Invalid DO loop control information in SAS Base - sas

I need to find for every row the last 3hr usage (Usage is one of the columns in dataset) grouped by User and ID_option.
Every line(row) represent one record (within 3 min time interval). For example (including desired column sum_usage_3hr):
User ID_option time usage sum_usage_3hr
1 a1 12OCT2017:11:20:32 3 10
1 a1 12OCT2017:10:23:24 7 14
1 b1 12OCT2017:09:34:55 12 12
2 b1 12OCT2017:08:55:06 4 6
1 a1 12OCT2017:07:59:53 7 7
2 b1 12OCT2017:06:59:12 2 2
I have used code below for hash table:
data want;
if _n_=1 then do;
if 0 then set have(rename=(usage=_usage));
declare hash h(dataset:'have(rename=(usage=_usage))',hashexp:20);
h.definekey('user','id_option','time');
h.definedata('_usage');
h.definedone();
end;
set have;
sum_usage_3hr=0;
do i=time-3*3600 to time ;
if h.find(key:user,key:id_option,key:i)=0 then sum_usage_3hr+_usage;
end;
drop _usage i;
run;
But I got an error: Invalid DO loop control information, either the INITIAL or TO expression is missing or the BY expression is missing, zero, or invalid. If I add:
output;
end:
just above the "run;" it gives me an error: 'No matching DO/Select statement'.
Anybody know what causes the problem?
I have also the version with sorting the table firstly and gives me the same error.
Thank you
After implementing the for answer:
User ID_option time usage sum_usage_3hr col_i_got
1 a1 12OCT2017:11:22:32 3 12 3
1 a1 12OCT2017:11:20:24 0 9 3
1 a1 12OCT2017:10:34:55 2 9 2
1 a1 12OCT2017:09:55:06 0 7 2
1 a1 12OCT2017:09:43:45 0 7 0
1 a1 12OCT2017:08:59:53 7 7 7
1 a1 12OCT2017:06:59:12 0 0 7

Try this out:
Problem 1:
Input:
data have;
input User ID_option $ time usage ;
informat time datetime18.;
format time datetime18.;
cards;
1 a1 12OCT2017:11:20:32 3
1 a1 12OCT2017:10:23:24 7
1 b1 12OCT2017:09:34:55 12
2 b1 12OCT2017:08:55:06 4
1 a1 12OCT2017:07:59:53 7
2 b1 12OCT2017:06:59:12 2
;
run;
Code:
proc sort data=have out=have1;
by user id_option time;
quit;
data have2;
set have1;
by user id_option;
format previous_time datetime18.;
previous_time = lag(time);
previous_usage = lag(usage);
if first.ID_option then previous_time=.;
if previous_time ~= . and intnx("hour",time,-3,"s") <= previous_time <= time then sum_usage_3hr=usage+previous_usage;
else sum_usage_3hr = usage;
drop previous_time previous_usage;
run;
proc sort data=have2 out=want;
by descending time ;
quit;
Output:
User ID_option time usage sum_usage_3hr
1 a1 12Oct2017 11:20:32 3 10
1 a1 12Oct2017 10:23:24 7 14
1 b1 12Oct2017 9:34:55 12 12
2 b1 12Oct2017 8:55:06 4 6
1 a1 12Oct2017 7:59:53 7 7
2 b1 12Oct2017 6:59:12 2 2
Problem2:
Input:
data have;
input user1 ID_option $ time usage ;
informat time datetime18.;
format time datetime18.;
cards;
1 a1 12OCT2017:11:22:32 3
1 a1 12OCT2017:11:20:24 0
1 a1 12OCT2017:10:34:55 2
1 a1 12OCT2017:09:55:06 0
1 a1 12OCT2017:09:43:45 0
1 a1 12OCT2017:08:59:53 7
1 a1 12OCT2017:06:59:12 0
;
run;
Code:
proc sql;
create table want as
select user1,id_option,time,min(usage) as usage,sum(usage1) as sum_usage_3hr
from
(
select a.*,b.time as time1 ,b.usage as usage1
from
have a
left join
have b
on a.user1 = b.user1 and a.id_option = b.id_option and b.time <= a.time
where intck("hour",a.time ,b.time) >= -3
)
group by 1,2,3
order by time desc;
quit;
Output:
user1 ID_option time usage sum_usage_3hr
1 a1 12Oct2017 11:22:32 3 12
1 a1 12Oct2017 11:20:24 0 9
1 a1 12Oct2017 10:34:55 2 9
1 a1 12Oct2017 9:55:06 0 7
1 a1 12Oct2017 9:43:45 0 7
1 a1 12Oct2017 8:59:53 7 7
1 a1 12Oct2017 6:59:12 0 0
Let me know in case of any queries.

Related

Identifying first occurrence after trigger event

I have a big panel dataset that looks somewhat like this:
data have;
input id t a b ;
datalines;
1 1 0 0
1 2 0 0
1 3 1 0
1 4 0 0
1 5 0 1
1 6 1 0
1 7 0 0
1 8 0 0
1 9 0 0
1 10 0 1
2 1 0 0
2 2 1 0
2 3 0 0
2 4 0 0
2 5 0 1
2 6 0 1
2 7 0 1
2 8 0 1
2 9 1 0
2 10 0 1
3 1 0 0
3 2 0 0
3 3 0 0
3 4 0 0
3 5 0 0
3 6 0 0
3 7 1 0
3 8 0 0
3 9 0 0
3 10 0 0
;
run;
For every ID I want to record all 'trigger' events, namely when a=1 and then I need to how long it takes to the next occurrence of b=1. The final output should then give me the following:
data want;
input id a_no a_t b_t diff ;
datalines;
1 1 3 5 2
1 2 6 10 4
2 1 2 5 3
2 2 9 10 1
3 1 7 . .
;
run;
It is of course no problem to get all a=1 and b=1 events, but as it is a very big dataset with a lot of both events for every ID I am searching for an elegant and straight-forward solution. Any ideas?
Here's a fairly simple SQL approach that gives more or less the desired output:
proc sql;
create table want
as select
t1.id,
t1.t as a_t,
t2.t as b_t,
t2.t - t1.t as diff
from
have(where = (a=1)) t1
left join
have(where = (b=1)) t2
on
t1.id = t2.id
and t2.t > t1.t
group by t1.id, t1.t
having diff = min(diff)
;
quit;
The only part missing is a_no. This sort of row-incrementing ID is quite a lot of work to generate consistently in SQL, but it's trivial with an extra data step:
data want;
set want;
by id;
if first.id then a_no = 0;
a_no + 1;
run;
An elegant DATA step way can use nested DOW loops. It's straight forward when you understand DOW loops.
data want(keep=id--diff);
length id a_no a_t b_t diff 8;
do until (last.id); * process each group;
do a_no = 1 by 1 until(last.id); * counter for each output;
do until ( output_condition or end); * process each triggering state change;
SET have end=end; * read data;
by id; * setup first. last. variables for group;
if a=1 then a_t = t; * detect and record start of trigger state;
output_condition = (b=1 and t > a_t > 0); * evaluate for proper end of trigger state;
end;
if output_condition then do;
b_t = t; * compute remaining info at output point;
diff = b_t - a_t;
OUTPUT;
a_t = .; * reset trigger state tracking variables;
b_t = .;
end;
else
OUTPUT; * end of data reached without triggered output;
end;
end;
run;
Note: A SQL way (not shown) can use self join within groups.

Generating Unique ID for same group

I have data set,
CustID Rating
1 A
1 A
1 B
2 A
2 B
2 C
2 D
3 X
3 X
3 Z
4 Y
4 Y
5 M
6 N
7 O
8 U
8 T
8 U
And expecting Output
CustID Rating ID
1 A 1
1 A 1
1 B 1
2 A 1
2 B 2
2 C 3
2 D 4
3 X 1
3 X 1
3 Z 2
4 Y 1
4 Y 1
5 M 1
6 N 1
7 O 1
8 U 1
8 T 2
8 U 1
In the solution below, I selected the distinct possible ratings into a macro variable to be used in an array statement. These distinct values are then searched in the ratings tolumn to return the number assigned at each successful find.
You can avoid the macro statement in this case by replacing the %sysfunc by 3 (the number of distinct ratings, if you know it before hand). But the %sysfunc statement helps resolve this in case you don't know.
data have;
input CustomerID Rating $;
cards;
1 A
1 A
1 B
2 A
2 A
3 A
3 A
3 B
3 C
;
run;
proc sql noprint;
select distinct quote(strip(rating)) into :list separated by ' '
from have
order by 1;
%put &list.;
quit;
If you know the number before hand:
data want;
set have;
array num(3) $ _temporary_ (&list.);
do i = 1 to dim(num);
if findw(rating,num(i),'tips')>0 then id = i;
end;
drop i;
run;
Otherwise:
%macro Y;
data want;
set have;
array num(%sysfunc(countw(&list., %str( )))) $ _temporary_ (&list.);
do i = 1 to dim(num);
if findw(rating,num(i),'tips')>0 then id = i;
end;
drop i;
run;
%mend;
%Y;
The output:
Obs CustomerID Rating id
1 1 A 1
2 1 A 1
3 1 B 2
4 2 A 1
5 2 A 1
6 3 A 1
7 3 A 1
8 3 B 2
9 3 C 3
Assuming data is sorted by customerid and rating (as in the original unedited question). Is the following what you want:
data want;
set have;
by customerid rating;
if first.customerid then
id = 0;
if first.rating then
id + 1;
run;

SAS, calculate row difference

data test;
input ID month d_month;
datalines;
1 59 0
1 70 11
1 80 21
2 10 0
2 11 1
2 13 3
3 5 0
3 9 4
4 8 0
;
run;
I have two columns of data ID and Month. Column 1 is the ID, the same ID may have multiple rows (1-5). The second column is the enrolled month. I want to create the third column. It calculates the different between the current month and the initial month for each ID.
you can do it like that.
data test;
input ID month d_month;
datalines;
1 59 0
1 70 11
1 80 21
2 10 0
2 11 1
2 13 3
3 5 0
3 9 4
4 8 0
;
run;
data calc;
set test;
by id;
retain current_month;
if first.id then do;
current_month=month;
calc_month=0;
end;
if ^first.id then do;
calc_month = month - current_month ;
end;
run;
Krs

sas run if statement over macro variables

I have the following two sas datasets:
data have ;
input a b;
cards;
1 15
2 10
3 40
4 200
1 25
2 15
3 10
4 75
1 1
2 99
3 30
4 100
;
data ref ;
input x y;
cards;
1 10
2 20
3 30
4 100
;
I would like to have the following dataset:
data want ;
input a b outcome ;
cards;
1 15 0
2 10 1
3 40 0
4 200 0
1 25 0
2 15 1
3 10 1
4 75 1
1 1 1
2 99 0
3 30 1
4 100 1
;
I would like to create a variable 'outcome' which is produced by an if statement upon conditions of variables a, b, x and y. As in reality the 'have' dataset is extremely large I would like to avoid a sort and merging the two datasets together (where a = x).
I am trying to use macro variables with the following code:
data _null_ ;
set ref ;
call symput('listx', x) ;
call symput('listy', y) ;
run ;
data want ;
set have ;
if a=&listx and b le &listy then outcome = 1 ; else outcome = 0 ;
run ;
which does not however produce the desired result:
data want ;
input a b outcome ;
cards;
1 15 0
2 10 1
3 40 0
4 200 0
1 25 0
2 15 1
3 10 1
4 75 1
1 1 1
2 99 0
3 30 1
4 100 1
;
redone my solution using hash tables. Below my approach
data ref2(rename=(x=a));
set ref ;
run;
data want;
declare Hash Plan ();
rc = plan.DefineKey ('a'); /*x originally*/
rc = plan.DefineData('a', 'y');
rc = plan.DefineDone();
do until (eof1);
set ref2 end=eof1;
rc = plan.add(); /*add each record from ref2 to plan (hash table)*/
end;
do until (eof2);
set have end=eof2;
call missing(y);
rc = plan.find();
outcome = (rc =0 and b<y);
output;
end;
stop;
run;
hope it helps

subset of dataset using first and last in sas

Hi I am trying to subset a dataset which has following
ID sal count
1 10 1
1 10 2
1 10 3
1 10 4
2 20 1
2 20 2
2 20 3
3 30 1
3 30 2
3 30 3
3 30 4
I want to take out only those IDs who are recorded 4 times.
I wrote like
data AN; set BU
if last.count gt 4 and last.count lt 4 then delete;
run;
But there is something wrong.
EDIT - Thanks for clarifying. Based on your needs, PROC SQL will be more direct:
proc sql;
CREATE TABLE AN as
SELECT * FROM BU
GROUP BY ID
HAVING MAX(COUNT) = 4
;quit;
For posterity, here is how you could do it with only a data step:
In order to use first. and last., you need to use a by clause, which requires sorting:
proc sort data=BU;
by ID DESCENDING count;
run;
When using a SET statement BY ID, first.ID will be equal to 1 (TRUE) on the first instance of a given ID, 0 (FALSE) for all other records.
data AN;
set BU;
by ID;
retain keepMe;
If first.ID THEN DO;
IF count = 4 THEN keepMe=1;
ELSE keepMe=0;
END;
if keepMe=0 THEN DELETE;
run;
During the datastep BY ID, your data will look like:
ID sal count keepMe first.ID
1 10 4 1 1
1 10 3 1 0
1 10 2 1 0
1 10 1 1 0
2 20 3 0 1
2 20 2 0 0
2 20 1 0 0
3 30 4 1 1
3 30 3 1 0
3 30 2 1 0
3 30 1 1 0
If I understand correct, you are trying to extract all observations are are repeated 4 time or more. if so, your use of last.count and first.count is wrong. last.var is a boolean and it will indicate which observation is last in the group. Have a look at Tim's suggestion.
In order to extract all observations that are repeated four times or more, I would suggest to use the following PROC SQL:
PROC SQL;
CREATE TABLE WORK.WANT AS
SELECT /* COUNT_of_ID */
(COUNT(t1.ID)) AS COUNT_of_ID,
t1.ID,
t1.SAL,
t1.count
FROM WORK.HAVE t1
GROUP BY t1.ID
HAVING (CALCULATED COUNT_of_ID) ge 4
ORDER BY t1.ID,
t1.SAL,
t1.count;
QUIT;
Result:
1 10 1
1 10 2
1 10 3
1 10 4
3 30 1
3 30 2
3 30 3
3 30 4
Slight variation on Tims - assuming you don't necessarily have the count variable.
proc sql;
CREATE TABLE AN as
SELECT * FROM BU
GROUP BY ID
HAVING Count(ID) >= 4;
quit;