I'm trying to store random numbers in vector, but I want each number to be unique. Can I do that with for loop without using unique() or random_shuffle() ?
#include <iostream>
#include <vector>
#include <ctime>
using namespace std;
int main()
{
srand(time(NULL));
vector<int> v;
for (unsigned int i = 0; i < 30; i++) {
v.push_back(rand() % 30);
}
for (unsigned int j = 0; j < 30; j++) {
cout << v[j] << endl;
}
return 0;
}
The classic Fisher–Yates shuffle can also be used to generate a shuffled vector directly, in one pass
vector<unsigned> v;
for (unsigned i = 0; i < 30; ++i)
{
unsigned j = rand() % (i + 1);
if (j < i)
{
v.push_back(v[j]);
v[j] = i;
}
else
v.push_back(i);
}
You should probably generate vector and just shuffle it:
#include <iostream>
#include <ctime>
#include <utility>
int main()
{
std::srand(static_cast<unsigned int>(std::time(NULL)));
size_t const n = 30;
std::vector<int> v(n);
//make vector
for (size_t i = 0; i < n; ++i)
v[i] = static_cast<int>(i);
//shuffle
for (size_t i = n - 1; i > 0; --i)
std::swap(v[i], v[static_cast<size_t>(rand()) % (i + 1)]);
//print
for (size_t i = 0; i < n; ++i)
std::cout << (i > 0 ? "," : "") << v[i];
return 0;
}
Prints, for example:
27,24,2,23,13,6,9,14,11,5,15,18,16,29,22,12,26,20,10,8,28,25,7,4,1,17,0,3,19,21
Related
I am trying to sort a list of indexes based on a list of string, and I receive bellow error - Segmentation fault. I cannot understand why I receive this error and how to solve it?
#include <iostream>
#include <string.h>
using namespace std;
int main() {
int size = 5;
char* mass[size];
int num[size];
for(int i = 0; i < size; i++) {
mass[i] = new char[20];
num[i] = i;
cin >> mass[i];
}
for(int i = 0; i < size; i++){
for(int j = size; j > i; j--)
if(strcmp(mass[num[j-1]], mass[num[j]]) > 0){
int tmp = num[j-1];
num[j-1] = num[j];
num[j] = tmp;
}
}
for(int i = 0; i < size; i++){
cout << mass[num[i]] << ", ";
}
return 0;
}
In the inner loop you start with j = size and then num[j] is an out-of-bounds array access.
In modern C++ you would solve this like this:
#include <iostream>
#include <array>
#include <algorithm>
int main() {
const int size = 5;
std::array<std::string, size> mass;
std::array<int, size> num;
for (int i = 0; i < size; i++) {
std::cin >> mass[i];
num[i] = i;
}
std::ranges::sort(num, [mass](int a, int b) { return mass[a] <= mass[b];});
for(int i = 0; i < size; i++){
std::cout << mass[num[i]] << ", ";
}
std::cout << std::endl;
return 0;
}
int temp;
for (int j = 0; j < vecsize - 1; ++j) {
int min = sort.at(j);
for (int i = j+1; i < vecsize; ++i) {
if (min > sort.at(i)) {
min = sort.at(i);
temp = i;
}
}
swap(sort.at(j), sort.at(temp));
}
I am trying to sort (in ascending order) the vector of: 23 42 4 16 8 15
However, my attempt at using selection sort outputs: 4 8 15 23 16 42
What am I doing wrong?
When you define min, you seem to be assigning it the value of the array sort at jth index. Yet, you are using an extra variable tmp to swap the elements, and you seem to fail to initialize it before the inner for loop, similar to how you initialize min. And if all the other elements in the array are smaller than the element at sort[j], tmp will be uninitialized for that iteration of the outer loop, possibly causing it to have an incorrect value in it.
int temp;
for (int j = 0; j < vecsize - 1; ++j) {
int min = sort.at(j);
temp = j; # HERE'S WHAT'S NEW
for (int i = j+1; i < vecsize; ++i) {
if (min > sort.at(i)) {
min = sort.at(i);
temp = i;
}
}
swap(sort.at(j), sort.at(temp));
}
You may see this code at work here. It seems to produce the desired output.
Try this : corrected-code
#include <iostream>
#include <vector>
using namespace std;
void print (vector<int> & vec) {
for (int i =0 ; i < vec.size(); ++i) {
cout << vec[i] << " ";
}
cout << endl;
}
int main() {
int temp;
vector<int> sort;
sort.push_back(23);
sort.push_back(42);
sort.push_back( 4);
sort.push_back( 16);
sort.push_back( 8);
sort.push_back(15);
print(sort);
int vecsize = sort.size();
for (int j = 0; j < vecsize - 1; ++j) {
int min = j;
for (int i = j+1; i < vecsize; ++i) {
if (sort.at(min) > sort.at(i)) {
min = i;
}
}
if (min != j)
swap(sort.at(j), sort.at(min));
}
print(sort);
return 0;
}
If you can use C++11, you can also solve sorting (as in your example) with lambdas. It's a more powerful and optimized way. You should try it maybe in the future.
[EDITED]:
A short example:
// Example program
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
int main()
{
std::vector<int> myVector;
myVector.emplace_back(23);
myVector.emplace_back(42);
myVector.emplace_back(4);
myVector.emplace_back(16);
myVector.emplace_back(8);
myVector.emplace_back(15);
std::sort(myVector.begin(), myVector.end(),
[](int a, int b) -> bool
{
return a < b;
});
}
I have problem with sorting an array. I don't know why my codes does not sort an array properly. I am new in programming so be gentle on me. Here's a code. Also other functions like merge or quick sort does not work too. Thanks in advance for answer.
#include <iostream>
#include <cstdlib>
#include <vector>
#include <algorithm>
#include <iterator>
std::vector<int> bubbleSort(std::vector<int>& Array)
{
for (unsigned int j = 1; j < Array.size() - 1; ++j)
{
for (unsigned int i = 0; i < Array.size() - 1; i++)
{
if (Array[i] > Array[++i])
{
std::swap(Array[i], Array[++i]);
}
}
}
return Array;
}
int main()
{
for (int i = 0; i < 10;i++)
{
int N; //array size
srand(std::time(NULL));
std::cout << " array size: ";
std::cin >> N;
std::vector <int> Array;
//fill array
for (int i = 1; i <= N; i++)
Array.push_back(i);
for (int i = N - 1; i > 0; i--)
{
int j = rand() % i;
std::swap(Array[i], Array[j]);
}
bubbleSort(Array);
for (unsigned int i = 0; i < Array.size(); i++)
{
std::cout << Array.at(i) << std::endl;
}
}
system("pause");
}
It looks like you're unintentionally incrementing i within the loop. Don't use ++i, use i+1 instead. Also change your loop termination condition to just i < Array.size() instead of i < Array.size() - 1
I have written code to test how many of the same numbers are present in both arrays, but for some reason it throws 'std::bad_alloc' could anyone explain why? It only throws it when N = 1000000 for some reason, is it because I have allocated 4000000 bytes of memory?
Here's the code:
#include <iostream>
#include <vector>
#include <string>
#include <random>
#include <algorithm>
#include <math.h>
#include <iomanip>
using namespace std;
int find_last_before_zero(const vector<int>& vec) {
for (int i = vec.size() - 1; i >= 0; --i) {
if (vec[i] != 0) return i + 1;
}
return vec.size();
}
void gen_random_array(vector<int>& vec){
random_device rd;
mt19937 gen(rd());
uniform_int_distribution<> dist(100000, 100200);
for(int i = 0; i < vec.size(); ++i){
vec[i] = dist(gen);
}
}
void binSearchClient(int T){
int counters[4] = {0,0,0,0};
string names[4] = {"for n = 1000 = ", "for n = 10000 = ", "for n = 100000 = ", "for n = 1000000 = "};
for(int i = 0; i < T; ++i){
int N = 1000;
for(int k = 0; k < 4; ++k){
N *= pow(10.0, k);
vector<int> first(N), second(N);
gen_random_array(first, N); gen_random_array(second, N);
vector<int> intersection(N);
sort(first.begin(), first.end()); sort(second.begin(), second.end());
set_intersection(first.begin(), first.end(), second.begin(), second.end(), intersection.begin());
counters[k] += find_last_before_zero(intersection);
}
}
}
}
for(int i = 0; i < 4; ++i){
cout << names[i] << setprecision(10) << std::fixed << (1.0 * counters[i]) / T << endl;
}
}
int main(){
binSearchClient(1);
}
In you first iteration you have N as 1000. Then in for(int k = 0; k < 4; ++k) you do N *= pow(10.0, k);. So for the first iteration N = 1000 (N(1000) * 10^0) The k becomes 1 and you N = 10000 (N(1000) * 10^1). Then k becomes 2 and N = 1,000,000 (N(10000) * 10^2). At k = 3 you get N = 1,000,000,000,000,000 (N(1,000,000) * 10^3) which is more than likely memory than you can allocate.
I'm new to C++ programming. I need to sort this matrix:
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
int main(int argc, char** argv) {
Mat10 a;
fillRand(a, 5, 5);
prnMat(a, 5, 5);
cout << endl;
return 0;
}
void fillRand(Mat10 m, int n, int k) {
for (int i = 0; i < n; i++)
for (int j = 0; j < k; j++)
m[i][j] = rand() % 1000;
}
void prnMat(Mat10 a, int m, int n) {
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++)
cout << setw(8) << a[i][j];
cout << endl;
}
}
I need to sort the matrix from the beginning from the beginning. The smallest value must be at the beginning of the of the first column. The next must be below it and so on. The result must be sorted matrix - the smallest number must be at the beginning of the left column - the biggest value must be at the end of the matrix. Would you please help to solve the problem?
EDIT
Maybe I found possible solution:
void sort(int pin[10][2], int n)
{
int y,d;
for(int i=0;i<n-1;i++)
{
for(int j=0; j<n-1-i; j++)
{
if(pin[j+1][1] < pin[j][1]) // swap the elements depending on the second row if the next value is smaller
{
y = pin[j][1];
pin[j][1] = pin[j+1][1];
pin[j+1][1] = y;
d = pin[j][0];
pin[j][0] = pin[j+1][0];
pin[j+1][0] = d;
}
else if(pin[j+1][1] == pin[j][1]) // else if the two elements are equal, sort them depending on the first row
{
if(pin[j+1][0] < pin[j][0])
{
y = pin[j][1];
pin[j][1] = pin[j+1][1];
pin[j+1][1] = y;
d = pin[j][0];
pin[j][0] = pin[j+1][0];
pin[j+1][0] = d;
}
}
}
}
}
But since I'm new to programming I don't understand is this the solution?
Here is a simple example for you:
#include <vector>
#include <algorithm>
using namespace std;
//This is the comparation function needed for sort()
bool compareFunction (int i,int j)
{
return (i<j);
}
int main()
{
//let's say you have this matrix
int matrix[10][10];
//filling it with random numbers.
for (int i = 0; i < 10; i++)
for (int j = 0; j < 10; j++)
matrix[i][j] = rand() % 1000;
//Now we get all the data from the matrix into a vector.
std::vector<int> vect;
for (int i = 0; i < 10; i++)
for (int j = 0; j < 10; j++)
vect.push_back(matrix[i][j]);
//and sort the vector using standart sort() function
std::sort( vect.begin(), vect.end(), compareFunction );
//Finally, we put the data back into the matrix
for (int i = 0; i < 10; i++)
for (int j = 0; j < 10; j++)
matrix[i][j] = vect.at(i*10 + j);
}
After this, the matrix will be sorted by rows:
1 2
3 4
If you want it to be sorted by cols:
1 3
2 4
You need to replace matrix[i][j] in the last cycle only with matrix[j][i]
If you need to read about the the sort() function, you can do it here
Hope this helps.
You can simply call std::sort on the array:
#include <algorithm> // for std::sort
int main() {
int mat[10][10];
// fill in the matrix
...
// sort it
std::sort(&mat[0][0], &mat[0][0]+10*10);
}