How do I make a large HTTP(S) request with Python? - python-2.7

Question

Edit: I extended the question to HTTPS. The "S" part is not yet solved and I don't really need it, but it might be interesting for others.
I want to do the equivalent of
hdr='GET / HTTP/1.1\r\nContent-Length: 10000000000\r\n\r\n'
(echo -en "$hdr"; dd if=/dev/zero bs=1000000 count=999; read tmp) | nc $SOME_IP 80
with Python 2.7. If possible, I'd like to use only standard library plus the requests and sockets modules.
FYI, the above script sends a large HTTP request (~1GB of zeros) to $SOME_IP without being to heavy on the senders RAM.

Answer 1

Something like this?
import socket
def get_content_length():
return 10000000000
def get_chunk_size():
return 1000000
def yield_content():
total_size = get_content_length()
chunk_size = get_chunk_size()
current_size = 0
end = total_size - chunk_size
chunk = '\x00' * chunk_size
while current_size < end:
yield chunk
current_size += chunk_size
yield chunk[:total_size - current_size]
s = socket.socket()
s.connect((host, port))
hdr='GET / HTTP/1.1\r\nContent-Length: %s\r\n\r\n' % get_content_length()
s.sendall(hdr)
for chunk in yield_content():
s.sendall(chunk)
# should I wait for the response?

Answer 2

Here is what I cooked up and seems to work:
import sys, socket
def flood(hostname, port, count=1):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((hostname, port))
s.sendall('GET / HTTP/1.1\r\nContent-Length: 10000000000\r\n\r\n')
with open('/dev/zero', 'rb', ) as data:
for _ in xrange(count):
s.sendall(data.read(1000000))
s.shutdown(socket.SHUT_WR)
while True:
data = s.recv(1024)
if data == "":
break
print("Received:", repr(data))
print("Connection closed.")
s.close()
The answer by freakish is of course more cross-plattform, as it does not require /dev/null