My regular expression is looks like this "\u003e(\d+)\u003c/td\u003e\u003ctd colName=\"FacilityName\" style=\"text-align:left\"\u003eFAC${JMETERVARIABLE}"
This is not working in Jmeter.Somebody please help me on this
Thanks in Advance
I had the same problem of getting regex to work when the returned text contains '\u003e' etc instead of the normal characters, and in the end I inserted a Beanshell sampler to put the variable ${whatever} together with the rest of the regex string, then passed the entire string as a variable into the regular expression extractor (REE). My jmeter script is on a different machine so please forgive the lack of screenshots.
I got this from another SO answer which i can't now find (do please someone insert the reference if you know it), but in brief it looks something like this (in the large 'Script' window of the Beanshell sampler)
String s = "your regex phrase ${jmeter variable}";
vars.put("RegPhrase",s);
and then in the REE for 'Regular Expression' field you just put ${RegPhrase}
It also has the advantage that the final RegPhrase appears as a variable in the debug PostProcessor, so you can copy and paste it into the RegEx field of the http request output in the view results tree, to test the phrase works with your data, then tweak as required.
Related
Example:
In a response headers I see,
state=a5d73a14-a728-4f0f-afae-de5fda55d002
Here I can use LB as state= and there is no right boundary.
So I tried using regular expression extractor as:
state=(.+)
and replaced the hard coded value in the next request as ${state}
The requests are failing as it takes ${state} itself in the request URL, it means regular expression extractor is not working. I know I have placed the function rightly. Still I don't know what I am doing wrong here. Any suggestion would really help!
Should search the response in main and sub samples. Before I was searching for response only in main sample's so it failed.
same regular expression worked: when there is no right boundary or new line right boundary.
state=(.+)
enter image description here
Actually your regex should work, maybe it fails due to line break or something, to be on the safe side try using state=(.*) as the regular expression, it should be less restrictive:
Also the value of your "state" looks like a GUID so you can try looking up a guid-like structure instead:
state=([A-Fa-f0-9]{8}[\-][A-Fa-f0-9]{4}[\-][A-Fa-f0-9]{4}[\-][A-Fa-f0-9]{4}[\-]([A-Fa-f0-9]){12})
And last but not the least, by default Regular Expression Extractor looks into response body so you need to change the "Field to check" to Response Headers
More information:
JMeter Regular Expressions
Perl 5 Regex Cheat sheet
Using Regular Expressions to Extract Tokens and Session IDs to Variables
I am trying to build a regex in Excel;s data validation. However, it is not working.
Would you please explain how could I put data validation in Excel
I want last name data validation with characters, quote('), space and dot.
=ISNUMBER(MATCH("^[a-zA-Z\s,.']*$",F:F,0))
I am using above formula and, again, it is not working
For SSN, I am using following formula and it is not working
=AND(ISNUMBER(MATCH("/^\d{3}-\d{2}-\d{4}$/",A2,0)),LEFT(A2,1)>=0)
Please help me to build data validation from data tab or VBA script for the data validation.
The MATCH function in Excel is not used for regex matching.
But you do not need it here, it looks like.
To allow only letters and ,.' you could use formula like this:
=ISNUMBER(SUMPRODUCT(SEARCH(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)," ,.'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")))
To validate an SSN try the formula from the guide here
=AND(LEFT(F1,1)>="0",LEN(F1)<10,ISNUMBER(F1))
Some more pointers:
More Data Validation examples
Adding validation to a cell using VBA is described here and using Regex in VBA here, as noted.
Unfortunately, the Match Function is not able to support regex. It can only match a single, constant value.
I suggest you take a look at This very detailed post, which explains beautifully how to use Regular Expressions in Excel.
Other than that, your Regular Expression looks to be in working order - if you get this set up, it should work immediately. Good luck!
I'm trying to extract a request ID for running load testing on J Meter that I need to use for the subsequent HTTP requests. I'm using the regular expression extractor to do this.
I've been trying for hours and hours to extract the value inside single quotations and have not had any success. The response looks similar to this.
RequestDateTime='2/12/2017 7:19:49 AM' RequestID='1234567' Client="14232" etc...
I want the exact numbers with no quotations around it. The value should be 1234567
I've tried using RequestID='(.*?)' but it gives the entire string whereas I just want the value inside.
Use regular expression RequestID='(\d+)
Template $1$
Match 1
Looking into "RegExp" Tester mode of the View Results Tree listener your regular expression itself is fine:
So my expectation is that your Regular Expression Extractor configuration is not correct, you should get expected value if use something like:
Reference Name: anything meaningful, i.e. RequestID
Regular Expression: RequestID='(.*?)'
Template: $1$
You should be able to refer the extracted value as ${RequestID} later on. Extracted JMeter Variable(s) can be visualised using Debug Sampler
See How to Debug your Apache JMeter Script article to learn more about JMeter tests troubleshooting techniques.
So the following regular expression should do the trick: '(\d*)'
Then Insert a Debug Sampler into your thread so you can see the reference name. The variable you are looking for will have the following name: referencename_g0
The _g0 represents the first group that was matched. If the expression matches other chars in your response, simply use the variable with the correct group number. (e.g _g1 or _g2, etc).
Hope this helps!
I have a variable
announcementName= test
I am trying to use regEx Extractor to match an expression in jmeter.
I am able to match data with the below expression.
{"id":(.*?),"announcementName":"test",
However I am unable to pass test as a variable to the same expression
{"id":(.*?),"announcementName":"${announcementName}",
I am unable to match anything with the above regEx matching.
Can someone please let me know on how to pass parameters to RegEx Extractor in Jmeter.
As per my experience, if you try this approach in listener to verify whether correlation is working or not than obviously it's not going to work.
But if you are passing this directly in reg ex extractor and trigger the script then it should work provided the variable does not contain any special character like (.,?) etc. (As you mentioned test as value so seems you took an example to display here but actual value is something else, so please check actual value once again to confirm it's a simple string without any special characters)
You can check with __V() function.
i.e.
{"id":(.*?),"announcementName":"${__V(${announcementName})}",
I am working on gradle script to go through large css file and scrap out the URLs for images. So far:
def temp = ".post-format background:url(image/goes/here.jpg); {background: .post-format {background: url(../img/post //formats.png);display:;display:.woocommerce-info:before {background: url(data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAIAAAAFCAYAAABvsz2cAAAAG0lEQVQIHWP8DwQMQMACxIwwBliECcQDATgDAMHrBQqJ6tMZAAAAAElFTkSuQmCC)center no-repeat #18919c }"
def list = temp.findAll(/background:[\s]?url\([^\)]*\)/){ match ->
match
}
This works but it also takes the 'data:image' file url that we don't need. So, here the temp variable contains both - the good 'image/goes/here.jpg' url and also the one we don't need 'data:image/png[..]'. How would we have to update the regular expression to make it work? If you could also share your rational behind of the correct regular expression to help us better learn regular expressions i would much appreciate. Thank You a lot
You can use the negative look ahead mechanism to accomplish what you want. Immediately following the escaped left parenthesis you insert (?!data:image) which means that you must not match that text at that point. So your regex becomes:
/background:[\s]?url\((?!data:image)[^\)]*\)/
You can see the approach illustrated in this rubular. See also How can I find everything BUT certain phrases with a regular expression?
You didn't specify what language you're using, but if the URL you want is always the first one, just don't do a global match (which is what findAll does, whatever language that is). Most likely, changing temp.findAll to temp.match and assigning the results to a scalar string variable will do it. But please tell us which language.