Current code:
const int MAX_CODENAME = 25;
const int MAX_SPOTS = 5;
struct Team {
string TeamName[MAX_CODENAME];
short int totalLeagueGames;
short int leagueWins;
short int leagueLoses;
};
//GLOBAL VARIABLES:
Team league[MAX_SPOTS];
void addTeams(){
int i = 0; //first loop
int j; //second loop
while(i < MAX_SPOTS){
cout << "****** ADD TEAMS ******" << endl;
cout << "Enter the teams name " << endl;
scanf("%s", league[i].TeamName) ;
}
void searchTeam(){
string decider[MAX_CODENAME];
cout << "Please enter the team name you would like the program to retrieve: " << endl;
cin >> decider[MAX_CODENAME];
for(int i = 0; i < MAX_SPOTS; i++){
if(decider == league[i].TeamName){
cout << endl;
cout << league[i].TeamName << endl;
break;
}else{
cout << "Searching...." << endl;
}
}
}
I really dont know why its not working but I have included all the perquisite header files such as and but the program crashes when i enter the data and then attempt to search. I get the circle of death and then program not responding then says Process returned 255 (0xFF) . It does not even out put Searching.... the program practically gives up as soon as I enter that name.
Also if this can be optimized by the use of pointers that would be great.
tl;dr run-time error causing the search to fail as soon as i type in a name. And for the record I have checked to make sure the name I entered is valid.
scanf doesn't know about std::string. Use std::cin >> league[i].TeamName.
scanf("%s", league[i].TeamName) ;
This should be changed to
std::cin >> league[i].TeamName ;
A couple of other things here....
string decider[MAX_CODENAME];
cout << "Please enter the team name you would like the program to retrieve: " << endl;
cin >> decider[MAX_CODENAME];
Every time you input a value, you are telling the computer to hold the inputted value at decider[25] but the computer only reads indexes 0-24.
if(decider == league[i].TeamName){
Which array slot are you comparing the team name to? If its the 25th element than the statement should be
if(decider[24] == league[i].TeamName){
Pointers are better suited if the number of TeamNames are unknown. Based on the limited code presented, I highly recommend you stay within the realm of basic data types. For the purposes of troubleshooting, please post your full code in the future.
Your TeamName member variable:
string TeamName[MAX_CODENAME];
is an array of 25 strings, so in this line:
scanf("%s", league[i].TeamName) ;
you are courrupting the array. You don't really want an array anyways, so change the TeamName declaration to:
string TeamName;
and then when you read the name, you'll need to use iostreams which knows how to populate a string type (scanf only works with c char arrays):
std::cin >> league[i].TeamName
Related
I have a dynamically resizing struct[]. I ask the user for how many records he wants then make that many struct.Then I store the name and age info in the struct. The problem is when printing out that data i am only printing the last name and age the user input. I would like to print all the values.
struct Records
{
char name [32] ;
int age;
};
void program2()
{
Records rec;
int size;
cout << "How many record would you like?";
cin >> size;
cout << "\n" << size;
Records* a = new Records[size];
for (int i = 0; i < size; i++)
{
cout << "Whats the name for the Record: ";
cin >> rec.name;
cout << rec.name;
cout << "What is the age for this record: ";
cin >> rec.age;
}
for (int i = 0; i < size; i++)
{
cout << "\n" << rec.name << rec.age;
}
}
In your code, the variable rec has nothing to do with the array. To access the element at position i of your array, you'll need to use a[i].
For example:
cin >> a[i].name;
or
cout << "\n" << a[i].name << " " << a[i].age;
No surprise - you are actually printing repeatedly the last record that you created (rec). Your last loop is not actually traversing the array.
Also, the first loop only creates a struct, but does not actually add it to the array.
What you are trying to do is actually easier and cleaner if you use vectors instead of arrays, adding each record to the vector using push_back(). This is the closest thing to the "dynamically resized array" that you are referring to (such a thing does not actually exist in C++, that's what vectors are for, amongst other things).
Have a look into doing it this way, and if you get stuck feel free to ask again, happy to help.
Disclaimer: I am a beginner to programming, so what I say might sound really stupid
I have to make a "Telephone Directory" for school. The program isn't complete, but there are some things that I need to fix before moving on. The array TelephoneNumbers either isn't storing the numbers from the file correctly, or isn't displaying them. For the SeaerchRecords function, the first number in the file is displayed correctly, the second is displayed as "2147483647," and the rest of the numbers display as "0." The modify function also doesn't change the number, and I confirmed this with the while in the function. The string array works perfectly fine, however. May someone explain what I'm doing incorrectly?
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
string TelephoneNames[100];
int TelephoneNumbers[100];
void ModifyRecords(); //Function to Modify Records
void SearchRecords(); //Function to Search Records
void DeleteRecords(); //Function to Delete Records
int main()
{
fstream inputFile;
fstream outputFile;
char choice;
inputFile.open("Telephone Names.txt"); //To store
for (int count=0;count<100;count++) //file names
{ //into a
inputFile >> TelephoneNames[count]; //string
}
inputFile.close();
inputFile.open("Telephone Numbers.txt");//To store
for (int count=0;count<100;count++) //file #'s
{ //into a
inputFile >> TelephoneNumbers[count];//string
}
inputFile.close();
//Display options available
cout << " Hello, do you want to:\n";
cout << " ======================\n";
cout << "-Modify Records|Enter M\n";
cout << "-Search Records|Enter S\n";
cout << "-Delete Records|Enter D\n";
//Store choice
cin >> choice;
//Send to different function
if (choice=='M'||choice=='m')
{
ModifyRecords();
}
if (choice=='S'||choice=='s')
{
SearchRecords();
}
return 0;
}
void ModifyRecords()
{
string name;
string newname;
int newnumber;
int count=0;
cout << "Enter the name of the person: ";
cin >> name;
for (count=0;TelephoneNames[count]!=name;count++)//To determine where in the strings the new numbers need to be
{
}
cout << "Enter the new name of the person: ";
cin >> newname;
cout << "Enter the new number of the person: ";
cin >> newnumber;
TelephoneNames[count]={newname};
TelephoneNumbers[count]={newnumber};
count=0;
while (count<6)
{
cout << TelephoneNames[count] << endl;
cout << TelephoneNumbers[count] << endl;
cout << endl;
count++;
}
}
void SearchRecords()
{
string name;
int count=0;
cout << "Enter the name of the person you would like to find: ";
cin >> name;
for (count=0;TelephoneNames[count]!=name;count++)//To determine where in the strings the new numbers need to be
{
}
cout << "Name: " << TelephoneNames[count] << endl;
cout << "Number: " << TelephoneNumbers[count] << endl;
}
Since there is no any answer still and I don't see exactly the problem at this point I'll provide some suggestions how you can find a problem in your code.
In any programming situation when you can't find a bug, first task is to locate it as much precisely as you can and check all input data and assumptions. Usually, debugger is used for such purposes, but you can just output text in console before creating final version of your program.
To start with, you must check that you really received names and telephones from your file:
inputFile.open("Telephone Names.txt"); //To store
for (int count=0;count<100;count++) //file names
{ //into a
inputFile >> TelephoneNames[count]; //string
cout << TelephoneNames[count] << endl; //WE MUST SEE WHAT IS REALLY STORED IN TelephoneNames
}
inputFile.close();
inputFile.open("Telephone Numbers.txt");//To store
for (int count=0;count<100;count++) //file #'s
{ //into a
inputFile >> TelephoneNumbers[count];//string
cout << TelephoneNumbers[count] << endl; //WE MUST SEE WHAT IS REALLY STORED IN TelephoneNumbers
}
inputFile.close();
Ok, when it is checked and you are defenitely sure there is no problem in your data we can move to SeaerchRecords function doing the same procedure. We must check what is happening while you are searching:
for (count=0;TelephoneNames[count]!=name;count++)//To determine where in the strings the new numbers need to be
{
cout << "Search step: " << count << " name " << name << " found name " << TelephoneNames[count] << " number " << TelephoneNumbers[count] << endl;
}
Doing so you will locate your bug rather quickly. The problem can be in input files format, in difference of "name" and stored names format etc.
I'll provide several additional suggestion how you can improve your code.
1) Try to use const declarations for such commonly used things as number of records (const int NUMBER_OF_RECORDS = 100; insted of just putting '100' everywhere), it will reduce the amout of work and possible bugs. 2) Try to check all possible problems that you program can encounter if someting is wrong with data. What will happen if you have less than 100 records in your files now? Program crush or silent reading of unappropriate data which is even worse. Check that you haven't reach file end on any step of reading along with current check that you've reached you number of records and do something in case of unappropriate data.
3) Check the possible problems with conditions in your cycles not to run them infinite number of times. Now your condition for(count=0;TelephoneNames[count]!=name;count++)
will execute forever if there is no such name or just crush the program on count 100 or more. You should check that count doesn't exceed that value. Good luck!
I am trying to read data from a text file formatted similarly to this:
knife, object, 0
bag, object, 15
kitchen, room, 400
Into an array composed of structures. Here is what I have so far, but it only reads the first element then returns garbage.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
struct itemlist
{
string type;
string selltype;
int price;
int diditsell=0;
};
int main()
{
string filename;
cout << "Please enter a file name. " << endl;
cin >> filename;
ifstream in(filename);
itemlist c[100];
for (int i=0;i<100;i++)
{
in >> c[i].type >> c[i].selltype >> c[i].price;
cout << c[i].type << endl;
cout << c[i].selltype << endl;
cout << c[i].price << endl;
}
}
I have tried to find examples that specifically suit what I am trying to do but implementing them has not fixed the problem. Any help would be greatly appreciated.
The crux of the visible problem is that with
for (int i=0;i<100;i++)
the entire 100 element array will be printed out whether there was data in the file to be loaded into the array or not.
Probably the easiest way to do this is with a std::vector. It's a dynamically sized array. As you add to it it gets bigger so you don't have to worry about it overflowing. We'll get back to it at the end.
The next thing you have to do is make sure you're reading the file successfully. Streams can be tested to see if they are valid.
if (in)
{
cout << "in is good!" << endl;
}
and the >> operator returns a reference to the stream so you can
if (in >> data)
{
cout << "data is good!" << endl;
}
If the stream is still good after reading data, you know that at the very least the file read something into data that was of the correct type or could be converted into the correct type. You owe it to yourself to check the value read after reading it in to make sure the user didn't typo or go out of their way to crash the program. If you want to loop through a lot of stuff, like a file, you wind up with something like this:
while (in >> c[i].type >> c[i].selltype >> c[i].price)
If any of the reads failed the the stream will return false when tested and the loop will exit.
Looking at your source data you have spaces and commas to deal with. >> only knows how to deal with spaces unless you're going to do a lot of extra work. What you will read in is
knife,
object,
0
and we don't want the comma. Fortunately, it's the last character so dealing with it is easy. A C++11 std::string can be used like a stack and you can just pop the unwanted character off:
c[i].type.pop_back();
c[i].selltype.pop_back();
All together, this gives us a loop that looks like
ifstream in(filename);
itemlist c[100];
int i = 0;
while (in >> c[i].type >> c[i].selltype >> c[i].price)
{
c[i].type.pop_back();
c[i].selltype.pop_back();
cout << c[i].type << endl;
cout << c[i].selltype << endl;
cout << c[i].price << endl;
i++;
}
but this can overrun the end of the 100 element array, so we need to change the while loop slightly:
while (i < 100 && in >> c[i].type >> c[i].selltype >> c[i].price )
If i is greater than or equal to 100, the i < 100 case fails and the loop exits without even trying in >> c[i].type >> c[i].selltype >> c[i].price and writing into the non-existent array slot.
Remember to keep the value of i around because arrays are dumb. They don't know how full they are.
But with a vector you don't need i to count or to keep track of how full it is and you don't need to worry about overflowing the array until you run your computer out of RAM. What we do need is one temporary variable to read into and we're good to go.
vector<itemlist> c;
itemlist temp;
while (in >> temp.type >> temp.selltype >> temp.price)
{
temp.type.pop_back();
temp.selltype.pop_back();
cout << temp.type << endl;
cout << temp.selltype << endl;
cout << temp.price << endl;
c.push_back(temp);
}
I had the same problem.
A debug showed that it was reading the first array element but skipping to the second element and outputting the info. from the first element.
This was fixed by making it read the first element twice.
For example see below.
I had other input in the array for the player also.
After that line was added everything worked great.
I had to do that for every array that I read.
I looked at the text file it was reading from and sure enough
there is a blank line before the start of every array.
I do not know why the program writing the file did that.
I did not put a blank line before the array.
Note: Instead of having it read the first array element twice,
you could probably have it read a blank line instead.
for (int i = 0; i < PLAYER; i++)
{
getline(teamRosterIn, playerName[i]);
cout << playerName[i] << endl;
getline(teamRosterIn, playerName[i]);
cout << playerName[i] << endl;
}
I am writing a library program that displays a menu of options letting the user add new books to the library, but in my add statement it accepts the title and then gets caught in an infinite loop. I wrote a book class that mainly uses pointers to assign things, if I need to post that I will. But when you run the program it compiles, displays the menu, and when you choose add a book it accepts the title but as soon as you hit enter it starts an a infinite loop.
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <string>
using namespace std;
int main()
{
int bookCounter = 0;
Book library[25];
int menuOption = 0;
char tempt[50] = "\0";
char tempauth[50] = "\0";
char search[50] = "\0";
unsigned int tempp = 0;
do
{
menuOption = 0;
cout << endl << "1. Show the Library" << endl;
cout << "2. Add a Book" << endl;
cout << "3. Search the Library by Title" << endl;
cout << "4. Exit Library" << endl;
cout << "Select a menu option (e.g. 1, 2, etc.): ";
cin >> menuOption;
if(menuOption == 1)
{
for(int i = 0; i < bookCounter; i++)
{
library[i].displayBook();
}
}
else if(menuOption == 2)
{
cout << "Enter the Title: ";
cin >> tempt[50];
cout << endl << "Enter the Author's name: " ;
cin >> tempauth[50];
cout << endl << "How many pages does the book have? (just enter a number, e.g. 675, 300): ";
cin >> tempp;
library[bookCounter].setAuthor(tempauth);
library[bookCounter].setTitle(tempt);
library[bookCounter].setPages(tempp);
bookCounter++;
menuOption = 0;
}
else if(menuOption == 3)
{
cout << "Enter a title you would like search for (will return partial matches): ";
cin >> search[50];
for (int i = 0; i < bookCounter; i++)
{
int temp = strcmp(search, library[i].getTitle());
if (temp == 1)
{
library[i].displayBook();
}
}
}
}while(menuOption != 4);
system("pause");
return 0;
}
The problem is caused by the way you are trying to read into the arrays:
cin >> tempt[50];
This tries to read a single character into the character at index 50 of the array tempt, which is outside the bounds of the array (which has valid indices in the range [0,49]).
This means only the first character of the entered title will be consumed from the output. Similarly for author. Hence, only the first two characters which you have entered are actually read. Then, this line will be encountered:
cin >> menuOption;
Here, what is left in the buffer (the remainder of the title) will be read, expecting a number. As this does not match a valid format for a number, you will get an error flag in cin. This will mean that all resulting inputs will also fail, menuOption will never change and your program gets stuck in a loop.
A solution to your problem would be to read into tempt without index. You can also check if a read has failed using if(cin.fail()) which should only trigger if there's been an error. If so, handle it and then call cin.clear() to reset the error flags.
I think that this line cause the problem,
cin >> search[50];
You're accessing out bound of search array.
One error is when you type in the menu option, the 'return' stays in the input buffer. The next read of char[] in your tempt variable, will be skipped.
Type cin.ignore(); after cin >> menuOption;
Also, you should read tempt instead instead of tempt[50].
This
cin >> tempt[50];
accesses a non-existent entry in the array. You probably meant to code
cin >> tempt;
Or, better, use std::string instead of raw char array.
I'm new to C++. I decided to not watch the next tutorial and put my skills to use, by making a funny Mind Reader application. I'm pleased with myself, however, even though I've ironed out most bugs, I still have one concerning the exit function. I read the C++ documentation for it, and I'm not sure what I did wrong. I did exit(0);. I have a very weird error, which is:
no match for call to '(std::string {aka std::basic_string<char>}) (int)
I have searched online, however I am still unaware of what the problem is. My error is on line 59 (marked in the code):
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main()
{
//declaring variables to be used later
string name;
string country;
int age;
//header goes below
cout << "#######################################";
" ############ MIND READER ############"
"#######################################\n\n";
//asks if the user would like to continue and in not, terminates
cout << "Would like you to have your mind read? Enter y for yes and n for no." << endl;
cout << "If you do not choose to proceed, this program will terminate." << endl;
string exitOrNot;
//receives user's input
cin >> exitOrNot;
//deals with input if it is 'y'
if (exitOrNot == "y"){
cout << "Okay, first you will need to sync your mind with this program. You will have to answer the following questions to synchronise.\n\n";
//asks questions
cout << "Firstly, please enter your full name, with correct capitalisation:\n\n";
cin >> name;
cout << "Now please enter the country you are in at the moment:\n\n";
cin >> country;
cout << "This will be the final question; please provide your age:\n\n";
cin >> age;
//asks the user to start the sync
cout << "There is enough information to start synchronisation. Enter p to start the sync...\n\n";
string proceed;
cin >> proceed;
//checks to see if to proceed and does so
if (proceed == "p"){
//provides results of mind read
cout << "Sync complete." << endl;
cout << "Your mind has been synced and read.\n\n";
cout << "However, due to too much interference, only limited data was aquired from your mind." << endl;
cout << "Here is what was read from your mind:\n\n";
//puts variables in sentence
cout << "Your name is " << name << " and you are " << age << " years old. You are based in " << country << "." << endl << "\n\n";
cout << "Thanks for using Mind Reader, have a nice day. Enter e to exit." << endl;
//terminates the program the program
string exit;
cin >> exit;
if (exit == "e"){
exit(0); // <------------- LINE 59
}
}
}
//terminates the program if the input is 'n'
if (exitOrNot == "n"){
exit(0);
}
return 0;
}
Thanks
The local variable exit shadows other identifiers from outer scopes with the same name.
To illustrate with a smaller example:
int main()
{
int i;
{
int i;
i = 0; // assign to the "nearest" i
// the other i cannot be reached from this scope
}
}
Since the only exit visible is an object of type std::string, the compiler sees exit(0) as a call to operator()(int) and throws a hissy fit when it doesn't find one among std::string members.
You can either qualify the name (std::exit(0);) or rename the variable. And since all of your code is in main you can simply say return 0; instead.
Try using return 0; or return EXIT_SUCCESS;. It's the exact same thing. Also, you can only input one word into a cin. Instead, use getline(cin, string name); If it still doesn't work, add a cin.ignore(); before your getline(cin, string name);, like this:
//stuff
string country;
cout << "Now please enter the country you are in at the moment:\n\n";
cin.ignore();
getline(cin, country);
//stuff
return 0;
The problem is arrising because you declared a standard keyword as the name of a local variable.
Now as the local variable is of type sting it is not able to take it as its value.