Excel Vba Regular Expression Not Detecting - regex

Question

I have tried to detect the same on regex101, but when I try to run the excel-VBA code it fails to detect.
I have been trying to detect and group the Following Text:
Test A1 (III’15) 270     10/12  ABC/DEF       PNR       AVC
Test Asd(II’05) 300     11/12  RtF/ZXC      PNR        NKL
Test 33 (I’01) PIL     11/12  KNP/ILO      IL 90.5    FX - NO
Test 4 (IIII’10) 270  11-12/12  JKI/IOP   PNR      RPTD - RPTD
My Pattern:
([\w ]+)\s+([\w()\’\’ ]+)\s+(\w+)\s+([\w/-]+)\s+([\w/+]+)\s+([\w.\s]+)\s+([\w -]+)
My Code:
Private Sub splitUpRegexPattern()
Dim regEx As New RegExp
Dim strPattern As String
Dim strInput As String
Dim strReplace As String
Dim Myrange As Range
Set Myrange = ActiveSheet.Range("A1:A63")
For Each C In Myrange
strPattern = "([\w ]+)\s+([\w\(\)\’\’ ]+)\s+(\w+)\s+([\w\/\-]+)\s+([\w\/\+]+)\s+([\w\.\s]+)\s+([\w \-]+)"
If strPattern <> "" Then
strInput = C.Value
'strReplace = "$1"
With regEx
.Global = False
.MultiLine = False
.IgnoreCase = True
.Pattern = strPattern
End With
If regEx.Test(strInput) Then
C.Offset(0, 1) = regEx.Replace(strInput, "$1")
C.Offset(0, 2) = regEx.Replace(strInput, "$2")
C.Offset(0, 3) = regEx.Replace(strInput, "$3")
C.Offset(0, 4) = regEx.Replace(strInput, "$4")
C.Offset(0, 5) = regEx.Replace(strInput, "$5")
C.Offset(0, 6) = regEx.Replace(strInput, "$6")
C.Offset(0, 7) = regEx.Replace(strInput, "$7")
Else
C.Offset(0, 1) = "(Not matched)"
End If
End If
Next
End Sub
I need to group then as
Group1: (Test A1) Group 2: ((III’15)) Group 3: (270) Group 4: (10/12) Group 5: (ABC/DEF) Group 6: (PNR) Group 7:(AVC)

Answer 1

This will work assuming your spaces are real spaces and not character 160 as they are when copied from here:
Private Sub splitUpRegexPattern()
Dim regEx As New RegExp
Dim strPattern As String
Dim strInput As String
Dim strReplace As String
Dim Myrange As Range
Dim matches
Set Myrange = ActiveSheet.Range("A1:A4")
For Each C In Myrange
strPattern = "([\w ]+)\s*(\([\w\’]+\))\s+(\w+)\s+([\w/-]+)\s+([\w/+]+)\s+(\w+\s?[\w.]*)\s+([\w -]+)"
If strPattern <> "" Then
strInput = C.Value
'strReplace = "$1"
With regEx
.Global = False
.MultiLine = False
.IgnoreCase = True
.Pattern = strPattern
End With
If regEx.Test(strInput) Then
Set matches = regEx.Execute(strInput)
C.Offset(0, 1) = matches(0).SubMatches(0)
C.Offset(0, 2) = matches(0).SubMatches(1)
C.Offset(0, 3) = matches(0).SubMatches(2)
C.Offset(0, 4) = "'" & matches(0).SubMatches(3)
C.Offset(0, 5) = matches(0).SubMatches(4)
C.Offset(0, 6) = matches(0).SubMatches(5)
C.Offset(0, 7) = matches(0).SubMatches(6)
Else
C.Offset(0, 1) = "(Not matched)"
End If
End If
Next
End Sub

Answer 2

I think your pattern was off, and you also need to set Global = True.
This pattern will target each group of your strings. I haven't tested it with the Replace though as not sure what you were trying to achieve there.
RegExr Fiddle
Updated with new pattern after comments:
Private Sub splitUpRegexPattern()
Dim regEx As New RegExp
Dim strPattern As String, strInput As String, strReplace As String
Dim j As Long
Dim match
Dim Myrange As Range
Set Myrange = Range("A1:A63")
strPattern = "(^.*(?=\())|(?:\().*(?:\))|((\d{2}(\/|\-)){1,2}\d{2})|(([a-z]{3}|[a-z]{1,2}\s[a-z]{1,2})(\/|(?!\/))){2}|((\w{2,4}(\s\-\s|$)){1,2})|((\w{2}\s)\d{1,2}\.\d{1,2}|[a-z]{3})|((?!\)\s+)(([a-z]|[0-9]){3}))"
If strPattern <> vbNullString Then
With regEx
.Global = True
.MultiLine = False
.IgnoreCase = True
.Pattern = strPattern
End With
For Each c In Myrange
strInput = c.Value
If regEx.test(strInput) Then
j = 1
For Each match In regEx.Execute(strInput)
c.Offset(0, j).Value2 = match
j = j + 1
Next match
Else
c.Offset(0, 1) = "(Not matched)"
End If
Next
End If
End Sub