How to search an element of an array? [closed] - c++

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My arrray looks like
int myarray[]={6,5,2,6,7,8,6};
I want my program to say
if a user enters '6'
"your number is found 3 times at 0,3,6".
And if its not found say"not found".
Here is my effort:
#include <iostream>
using namespace std;
int main() {
bool flag=false;
int x[]={9,11,6,7,6,4,6};
int count=0;
int n,i,j,c;
cout<<"What number do you want to search : ";
cin >>n;
for(int i=0;i<7;i++){
if(x[i]==n){
count++;
flag=true;
}
}
if(flag){
cout <<n<<" is found "<<count<<" times in :";
for(int i=0;i<7;i++){
if(x[i]==n) cout <<i<<',';
}
} else {
cout <<n<<" is not found"<<endl;
}
}

Answer 1

Here is a starting example:
#include <iostream>
using namespace std;
int main(void) {
int myarray[7] = {6,5,2,6,7,8,6};
int value;
cin >> value;
bool not_found = true;
for(int i = 0; i < 7; ++i) {
if(myarray[i] == value) {
cout << "Found value " << value << " at position " << i << "\n";
not_found = false;
}
}
if(not_found)
cout << "Not found\n";
return 0;
}
which, when the user inputs 6, will output:
Found value 6 at position 0
Found value 6 at position 3
Found value 6 at position 6
If you want to match the exact same output as the one in your question, you could store the indices (all the is in an std::vector for example), and then print them.

Answer 2

this is the code to search element in array .this method is linear search
int main()
{
int myarray[100]={6,5,2,6,7,8,6};
int sch,i,count;
int flag=1;
count=sizeof( myarray )/sizeof( myarray[0] );
cout<<"enter element to search";
cin>>sch;
for(i=0;i<count;i++)
{
if(myarray[i]==sch){
cout<<"element"<<sch<<"found. it is in position of"<<i+1;
int flag=0;
}
}
if(flag==1)
cout<<"not found";
return 0;
}