I was reading sehe's answer for fast text file reading in C++, which looks like this.
static uintmax_t wc(char const *fname)
{
static const auto BUFFER_SIZE = 16*1024;
int fd = open(fname, O_RDONLY);
if(fd == -1)
handle_error("open");
/* Advise the kernel of our access pattern. */
posix_fadvise(fd, 0, 0, 1); // FDADVICE_SEQUENTIAL
char buf[BUFFER_SIZE + 1];
uintmax_t lines = 0;
while(size_t bytes_read = read(fd, buf, BUFFER_SIZE))
{
if(bytes_read == (size_t)-1)
handle_error("read failed");
if (!bytes_read)
break;
for(char *p = buf; (p = (char*) memchr(p, '\n', (buf + bytes_read) - p)); ++p)
++lines;
}
return lines;
}
This is cool, but I was wondering if a similar approach can be taken when we aren't dealing with a character operation like counting newlines, but want to operate on each line of data. Say for instance I had a file of doubles, and already some function parse_line_to_double to use on each line.
12.44243
4242.910
...
That is, how can I read BUFFER_SIZE bytes into my buffer but avoid splitting the last line read? Effectively, can I ask "Give me BUFFER_SIZE or less bytes while ensuring that the last byte read is a newline character (or EOF)"?
Knowing extremely little about low level IO like this, ideas that came to mind were
Can I "back up" fd to the most recent newline between iterations?
Do I have to keep a second buffer holding a copy of the current line being read all the time?
Here is a comparison test. First, lets try the easy way. Just read the file with standard C++ functions:
#include <iostream>
#include <string>
#include <fstream> //std::ifstream
#include <sstream> //std::stringstream
uintmax_t test1(char const *fname)
{
std::ifstream fin(fname);
if(!fin) return 0;
uintmax_t lines = 0;
std::string str;
double value;
while(fin >> value)
{
//std::cout << value << "\n";
lines++;
}
return lines;
}
Next, with std::stringstream this is about 2.5 times faster:
uintmax_t test2(char const *fname)
{
std::ifstream fin(fname);
if(!fin) return 0;
uintmax_t lines = 0;
std::string str;
double value;
std::stringstream ss;
ss << fin.rdbuf();
while(ss >> value)
lines++;
return lines;
}
Next, lets read the whole file in to memory. This will be fine as long as the file is less than 1 GiB or so. Assuming there is a double value on each line, lets extract that value. test3 is more complicated and less flexible, and it's not any faster than test2:
uintmax_t test3(char const *fname)
{
std::ifstream fin(fname, std::ios::binary);
if(!fin) return 0;
fin.seekg(0, std::ios::end);
size_t filesize = (size_t)fin.tellg();
fin.seekg(0);
std::string str(filesize, 0);
fin.read(&str[0], filesize);
double value;
uintmax_t lines = 0;
size_t beg = 0;
size_t i;
size_t len = str.size();
for(i = 0; i < len; i++)
{
if(str[i] == '\n' || i == len - 1)
{
try
{
value = std::stod(str.substr(beg, i - beg));
//std::cout << value << "\n";
beg = i + 1;
lines++;
}
catch(...)
{
}
}
}
return lines;
}
For comparison to the wc function in the question, let's read the whole file in to memory and only count the number of lines. This runs a little faster than wc (as expected), suggesting that there is no need for additional optimizations
uintmax_t test_countlines(char const *fname)
{
std::ifstream fin(fname, std::ios::binary);
if(!fin) return 0;
fin.seekg(0, std::ios::end);
size_t filesize = (size_t)fin.tellg();
fin.seekg(0);
std::string str(filesize, 0);
fin.read(&str[0], filesize);
uintmax_t lines = 0;
for(auto &c : str)
if(c == '\n')
lines++;
return lines;
}
Related
I have a problem, mostly because I can't really understand how to handle the situation.
I have a char* buffer of X size, it's the content of an encrypted file who's got decrypted and will be then parsed by the ifstream handler class that i can't edit.
So my idea was to create an fstream object in which, with rdbuf() assign the buffer with sputn.
fstream _handle2;
_handle2.rdbuf()->sputn(_buffer, _size);
_handle2.flush();
But of course, it's not working and buffer does not get written into the fstream object, do you have any idea of how to make it so?
I tried different methods but I clearly can't figure out what to do.
I'm trying to create a buffer type that can be parsed similarly to a ifstream.
You might try something like this (adopted from the link I provided in the comment already):
std::ifstream ifs("test.txt", std::ifstream::binary);
if (ifs)
{
ifs.seekg (0, ifs.end);
int length = ifs.tellg();
ifs.seekg (0, ifs.beg);
std::string buffer;
buffer.resize(length);
ifs.read(const_cast<char*>(buffer.data()), length);
if (ifs)
{
// de-crypt the buffer here!
// something like:
// buffer[i] = decryptChar(buffer[i]);
std::istringstream iss(buffer);
// now you can use iss just the same way as ifs,
// if the file was not encrypted...
}
else
{
std::cout << "error: only " << ifs.gcount() << " bytes could be read";
}
ifs.close();
}
Edit in response to your comment:
std::istringstream is used to convert text into binary data, e. g. int n; iss >> n; would convert the string "20102012", represented by ascii sequence 0x32, 0x30, 0x31, 0x30, 0x32, 0x30, 0x31, 0x32 into the corresponding four-byte integer value of 0x0132bb7c). But if data is already binary, std::istringstream is not suitable. Then you might rather try to write your own stream class similar to this example:
class DecryptionStream
{
std::unique_ptr<char> mBuffer;
char* mEnd;
char* mPos;
unsigned int flags;
unsigned int const eofbit = 1 << 0;
unsigned int const failbit = 1 << 1;
// other flag bits as needed
public:
// fail/eof bits as needed
DecryptionStream(char const* fileName) : mPos(nullptr)
{
std::ifstream ifs(fileName, std::ifstream::binary);
if (ifs)
{
ifs.seekg (0, ifs.end);
int length = ifs.tellg();
ifs.seekg (0, ifs.beg);
mBuffer.reset(new char[length]);
ifs.read(mBuffer.get(), length);
if (ifs)
{
// de-crypt the buffer here!
// something like:
// buffer[i] = decryptChar(buffer[i]);
mPos = mBuffer.get();
mEnd = mBuffer.get() + length;
}
else
{
flags |= failbit;
}
ifs.close();
}
}
template<typename T>
DecryptionStream& operator >>(T& t)
{
// fail, if any fail bit set already
size_t avail = mPos - mEnd;
if (avail < sizeof(t))
{
flags |= eofbit | failbit;
}
else
{
if(avail == sizeof(t))
{
flags |= eofbit;
}
memcpy(&t, mPos, sizeof(t));
mPos += sizeof(t);
}
return *this;
}
operator bool()
{
return flags == 0;
}
};
You could even use this class with complex data types - then make sure, though, that you control byte alignment of these appropriately, otherwise you might fail badly!
Have a look at boost::iostreams::array_source.
It allows you to treat an array as a std::istream. The advantage over std::istringstream is that the array will not be copied into the stream, which reduces memory usage and increases performance. The array_source will just store a pointer to the existing buffer.
#include <iostream>
#include <string>
#include <boost/iostreams/device/array.hpp>
#include <boost/iostreams/stream.hpp>
namespace io = boost::iostreams;
int main()
{
// Create an array and wrap a stream interface around it.
const char buffer[] = "hello stackoverflow";
io::stream< io::array_source > strm( buffer, sizeof(buffer) - 1 ); //-1 to strip '\0'
// Use the stream like a standard istream.
std::string s;
while( strm >> s )
std::cout << s << "\n";
}
Live Demo on Coliru.
Loop isn't making 10 copies and i have no idea how to change file names
#include "iostream"
#include "fstream"
#include "windows.h"
using namespace std;
void main()
{
char str[200];
ifstream myfile("as-1.txt");
if (!myfile)
{
cerr << "file not opening";
exit(1);
}
for (int i = 0; i < 10; i++)
{
ofstream myfile2("as-2.txt");
while (!myfile.eof())
{
myfile.getline(str, 200);
myfile2 << str << endl;
}
}
system("pause");
}
Solution using plain C API from <cstdio>. Easily customizable.
const char* file_name_format = "as-%d.txt"; //Change that if you need different name pattern
const char* original_file_name = "as-1.txt"; //Original file
const size_t max_file_name = 255;
FILE* original_file = fopen(original_file_name, "r+");
if(!original_file)
//file not found, handle error
fseek(original_file, 0, SEEK_END); //(*)
long file_size = ftell(original_file);
fseek(original_file, 0, SEEK_SET);
char* original_content = (char*)malloc(file_size);
fread(original_content, file_size, 1, original_file);
fclose(original_file);
size_t copies_num = 10;
size_t first_copy_number = 2;
char file_name[max_file_name];
for(size_t n = first_copy_number; n < first_copy_number + copies_num; ++n)
{
snprintf(file_name, max_file_name, file_name_format, n);
FILE* file = fopen(file_name, "w");
fwrite(original_content, file_size, 1, file);
fclose(file);
}
free(original_content);
(*) As noted on this page, SEEK_END may not necessarily be supported (i.e. it is not a portable solution). However most POSIX-compliant systems (including the most popular Linux distros), Windows family and OSX support this without any problems.
Oh, and one more thing. This line
while (!myfile.eof())
is not quite correct. Read this question - it explains why you shouldn't write such code.
int main()
{
const int copies_of_file = 10;
for (int i = 1; i <= copies_of_file; ++i)
{
std::ostringstream name;
name << "filename as-" << i << ".txt";
std::ofstream ofile(name.str().c_str());
ofile.close();
}
return 0;
}
That will make 10 copies of a blank .txt file named "filename as-1.txt" "filename as-2.txt" etc.
Note also the use of int main: main always has a return of int, never void
I am running the following program below. I am taking the first 63 char values in B.txt and then attaching the float values in A.txt, beginning at the 62nd column in A.txt, at the end of the lines of B.txt
So if B.txt contains:
I am running the following program below. I am taking the firstXXXXXXXX
and A.txt contains:
I am running the following program below. I am taking the fir3.14
I want B.txt to look like:
I am running the following program below. I am taking the first3.14
However, the output I'm getting instead is:
I am running the following program below. I am taking the firstBUNCH OF JUNK3.14
int main()
{
loadfileB("B.txt");
return 0;
}
void loadfileB(char* fileName)
{
FILE* fp = fopen(fileName, "r");
char line[82];
vector<int> rownum;
vector<float> temp;
temp = loadfileA("A.txt");
int i = 0;
ofstream fout("output.txt");
while (fgets(line, 81, fp) != 0)
{
radius=temp[i];
char buffer[64];
strncpy(buffer, line, 63);
fout << buffer<< " " << radius << endl;
i++;
}
fclose(fp);
}
vector<float> loadfileA(char* fileName)
{
FILE* fp = fopen(fileName, "r");
char line[82];
vector<int> rownum;
vector <float> tempvec;
int i = 0;
while (fgets(line, 81, fp) != 0)
{
float temp;
getFloat(line, &temp, 60, 6);
tempvec.push_back(temp);
}
fclose(fp);
return tempvec;
}
void getFloat(char* line, float* d, int pos, int len)
{
char buffer[80];
*d = -1;
strncpy(buffer, &line[pos], len);
buffer[len] = '\0';
sscanf(buffer, "%f", d);
}
strncpy is a bad function to use. This is because it does not null-terminate its output if the input did not fit in the buffer. The garbage you are seeing is the result of passing a non-null-terminated buffer to a function that expected a null-terminated string.
The simplest fix is to replace:
char buffer[64];
strncpy(buffer, line, 63);
with:
std::string buffer = line;
buffer.resize(63);
In your other usage you do null-terminate, however you never check that len is smaller than 80 either. Again the simpler fix would be:
std::string buffer( line + pos, len );
sscanf(buffer.c_str(), "%f", d);
The getFloat function should have some way of signaling error (either a return value; or throw an exception if sscanf does not return 1).
Of course, you could replace a lot of your other C-style code with C++-style code too and avoid buffer size issues entirely.
I'm trying to read a binary file and store it in a buffer. The problem is, that in the binary file are multiple null-terminated characters, but they are not at the end, instead they are before other binary text, so if I store the text after the '\0' it just deletes it in the buffer.
Example:
char * a = "this is a\0 test";
cout << a;
This will just output: this is a
here's my real code:
this function reads one character
bool CStream::Read (int * _OutChar)
{
if (!bInitialized)
return false;
int iReturn = 0;
*_OutChar = fgetc (pFile);
if (*_OutChar == EOF)
return false;
return true;
}
And this is how I use it:
char * SendData = new char[4096 + 1];
for (i = 0; i < 4096; i++)
{
if (Stream.Read (&iChar))
SendData[i] = iChar;
else
break;
}
I just want to mention that there is a standard way to read from a binary file into a buffer.
Using <cstdio>:
char buffer[BUFFERSIZE];
FILE * filp = fopen("filename.bin", "rb");
int bytes_read = fread(buffer, sizeof(char), BUFFERSIZE, filp);
Using <fstream>:
std::ifstream fin("filename.bin", ios::in | ios::binary );
fin.read(buffer, BUFFERSIZE);
What you do with the buffer afterwards is all up to you of course.
Edit: Full example using <cstdio>
#include <cstdio>
const int BUFFERSIZE = 4096;
int main() {
const char * fname = "filename.bin";
FILE* filp = fopen(fname, "rb" );
if (!filp) { printf("Error: could not open file %s\n", fname); return -1; }
char * buffer = new char[BUFFERSIZE];
while ( (int bytes = fread(buffer, sizeof(char), BUFFERSIZE, filp)) > 0 ) {
// Do something with the bytes, first elements of buffer.
// For example, reversing the data and forget about it afterwards!
for (char *beg = buffer, *end=buffer + bytes; beg < end; beg++, end-- ) {
swap(*beg, *end);
}
}
// Done and close.
fclose(filp);
return 0;
}
static std::vector<unsigned char> read_binary_file (const std::string filename)
{
// binary mode is only for switching off newline translation
std::ifstream file(filename, std::ios::binary);
file.unsetf(std::ios::skipws);
std::streampos file_size;
file.seekg(0, std::ios::end);
file_size = file.tellg();
file.seekg(0, std::ios::beg);
std::vector<unsigned char> vec;
vec.reserve(file_size);
vec.insert(vec.begin(),
std::istream_iterator<unsigned char>(file),
std::istream_iterator<unsigned char>());
return (vec);
}
and then
auto vec = read_binary_file(filename);
auto src = (char*) new char[vec.size()];
std::copy(vec.begin(), vec.end(), src);
The problem is definitievely the writing of your buffer, because you read a byte at a time.
If you know the length of the data in your buffer, you could force cout to go on:
char *bf = "Hello\0 world";
cout << bf << endl;
cout << string(bf, 12) << endl;
This should give the following output:
Hello
Hello world
However this is a workaround, as cout is foreseent to output printable data. Be aware that the output of non printable chars such as '\0' is system dependent.
Alternative solutions:
But if you manipulate binary data, you should define ad-hoc data structures and printing. Here some hints, with a quick draft for the general principles:
struct Mybuff { // special strtucture to manage buffers of binary data
static const int maxsz = 512;
int size;
char buffer[maxsz];
void set(char *src, int sz) // binary copy of data of a given length
{ size = sz; memcpy(buffer, src, max(sz, maxsz)); }
} ;
Then you could overload the output operator function:
ostream& operator<< (ostream& os, Mybuff &b)
{
for (int i = 0; i < b.size; i++)
os.put(isprint(b.buffer[i]) ? b.buffer[i]:'*'); // non printables replaced with *
return os;
}
ANd you could use it like this:
char *bf = "Hello\0 world";
Mybuff my;
my.set(bf, 13); // physical copy of memory
cout << my << endl; // special output
I believe your problem is not in reading the data, but rather in how you try to print it.
char * a = "this is a\0 test";
cout << a;
This example you show us prints a C-string. Since C-string is a sequence of chars ended by '\0', the printing function stops at the first null char.
This is because you need to know where the string ends either by using special terminating character (like '\0' here) or knowing its length.
So, to print whole data, you must know the length of it and use a loop similar to the one you use for reading it.
Are you on Windows? If so you need to execute _setmode(_fileno(stdout), _O_BINARY);
Include <fcntl.h> and <io.h>
I need to search a (non-text) file for the byte sequence "9µ}Æ" (or "\x39\xb5\x7d\xc6").
After 5 hours of searching online this is the best I could do. It works but I wanted to know if there is a better way:
char buffer;
int pos=in.tellg();
// search file for string
while(!in.eof()){
in.read(&buffer, 1);
pos=in.tellg();
if(buffer=='9'){
in.read(&buffer, 1);
pos=in.tellg();
if(buffer=='µ'){
in.read(&buffer, 1);
pos=in.tellg();
if(buffer=='}'){
in.read(&buffer, 1);
pos=in.tellg();
if(buffer=='Æ'){
cout << "found";
}
}
}
}
in.seekg((streampos) pos);
Note:
I can't use getline(). It's not a text file so there are probably not many line breaks.
Before I tried using a multi-character buffer and then copying the buffer to a C++ string, and then using string::find(). This didn't work because there are many '\0' characters throughout the file, so the sequence in the buffer would be cut very short when it was copied to the string.
Similar to what bames53 posted; I used a vector as a buffer:
std::ifstream ifs("file.bin");
ifs.seekg(0, std::ios::end);
std::streamsize f_size = ifs.tellg();
ifs.seekg(0, std::ios::beg);
std::vector<unsigned char> buffer(f_size);
ifs.read(buffer.data(), f_size);
std::vector<unsigned char> seq = {0x39, 0xb5, 0x7d, 0xc6};
bool found = std::search(buffer.begin(), buffer.end(), seq.begin(), seq.end()) != buffer.end();
If you don't mind loading the entire file into an in-memory array (or using mmap() to make it look like the file is in memory), you could then search for your character sequence in-memory, which is a bit easier to do:
// Works much like strstr(), except it looks for a binary sub-sequence rather than a string sub-sequence
const char * MemMem(const char * lookIn, int numLookInBytes, const char * lookFor, int numLookForBytes)
{
if (numLookForBytes == 0) return lookIn; // hmm, existential questions here
else if (numLookForBytes == numLookInBytes) return (memcmp(lookIn, lookFor, numLookInBytes) == 0) ? lookIn : NULL;
else if (numLookForBytes < numLookInBytes)
{
const char * startedAt = lookIn;
int matchCount = 0;
for (int i=0; i<numLookInBytes; i++)
{
if (lookIn[i] == lookFor[matchCount])
{
if (matchCount == 0) startedAt = &lookIn[i];
if (++matchCount == numLookForBytes) return startedAt;
}
else matchCount = 0;
}
}
return NULL;
}
.... then you can just call the above function on the in-memory data array:
char * ret = MemMem(theInMemoryArrayContainingFilesBytes, numBytesInFile, myShortSequence, 4);
if (ret != NULL) printf("Found it at offset %i\n", ret-theInMemoryArrayContainingFilesBytes);
else printf("It's not there.\n");
This program loads the entire file into memory and then uses std::search on it.
int main() {
std::string filedata;
{
std::ifstream fin("file.dat");
std::stringstream ss;
ss << fin.rdbuf();
filedata = ss.str();
}
std::string key = "\x39\xb5\x7d\xc6";
auto result = std::search(std::begin(filedata), std::end(filedata),
std::begin(key), std::end(key));
if (std::end(filedata) != result) {
std::cout << "found\n";
// result is an iterator pointing at '\x39'
}
}
const char delims[] = { 0x39, 0xb5, 0x7d, 0xc6 };
char buffer[4];
const size_t delim_size = 4;
const size_t last_index = delim_size - 1;
for ( size_t i = 0; i < last_index; ++i )
{
if ( ! ( is.get( buffer[i] ) ) )
return false; // stream to short
}
while ( is.get(buffer[last_index]) )
{
if ( memcmp( buffer, delims, delim_size ) == 0 )
break; // you are arrived
memmove( buffer, buffer + 1, last_index );
}
You are looking for 4 bytes:
unsigned int delim = 0xc67db539;
unsigned int uibuffer;
char * buffer = reinterpret_cast<char *>(&uibuffer);
for ( size_t i = 0; i < 3; ++i )
{
if ( ! ( is.get( buffer[i] ) ) )
return false; // stream to short
}
while ( is.get(buffer[3]) )
{
if ( uibuffer == delim )
break; // you are arrived
uibuffer >>= 8;
}
Because you said you cannot search the entire file because of null terminator characters in the string, here's an alternative for you, which reads the entire file in and uses recursion to find the first occurrence of a string inside of the whole file.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
string readFile (char *fileName) {
ifstream fi (fileName);
if (!fi)
cerr << "ERROR: Cannot open file" << endl;
else {
string str ((istreambuf_iterator<char>(fi)), istreambuf_iterator<char>());
return str;
}
return NULL;
}
bool findFirstOccurrenceOf_r (string haystack, char *needle, int haystack_pos, int needle_pos, int needle_len) {
if (needle_pos == needle_len)
return true;
if (haystack[haystack_pos] == needle[needle_pos])
return findFirstOccurrenceOf_r (haystack, needle, haystack_pos+1, needle_pos+1, needle_len);
return false;
}
int findFirstOccurrenceOf (string haystack, char *needle, int length) {
int pos = -1;
for (int i = 0; i < haystack.length() - length; i++) {
if (findFirstOccurrenceOf_r (haystack, needle, i, 0, length))
return i;
}
return pos;
}
int main () {
char str_to_find[4] = {0x39, 0xB5, 0x7D, 0xC6};
string contents = readFile ("input");
int pos = findFirstOccurrenceOf (contents, str_to_find, 4);
cout << pos << endl;
}
If the file is not too large, your best solution would be to load the whole file into memory, so you don't need to keep reading from the drive. If the file is too large to load in at once, you would want to load in chunks of the file at a time. But if you do load in chucks, make sure you check to edges of the chunks. It's possible that your chunk happens to split right in the middle of the string you're searching for.