C++ function prototype outside class - c++

In c++ how is this a proper function prototype?
class Car{
//some member variables and functions
};
Car someFunctionName();
I understand that when making member functions and variables you would prototype the function in the class and then later the definition would be something like this
double Car::someOtherFunctionName() {}
My professor keeps putting the first example of a prototype in example code and I can't seem to grasp the concept. TIA

Not all functions in C++ are member functions. The function your professor has prototyped is a standalone function which returns a Car.
To quote UKMonkey:
People like to say that C++ is Object Oriented. It's not. It's Object Capable. You CAN use objects, if you want.

Related

Non-member functions vs static functions in C++

When should we use non-member functions (or free functions) or static member functions? As far as I know, in Java or C# we use static member funtions in such cases when in C++ we could use free functions. But what is the practial usage difference?
The main difference is that static functions have access to private/protected members/methods of the class. Also, IDE can find static functions as members/methods to the class and it will be easier to code.
Only restriction is that you have to declare static functions with the class while free functions can be declared freely.
In Java or C# you have to use static member functions because there is no way to write functions which are not part of a class.
In C++, you have that choice. There's little practical difference, so the decision is about code structure. Does the function you want to write seem to belong to a class, but not to a specific instance of that class? Then you might want a static member function. Does it need access to private static data in the class? Then you definitely need a member function!
Otherwise, it can be a free function in an appropriate namespace. And indeed should be, because there's no reason to make a class when a namespace will do.

convert double (class::*)(const gsl_vector*, void*) to double (*)(const_gsl vector*,void*) [duplicate]

So here's the situation: I'm using C++, SDL and GLConsole in conjunction. I have a class, SDLGame, which has the Init(), Loop(), Render() etc - essentially, it holds the logic for my game class.
GLConsole is a nice library so far - it lets me define CVars and such, even inside my SDL class. However, when defining commands, I have to specify a ConsoleFunc, which is typedef'd as
typedef bool (*ConsoleFunc)( std::vector<std::string> *args);
Simple enough. However, like I said, my functions are all in my class, and I know I can't pass pointer-to-class-functions as pointer-to-function arguments. I can't define static functions or make functions outside my class because some of these ConsoleFuncs must access class data members to be useful. I'd like to keep it OOP, since - well, OOP is nice.
Well, I actually have this problem "solved" - but it's extremely ugly. I just have an instance of SDLGame declared as an extern variable, and use that in my ConsoleFuncs/main class.
So, the question is: Is there a way to do this that isn't stupid and dumb like the way I am doing it? (Alternatively: is there a console library like GLConsole that supports SDL and can do what I'm describing?)
If the only interface you have is that function pointer, then you're screwed.
A member function needs a this pointer to be called, and if you have no way of passing that, you're out of luck (I guess the std::vector<std::string>* args pointer is what you get passed from the library).
In other words, even though that library uses C++ containers, it's not a good C++ library, because it relies on free functions for callbacks. A good C++ library would use boost::function or something similar, or would at the very least let you pass a void* user_data pointer that gets passed through to your callback. If you had that, you could pass the this pointer of your class, cast it back inside the callback, and call the appropriate member function.

Is it better to use a class with member functions, or just use "free" functions, if I only need one instance of that class

I am programming in c++. I have made a main class that has a bunch of member functions and variables etc. The thing is, I only really need one instance of this class, and was thinking that maybe it is unnecessary to have all the function in a class. Is it better to remove the class, and just have the functions and variables not in a class? Does in matter?
The main reason I ask is because it would simplify a bit if a the functions not in a class (becuase the member functions cant be used as arguments in other functions without making them static).

Class member function cannot call another member function of same class?

I'm writing a private member function for a class (function1) and for a chunk of the code I decided it'd be easier to put that chunk into it's own function (function2) , and call it from function1. However, the compiler is saying that function2 needs an object. This doesn't make sense to me, because an object has to be created in order for function1 to work, so the object for function2 seems like it should just be "this".
int ClassName::function1(args)
{
//some code;
//some code;
function2(args); //says I need an object to call the function here
//some code;
}
int ClassName::function2(args)
{
//some code;
}
The exact error code is "A nonstatic member reference must be relative to a specific object". I've been searching for hours and every instance of this comes from someone calling a class member function from outside of the class without using a object pointer. I cannot find anything for a class member function calling another class member function. I also thought I had called member functions from other member functions in the past without trouble, so I'm super confused. I could just delete function2 and do all calculations inside function2, but then I wouldn't learn anything!
I tried switching the order of the function definitions in the cpp file. The order of the prototypes in the header. Changed function2 from private to public. No dice. I've exhausted google, my own programming knowledge, and any experimentation that I could think of, so I have to ask you guys for help now. If you need extra info, let me know, although it seems like the exact code inside my functions would be irrelevant as far as the problem goes.

Which is best for a repeating piece of code?

I have a class with two member functions that share a piece of code:
void A::First()
{
firstFunctionEpilogue();
sharedPart();
}
void A::Second()
{
secondFunctionEpilogue();
sharedPart();
}
Currently firstFunctionEpilogue(), secondFunctionEpilogue() and sharedPart() are not function calls but just pieces of code, sharedPart() code being duplicated. I want to get rid of the duplication.
The shared piece of code doesn't need access to any members of the class. So I can implement it as any of the three:
a static member function,
a const non-static member function or
a local function.
Which variant is better and why?
If your function accesses state but does not change it then use a const member function.
Your case:
If it your function 1) doesn't need access to any member of the code, and 2) is related to that class, then make it a static function of your class.
That way it is clear that it is not modifying state, nor based on the state of the object.
An extra case you didn't mention:
There is another thing you can do too. And that is to make your SharedPart take in a member function pointer and to call it and then process it's main body. If you have a lot of First(), Second(), Third(), Fourth(), ... such functions then this can lead to less code duplication. That way you don't need to keep calling SharedPart(); at the end of each member function, and you can re-use First(), Second(), THird(), ... without calling the SharedPart() of the code.
I'd say:
It probably doesn't matter, so it's not so much "best practice" as "just don't do anything crazy".
If the class and all its members are defined in its header, then a private static member function is probably best, since it clearly indicates "not for clients". But there are ways to do this for a non-member function: don't document it, put in a comment "not for clients", and stick the whole thing in namespace beware_of_the_leopard.
If the class member functions are defined in a .cpp file, then little helper functions like this are best as free functions in the .cpp file. Either static, or in an anonymous namespace.
Or it could be in a different class.
Or, if it's a member, it could be virtual.
There are a lot of decisions, and I wouldn't stress out about it too much. Generally, I opt for a const non-static member function as a default unless I have a good reason not to do it that way.
Prefer static if clients need to call it without having an instance
Prefer local functions if you don't want to clutter the .h file or you want it completely hidden in the .c
Make it a non-member function
The shared piece of code doesn't need access to any members of the class.
As a general rule, if a piece of code doesn't need access to any members of the class don't make it a member function! Try to encapsulate your classes as much as possible.
I'd suggest doing a non-member function in a separate namespace that would call the public methods and then call the function you made for the shared code.
Here is an example of what I mean :
namepsace Astuff{
class A{...};
void sharedPart(){...};
void first(const A& a);
void second(const A& a);
}
void Astuff::first(const A& a){
a.first();
sharedPart();
}
a static member function, a const
non-static member function or a local
function.
Generally, it should be a member function of another class, or at least non-static member of the class itself.
If this function is only called from instance members of a class - probably its logical meaning requires an instance, even if syntax does not. Can anything except this object provide meaningful parameters or make use of the result?
Unless it makes sense to call this function from outside of the object instance, it shouldn't be static. Unless it makes sense to call this function without accessing your class at all, it shouldn't be local.
Borrowing examples from Brian's comment:
if this function changes global state, it should be member of a class of global state;
if this function writes to file, it should be member of a class of file format;
if it's refreshing screen, it should be member of... etc
Even if it's a plain arithmetic expression, it may be useful to make it a member (static or not) of some ArithmeticsForSpecificPurpose class.
Make it a non-member non-friend function. Scott Meyer's has a great explanation for this here (and also Item 23 of Effective C++ 3rd Edition).
As a rule of thumb "try to keep it as local as possible but as visible as necessary".
If all code calling the function resides in the same implementation file, this means keeping it local to the implementation file.
If you'd make it a private static method of your class, it would not be callable by implementaions including your class, but it would still be visible to them. So every time you change the semantics of that method, all implementaions including your calls will have to recompile - which is quite a burden, since from their point of view, they don't even need to know those sementics.
Thus, in order to minimize unnecessary dependencies, you would want to make it a static global function.
However, if you should ever find yourself repeating this global function in mulitple implementation files, it would be time to move the function into a seperate header/implementaion file pair, so that all callers can include it.
Whether you place that function into a namespace, at global scope, or as a static function in a class is really up to taste.
On a final note, if you go for the global static function, there's a "more c++ like" version: anonymous namespaces. It has the nice property that it can actually store state and also prevents users for being able to even forward declare any of its functions.
// in your .cpp file
namespace /*anonymous*/
{
void foo()
{
// your code here
}
};
void MyClass::FooUser1() { foo(); }
void MyClass::FooUser2() { foo(); }