I've been struggling to get all items of below string into an array.
abc,"de,f",hi,"hello","te,st&" items into an array in Typescript.
If any string has comma (,) or ampersand (&) in it,It will be placed in double quotes.
Tried split function but it fails as my strings can have comma as well.
Any help in this regard is highly appreciated.
Thank you.
If you are looking to use a regular expression matching, can you try a different regEx that would match strings inside quotes first, then strings outside quotes, something like (\".+?\")|(^[^\"]+,)|(,[^\"]+,)
I don't know how relevant it would be in case of TypeScript, but I am guessing you'd be able to work something out that takes this Pattern and gives you the matches one by one
First of all, I think that you are making the things more complicated than what they are by implementing the following logic:
has comma (,) or ampersand (&) in it,It will be placed in double quotes.
Instead of doing this that way, you should systematically put your elements inside double quote:
abc,"de,f",hi,"hello","te,st&"
→
"abc","de,f","hi","hello","te,st&"
you will have then the following string to parse.
A regex like this one will do the job:
(?<=,")([^"]*)(?=",)|(?<=")([^"]*)(?=",)|(?<=")([^"]*)(?="$)
using back references $1$2$3, you can extract your elements.
RegEx /(?:^|,)(\"(?:[^\"])\"|[^,])/ has helped me get the required values.
var test = '"abc,123",test,123,456,"def:get"';
test.split(/(\"(?:[^\"])\"|[^,])/);
Its returning the below array.
["", ""abc,123"", ",", "test", ",", "123", ",", "456", ",", ""def:get"", ""]
And when a particular values in side double quotes,I just trimmed them to get the actual values and have ignore empty items of array..
use the split a string .....
let fullName = "First,Last"
let fullNameArr = fullName.characters.split{$0 == ","}.map(String.init)
fullNameArr[0] // First
fullNameArr[1] // Last
Related
Is there any way to use the split function in scala so that it splits a line at commas but doesn't at commas contained within 2 double quotes?
For example, I have the following:
x: String = """"??", "hamburger", "ketchup, mayo, mustard", "pizza""""
and I tried this:
x.split(',') but it didn't work. I then thought about removing all double quotes but that still doesn't solve my problem.
Any help would be greatly appreciated!
EDIT:
Here's a snippet of my code to see how I can incorporate this:
val data1 = noheader1.map { line =>
val values = line._1.split(',') //This is what I am trying to change
val name = values(2).replaceAll("\"", ""))
I am a bit new to scala and even more so to regex, so could someone clarify how to write that weird regex expression in my code so that I can obtain an ARRAY of the comma separated words of the line?
Try this!
(?>"(?>\\.|[^"])*?"|(,))
Regex101
Instead of split() you can use a regular expression and findAllIn(), like such:
val x = """"??", "hamburger", "ketchup, mayo, mustard", "pizza""""
""""[^"]+"""".r.findAllIn(x).toList
This will result in, List("??", "hamburger", "ketchup, mayo, mustard", "pizza")
Note: I am using triple-quotes (""") in the example.
Perhaps not so elegant as other regex already suggested, consider the splitting element between items as ", " and so
x.split("\",\\s+\"")
Array("??, hamburger, ketchup, mayo, mustard, pizza")
Then in the resulting array, to the head "?? apply stripPrefix("\"") and to the last pizza" apply stripSuffix("\"").
I need to use RegEx to run through a string of text but only return that parts that I need. Let's say for example the string is as follows:
1234,Weapon Types,100,Handgun,"This is the text, "and", that is all."""
\d*,Weapon Types,(\d*),(\w+), gets me most of the way, however it is the last part that I am having an issue with. Is there a way for me to capture the rest of the string i.e.
"This is the text, "and", that is all."""
without picking up the quotes? I've tried negating them, however it just stops the string at the quote.
Please keep in mind that the text for this string is unknown so doing literal matches will not work.
You've given us something very difficult to solve. It's okay that you have nested commas inside your string. Once we come across a double-quote, we can ignore everything until the end quote. This would gooble up commas.
But how will your parser know that the next double-quote isn't ending the string. How does it know that it a nested double-quote?
If I could slightly modify your input string to make it clear what is a nested quote, then parsing is easy...
var txt = "1234,Weapon Types,100,Handgun,\"This is the text, "and", that is all.\",other stuff";
var m = Regex.Match(txt, #"^\d*,Weapon Types,(\d*),(\w+),""([^""]+)""");
MessageBox.Show(m.Groups[3].Value);
But if your input string must have nested quotes like that, then we must come up with some other rule for detecting what is the real end of the string. How about this?
var txt = "1234,Weapon Types,100,Handgun,\"This is the text, \"and\", that is all.\",other stuff";
var m = Regex.Match(txt, #"^\d*,Weapon Types,(\d*),(\w+),""(.+)"",");
MessageBox.Show(m.Groups[3].Value);
The result is...
This is the text, "and", that is all.
I have a character vector in which each element is enclosed in brackets. I want
to remove the brackets and just have the string.
So I tried:
n = c("[Dave]", "[Tony]", "[Sara]")
paste("", n, "", sep="")
Unfortunately, this doesn't work for some reason.
I've performed the same task before using this same code, and am not sure why it's not working this time.
I want to go from '[Dave]' to 'Dave'.
What am I doing wrong?
You could gsub out the brackets like so:
n = c("[Dave]", "[Tony]", "[Sara]")
gsub("\\[|\\]", "", n)
[1] "Dave" "Tony" "Sara"
A regular expression substitution will do it. Look at the gsub() function.
This gives you what you want (it removes any instance of '[' or ']'):
gsub("\\[|\\]", "", n)
The other answers should be enough to get your desired output. I just wanted to provide a brief explanation of why what you tried didn't work.
paste concatenates character strings. If you paste an empty character string, "", to something with a separator that is also an empty character string, you really haven't altered anything. So paste can't make a character string shorter; the result will either be the same (as in your example) or longer.
If working within tidyverse:
library(tidyverse); library(stringr)
n = c("[Dave]", "[Tony]", "[Sara]")
n %>% str_replace_all("\\[|\\]", "")
[1] "Dave" "Tony" "Sara"
I'm comparing 2 URL query strings to see if they're equal; however, I want to ignore a specific query parameter (always with a numeric value) if it exists. So, these 2 query strings should be equal:
firstName=bobby&lastName=tables¶mToIgnore=2
firstName=bobby&lastName=tables¶mToIgnore=5
So, I tried to use a regex replace using the REReplaceNoCase function:
REReplaceNoCase(myQueryString, "¶mToIgnore=[0-9]*", "")
This works fine for the above example. I apply the replace to both strings and then compare. The problem is that I can't be sure that the param will be the last one in the string... the following 2 query strings should also be equal:
firstName=bobby&lastName=tables¶mToIgnore=2
paramToIgnore=5&firstName=bobby&lastName=tables
So, I changed the regex to make the preceding ampersand optional... "&?paramToIgnore=[0-9]*". But - these strings will still not be equal as I'll be left with an extra ampersand in one of the strings but not the other:
firstName=bobby&lastName=tables
&firstName=bobby&lastName=tables
Similarly, I can't just remove preceding and following ampersands ("&?paramToIgnore=[0-9]*&?") as if the query param is in the middle of the string I'll strip one ampersand too many in one string and not the other - e.g.
firstName=bobby&lastName=tables¶mToIgnore=2
firstName=bobby¶mToIgnore=5&lastName=tables
will become
firstName=bobby&lastName=tables
firstName=bobbylastName=tables
I can't seem to get my head around the logic of this... Can anyone help me out with a solution?
If you can't be sure of the order the parameters appear i would recommend, that you don't compare them by the string itsself.
I recommend splitting the string up like this:
String stringA = "firstName=bobby&lastName=tables¶mToIgnore=2";
String stringB = "firstName=bobby&lastName=tables¶mToIgnore=5";
String[] partsA = stringA.split("&");
String[] partsB = stringB.split("&");
Then go through arrays and make the paramToIgnore somehow euqal:
for(int i = 0; i < partsA.length; i++)
{
if(partsA[i].startsWith("paramToIgnore"){
partsA[i] = "IgnoreMePlease";
}
}
for(int j = 0; j < partsB.length; j++)
{
if(partsB[i].startsWith("paramToIgnore"){
partsB[i] = "IgnoreMePlease";
}
}
Then you can sort and compare the arrays to see if they are equal:
Arrays.sort(partsA);
Arrays.sort(partsB);
boolean b = Arrays.equals(partsA, partsB);
I'm pretty sure it's possible to make this more compact and give it a better performance. But with comparing strings like you do, you somehow alsways have to care about the order of your parameters.
You can use the QueryStringDeleteVar UDF on cflib to remove the query string variables you want to ignore from both strings, then compare them.
Make it in two steps:
first remove your param, as you described in example
then remove ampersand which is left at the begining or the end of query with separate regex, or any double/triple/... ampersands in the middle of the query
How about having an 'or' in the RegEx to match an ampersand at the start or the end?
¶mToIgnore=[0-9]*|paramToIgnore=[0-9]*&
Seems to do the job when testing in regexpal.com
try changing it to:
REReplaceNoCase(myQueryString, "&?paramToIgnore=[0-9]+", "")
plus instead of star should capture 1 or more of the preceding matched characters. It won't match anything but 0-9 so if there is another parameter after that it'll stop when it can't match any more digits.
Alternatively, you could use:
REReplaceNoCase(myQueryString, "&?paramToIgnore=[^&]", "")
This will match anything but an ampersand. It will cover the case if the parameter exists but there is no value; which is probably something you'd want to account for.
What is the regular expression to validate a comma delimited list like this one:
12365, 45236, 458, 1, 99996332, ......
I suggest you to do in the following way:
(\d+)(,\s*\d+)*
which would work for a list containing 1 or more elements.
This regex extracts an element from a comma separated list, regardless of contents:
(.+?)(?:,|$)
If you just replace the comma with something else, it should work for any delimiter.
It depends a bit on your exact requirements. I'm assuming: all numbers, any length, numbers cannot have leading zeros nor contain commas or decimal points. individual numbers always separated by a comma then a space, and the last number does NOT have a comma and space after it. Any of these being wrong would simplify the solution.
([1-9][0-9]*,[ ])*[1-9][0-9]*
Here's how I built that mentally:
[0-9] any digit.
[1-9][0-9]* leading non-zero digit followed by any number of digits
[1-9][0-9]*, as above, followed by a comma
[1-9][0-9]*[ ] as above, followed by a space
([1-9][0-9]*[ ])* as above, repeated 0 or more times
([1-9][0-9]*[ ])*[1-9][0-9]* as above, with a final number that doesn't have a comma.
Match duplicate comma-delimited items:
(?<=,|^)([^,]*)(,\1)+(?=,|$)
Reference.
This regex can be used to split the values of a comma delimitted list. List elements may be quoted, unquoted or empty. Commas inside a pair of quotation marks are not matched.
,(?!(?<=(?:^|,)\s*"(?:[^"]|""|\\")*,)(?:[^"]|""|\\")*"\s*(?:,|$))
Reference.
/^\d+(?:, ?\d+)*$/
i used this for a list of items that had to be alphanumeric without underscores at the front of each item.
^(([0-9a-zA-Z][0-9a-zA-Z_]*)([,][0-9a-zA-Z][0-9a-zA-Z_]*)*)$
You might want to specify language just to be safe, but
(\d+, ?)+(\d+)?
ought to work
I had a slightly different requirement, to parse an encoded dictionary/hashtable with escaped commas, like this:
"1=This is something, 2=This is something,,with an escaped comma, 3=This is something else"
I think this is an elegant solution, with a trick that avoids a lot of regex complexity:
if (string.IsNullOrEmpty(encodedValues))
{
return null;
}
else
{
var retVal = new Dictionary<int, string>();
var reFields = new Regex(#"([0-9]+)\=(([A-Za-z0-9\s]|(,,))+),");
foreach (Match match in reFields.Matches(encodedValues + ","))
{
var id = match.Groups[1].Value;
var value = match.Groups[2].Value;
retVal[int.Parse(id)] = value.Replace(",,", ",");
}
return retVal;
}
I think it can be adapted to the original question with an expression like #"([0-9]+),\s?" and parse on Groups[0].
I hope it's helpful to somebody and thanks for the tips on getting it close to there, especially Asaph!
In JavaScript, use split to help out, and catch any negative digits as well:
'-1,2,-3'.match(/(-?\d+)(,\s*-?\d+)*/)[0].split(',');
// ["-1", "2", "-3"]
// may need trimming if digits are space-separated
The following will match any comma delimited word/digit/space combination
(((.)*,)*)(.)*
Why don't you work with groups:
^(\d+(, )?)+$
If you had a more complicated regex, i.e: for valid urls rather than just numbers. You could do the following where you loop through each element and test each of them individually against your regex:
const validRelativeUrlRegex = /^(^$|(?!.*(\W\W))\/[a-zA-Z0-9\/-]+[^\W_]$)/;
const relativeUrls = "/url1,/url-2,url3";
const startsWithComma = relativeUrls.startsWith(",");
const endsWithComma = relativeUrls.endsWith(",");
const areAllURLsValid = relativeUrls
.split(",")
.every(url => validRelativeUrlRegex.test(url));
const isValid = areAllURLsValid && !endsWithComma && !startsWithComma