django restframework _ OneToOne field save() - django

Question

I have two models in my project. Model A and B. Model B has a 'OneToOne' relationship with model A. I wrote a serializer class for model B. in ".create()" function I have a problem with saving model B, because I need to override the save() function in B model for inserting Slug value. The error is:
save() got an unexpected keyword argument 'force_insert'
class A(models.Model):
address = models.Charfield(max_length=160)
class b(models.Model):
a = models.OneToOneField(AdIfo, related_name='ad_info', primary_key=True,
on_delete=models.CASCADE)
slug = models.SlugField(unique=True, db_index=True, blank=True)
def save(self):
self.slug ="%d%s" %(self.pk, slugify(self.title))
super(B, self).save()
serializers.py
class ASerializer(serializers.ModelSerializer):
class Meta:
model = A
fields = "__all__"
class BSerilizer(serializers.ModelSerializer):
a = ASerializer(many=False, required=False, allow_null=True)
slug = serializers.SlugField(read_only=True)
class Meta:
model = B
fields = '__all__'
def create(self, validated_data):
info_data = validated_data.pop('ad_info')
A.objects.create(**info_data)
ad = B.objects.update_or_create(**validated_data)
A.objects.update_or_create(ad_info=adgame, **info_data)
ad.save()
return ad

Answer 1

The problem is that you didn't accept the default arguments in B's save method. Generally when overriding a method you need to ensure you accept all the arguments that could be passed, and make sure you pass them on to the super class method. One way of doing that is with *args, **kwargs:
def save(self, *args, **kwargs):
self.slug ="%d%s" % (self.pk, slugify(self.title))
super(B, self).save(*args, **kwargs)

Answer 2

well your problem is you are trying to make model A and model B then.the model B depends on primary key of model A .this structure you made is making model A and there is no relating on model B and then you are creating model A again.
you just need to create model A and then model B but you should refer the model B id to model A. i know its confusing but try this :
def create(self, validated_data):
info_data = validated_data.pop('ad_info')
info = A.objects.create(**info_data)
ad = B.objects.create(pk=info.id, **validated_data)
return ad
pk=info.id is the key for this problem.

Answer 3

After you done the fix by #Daniel Roseman t think you should updated your validated_data with new instance of the A instance
def create(self, validated_data):
info_data = validated_data.pop('ad_info')
# Next two rows
a = A.objects.create(**info_data)
validated_data.update({'a': a})
ad = B.objects.update_or_create(**validated_data)
A.objects.update_or_create(ad_info=adgame, **info_data)
ad.save()
return ad