Support BOOST_FUSION_ADAPT_STRUCT for objects with fixed arrays? - c++

Question

Assume I already have a struct that looks like this:
struct LETTER
{
double one;
char[12] two;
double three;
char[12] four;
};
And my inputs are comma separated, for example:
"32,CATSANDDOGS,42,WHAT"
"43,BATANDZEBRAS,23,PARROT"
I've been trying to adapt this example (Spirit Qi : rule for char [5]) to to roll through BOOST_FUSION_ADAPT_STRUCT but haven't had any luck. I tried using std::array as shown here (http://www.boost.org/doc/libs/1_64_0/libs/spirit/example/qi/boost_array.cpp) but I haven't been able to make it work in a struct. Is what I'm trying to do even possible? What am I doing wrong here? I would think this would be the most obvious use case.
Is what I'm trying to do even possible?

Answer 1

I'm going to assume you want to write idiomatic C++ code (which is obviously the target domain for Spirit Qi), so you can use std::string:
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#include <boost/fusion/adapted.hpp>
#include <boost/fusion/include/io.hpp>
#include <boost/spirit/include/qi.hpp>
#include <iostream>
namespace qi = boost::spirit::qi;
struct Letter {
double one;
std::string two;
double three;
std::string four;
};
BOOST_FUSION_ADAPT_STRUCT(Letter, one, two, three, four)
template <typename Iterator> struct LETTERParser : qi::grammar<Iterator, Letter()> {
LETTERParser() : LETTERParser::base_type(start) {
using namespace qi;
_11c = repeat(11) [char_];
start = skip(space) [ "LETTER" >> double_ >> _11c >> double_ >> _11c ];
}
private:
qi::rule<Iterator, Letter()> start;
qi::rule<Iterator, std::string()> _11c;
};
int main() {
const std::string input("LETTER 42 12345678901 +Inf abcdefghijk ");
using It = std::string::const_iterator;
LETTERParser<It> parser;
Letter example;
It f = input.begin(), l = input.end();
if (phrase_parse(f, l, parser, qi::ascii::space, example)) {
std::cout << "parsed: " << boost::fusion::as_vector(example) << "\n";
std::cout << " example.one: " << example.one << "\n";
std::cout << " example.two: '" << example.two << "'\n";
std::cout << " example.three: " << example.three << "\n";
std::cout << " example.four: '" << example.four << "'\n";
} else {
std::cout << "couldn't parse '" << input << "'\n";
}
if (f != l)
std::cout << "Remaining unparsed input: '" << std::string(f,l) << "'\n";
}
Prints
parsed: (42 12345678901 inf abcdefghijk)
example.one: 42
example.two: '12345678901'
example.three: inf
example.four: 'abcdefghijk'