1

So, I chose a different approach and i ended up with this solution:
base.html
<form action="{% url 'mark_read' %}" method="POST">{% csrf_token %}
<input type="hidden" name="next" value="{{ request.path }}">
<button type="submit" class="btn m-btn--square btn-primary" name="action" value="mark_read">Marchează ca citite</button>
</form>
views.py
#login_required()
def read_notifications(request):
if request.method == 'POST':
if 'action' in request.POST:
notifications = Notification.objects.filter(user=request.user, read=False)
for notification in notifications:
notification.read = True
notification.save()
next = request.POST.get('next', '/')
return redirect(next)
urls.py
url(r'^mark-read/$', views.read_notifications, name='mark_read'),
Basically, the form action will redirect me to the view function, it will do what it has to do and it will redirect me back on the same page.