Given a string I have to test whether that ends with a known set of suffixes. Now as the the of suffixes are not very small and every word in the document has to be checked against that list of known suffixes. Every character in the word and suffix is char32_t. As a naive iterative matching will be expensive. Though most of the suffixes are not sub suffix or prefix of another suffix, most of them are constructed with a small set of characters. Most of the checks will be a miss rather than being a hit.
So I want to build a DFA of the suffixes to minimize the cost of miss. I can manually parse the unicode codepoints and create a DFA using boost-graph. But is there any existing library that will build that for me ?
Will a huge regex containing all the suffixes be less expensive than the DFA, because regex search also builds a DFA for matching in the similar way ? But I want to know which suffix was matched when there is a hit. In regex case I'll need to perform another linear search to get that (I cannot label the vertices of the regex's internal DFA). Also I need unicode regex. Just putting all the suffixes with a | will be as expensive as a linear search I guess. I think I need to check the common characters and create the regex accordingly with lookahed and lookbacks. Isn't it the same difficulty that I need to face to construct the DFA manually ?
I am using utf-32 for random access. However it is not a problem to switch to utf-8 if I can solve it easily with that. I will reverse the string and the pattern right to left.
Have you considered Spirit? Of course you didn't specify how you detect suffixes in context (do you require them at the end, do you require some grammar preceding it etc.) but you could do something like this:
x3::symbols<Char> sym;
sym += "foo", "bar", "qux";
It builds a Trie, which is pretty effective. It can parse any kind of input iterator (including streams if you are so inclined). Just add a bit of magic constrain for contextual requirements, like end-of-input:
bool has_suffix(string_view sv) {
return parse(sv.cbegin(), sv.cend(), x3::seek[suffix >> x3::eoi]);
}
If you even wish to return the text value of the string, simply do this:
string_view get_suffix(string_view sv) {
boost::iterator_range<string_view::const_iterator> output;
parse(sv.cbegin(), sv.cend(), x3::seek[x3::raw[suffix >> x3::eoi]], output);
return {output.begin(), output.size()};
}
Spirit leaves you a lot of freedom to surround with smarts, dynamically add/remove symbols, e.g. use no_case with the Trie etc.
Full Demo
Using X3 (c++14)
Live On Coliru
#include <boost/spirit/home/x3.hpp>
#include <string_view>
#include <cstdint>
namespace Demo {
using Char = char32_t;
using string_view = std::basic_string_view<Char>;
namespace x3 = boost::spirit::x3;
static auto const suffix = [] {
x3::symbols<Char> sym;
sym += "foo", "bar", "qux";
return sym; // x3::no_case[sym];
}();
bool has_suffix(string_view sv) {
return parse(sv.cbegin(), sv.cend(), x3::seek[suffix >> x3::eoi]);
}
string_view get_suffix(string_view sv) {
boost::iterator_range<string_view::const_iterator> output;
parse(sv.cbegin(), sv.cend(), x3::seek[x3::raw[suffix >> x3::eoi]], output);
return {output.begin(), output.size()};
}
}
#include <iostream>
#include <iomanip>
int main() {
using namespace Demo;
auto widen = [](string_view sv) { return std::wstring(sv.begin(), sv.end()); };
std::wcout << std::boolalpha;
for (string_view testcase : { U"nope", U"lolbar you betqux" }) {
std::wcout
<< widen(testcase)
<< L" -> " << has_suffix(testcase)
<< L" (" << widen(get_suffix(testcase))
<< L")\n";
}
}
Prints
nope -> false ()
lolbar you betqux -> true (qux)
Spirit Qi Version
A literal port: Live On Coliru
A C++11 only version: Live On Coliru
And a C++03 version for the really retro programming experience: Live On Coliru
Related
I am trying to write a simple grammar using boost spirit to validate that a string is a valid directory. I am using these tutorials since this is the first grammar I have attempted:
http://www.boost.org/doc/libs/1_36_0/libs/spirit/doc/html/spirit/qi_and_karma.html
http://www.boost.org/doc/libs/1_48_0/libs/spirit/doc/html/spirit/qi/reference/directive/lexeme.html
http://www.boost.org/doc/libs/1_44_0/libs/spirit/doc/html/spirit/qi/tutorials/employee___parsing_into_structs.html
Currently, what I have come up with is:
// I want these to be valid matches
std::string valid1 = "./";
// This string could be any number of sub dirs i.e. /home/user/test/ is valid
std::string valid2 = "/home/user/";
using namespace boost::spirit::qi;
bool match = phrase_parse(valid1.begin(), valid1.end(), lexeme[
((char_('.') | char_('/')) >> +char_ >> char_('/')],
ascii::space);
if (match)
{
std::cout << "Match!" << std::endl;
}
However, this matches nothing. I had a few ideas as to why; however, after doing some research I haven't found the answers. For example I assume the +char_ will probably consume all chars? So how can I find out if some sequence of characters all end with /?
Essentially my thoughts behind writing the above code was I want directories starting with . and / to be valid and then the last character has to be a /. Could someone help me with my grammar or point me to something more similar example to what I want to do? This is purely an excise to learn how to use spirit.
Edit
So I have got the parser to match using:
bool match = phrase_parse(valid1.begin(), valid1.end(), lexeme[
((char_('.') | char_('/')) >> *(+char_ >> char_('/'))],
ascii::space);
if (match)
{
std::cout << "Match!" << std::endl;
}
Not sure if that is proper or not? Or if it is matching for other reasons... Also should the ascii::space be used here? I read in a tutorial that it was to make spaces agnostic i.e. a b is equivalent to ab. Which I wouldn't want in a path name? If it isn't the correct thing to use what would be?
SSCCE:
#include <string>
#include <iostream>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/qi_char.hpp>
#include <boost/spirit/include/qi_eoi.hpp>
int main()
{
namespace qi = boost::spirit::qi;
std::string valid1 = "./";
std::string valid2 = "/home/blah/";
bool match = qi::parse(valid2.begin(), valid2.end(), &((qi::lit("./")|'/') >> (+~qi::char_('/') % '/') >> qi::eoi));
if (match)
{
std::cout << "Match" << std::endl;
}
}
If you don't want to ignore space differences (which you shouldn't), use parse instead of phrase_parse. The use of lexeme inhibits the skipper again (so you were just stripping leading/trailing space). See also stackoverflow.com/questions/17072987/boost-spirit-skipper-issues/17073965#17073965
Use char_("ab") instead of char_('a')|char_('b').
*char_ matches everything. You may have meant *~char_('/').
I'd suggest something like
bool ok = qi::parse(b, f, &(lit("./")|'/') >> (*~char_('/') % '/'));
This won't expose the matched input. Add raw[] around it to achieve that .
Add > qi::eoi to assert all of the input was consumed.
Using the C++ Standard Template Library function regex_replace(), how do I remove non-numeric characters from a std::string and return a std::string?
This question is not a duplicate of question
747735
because that question requests how to use TR1/regex, and I'm
requesting how to use standard STL regex, and because the answer given
is merely some very complex documentation links. The C++ regex
documentation is extremely hard to understand and poorly documented,
in my opinion, so even if a question pointed out the standard C++
regex_replace
documentation,
it still wouldn't be very useful to new coders.
// assume #include <regex> and <string>
std::string sInput = R"(AA #-0233 338982-FFB /ADR1 2)";
std::string sOutput = std::regex_replace(sInput, std::regex(R"([\D])"), "");
// sOutput now contains only numbers
Note that the R"..." part means raw string literal and does not evaluate escape codes like a C or C++ string would. This is very important when doing regular expressions and makes your life easier.
Here's a handy list of single-character regular expression raw literal strings for your std::regex() to use for replacement scenarios:
R"([^A-Za-z0-9])" or R"([^A-Za-z\d])" = select non-alphabetic and non-numeric
R"([A-Za-z0-9])" or R"([A-Za-z\d])" = select alphanumeric
R"([0-9])" or R"([\d])" = select numeric
R"([^0-9])" or R"([^\d])" or R"([\D])" = select non-numeric
Regular expressions are overkill here.
#include <algorithm>
#include <iostream>
#include <iterator>
#include <string>
inline bool not_digit(char ch) {
return '0' <= ch && ch <= '9';
}
std::string remove_non_digits(const std::string& input) {
std::string result;
std::copy_if(input.begin(), input.end(),
std::back_inserter(result),
not_digit);
return result;
}
int main() {
std::string input = "1a2b3c";
std::string result = remove_non_digits(input);
std::cout << "Original: " << input << '\n';
std::cout << "Filtered: " << result << '\n';
return 0;
}
The accepted answer if fine for the specifics of the given sample.
But it will fail for a number such as "-12.34" (it would result in "1234").
(note how the sample could be negative numbers)
Then the regex should be:
(-|\+)?(\d)+(.(\d)+)*
explanation: (optional ( "-" or "+" )) with (a number, repeated 1 to n times) with (optionally end's with: ( a "." followed by (a number, repeated 1 to n times) )
A bit over-reaching, but I was looking for this and the page showed up first in my search, so I'm adding my answer for future searches.
Consider the following string content:
string content = "{'name':'Fantastic gloves','description':'Theese gloves will fit any time period.','current':{'trend':'high','price':'47.1000'}";
I have never used regex_search and I have been searching around for ways to use it - I still do not quite get it. From that random string (it's from an API) how could I grab two things:
1) the price - in this example it is 47.1000
2) the name - in this example Fantastic gloves
From what I have read, regex_search would be the best approach here. I plan on using the price as an integer value, I will use regex_replace in order to remove the "." from the string before converting it. I have only used regex_replace and I found it easy to work with, I don't know why I am struggling so much with regex_search.
Keynotes:
Content is contained inside ' '
Content id and value is separated by :
Conent/value are separated by ,
Value of id's name and price will vary.
My first though was to locate for instance price and then move 3 characters ahead (':') and gather everything until the next ' - however I am not sure if I am completely off-track here or not.
Any help is appreciated.
boost::regex would not be needed. Regular expressions are used for more general pattern matching, whereas your example is very specific. One way to handle your problem is to break the string up into individual tokens. Here is an example using boost::tokenizer:
#include <iostream>
#include <string>
#include <boost/tokenizer.hpp>
#include <map>
int main()
{
std::map<std::string, std::string> m;
std::string content = "{'name':'Fantastic gloves','description':'Theese gloves will fit any time period.','current':{'trend':'high','price':'47.1000'}";
boost::char_separator<char> sep("{},':");
boost::tokenizer<boost::char_separator<char>> tokenizer(content, sep);
std::string id;
for (auto tok = tokenizer.begin(); tok != tokenizer.end(); ++tok)
{
// Since "current" is a special case I added code to handle that
if (*tok != "current")
{
id = *tok++;
m[id] = *tok;
}
else
{
id = *++tok;
m[id] = *++tok; // trend
id = *++tok;
m[id] = *++tok; // price
}
}
std::cout << "Name: " << m["name"] << std::endl;
std::cout << "Price: " << m["price"] << std::endl;
}
Link to live code.
As the string you are attempting to parse appears to be JSON (JavaScript Object Notation), consider using a specialized JSON parser.
You can find a comprehensive list of JSON parsers in many languages including C++ at http://json.org/. Also, I found a discussion on the merits of several JSON parsers for C++ in response to this SO question.
Migrated from [Spirit-general] list
Good morning,
I'm trying to parse a relatively simple pattern across 4 std::strings,
extracting whatever the part which matches the pattern into a separate
std::string.
In an abstracted sense, here is what I want:
s1=<string1><consecutive number>, s2=<consecutive number><string2>,
s3=<string1><consecutive number>, s4=<consecutive number><string2>
Less abstracted:
s1="apple 1", s2="2 cheese", s3="apple 3", s4="4 cheese"
Actual contents:
s1="lxckvjlxcjvlkjlkje xvcjxzlvcj wqrej lxvcjz ljvl;x czvouzxvcu
j;ljfds apple 1 xcvljxclvjx oueroi xcvzlkjv; zjx", s2="xzljlkxvc
jlkjxzvl jxcvljzx lvjlkj wre 2 cheese", s3="apple 3", s4="kxclvj
xcvjlxk jcvljxlck jxcvl 4 cheese"
How would I perform this pattern matching?
Thanks for all suggestions,
Alec Taylor
Update 2
Here is a really simple explanation I just figured out to explain the
problem I am trying to solve:
std::string s1=garbagetext1+number1+name1+garbagetext4;
std::string s3=garbagetext2+(number1+2)+name1+garbagetext5;
std::string s5=garbagetext3+(number1+4)+name1+garbagetext6;
Edit for context:
Feel free to add it to stackoverflow (I've been having some trouble
posting there)
I can't give you what I've done so far, because I wasn't sure if it
was within the capabilities of the boost::spirit libraries to do what
I'm trying to do
Edit: Re Update2
Here is a really simple explanation I just figured out to explain the
problem I am trying to solve:
std::string s1=garbagetext1+number1+name1+garbagetext4;
std::string s3=garbagetext2+(number1+2)+name1+garbagetext5;
std::string s5=garbagetext3+(number1+4)+name1+garbagetext6;
It starts looking like a job for:
Tokenizing the 'garbage text/names' - you could make a symbol table of sorts on the fly and use it to match patterns (spirit Lex and Qi's symbol table (qi::symbol) could facilitate it, but I feel you could write that in any number of ways)
conversely, use regular expressions, as suggested before (below, and at least twice in mailing list).
Here's a simple idea:
(\d+) ([a-z]+).*?(\d+) \2
\d+ match a sequence of digits in a "(subexpression)" (NUM1)
([a-z]+) match a name (just picked a simple definition of 'name')
.*? skip any length of garbage, but as little as possible before starting subsequent match
\d+ match another number (sequence of digits) (NUM2)
\2 followed by the same name (backreference)
You can see how you'd already be narrowing the list of matches to inspect down to 'potential' hits. You'd only have to /post-validate/ to see that NUM2 == NUM1+2
Two notes:
Add (...)+ around the tail part to allow repeated matching of patterns
(\d+) ([a-z]+)(.*?(\d+) \2)+
You may wish to make the garbage skip (.*?) aware of separators (by doing negative zerowidth assertions) to avoid more than 2 skipping delimiters (e.g. s\d+=" as a delimiting pattern). I leave it out of scope for clarity now, here's the gist:
((?!s\d+=").)*? -- beware of potential performance degradation
Alec, The following is a show-case of how to do a wide range of things in Boost Spirit, in the context of answering your question.
I had to make assumptions about what is required input structure; I assumed
whitespace was strict (spaces as shown, no newlines)
the sequence numbers should be in increasing order
the sequence numbers should recur exactly in the text values
the keywords 'apple' and 'cheese' are in strict alternation
whether the keyword comes before or after the the sequence number in the text value, is also in strict alternation
Note There are about a dozen places in the implementation below, where significantly less complex choices could possibly have been made. For example, I could have hardcoded the whole pattern (as a de facto regex?), assuming that 4 items are always expected in the input. However I wanted to
make no more assumptions than necessary
learn from the experience. Especially the topic of qi::locals<> and inherited attributes have been on my agenda for a while.
However, the solution allows a great deal of flexibility:
the keywords aren't hardcoded, and you could e.g. easily make the parser accept both keywords at any sequence number
a comment shows how to generate a custom parsing exception when the sequence number is out of sync (not the expected number)
different spellings of the sequence numbers are currently accepted (i.e. s01="apple 001" is ok. Look at Unsigned Integer Parsers for info on how to tune that behaviour)
the output structure is either a vector<std::pair<int, std::string> > or a vector of struct:
struct Entry
{
int sequence;
std::string text;
};
both versions can be switched with the single #if 1/0 line
The sample uses Boost Spirit Qi for parsing.
Conversely, Boost Spirit Karma is used to display the result of parsing:
format((('s' << auto_ << "=\"" << auto_) << "\"") % ", ", parsed)
The output for the actual contents given in the post is:
parsed: s1="apple 1", s2="2 cheese", s3="apple 3", s4="4 cheese"
On to the code.
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/karma.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
namespace qi = boost::spirit::qi;
namespace karma = boost::spirit::karma;
namespace phx = boost::phoenix;
#if 1 // using fusion adapted struct
#include <boost/fusion/adapted/struct.hpp>
struct Entry
{
int sequence;
std::string text;
};
BOOST_FUSION_ADAPT_STRUCT(Entry, (int, sequence)(std::string, text));
#else // using boring std::pair
#include <boost/fusion/adapted/std_pair.hpp> // for karma output generation
typedef std::pair<int, std::string> Entry;
#endif
int main()
{
std::string input =
"s1=\"lxckvjlxcjvlkjlkje xvcjxzlvcj wqrej lxvcjz ljvl;x czvouzxvcu"
"j;ljfds apple 1 xcvljxclvjx oueroi xcvzlkjv; zjx\", s2=\"xzljlkxvc"
"jlkjxzvl jxcvljzx lvjlkj wre 2 cheese\", s3=\"apple 3\", s4=\"kxclvj"
"xcvjlxk jcvljxlck jxcvl 4 cheese\"";
using namespace qi;
typedef std::string::const_iterator It;
It f(input.begin()), l(input.end());
int next = 1;
qi::rule<It, std::string(int)> label;
qi::rule<It, std::string(int)> value;
qi::rule<It, int()> number;
qi::rule<It, Entry(), qi::locals<int> > assign;
label %= qi::raw [
( eps(qi::_r1 % 2) >> qi::string("apple ") > qi::uint_(qi::_r1) )
| qi::uint_(qi::_r1) > qi::string(" cheese")
];
value %= '"'
>> qi::omit[ *(~qi::char_('"') - label(qi::_r1)) ]
>> label(qi::_r1)
>> qi::omit[ *(~qi::char_('"')) ]
>> '"';
number %= qi::uint_(phx::ref(next)++) /*| eps [ phx::throw_(std::runtime_error("Sequence number out of sync")) ] */;
assign %= 's' > number[ qi::_a = _1 ] > '=' > value(qi::_a);
std::vector<Entry> parsed;
bool ok = false;
try
{
ok = parse(f, l, assign % ", ", parsed);
if (ok)
{
using namespace karma;
std::cout << "parsed:\t" << format((('s' << auto_ << "=\"" << auto_) << "\"") % ", ", parsed) << std::endl;
}
} catch(qi::expectation_failure<It>& e)
{
std::cerr << "Expectation failed: " << e.what() << " '" << std::string(e.first, e.last) << "'" << std::endl;
} catch(const std::exception& e)
{
std::cerr << e.what() << std::endl;
}
if (!ok || (f!=l))
std::cerr << "problem at: '" << std::string(f,l) << "'" << std::endl;
}
Provided you can use c++11 compiler, parsing these patterns is pretty simple using AXE†:
#include <axe.h>
#include <string>
template<class I>
void num_value(I i1, I i2)
{
unsigned n;
unsigned next = 1;
// rule to match unsigned decimal number and compare it with another number
auto num = axe::r_udecimal(n) & axe::r_bool([&](...){ return n == next; });
// rule to match a single word
auto word = axe::r_alphastr();
// rule to match space characters
auto space = axe::r_any(" \t\n");
// semantic action - print to cout and increment next
auto e_cout = axe::e_ref([&](I i1, I i2)
{
std::cout << std::string(i1, i2) << '\n';
++next;
});
// there are only two patterns in this example
auto pattern1 = (word & +space & num) >> e_cout;
auto pattern2 = (num & +space & word) >> e_cout;
auto s1 = axe::r_find(pattern1);
auto s2 = axe::r_find(pattern2);
auto text = s1 & s2 & s1 & s2 & axe::r_end();
text(i1, i2);
}
To parse the text simply call num_value(text.begin(), text.end()); No changes required to parse unicode strings.
† I didn't test it.
Look into Boost.Regex. I've seen an almost-identical poosting in boost-users and the solution is to use regexes for some of the match work.
Hey, let's say I have this regex: (test[0-9])+
And that I match it against: test1test2test3test0
const bool ret = boost::regex_search(input, what, r);
for (size_t i = 0; i < what.size(); ++i)
cout << i << ':' << string(what[i]) << "\n";
Now, what[1] will be test0 (the last occurrence). Let's say that I need to get test1, 2 and 3 as well: what should I do?
Note: the real regex is extremely more complex and has to remain one overall match, so changing the example regex to (test[0-9]) won't work.
I think Dot Net has the ability to make single capture group Collections so that (grp)+ will create a collection object on group1. The boost engine's regex_search() is going to be just like any ordinary match function. You sit in a while() loop matching the pattern where the last match left off. The form you used does not use a bid-itterator, so the function won't start the next match where the last match left off.
You can use the itterator form:
(Edit - you can also use the token iterator, defining what groups to iterate over. Added in the code below).
#include <boost/regex.hpp>
#include <string>
#include <iostream>
using namespace std;
using namespace boost;
int main()
{
string input = "test1 ,, test2,, test3,, test0,,";
boost::regex r("(test[0-9])(?:$|[ ,]+)");
boost::smatch what;
std::string::const_iterator start = input.begin();
std::string::const_iterator end = input.end();
while (boost::regex_search(start, end, what, r))
{
string stest(what[1].first, what[1].second);
cout << stest << endl;
// Update the beginning of the range to the character
// following the whole match
start = what[0].second;
}
// Alternate method using token iterator
const int subs[] = {1}; // we just want to see group 1
boost::sregex_token_iterator i(input.begin(), input.end(), r, subs);
boost::sregex_token_iterator j;
while(i != j)
{
cout << *i++ << endl;
}
return 0;
}
Output:
test1
test2
test3
test0
Boost.Regex offers experimental support for exactly this feature (called repeated captures); however, since it's huge performance hit, this feature is disabled by default.
To enable repeated captures, you need to rebuild Boost.Regex and define macro BOOST_REGEX_MATCH_EXTRA in all translation units; the best way to do this is to uncomment this define in boost/regex/user.hpp (see the reference, it's at the very bottom of the page).
Once compiled with this define, you can use this feature by calling/using regex_search, regex_match and regex_iterator with match_extra flag.
Check reference to Boost.Regex for more info.
Seems to me like you need to create a regex_iterator, using the (test[0-9]) regex as input. Then you can use the resulting regex_iterator to enumerate the matching substrings of your original target.
If you still need "one overall match" then perhaps that work has to be decoupled from the task of finding matching substrings. Can you clarify that part of your requirement?