Implementing assignment operator in linked list stack - c++

I'm trying to do a deep copy assignment operator for a linked list stack. I think I've wrapped my head around what I need to do, but I can't quite get it.
Here is my code:
// Purpose: performs a deep copy of the data from rhs into this linked stack
// Parameters: rhs is linked stack to be copied
// Returns: *this
// Postconditions: this stack contains same data values (in the same order) as are in rhs; any memory previously used by this stack has been deallocated.
template <typename T>
const LinkedStack<T>& LinkedStack<T>::operator=(const LinkedStack<T>& rhs) {
while(rhs.m_head != NULL) {
m_head->m_data = rhs.m_head->m_data;
m_head->m_next = new Node<T>();
rhs.m_head = rhs.m_head->m_next;
m_head = m_head->m_next;
}
m_size = rhs.m_size;
}
So my thought process is to copy the data, make a new node, and then pop a node off of the rhs variable.
It currently errors on "rhs.m_head = rhs.m_head->m_next;" for "error: assignment of member 'LinkedStack::m_head' in read-only object". I'm not sure how to work around this since I'm being passed a constant reference.
Where am I going wrong?
The node header (templated):
template <class T>
class Node {
public:
T m_data; // Data to be stored
Node<T>* m_next; // Pointer to the next element in the list
Node() : m_next(NULL) {}
Node(const T& x, Node<T>* p) : m_data(x), m_next(p) {}
};
The linked stack header (templated):
template <class T>
class LinkedStack {
Node<T>* m_head; // Pointer to the top of the stack
int m_size; // The number of elements in the stack
public:
LinkedStack();
~LinkedStack();
const LinkedStack<T>& operator= (const LinkedStack<T>& rhs);
bool isEmpty() const;
const T& top() const throw (Oops);
void push(const T& x);
void pop();
void clear();
};
EDIT: Found the solution.
template <typename T>
const LinkedStack<T>& LinkedStack<T>::operator=(const LinkedStack<T>& rhs) {
clear();
Node<T>* temp = rhs.m_head;
m_head = new Node<T>();
Node<T>* c_head = m_head;
while(temp != NULL) {
m_head->m_data = temp->m_data;
temp = temp->m_next;
m_head->m_next = new Node<T>;
m_head = m_head->m_next;
}
m_head = c_head;
m_size = rhs.m_size;
return *this;
}
My major hangup was forgetting to reset m_head to the original head before I started using m_next.

Related

Exception thrown: write access violation. prev_ptr was 0x4

I am learning about linked lists, and I decided to try implementing linked lists in C++ on my own.
I made a Node class with attributes int val and Node* ptr.
Then I made a Linked_list class with the attribute first_node, and the constructor functions work.
The append() function 'appends' a node to the list (like in Python). I first thought of just making ptr a reference to the node's pointer and then changing it when its null, but references once made, can't be changed to refer to any other variable, so I made another variable prev_ptr that points to the Node's pointer (which makes it a Node**).
Every loop, it checks if ptr is NULL, if not, ptr and prev_ptr get updated to the next Node's pointer value, and the address of the next Node's pointer value, respectively.
This keeps happening until it finds a null pointer, and then changes it to the inputted node's address.
But I'm getting an error saying:
Exception thrown: write access violation. prev_ptr was 0x4.
I can't figure out what is wrong.
Classes:
#include <iostream>
#include <string>
#include <cmath>
class Node {
public:
int val;
Node* ptr = nullptr;
Node(int Val = NULL) {
val = Val;
}
};
class Linked_list {
public:
Node first_node;
Linked_list(int F) {
Node f(F);
first_node = f;
}
void append(Node& element) {
Node* ptr = first_node.ptr;
Node** prev_ptr = &first_node.ptr;
while (true) {
if (ptr == nullptr) {
*prev_ptr = &element;
break;
}
ptr = (*ptr).ptr;
prev_ptr = &((*ptr).ptr);
}
}
};
main()
int main() {
Linked_list list(5);
Node three(3);
list.append(three);
Node four(4);
list.append(four);
return 0;
}
ptr = (*ptr).ptr;
prev_ptr = &((*ptr).ptr);
First you advance ptr to the next node. Then, you use ptr again forgetting that it has already been advanced: (*ptr).ptr now points two nodes forward, and we don't know if we can go that much far.
Perhaps you need to swap the assignments.
prev_ptr = &((*ptr).ptr);
ptr = (*ptr).ptr;
(Further, why not ptr->ptr?)
Okay, you're doing a few things in an odd fashion. First, your Linked_List should probably NOT have a Node for firstNode. It should have a Node *. After all, an empty list is possible. So is (normally) deleting the first node. Also, there's an informal naming convention of calling it head. There's also a standard convention of calling the link in your Node next rather than ptr.
But there are two simpler methods for your append() method. First, you can also keep a Node * tail in Linked_List. This is common. It points to the last node in the list. If you do that, then append looks like:
void append(Node &nodeToAppend) {
if (head == nullptr) {
head = &nodeToAppend;
tail = &nodeToAppend;
}
else {
tail->next = nodeToAppend;
tail = &nodeToAppend;
}
}
However, it's also worthwhile to be able to insert anywhere or append without a tail:
void append(Node &nodeToAppend) {
if (head == nullptr) {
head = &nodeToAppend;
}
else {
Node *ptr = head;
while (ptr->next != nullptr) {
ptr = ptr->next;
}
ptr->next = &nodeToAppend;
}
}
An insert in some sort of sorted order would be nearly identical, although slightly different. The while-loop would look like:
while (ptr->next != nullptr && ptr->value < nodeToAppend.value) ...
but would otherwise be identical.
This code doesn't solve your immediate issue, but answers a question raised in the comments.
Linked lists are usually (where I taught) a 300-400 level assignment. There are a lot of principles that one must be competent in to write a decent linked list. First, I'll show the main.cpp and its output.
main.cpp
#include "list.hpp"
#include <iostream>
template <typename Container>
void print(Container& container, std::ostream& sout = std::cout)
{
for (auto i : container) {
sout << i << ' ';
}
sout << '\n';
}
int main()
{
List<int> list;
for (int i = 1; i <= 10; ++i) {
list.push_back(i);
}
print(list);
list.erase(list.find(4));
print(list);
list.erase(list.find(1));
print(list);
list.erase(list.find(10));
print(list);
}
Output:
1 2 3 4 5 6 7 8 9 10
1 2 3 5 6 7 8 9 10
2 3 5 6 7 8 9 10
2 3 5 6 7 8 9
It doesn't test every aspect of the linked list, but it serves to demonstrate what a user should be expected to work with. Users will want to interact directly with the list and its iterators in C++. You create a Node, and then add the Node to your list. That's a level of DIY that no user wants to be bothered with. In the code below, you'll see that a Node is still used, but it only exists within the List class. Users will never see a Node.
You can look in functions like push_back() (similar to your append) for specific answers related to your question.
To explain it a bit more, the pointers are key. Yes, I declare a local Node* that will go out of scope, but the object created continues to exist on the heap. And the list is able to keep track of these Nodes due to how linked lists work, namely that the Nodes know where their neighbors live (hold their addresses).
There is also a List<T>::iterator class. In the declaration, functions marked as // minimum are required if you want to use your linked list in a range-based for loop. The other functions do work toward satisfying the requirements of LegacyBidirectionalIterator; this is the level of iterator used by std::list in the C++ Standard Library.
The code below should only be considered a decent example (Hopefully not too presumptuous on my part). It is lacking some functionality that's found in std::list, and likely does a few things in non-optimal manners. A big thing that will need tweaking is removing the member function find() and make the class work with std::find().
list.hpp
#ifndef MY_LIST_HPP
#define MY_LIST_HPP
#include <algorithm> // std::swap
#include <cstddef> // std::size_t
/*
* Pre-declare template class and friends
*/
template <typename T>
class List;
template <typename T>
void swap(List<T>& lhs, List<T>& rhs);
/*
* List Class Declaration
*/
template <typename T>
class List {
public:
List() = default;
List(T val);
List(const List& other);
List(List&& other);
~List();
void push_front(T val);
void push_back(T val);
class iterator;
iterator begin();
iterator end();
iterator find(T val);
std::size_t size() const;
iterator erase(iterator toErase); // Implement
void clear();
bool operator=(List other);
friend void swap<T>(List& lhs, List& rhs);
private:
struct Node {
T data;
Node* prev = nullptr;
Node* next = nullptr;
Node(T val) : data(val) {}
};
Node* m_head = nullptr;
Node* m_tail = nullptr;
std::size_t m_size = 0;
// Helper functions
void make_first_node(T val);
Node* find_node(T val);
};
/*
* List Iterator Declaration
*/
template <typename T>
class List<T>::iterator {
public:
iterator() = default;
iterator(List<T>::Node* node); // minimum
T& operator*(); // minimum
iterator& operator++(); // minimum
iterator operator++(int);
iterator& operator--();
iterator operator--(int);
bool operator==(const iterator& other); // minimum
bool operator!=(const iterator& other); // minimum
private:
Node* m_pos = nullptr;
};
/*
* List Implementation
*/
template <typename T>
List<T>::List(T val) : m_head(new Node(val)), m_tail(m_head), m_size(1) {}
template <typename T>
List<T>::List(const List<T>& other) {
m_head = new Node((other.m_head)->data);
m_tail = m_head;
m_size = 1;
Node* walker = (other.m_head)->next;
while (walker) {
push_back(walker->data);
++m_size;
walker = walker->next;
}
}
template <typename T>
List<T>::List(List&& other) : List() {
swap(*this, other);
}
template <typename T>
List<T>::~List() {
clear();
}
template <typename T>
void List<T>::push_front(T val)
{
if (!m_head) {
make_first_node(val);
return;
}
Node* tmp = new Node(val);
tmp->next = m_head;
m_head->prev = tmp;
m_head = tmp;
++m_size;
}
template <typename T>
void List<T>::push_back(T val) {
if (!m_head) {
make_first_node(val);
return;
}
Node* tmp = new Node(val);
tmp->prev = m_tail;
m_tail->next = tmp;
m_tail = tmp;
++m_size;
}
template <typename T>
typename List<T>::iterator List<T>::begin() {
return iterator(m_head);
}
template <typename T>
typename List<T>::iterator List<T>::end() {
return iterator(nullptr);
}
template <typename T>
typename List<T>::iterator List<T>::find(T val) {
return iterator(find_node(val));
}
template <typename T>
std::size_t List<T>::size() const {
return m_size;
}
template <typename T>
typename List<T>::iterator List<T>::erase(typename List<T>::iterator toErase)
{
Node* node = find_node(*toErase);
if (node->prev) {
node->prev->next = node->next;
} else {
m_head = node->next;
}
if (node->next) {
node->next->prev = node->prev;
} else {
m_tail = node->prev;
}
Node* toReturn = node->next;
delete node;
return toReturn;
}
template <typename T>
void List<T>::clear() {
Node* tmp = m_head;
while (m_head) {
m_head = m_head->next;
delete tmp;
tmp = m_head;
}
m_tail = nullptr;
m_size = 0;
}
template <typename T>
bool List<T>::operator=(List other) {
swap(*this, other);
return *this;
}
template <typename T>
void List<T>::make_first_node(T val) {
m_head = new Node(val);
m_tail = m_head;
m_size = 1;
}
template <typename T>
typename List<T>::Node* List<T>::find_node(T val) {
if (!m_head) {
return nullptr;
}
Node* walker = m_head;
while (walker != nullptr && walker->data != val) {
walker = walker->next;
}
return walker;
}
template <typename T>
void swap(List<T>& lhs, List<T>& rhs) {
using std::swap;
swap(lhs.m_head, rhs.m_head);
swap(lhs.m_tail, rhs.m_tail);
swap(lhs.m_size, rhs.m_size);
}
/*
* List Iterator Implementation
*/
template <typename T>
List<T>::iterator::iterator(Node* node) : m_pos(node) {}
template <typename T>
T& List<T>::iterator::operator*() {
return m_pos->data;
}
template <typename T>
typename List<T>::iterator& List<T>::iterator::operator++() {
m_pos = m_pos->next;
return *this;
}
template <typename T>
typename List<T>::iterator List<T>::iterator::operator++(int) {
iterator tmp(m_pos);
++(*this);
return tmp;
}
template <typename T>
typename List<T>::iterator& List<T>::iterator::operator--() {
m_pos = m_pos->prev;
return *this;
}
template <typename T>
typename List<T>::iterator List<T>::iterator::operator--(int) {
iterator tmp(m_pos);
--(*this);
return tmp;
}
template <typename T>
bool List<T>::iterator::operator==(const iterator& other) {
return m_pos == other.m_pos;
}
template <typename T>
bool List<T>::iterator::operator!=(const iterator& other) {
return !(*this == other);
}
#endif
Code and explaination
I think this code should work as well, so there is no need to have two pointers. It's based on an example of “good taste” that Linus Torvalds gave in an interview.
void append(Node &element)
{
Node** cursor = &first_node.ptr;
while ((*cursor) != nullptr)
cursor = &(*cursor)->ptr;
*cursor = &element;
}
It eliminates the need for multiple pointers, it eliminates edge cases and it allows us to evaluate the condition of the while loop without having to let go of the pointer that points to the next element. This allows us to modify the pointer that points to NULL and to get away with a single iterator as opposed to ptr and prev_ptr.
Naming conventions
Also the norm is to call the first node in the linked list head and to call the pointer to the next node next instead of ptr, so I will rename them in the following code.
void append(Node &new)
{
Node** cursor = &head.next;
while ((*cursor) != nullptr)
cursor = &(*cursor)->next;
*cursor = &new;
}

What i am making wrong with operator overloading?

I don't understand what is wrong when I overload operator +
(purpose of this is to join 2 stacks in one new) ...
it returns "sum" of but change values for those previous.
///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
template <typename T>
classStack
{
private:
struct Node
{
T data;
Node *next;
} *top;
std::size_t size;
public:
Stack();
~Stack();
void push(T data);
void pop(void);
size_t get_size(void);
const Stack& operator=(const Stack &stack_obj);
const Stack operator+(const Stack &stack_obj);
void show_all_stack(void);
};
template <typename T>
const Stack<T> Stack<T>::operator+(const Stack &stack_obj)
{
Stack stack;
Node *tmp;
if (!this->size && !stack_obj.size) {
return stack;
}
if (!stack_obj.size)
{
stack.size = size;
stack.top = top;
}
else if (!size)
{
stack.size = stack_obj.size;
stack.top = stack_obj.top;
}
else
{
stack.size = size + stack_obj.size;
stack.top = new Node;
stack.top = top;
tmp = stack.top;
while (tmp->next)
tmp = tmp->next;
tmp->next = new Node;
tmp->next = stack_obj.top;
}
return stack;
}
Default constructor
template <typename T>
Stack<T>::Stack(void): top(nullptr), size(0)
{
}
Destructor
template <typename T>
Stack<T>::~Stack(void)
{
Node *next;
if (!size)
std::cout << "Stack is empty!\n";
else
{
while (top != nullptr)
{
next = top->next;
delete top;
top = next;
}
top = nullptr;
}
}
Assignment operator
template <typename T>
const Stack<T>& Stack<T>::operator=(const Stack<T> &stack_obj)
{
Node *tmp;
Node *ptr;
Node *last;
Node *new_node;
if (&stack_obj != this)
{
while (top != nullptr)
{
tmp = top;
top = top->next;
delete tmp;
}
top = nullptr;
size = stack_obj.size;
ptr = stack_obj.top;
while (ptr)
{
new_node = new Node;
new_node->data = ptr->data;
new_node->next = nullptr;
if (!top)
{
top = new_node;
last = new_node;
}
else
{
last->next = new_node;
last = new_node;
}
ptr = ptr->next;
}
}
}
Before creating functions that return Stack<T> by value, or have functions that require copy semantics for Stack<T> (as in your operator +), you need to make sure that Stack<T> is safely copyable. Right now, you are lacking a copy constructor, thus your operator + would never work correctly, even if the function itself is bug-free.
You're missing this function:
Stack::Stack(const Stack<T>&)
The easiest way to implement the copy constructor is to take most of your code out of the assignment operator, and place that into the copy constructor. More or less, the code should look something like this (the code has not been compiled or tested -- it is there to illustrate the main point of this answer):
template <typename T>
Stack<T>::Stack<T>(const Stack<T> &stack_obj) : top(nullptr), size(0)
{
Node *tmp;
Node *ptr;
Node *last;
Node *new_node;
ptr = stack_obj.top;
while (ptr)
{
new_node = new Node;
new_node->data = ptr->data;
new_node->next = nullptr;
if (!top)
{
top = new_node;
last = new_node;
}
else
{
last->next = new_node;
last = new_node;
}
ptr = ptr->next;
}
}
You have already written a destructor that should work, so we won't get into that function, but a working destructor is required for the next step -- implementation of the assignment operator.
Now that you have a copy constructor and destructor, you can now write the assignment operator. The technique used here is the copy / swap idiom
#include <algorithm>
//...
template <typename T>
Stack<T>& Stack<T>::operator=(const Stack<T> &stack_obj)
{
if ( &stack_obj != this )
{
Stack<T> temp(stack_obj);
std::swap(top, temp.top);
std::swap(size, temp.size);
}
return *this;
}
Believe it or not, this works. The code that used to be here was moved to the copy constructor, and thus the assignment operator is going to take advantage of the copy constructor.
To explain briefly, the code creates a temporary Stack<T> object from the passed-in stack_obj (this is why you need a working copy constructor). Then all that is done is to swap out the this members with the temporary members. Last, the temp dies off with the old data (this is why the destructor needs to be working correctly).
Note that you need to swap all of the members, so if you add more members to the Stack<T> class, you need to swap them in the assignment operator.
Once you have the basic 3 functions (copy, assign, destroy) written correctly, then and only then should you write functions that return Stack<T> by value, or write functions that take a Stack<T> by value.
You may have other issues with operator + that lie outside the scope of what this answer is presenting to you, but the gist of it is that your class requires that it has correct copy semantics before implementing +.

SinglyLinkedList implementation with rule of 3

I'm new to C++ and have been trying to implement a Singly Linked List, that provides an implementation the destructor, copy constructor and assignment operator. I'm running into compilation issues when trying to implement the copy constructor and the assignment operator.
Here's node.hpp
#ifndef LINKED_LIST_NODE_HPP
#define LINKED_LIST_NODE_HPP
template <typename T>
class Node{
public:
T data;
Node* next;
Node();
Node(T);
Node(const Node&);
~Node();
};
template <typename T>
Node<T>::Node(){}
template <typename T>
Node<T>:: Node(const T data): data(data), next(nullptr){}
template <typename T>
Node<T>::Node(const Node<T>& source) : data(source.data),
next(new Node)
{
(*next) = *(source.next) ;
}
template <typename T>
Node<T>::~Node(){}
#endif //LINKED_LIST_NODE_HPP
This is singly_linked_list.hpp
#ifndef LINKED_LIST_SINGLYLINKEDLIST_HPP
#define LINKED_LIST_SINGLYLINKEDLIST_HPP
#include <iostream>
#include "node.hpp"
template <typename T>
class SinglyLinkedList {
private:
Node<T>* head;
std::size_t count;
public:
SinglyLinkedList();
SinglyLinkedList(const SinglyLinkedList& source);
SinglyLinkedList& operator=(const SinglyLinkedList& source);
~SinglyLinkedList();
void insert(T);
void remove(T);
bool isEmpty();
int length();
void print();
};
template <typename T>
SinglyLinkedList<T>::SinglyLinkedList() : head(nullptr), count(0){}
template <typename T>
template <typename T>
SinglyLinkedList<T>::SinglyLinkedList(const SinglyLinkedList& source){
Node<T>* curr = source.head;
while(curr != nullptr){
Node<T>* p = new Node<T>;
p->data = curr->data;
curr = curr->next;
}
}
//template <typename T>
//SinglyLinkedList<T>::SinglyLinkedList& operator=(const SinglyLinkedList<T>& source){
// //not sure how to implment this.
//}
template <typename T>
SinglyLinkedList<T>::~SinglyLinkedList() {
if(!isEmpty()){
Node<T>* temp = head;
Node<T>* prev = nullptr;
while(temp->next != nullptr){
prev = temp;
temp = temp->next;
delete prev;
}
delete temp;
}
}
template <typename T>
bool SinglyLinkedList<T>::isEmpty() {
return head == nullptr;
}
template <typename T>
void SinglyLinkedList<T>::insert(T item) {
Node<T>* p = new Node<T>(item);
p->next = head;
head = p;
count += 1;
}
template <typename T>
void SinglyLinkedList<T>::remove(T item) {
bool present = false;
if (head->data == item){
Node<T>* temp = head;
head = head->next;
delete(temp);
count -= 1;
return;
}
Node<T>* temp = head;
while (temp->next != nullptr){
if (temp->next->data == item){
Node<T>* removable = temp->next;
temp->next = temp->next->next;
delete(removable);
present = true;
count -= 1;
break;
} else{
temp = temp->next;
}
}
if(!present){
throw std::invalid_argument("item not present in list");
}
}
template <typename T>
int SinglyLinkedList<T>::length() {
return count;
}
template <typename T>
void SinglyLinkedList<T>::print() {
if(isEmpty()){
throw std::invalid_argument("Can't print an empty list!");
}
Node<T>* temp = head;
while(temp != nullptr){
if(temp->next != nullptr){
std::cout<<temp->data;
std::cout<<"->";
}else{
std::cout<<temp->data;
}
temp = temp->next;
}
std::cout<<std::endl;
}
#endif //LINKED_LIST_SINGLYLINKEDLIST_HPP
I've commented out the copy constructor code to make this compile. What is the correct way of doing this? I'm just learning C++.
One issue that introduces complexity is that it is not well defined what the copy constructor of a node should do? Should the next field of the copy point to the next of the original, or it should create a copy of the next and point to that? The former is inadequate and error-prone, the latter would recursively create a copy of the whole list, one node at a time. This will work for lists of small size but will cause stack overflow for lists with many elements due to the depth of the recursive calls.
So to keep things simple, I wouldn't bother with copy constructor of a node.
template <typename T>
class Node {
public:
T data;
Node* next = nullptr;
Node() = default;
Node(const Node&) = delete; // since copying is not well defined, make it impossible to copy a node.
};
Copying a list is a well defined operation, so implementing the copy constructor makes sense. A mistake with your current implementation is that you allocate a new node, only to leak it later (nothing keeps track of the newly allocated node p). What you need looks more like this:
template <typename T>
SinglyLinkedList<T>::SinglyLinkedList(const SinglyLinkedList<T>& source)
: head(nullptr)
, count(0)
{
// deal with the trivial case of empty list
if (source.head == nullptr)
return;
// deal with the case where count >= 1
head = new Node<T>;
head->data = source.head->data;
head->next = nullptr;
count = 1;
Node<T>* lastCopied = source.head; // last node to be copied
Node<T>* lastAdded = head; // last node to be added to the current list
while (lastCopied->next != nullptr)
{
// create new node
Node<T>* p = new Node<T>;
p->data = lastCopied->next->data;
p->next = nullptr;
// link the newly created node to the last of the current list
lastAdded->next = p;
lastAdded = p;
// advance lastCopied
lastCopied = lastCopied->next;
count++;
}
}
Now regarding the assignment operator, luckily you can use the 'copy and swap' idiom that greatly simplifies things.
template <typename T>
SinglyLinkedList<T>& SinglyLinkedList<T>::operator =(SinglyLinkedList<T> source) // note that you pass by value.
{
std::swap(head, source.head);
std::swap(count, source.count);
return *this;
}
My answer would become too long if I tried to explain the copy and swap technique. It is a clever trick to write exception safe code and avoid duplication (implements assignment by using the copy ctor) at the same time. It is worth reading about it here.
Btw, the declaration of your class should look like this
template <typename T>
class SinglyLinkedList
{
private:
Node<T>* head = nullptr;
std::size_t count = 0;
public:
SinglyLinkedList(const SinglyLinkedList& source);
SinglyLinkedList& operator=(SinglyLinkedList source);
// other members here...
};
PS. My code assumes you are using c++11 or a later standard.
I don't like the direction this is headed. I'm going to explain how to do this approach right because it is an excellent lesson on recursion, but because it's recursion it can run the program out of Automatic storage (march off the end of the stack, most likely) with a sufficiently large list. Not cool.
The logic:
Copying a node copies the next node if there is one. This looks something like
template <typename T>
Node<T>::Node(const Node<T>& source) : data(source.data)
{
if (source.next) // if there is a next, clone it
{
next = new Node<T>(*source.next);
}
else
{
next = nullptr;
}
}
This reduces the linked list copy constructor to
template <typename T>
SinglyLinkedList<T>::SinglyLinkedList(const SinglyLinkedList& source){
head = new Node<T>(*source.head); //clone the head. Cloning the head will clone everything after
count = source.count;
}
A helper function may, uh... help here to make the Node copy constructor a bit more idiomatic
template <typename T>
Node<T> * initnext(const Node<T> & source)
{
if (source.next)
{
return new Node<T>(*source.next);
}
else
{
return nullptr;
}
}
template <typename T>
Node<T>::Node(const Node<T>& source) : data(source.data),
next(initnext(source))
{
}
but I don't think you gain much.
So... I don't like the above. What would I do instead? Something a lot like opetroch's solution above, but different enough that I'll write this up.
The node stays brutally stupid. As far as I'm concerned all a Node should ever know is how to store the payload and find other Nodes. This means the linked list should do all of the heavy lifting.
Concept 1: head is nothing but a next pointer. Once you abstract away its differences, unimportant here, you can use it exactly the same way you would next.
Concept 2: If you only know where next points, you have to do a bunch of extra book-keeping to track the previous node to update it's next. But if you take advantage of the previous's next pointing to the current node, you can throw out even more code. By tracking the previous node's next you have all of the information you need.
Concept 3: If you keep a pointer to the previous node's next, you can update that previous node's next any time you want by dereferencing it.
template <typename T>
SinglyLinkedList<T>::SinglyLinkedList(const SinglyLinkedList& obj)
{
Node<T>* tocopy = obj.head;
Node<T>** nextpp = &head; // head is a next. We are now pointing to a pointer to next
while (tocopy) // keep looping until there is no next node to copy
{
*nextpp = new Node<T>(tocopy->data); // copy source and update destination's next
nextpp = &(*nextpp)->next; // advance to point at the next of the node we just added
tocopy= tocopy->next; // get next node to copy
}
count = obj.count;
}
Because this iterates rather than recurses it doesn't eat up Automatic storage (probably the stack) and can keep going until the cows come home.
This logic can also be applied to remove
template <typename T>
void SinglyLinkedList<T>::remove(T item) {
Node<T>** temp = &head; //head is nothing but a next pointer.
// by pointing to where the next is, we don't
// need to track a previous or have special handling
// for the head node
while (*temp){ // because we now have a pointer to a pointer, we need an
// extra dereference
if ((*temp)->data == item){
Node<T>* removable = *temp;
*temp = (*temp)->next;
delete(removable);
count -= 1;
return; // no need for any special magic. Just get out.
} else{
temp = &(*temp)->next; // update the pointer to the next
}
}
// if we got here the node was not found.
throw std::invalid_argument("item not present in list");
}
And following through on head is just a next, we can also gut the destructor:
template <typename T>
SinglyLinkedList<T>::~SinglyLinkedList() {
while(head){ // if head null, list empty
Node<T>* temp = head; // cache so we can delete
head = head->next; // move head
delete temp; //delete removed node
}
}

Stack Inheritance

I have just finished a project for Post Fix Notation(RPN) using stack. I am not having much luck with some of the compiler errors so I come to you guys while I work on debugging on my side also.
This file given to us. We are suppose to derive a stack class from it.
#ifndef ABSTRACTSTACK_H
#define ABSTRACTSTACK_H
#include <string>
using namespace std;
/* --------------- Class 'Oops' ---------------
Class
Thrown when an error is encountered.
Member 'm_msg' stores an error message.
*/
class Oops
{
string m_errormsg;
public:
Oops(string msg) : m_errormsg(msg) {}
const string& getMsg() const
{
return m_errormsg;
}
};
/* --------------- Abstract Class AbstractStack --------------- */
template < typename T >
class AbstractStack
{
public:
// Purpose: Checks if a stack is empty
// Returns: 'true' if the stack is empty
// 'false' otherwise
virtual bool isEmpty() const = 0;
// Purpose: looks at the top of the stack
// Returns: a const reference to the element currently on top of the stack
// Exception: if the stack is empty, THROW a 'Oops' object with an error message!!!
virtual const T& top() const throw ( Oops ) = 0;
// Purpose: push an element into the stack
// Parameters: x is the value to push into the stack
// Postconditions: x is now the element at the top of the stack,
virtual void push(const T& x) = 0;
// Purpose: pop the stack
// Postconditions: the element formerly at the top of the stack has
// been removed
// Note: Poping an empty stack results in an empty stack.
virtual void pop() = 0;
// Purpose: clears the stack
// Postconditions: the stack is now empty
virtual void clear() = 0;
};
#endif
Here is my derived class and it's implementation.
#ifndef STACK_H
#define STACK_H
#include<string>
#include<iostream>
#include<cstdlib>
#include "abstractstack.h"
using namespace std;
template<typename T>
struct Node
{
T Data;
Node<T>* next;
};
template<typename T>
class Stack : public AbstactStack<T>
{
private:
Node<T>* Top;
public:
//Purpose: Destructor
//Postconditions: The stack is now empty
~Stack() {};
//Purpose: Default Constructor
//Postconditions: Top is initialized to 'NULL'
Stack(); Top(NULL){};
//Overloaded = Operator
//Postconditions: *this is now equal to rhs
const Stack<T>& operator = (const Stack<T>& rhs);
//Purpose: Check if a stack is empty
//Returns: 'true' if the stakc is empty, 'false' otherwise
bool isEmpty() const;
//Purpose: Looks at the top of the stack
//Returns: a const reference to the element currently on top of the stack
//Exception: if the stack is empty, THROW a 'Oops' object with an error message!!!"
const T& top() const throw(Oops);
//Purpose: push an element into the stack
//Parameters: x is the value to push into the stack
//Postconditions: x is now the element at the top of the stack
void push(const T& x);
//Purpose: pop the stack
//Postconditions: the element formerly at the top of the stack has been removed
//Popping an empty stack results in an empty stack
void pop();
//Purpose: clears the stack
//Postconditions: the stack is now empty
void clear();
//Reverses the stack
//Postconditions: stack is now in reverse order
void reverse();
};
#include "stack.hpp"
#endif
Implementation (.hpp)
#include <string>
#include <iostream>
using namespace std;
template<typename T>
const Stack<T>& Stack<T>::operator = (const Stack<T>& rhs)
{
if (this != &rhs)
{
if (Top != NULL)
clear();
Node<T>* rhsPtr = rhs.Top;
Node<T>* copyPtr = Top = new Node<T>;
copyPtr->Data = rhsPtr->Data;
while (rhsPtr->next != NULL)
{
rhsPtr = rhsPtr->next;
copyPtr->next = new Node<T>;
copyPtr = copyPtr->next;
copyPtr->Data = rhsPtr->Data;
}
copyPtr->next = NULL;
}
return(*this)
}
template<typename T>
Stack<T>::Stack(const Stack<T>& rhs)
{
Top = NULL;
*this = rhs;
}
template<typename T>
bool Stack<T>::isEmpty()
{
return(Top == NULL);
}
template<typename T>
const T& top() const throw(Oops)
{
if (Top != NULL)
return(Top->Data);
else
throw Oops(Stack is Empty!);
}
template<typename T>
void Stack<T>::push(const T& x)
{
Node<T>* newNode = new Node;
newNode->Data = x;
if (isEmpty())
{
Top = newNode;
return;
}
newNode->next = Top;
Top->next = newNode;
}
template<typename T>
void Stack<T>::pop()
{
Node<T>* temp;
if (Top != NULL)
{
temp = Top;
Top = Top->next;
delete temp;
}
}
template<typename T>
void Stack<T>::clear()
{
Node<T>* temp;
while (Top != NULL)
{
temp = Top;
Top = Top->next;
delete temp;
}
}
template<typename T>
void Stack<T>::reverse()
{
Node<T>* current;
Node<T>* previous;
Node<T>* next;
previous = NULL;
current = Top;
while (current != NULL)
{
next = current->next;
current->next = previous;
previous = current;
current = next;
}
Top = previous;
}
The compiler is unhappy with my Stack class. "stack.h:25:34: error: expected template-name before ‘<’ token
class Stack : public AbstactStack
I've been told that I cannot inherit from Abstract because it is not a class but my professor tells me that it is fine and that I should add a forward declaration in my .cpp of Stack but I'm not sure how this goes. I know I am far from done but I would like to be able to solve at least this error so I can see if my program works correctly or not.
I posted my main program into Pastebin with its headers and implementation here in case it is needed. http://pastebin.com/1t2YGa2c
Seems to me that the problem that you are having is just a typo in the following line :
class Stack : public AbstactStack<T>
Change AbstactStack<T> to AbstractStack<T> and this should work.
The error you are getting explains that the class name before the character < should be a template, but since you made a typo in the name of the class, it does not recognize.
Make sure you read and understand the error messages! They are often very helpful when solving problems like these.
Little side note : If you take a look at your error messages, you'll see the filename where the error is, followed by the line number and the column number (stack.h:25:34). Very useful information when debugging.

Error on build but no compile errors

I am having some trouble with my homework and could use your help.
I am getting some sort of error when I try to run my program. When i compile it i get the success mssage but when i try to run it i get a popup with the error "Unhandled exception at 0x011b18d2 in Project 2.exe: 0xC0000005: Access violation reading location 0xccccccd0." If anyone can help me i would appreciate it, thank you.
This is the code i was assigned to build on (this cannot be changed)
#include <iostream >
#include "stack.h"
using namespace std ;
int main ()
{
Stack < int > s1 , s2 ;
int element ;
s1 . push (1); s1 . push (2); s1 . push (3);
s1 . pop ( element );
cout << " s1 popped element : " << element << endl ;
s2 = s1 ;
s2 . push (4);
s2 . pop ( element );
cout << " s2 popped element : " << element << endl ;
s1 . pop ( element );
cout << " s1 popped element : " << element << endl ;
s2 . makeEmpty ();
s2 . isEmpty () ? cout << " s2 is empty \n": cout << " s2 is not empty \n ";
system ("pause");
return 0;
}
This is what i wrote to compliment the code above
template <class DataType>
struct Node{
DataType info;
Node<DataType>*next;
};
template <class DataType>
class Stack
{
public:
Stack();
void push(DataType elementToPush);
bool pop(DataType & poppedElement);
bool peek(DataType & topElement);
Stack(const Stack<DataType> &element); // Copy constructor
~Stack(); // Destructor
Stack<DataType> & operator=(const Stack<DataType> &element); //Overload assignment operator
bool isEmpty()const;
void makeEmpty();
private:
Node<DataType>*top;
Node<DataType>*header;
inline void deepCopy(const Stack<DataType> & original);
};
template<class DataType>
Stack<DataType>::Stack()
{
Node<DataType>*top=new Node<DataType>;
}
template<class DataType> // Remove the node at the front of the list and return the element
bool Stack<DataType>::pop(DataType & poppedElement)
{
Node<DataType>*ptr=top;
ptr=ptr->next;
Node<DataType>*ptr2=ptr->next;
top->next=ptr2;
poppedElement = ptr->info;
delete ptr;
return true;
}
template<class DataType> // Return the element at the front of the list wothout deleting it
bool Stack<DataType>::peek(DataType & topElement)
{
if(top->next==NULL)
return false;
topElement=top->next->info;
return true;
}
template<class DataType> // Make a new node for the element and push it to the front of the list
void Stack<DataType>::push(DataType elementToPush)
{
Node<DataType>*ptr=top;
Node<DataType>*ptr2=new Node<DataType>;
ptr2->info=elementToPush;
ptr2->next=ptr->next;
ptr->next=ptr2;
}
template<class DataType> // Check to see if the list is empty
bool Stack<DataType>::isEmpty()const
{
return top->next==NULL;
}
template<class DataType> // Empry the list out
void Stack<DataType>::makeEmpty()
{
Node<DataType>*ptr=top;
while(top->next != NULL)
{
while(ptr->next != NULL)
ptr->next;
delete ptr->next;
}
}
template<class DataType> // Deep copy
inline void Stack<DataType>::deepCopy(const Stack<DataType> & original)
{
Node<DataType>*copyptr=new Node<DataType>;
Node<DataType>*originalptr=top;
while(originalptr != NULL)
{
originalptr=originalptr->next;
copyptr->next=new Node<DataType>;
copyptr->info=originalptr->info;
}
}
template<class DataType> // Copy Constructor
Stack<DataType>::Stack(const Stack<DataType> &element)
{
deepCopy(element);
}
template<class DataType> // Destructor
Stack<DataType>::~Stack()
{
makeEmpty();
}
template<class DataType> // Overload assignment operator
Stack<DataType> & Stack<DataType>::operator=(const Stack<DataType> &element)
{
if(this == &element)
return *this;
makeEmpty();
deepCopy(element);
return *this;
}
I got pushback on my previous answer. Maybe this one will be better received. If you don't like my choice of white space, that is what pretty-printers are for. The code below is the original code reformatted. My thoughts are included as interlinear gloss.
Node is an implementation detail of your Stack. It should be scoped as a private type declaration, putting here pollutes the namespace. Also, if this class had a constructor that either initialized next to nullptr or required it to be set explicitly, some bugs, such as the one you found, would be easier to diagnose. As it stands, after Node is constructed, next can point to a random memory location.
template <class DataType>
struct Node {
DataType info;
Consider using a smart pointer here.
Node<DataType>* next; };
template <class DataType>
class Stack {
public:
Stack();
The argument should be const& to avoid extra copying.
void push(DataType elementToPush);
bool pop(DataType& poppedElement);
This can be a const method.
bool peek(DataType& topElement);
element is a poor name. The copy constructor copies an entire stack, not just an element.
Stack(const Stack<DataType>& element); // Copy constructor
~Stack(); // Destructor
Stack<DataType>& operator=(const Stack<DataType>&
element); //Overload assignment operator
bool isEmpty() const;
void makeEmpty();
private:
Consider using a smart pointer here.
Node<DataType>* top;
header is not used. It should be deleted.
Node<DataType>* header;
inline void deepCopy(const Stack<DataType>& original); };
template<class DataType>
Stack<DataType>::Stack() {
top should be initialized to nullptr in a member initialization list. The empty node you
are using here is not required, it makes you code more complex, and you end up leaking it later.
Also, this is a major bug. You are assigning to a local here, not the member variable!
Node<DataType>* top = new Node<DataType>; }
template<class DataType> // Remove the node at the front of the list and return the element
bool Stack<DataType>::pop(DataType& poppedElement) {
If you want ptr to be top->next just say that.
Node<DataType>* ptr = top;
ptr = ptr->next;
This ptr2 variable is not needed. You just need top->next = top->next->next. Also note that the empty head element is adding noise here.
Node<DataType>* ptr2 = ptr->next;
top->next = ptr2;
poppedElement = ptr->info;
delete ptr;
You need to have tested for underflow to return false in that case.
return true; }
People are pretty forgiving about comments, but it is best if they are properly spelled and punctuated.
template<class DataType> // Return the element at the front of the list wothout deleting it
bool Stack<DataType>::peek(DataType& topElement) {
if (top->next == NULL) {
return false; }
topElement = top->next->info;
return true; }
template<class DataType> // Make a new node for the element and push it to the front of the list
void Stack<DataType>::push(DataType elementToPush) {
This variable is meaningless, just use top.
Node<DataType>* ptr = top;
ptr2 can be constructed with the values you need instead of being mutated afterwards. Try auto ptr2 = new Node<DataType> { elementToPush, ptr->next };. Also, consider using a smart pointer.
Node<DataType>* ptr2 = new Node<DataType>;
ptr2->info = elementToPush;
ptr2->next = ptr->next;
ptr->next = ptr2; }
template<class DataType> // Check to see if the list is empty
bool Stack<DataType>::isEmpty()const {
return top->next == NULL; }
This function is just broken. You need to rethink it.
template<class DataType> // Empry the list out
void Stack<DataType>::makeEmpty() {
Node<DataType>* ptr = top;
while (top->next != NULL) {
One while loop will do you. Lists are linear, not square.
while (ptr->next != NULL) {
This statement has no effect; it does nothing. Your compiler should be warning about that, turn on warnings, or turn the warning level up.
ptr->next; }
delete ptr->next; } }
This is very broken too. You need to iterate over two lists, so you need two iterator variables. One iterator is the stuff you are copying and just needs to be bumped along as you read it. The other is mutating the current object and has slightly more book keeping.
template<class DataType> // Deep copy
inline void Stack<DataType>::deepCopy(const Stack<DataType>& original) {
Node<DataType>* copyptr = new Node<DataType>;
Node<DataType>* originalptr = top;
while (originalptr != NULL) {
originalptr = originalptr->next;
copyptr->next = new Node<DataType>;
copyptr->info = originalptr->info; } }
template<class DataType> // Copy Constructor
Stack<DataType>::Stack(const Stack<DataType>& element) {
deepCopy(element); }
template<class DataType> // Destructor
Stack<DataType>::~Stack() {
Note that makeEmpty does not delete your empty head node. This will leak a node.
makeEmpty(); }
template<class DataType> // Overload assignment operator
Stack<DataType>& Stack<DataType>::operator=(const Stack<DataType>&
element) {
if (this == &element) {
return *this; }
makeEmpty();
Again, your empty head node is causing pain here. Does deepCopy create the empty head node or not? Your use of it in your copy constructor seems to assume it does. Your use of it here seems to assume it does not. In fact, I think the problem is that makeEmpty does not delete your head node, if it did, both this function and your destructor would work properly.
deepCopy(element);
return *this; }
What you are seeing is a run-time error, not a build error. And your IDE reports a successful build, not your debugger. Your debugger is what allows you to trace through the program line-by-line and inspect the values of your variables.
Compare your code to the following.
template <class DataType>
struct Node {
DataType info;
Node<DataType>* next; };
template <class DataType>
class Stack {
public:
Stack();
void push(DataType elementToPush);
bool pop(DataType& poppedElement);
bool peek(DataType& topElement);
Stack(const Stack<DataType>& element);
~Stack();
Stack<DataType>& operator=(const Stack<DataType>& element);
bool isEmpty()const;
void makeEmpty();
private:
Node<DataType>* top;
inline void deepCopy(const Stack<DataType>& original); };
// Linked list stack implementation.
template<class DataType>
Stack<DataType>::Stack() {
// Head of the list. Not actually used for anything. Why is this here?
top = new Node<DataType>; }
// Remove the node at the front of the list and return the element
// Does not check for underflow.
template<class DataType>
bool Stack<DataType>::pop(DataType& poppedElement) {
Node<DataType>* ptr = top->next;
Node<DataType>* ptr2 = ptr->next;
top->next = ptr2;
poppedElement = ptr->info;
delete ptr;
return true; }
// Return the element at the front of the list without deleting it
template<class DataType>
bool Stack<DataType>::peek(DataType& topElement) {
if (top->next == NULL) {
return false; }
topElement = top->next->info;
return true; }
// Make a new node for the element and push it to the front of the list
template<class DataType>
void Stack<DataType>::push(DataType elementToPush) {
Node<DataType>* ptr2 = new Node<DataType>;
ptr2->info = elementToPush;
ptr2->next = top->next;
top->next = ptr2; }
// Check to see if the list is empty
template<class DataType>
bool Stack<DataType>::isEmpty()const {
return top->next == NULL; }
// Empty the list out
template<class DataType>
void Stack<DataType>::makeEmpty() {
while (top->next != NULL) {
Node<DataType>* ptr = top->next;
top->next = ptr->next;
delete ptr; } }
// Deep copy
template<class DataType>
inline void Stack<DataType>::deepCopy(const Stack<DataType>& original) {
Node<DataType>* origiter = original.top;
Node<DataType>* thisiter = top;
while (origiter->next != NULL) {
thisiter->next = new Node<DataType>(*(origiter->next));
origiter = origiter->next;
thisiter = thisiter->next; }
thisiter->next = NULL; }
// Copy Constructor
template<class DataType>
Stack<DataType>::Stack(const Stack<DataType>& element) {
deepCopy(element); }
// Destructor
template<class DataType>
Stack<DataType>::~Stack() {
// This leaks because the head node is still there.
makeEmpty(); }
// Overload assignment operator
template<class DataType>
Stack<DataType>& Stack<DataType>::operator=(const Stack<DataType>&
element) {
if (this == &element) {
return *this; }
makeEmpty();
deepCopy(element);
return *this; }