Overloading double subscript operator of std::array [duplicate] - c++

Question

I'm porting code that uses a very large array of floats, which may trigger malloc failures from c to c++. I asked a question about whether I should use vectors or deques and Niki Yoshiuchi generously offered me this example of a safely wrapped type:
template<typename T>
class VectorDeque
{
private:
enum TYPE { NONE, DEQUE, VECTOR };
std::deque<T> m_d;
std::vector<T> m_v;
TYPE m_type;
...
public:
void resize(size_t n)
{
switch(m_type)
{
case NONE:
try
{
m_v.resize(n);
m_type = VECTOR;
}
catch(std::bad_alloc &ba)
{
m_d.resize(n);
m_type = DEQUE;
}
break;
}
}
};
I needed a 2D vector of vectors/deque of deques, so I modified it to the following code:
template<typename T>
class VectorDeque
{
private:
enum STORAGE_CONTAINER { NONE, DEQUE, VECTOR };
std::deque<std::deque<T> > x_d,y_d,z_d;
std::vector<std::vector<T> > x_v,y_v,z_v;
TYPE my_container;
public:
void resize(size_t num_atoms, size_t num_frames)
{
switch(m_type)
{
case NONE:
try
{
x_v.resize(num_atoms);
for (unsigned int couter=0;couter < num_frames; counter++)
x_v[counter].resize(num_frames);
y_v.resize(num_atoms);
for (unsigned int couter=0;couter < num_frames; counter++)
y_v[counter].resize(num_frames);
z_v.resize(num_atoms);
for (unsigned int couter=0;couter < num_frames; counter++)
z_v[counter].resize(num_frames);
my_container = VECTOR;
}
catch(std::bad_alloc &e)
{
x_d.resize(num_atoms);
for (unsigned int couter=0;couter < num_frames; counter++)
x_d[counter].resize(num_frames);
y_d.resize(num_atoms);
for (unsigned int couter=0;couter < num_frames; counter++)
y_d[counter].resize(num_frames);
z_d.resize(num_atoms);
for (unsigned int couter=0;couter < num_frames; counter++)
z_d[counter].resize(num_frames);
my_container = DEQUE;
}
break;
}
}
};
I now want to be able to define my bracket operators so that I can have a statement like
x[1][2] directly access whichever is the real memory container I'm using (given by the value of my enumerated variable.
I've seen a couple of tutorials floating around about overriding the brackets operator, but have positively no idea to override double brackets.
How can you overload double brackets?
Additionally, how would you overload double iterators (in case I want to use an iterator, as opposed to direct indexing)?
EDIT 1:
Based on the solution from Martin York/Matteo Italia I devised the following class:
template<typename T>
class VectorDeque2D
{
public:
class VectorDeque2D_Inner_Set
{
VectorDeque2D& parent;
int first_index;
public:
// Just init the temp object
VectorDeque2D_Inner_Set(My2D& p, int first_Index) :
parent(p),
first_Index(first_index) {}
// Here we get the value.
T& operator[](int second_index) const
{ return parent.get(first_index,second_index);}
};
// Return an object that defines its own operator[] that will access the data.
// The temp object is very trivial and just allows access to the data via
// operator[]
VectorDeque2D_Inner_Set operator[](unsigned int first_index) {
return (*this, x);
}
void resize_first_index(unsigned int first_index) {
try {
my_vector.resize(first_index);
my_container = VECTOR;
}
catch(std::bad_alloc &e) {
my_deque.resize(first_index);
my_container = DEQUE;
}
}
void resize_second_index(unsigned int second_index) {
try {
for (unsigned int couter=0;couter < my_vector.size(); counter++) {
my_vector[counter].resize(second_index);
}
my_container = VECTOR;
}
catch(std::bad_alloc &e) {
for (unsigned int couter=0;couter < my_deque.size(); counter++) {
my_deque[counter].resize(second_index);
}
my_container = DEQUE;
}
}
void resize(unsigned int first_index,
unsigned int second_index) {
try {
my_vector.resize(first_index);
for (unsigned int couter=0;couter < my_vector.size(); counter++) {
my_vector[counter].resize(second_index);
}
my_container = VECTOR;
}
catch(std::bad_alloc &e) {
my_deque.resize(first_index);
for (unsigned int couter=0;couter < my_deque.size(); counter++) {
my_deque[counter].resize(second_index);
}
my_container = DEQUE;
}
}
private:
enum STORAGE_CONTAINER { NONE, DEQUE, VECTOR };
friend class VectorDeque2D_Inner_Set;
std::vector<std::vector<T> > my_vector;
std::deque<std::deque<T> > my_deque;
STORAGE_CONTAINER my_container;
T& get(int x,int y) {
T temp_val;
if(my_container == VECTOR) {
temp_val = my_vector[first_index][second_index];
}
else if(my_container == DEQUE) {
temp_val = my_deque[first_index][second_index];
}
return temp_val;
}
};
Finally a size-safe 2D container!! Thanks guys!

Answer 1

There are two main techniques:
1) Use operator() rather than operator[].
This is because the operator() allows multiple parameters.
class My2D
{
public:
int& operator()(int x,int y) { return pget(x,y);}
private:
int& pget(int x,int y) { /* retrieve data from 2D storage */ }
};
2) Use operator[] but return an intermediate object.
You can then apply the second operator[] to the intermediate object.
class My2D
{
public:
class My2DRow
{
My2D& parent;
int x;
public:
My2DRow(My2D& p, int theX) : parent(p), x(theX) {} // Just init the temp object
int& operator[](int y) const { return parent.pget(x,y);} // Here we get the value.
};
// Return an object that defines its own operator[] that will access the data.
// The temp object is very trivial and just allows access to the data via operator[]
My2DRow operator[](int x) { return My2DRow(*this, x);}
private:
friend class My2DRow;
int& pget(int x,int y) { /* retrieve data from 2D storage */ }
};
int main()
{
My2D data;
int& val = data[1][2]; // works fine.
// This is the same as
My2D::My2DRow row = data[1];
int& val2 = row[2];
}
I prefer the second technique.
This is because it leaves the original code untouched and more natural to read (in an array context). Of course you pay for the simplicity at the high level with slightly more complex code implementing your 2D array.

Answer 2

How can you overload double brackets?
I didn't fully understand your question, but you have to overload brackets, and make them return an object who overloads its own bracket operator.
For example, if you have a vector of vectors, the work is already done: vector < vector < something > > overloads operator[], which returns a vector< something >; this, in turn, has its bracket operator overloaded (and it returns a something object), so you can simply do:
vector<vector<something> > vec;
// ...
something s = vec[2][3];
Example with a proxy object:
template <typename T>
class Container
{
private:
// ...
public:
// Proxy object used to provide the second brackets
template <typename T>
class OperatorBracketHelper
{
Container<T> & parent;
size_t firstIndex;
public:
OperatorBracketHelper(Container<T> & Parent, size_t FirstIndex) : parent(Parent), firstIndex(FirstIndex) {}
// This is the method called for the "second brackets"
T & operator[](size_t SecondIndex)
{
// Call the parent GetElement method which will actually retrieve the element
return parent.GetElement(firstIndex, SecondIndex);
}
}
// This is the method called for the "first brackets"
OperatorBracketHelper<T> operator[](size_t FirstIndex)
{
// Return a proxy object that "knows" to which container it has to ask the element
// and which is the first index (specified in this call)
return OperatorBracketHelper<T>(*this, FirstIndex);
}
T & GetElement(size_t FirstIndex, size_t SecondIndex)
{
// Here the actual element retrieval is done
// ...
}
}
(add overloaded const methods wherever appropriate :) )
Note that with this method you lose almost nothing in respect to an operator() implementation, since the retrieval is still done in one single place, without constraints on the usage of the two indexes, having both indexes at the moment of performing the retrieval, and without returning "fat" temporary objects (OperatorBracketHelper is just as big as two pointers, and can be easily optimized away by the compiler).

Answer 3

There is no "double brackets" operator in C++. What you need to do is define a single [] operator and have it return a reference to another object, which can in turn respond to its own [] operator. This can be nested as many levels deep as you require.
For example, when you create a vector of vectors, the [] operator on the outer vector returns a reference to one of the inner vectors; the [] operator on that vector returns a reference to an individual element of the vector.
std::vector<std::vector<float> > example;
std::vector<float> & first = example[0]; // the first level returns a reference to a vector
float & second = example[0][0]; // the same as first[0]

Answer 4

Don't overload the [] operator, overload the () operator.
See this link:Overloading Subscript Operator.
I highly suggest reading through the C++ FAQ Lite at least once before posting to Stack Overflow. Also, searching Stack Overflow may yield some useful information also.

Answer 5

I covered overloading operator[] for a multi-dimensional array in an answer to a previous question.
I'd probably deal with iterators pretty similarly: Have one iterator that represents a "slice" (row or column) of the multi-dimensional array, and then another that represents an element in that slice.