I have the following text
Cool Title Here 12345
Other title here 13455
That I want to turn into this using Atom's find and replace
Cool Title Here, 12345
Other title here, 13455
My goal is to select the space between the end of a word and the start of a number. My first instinct is this statement
[A-Za-z][\s][0-9]
However that also selects the last letter and the first number which is not good for this replacement as I would loose data.
How would I accomplish finding the space inbetween two sections using pure Regex
You can capture the letter and the number, and in the replacement, use back reference to add them back:
So specify the pattern:
([A-Za-z]) ([0-9])
In the replacement:
$1, $2
I am not familiar with the specifics of Atom regular expression processing but some Googling suggests these general regex techniques should work:
You could use \b to identify the word boundary of the preceding word (without capturing it).
You can use (?=\d) to look ahead to the digit without capturing.
so for your example:
\b\s(?=\d)
Related
For example, I have the word: sh0rt-t3rm.
How can I get the t3rm part using perl regex?
I could get sh0rt by using [(a-zA-Z0-9)+]\[-\], but \[-\][(a-zA-Z0-9)+] doesn't work to get t3rm.
The syntax used for the regex is not correct to get either sh0rt or t3rm
You flipped the square brackets and the parenthesis, and the hyphen does not have to be between square brackets.
To get sh0rt in sh0rt-t3rm you you might use for example one of:
Regex
Demo
Explanation
\b([a-zA-Z0-9]+)-
Demo 1
\b is a word boundary to prevent a partial word match, the value is in capture group 1.
\b[a-zA-Z0-9]+(?=-)
Demo 2
Match the allowed chars in the character class, and assert a - to the right using a positive lookahead (?=-)
To get t3rm in sh0rt-t3rm you might use for example one of:
Regex
Demo
Explanation
-([a-zA-Z0-9]+)\b
Demo 3
The other way around with a leading - and get the value from capture group 1.
-\K[a-zA-Z0-9]+\b
Demo 4
Match - and use \K to keep out what is matched so far. Then match 1 or more times the allowed chars in the character class.
If your whole target string is literally just sh0rt-t3rm then you want all that comes after the -.
So the barest and minimal version, cut precisely for this description, is
my ($capture) = $string =~ /-(.+)/;
We need parenthesis on the left-hand-side so to make regex run in a list context because that's when it returns the matches (otherwise it returns true/false, normally 1 or '').
But what if the preceding text may have - itself? Then make sure to match all up to that last -
my ($capture) = $string =~ /.*-(.+)/;
Here the "greedy" nature of the * quantifier makes the previous . match all it possibly can so that the whole pattern still matches; thus it goes up until the very last -.
There are of course many other variations on how the data may look like, other than just being one hyphenated-word. In particular, if it's a part of a text, you may want to include word-boundaries
my ($capture) = $string =~ /\b.*?-(.+?)\b/;
Here we also need to adjust our "wild-card"-like pattern .+ by limiting it using ? so that it is not greedy. This matches the first such hyphenated word in the $string. But if indeed only "word" characters fly then we can just use \w (instead of . and word-boundary anchors)
my ($capture) = $string =~ /\w*?-(\w+)/;
Note that \w matches [a-zA-Z0-9_] only, which excludes some characters that may appear in normal text (English, not to mention all other writing systems).
But this is clearly getting pickier and cookier and would need careful close inspection and testing, and more complete knowledge of what the data may look like.
Perl offers its own tutorial, perlretut, and the main full reference is perlre
-([a-zA-Z0-9]+) will match a - followed by a word, with just the word being captured.
Demo
I have the following data:
SOMEDATA .test 01/45/12 2.50 THIS IS DATA
and I want to extract the number 2.50 out of this. I have managed to do this with the following RegEx:
(?<=\d{2}\/\d{2}\/\d{2} )\d+.\d+
However that doesn't work for input like this:
SOMEDATA .test 01/45/12 2500 THIS IS DATA
In this case, I want to extract the number 2500.
I can't seem to figure out a regex rule for that. Is there a way to extract something between two spaces ? So extract the text/number after the date until the next whitespace ? All I know is that the date will always have the same format and there will always be a space after the text and then a space after the number I want to extract.
Can someone help me out on this ?
Capture number between two whitespaces
A whitespace is matched with \s, and non-whitespace with \S.
So, what you can use is:
\d{2}\/\d{2}\/\d{2} +(\S+)
^^^
See the regex demo
The 1+ non-whitespace symbols are captured into Group 1.
If - for some reason - you need to only get the value as a whole match, use your lookbehind approach:
(?<=\d{2}\/\d{2}\/\d{2} )\S+
Or - if you are using PCRE - you may leverage the match reset operator \K:
\d{2}\/\d{2}\/\d{2} +\K\S+
^^
See another demo
NOTE: the \K and a capture group approaches allow 1 or more spaces after the date and are thus more flexible.
I see some people helped you already, but if you would want an alternative working one for some reason, here's what works too :)
.+ \d+\/\d+\/\d+ (\d+[\.\d]*)
So the .+ matches anything plus the first space
then the \d+/\d+/\d+ is the date parsing plus a space
the capturing group is the number, as you can see I made the last part optional, so both floating point values and normal values can be matched. Hope this helped!
Proof: https://regex101.com/r/fY3nJ2/1
Just make the fractal part optional:
(?<=\d{2}\/\d{2}\/\d{2} )\d+(?:\.\d+)?
Demo: https://regex101.com/r/jH3pU7/1
Update following clarifications in comments:
To match anything (but space) surrounded by spaces and prepended by date use:
(?<=\d{2}\/\d{2}\/\d{2} )\S+
Demo: https://regex101.com/r/jH3pU7/3
Rather than capture, you can make your entire match be the target text by using a look behind:
(?<=\d\d(\/\d\d){2} )\S+
This matches the first series of non-whitespace that follows a "date like" part.
Note also the reduction in the length of the "date like" pattern. You may consider using this part of the regex in whatever solution you use.
I am trying out the quiz from Regex 101
In Task 6, the question is
Oh no! It seems my friends spilled beer all over my keyboard last night and my keys are super sticky now. Some of the time when I press a key, I get two duplicates. Can you pppllleaaaseee help me fix this? Content in bold should be removed.
I have tried this regex
([a-z])(\1{2})
But couldn't get the solution.
The solution for the riddle on that website is:
/(.)\1{2}/g
Since any key on the keyboard can get stuck, so we need to use ..
\1 in the regex means match whatever the 1st capturing group (.) matches.
Replacement is $1 or \1.
The rest of your regex is correct, just that there are unnecessary capturing groups.
Your regex is correct if you want to match exactly three characters. If you want to match at least three, that is
([a-z])(\1{2,})
or
([a-z])(\1\1+)
Since you don't need to capture anything but the first occurence, these are slightly better:
([a-z])\1{2} # your original regex (exactly three occurences)
([a-z])\1{2,}
([a-z])\1\1+
Now, the replacement should be exactly one occurence of the character, and nothing more:
\1
Replace:
(.)\1+
with:
\1
This of course requires that your regex engine suports backreferences... Also, in the replacement part, and according to regex engines, \1 may have to be written as $1.
I'd do it with (\w)(\1+)? but can't find out how to "remove" within the given site...
Best way would be to replace the results of the secound match with empty strings
I have difficulty using Regular Expression (Grep) in TextWrangler to find occurrences of lowercase letter followed by uppercase. For example:
This announcement meansStudents are welcome.
In fact, I want to split the occurrence by adding a colon so that it becomes means: Students
I have tried:
[a-z][A-Z]
But this expression does not work in TextWrangler.
*EDIT: here are the exact contexts in which the occurrences appear (I mean only with these font colors).*
<font color =#48B700> - Stột jlăm wẻ baOne hundred and three<br></font>
<font color =#C0C0C0> »» Qzống pguộc lyời ba yghìm fảy dyổiTo live a life full of vicissitudes, to live a life marked by ups and downs<br></font>
"baOne" and "dyổiTo" must be "ba: One" and "dyổi: To"
Could anyone help? Many thanks.
I do believe (don't have TextWrangler at hand though) that you need to search for ([a-z])([A-Z]) and replace it with: \1: \2
Hope this helps.
Replace ([a-z])([A-Z]) with \1:\2 - I don't have TextWrangler, but it works on Notepad++
The parenthesis are for capturing the data, which is referred to using \1 syntax in the replacement string
This question is ages old, but I stumbled upon it, so someone else might, as well. The OP's comment to Igor's response clarified how the task was meant to be described (& could have be added to the description).
To match only those font-specific lines of the HTML replace
(?<=<font color =#(?:48B700|C0C0C0)>)(.*?[a-z])([A-Z])
with \1: \2
Explanation:
(?<=[fixed-length regex]) is a positive lookbehind and means "if my match has this just before it"
(?:48B700|C0C0C0) is an unnamed group to match only 2 colours. Since they are of the same length, they work in a lookbehind (that needs to be of fixed length)
(.*?[a-z])([A-Z]) will match everything after the > of those begin font tags up to your Capital letters.
The \1: \2 replacement is the same as in Igor's response, only that \1 will match the entire first string that needs separating.
Addition:
Your input strings contain special characters and the part you want to split may very well end in one. In this case they won't be caught by [a-z] alone. You will need to add a character ranger that captures all the letters you care about, something like
(?<=<font color =#(?:48B700|C0C0C0)>)(.*?[a-zḁ-ῼ])([A-Z])
That is the correct pattern for identifying lower case and upper case letters, however, you will need to check matching to be Case Sensitive within the Find/Replace dialogue.
I have a file with lines like
text text text 3424 text text 3423 50 US text 342 text
What I want to match is 50 US (yes, dollars) and ultimately extract that number.
Everything else changes in different lines, there may be more text or less surrounding, but in each line there is only one "US" anchor that I can match.
So what I want to do is to find a way to match US and get the preceding 3 or 4 characters.
Any ideas? Preferably with sed/awk, but any solution will do.
Perl regexes (or anything that understands non-greedy .*? expressions) are easier than sed for this:
perl -pe 's/^.*?(\d+\.?\d*)\s*US.*$/$1/'
That will handle things like "11.23" as well.
\d+ US
This should work given that US is present only once in the string.
Use lookarounds:
\d+(?= US)
This regex will only capture the numeric amount. The (?= US) tells it to match on "US" but not capture it.
This is what you could use in VBA regex flavor, which also supports lookaheads:
" ((.+)(?= US))"
Starts with a space
Next is the capture group. (.+) I use that instead of \d so that stuff like 5,000 and 11.3 works. In fact, anything works, so if you want the word/number that precedes "US" then this is the way to write it.
Next is the lookahead. So you only want the capture group that is immediately followed by " US". If it finds it, it will only give you back the capture group, not the lookahead value.