If i have a big text, and i'm needind to keep only matched content, how can i do that?
For example, if I have a text like this:
asdas8Isd8m8Td8r
asdia8y8dasd
asd8is88n8gd
asd8t8od8lsdas
as9ea9ad8r1n88r8e87g6765ejasdm8x
And use this regex: [0-9]([a-z]) to group all letters after a number and replace with \1 i will repace all (number)(letter) to (letter) (And if i want to delete the rest and stay only with the letter matched)?...
Converting this text to
ImTr
y
ing
tol
earnregex
How can i replace this text with grouped and delete the rest?
And if i want to delete all but no matched?
In this case, converting the text to:
8I8m8T8r
8y8d
8i8n8g
8t8o8l
9e9a9r1n8r7g5e8x
Can i match all that is not [0-9]([a-z])?
Thanks! :D
You may use the following regex:
(?i-s)[0-9]([a-z])|.
Replace with (?{1}$1:).
To delete all but non-matched, use the (?{1}$0:) replacement with the same regex.
Details:
(?i-s) - an inline modifier turning on case insensitive mode and turning off the DOTALL mode (. does not match a newline)
[0-9]([a-z]) - an ASCII digit and any ASCII letter captured into Group 1 (later referred to with $1 or \1 backreference from the string replacement pattern)
| - or
. - any char but a line break char.
Replacement details
(?{1} - start of the conditional replacement: if Group 1 matched then...
$1 - the contents of Group 1 (or the whole match if $0 backreference is used)
: - else... nothing
) - end of the conditional replacement pattern.
Related
I only have access to a function that can match a pattern and replace it with some text:
Syntax
regexReplace('text', 'pattern', 'new text'
And I need to return only the 5 digit string from text in the following format:
CRITICAL - 192.111.6.4: rta nan, lost 100%
Created Time Tue, 5 Jul 8:45
Integration Name CheckMK Integration
Node 192.111.6.4
Metric Name POS1
Metric Value DOWN
Resource 54871
Alert Tags 54871, POS1
So from this text, I want to replace everything with "" except the "54871".
I have come up with the following:
regexReplace("{{ticket.description}}", "\w*[^\d\W]\w*", "")
Which almost works but it doesn't match the symbols. How can I change this to match any word that includes a letter or symbol, essentially.
As you can see, the pattern I have is very close, I just need to include special characters and letters, whereas currently it is only letters:
You can match the whole string but capture the 5-digit number into a capturing group and replace with the backreference to the captured group:
regexReplace("{{ticket.description}}", "^(?:[\w\W]*\s)?(\d{5})(?:\s[\w\W]*)?$", "$1")
See the regex demo.
Details:
^ - start of string
(?:[\w\W]*\s)? - an optional substring of any zero or more chars as many as possible and then a whitespace char
(\d{5}) - Group 1 ($1 contains the text captured by this group pattern): five digits
(?:\s[\w\W]*)? - an optional substring of a whitespace char and then any zero or more chars as many as possible.
$ - end of string.
The easiest regex is probably:
^(.*\D)?(\d{5})(\D.*)?$
You can then replace the string with "$2" ("\2" in other languages) to only place the contents of the second capture group (\d{5}) back.
The only issue is that . doesn't match newline characters by default. Normally you can pass a flag to change . to match ALL characters. For most regex variants this is the s (single line) flag (PCRE, Java, C#, Python). Other variants use the m (multi line) flag (Ruby). Check the documentation of the regex variant you are using for verification.
However the question suggest that you're not able to pass flags separately, in which case you could pass them as part of the regex itself.
(?s)^(.*\D)?(\d{5})(\D.*)?$
regex101 demo
(?s) - Set the s (single line) flag for the remainder of the pattern. Which enables . to match newline characters ((?m) for Ruby).
^ - Match the start of the string (\A for Ruby).
(.*\D)? - [optional] Match anything followed by a non-digit and store it in capture group 1.
(\d{5}) - Match 5 digits and store it in capture group 2.
(\D.*)? - [optional] Match a non-digit followed by anything and store it in capture group 3.
$ - Match the end of the string (\z for Ruby).
This regex will result in the last 5-digit number being stored in capture group 2. If you want to use the first 5-digit number instead, you'll have to use a lazy quantifier in (.*\D)?. Meaning that it becomes (.*?\D)?.
(?s) is supported by most regex variants, but not all. Refer to the regex variant documentation to see if it's available for you.
An example where the inline flags are not available is JavaScript. In such scenario you need to replace . with something that matches ALL characters. In JavaScript [^] can be used. For other variants this might not work and you need to use [\s\S].
With all this out of the way. Assuming a language that can use "$2" as replacement, and where you do not need to escape backslashes, and a regex variant that supports an inline (?s) flag. The answer would be:
regexReplace("{{ticket.description}}", "(?s)^(.*\D)?(\d{5})(\D.*)?$", "$2")
If i have a big text, and i'm needind to keep only matched content, how can i do that?
For example, if I have a text like this:
asdas8Isd8m8Td8r
asdia8y8dasd
asd8is88n8gd
asd8t8od8lsdas
as9ea9ad8r1n88r8e87g6765ejasdm8x
And use this regex: [0-9]([a-z]) to group all letters after a number and replace with \1 i will repace all (number)(letter) to (letter) (And if i want to delete the rest and stay only with the letter matched)?...
Converting this text to
ImTr
y
ing
tol
earnregex
How can i replace this text with grouped and delete the rest?
And if i want to delete all but no matched?
In this case, converting the text to:
8I8m8T8r
8y8d
8i8n8g
8t8o8l
9e9a9r1n8r7g5e8x
Can i match all that is not [0-9]([a-z])?
Thanks! :D
You may use the following regex:
(?i-s)[0-9]([a-z])|.
Replace with (?{1}$1:).
To delete all but non-matched, use the (?{1}$0:) replacement with the same regex.
Details:
(?i-s) - an inline modifier turning on case insensitive mode and turning off the DOTALL mode (. does not match a newline)
[0-9]([a-z]) - an ASCII digit and any ASCII letter captured into Group 1 (later referred to with $1 or \1 backreference from the string replacement pattern)
| - or
. - any char but a line break char.
Replacement details
(?{1} - start of the conditional replacement: if Group 1 matched then...
$1 - the contents of Group 1 (or the whole match if $0 backreference is used)
: - else... nothing
) - end of the conditional replacement pattern.
If i have a big text, and i'm needind to keep only matched content, how can i do that?
For example, if I have a text like this:
asdas8Isd8m8Td8r
asdia8y8dasd
asd8is88n8gd
asd8t8od8lsdas
as9ea9ad8r1n88r8e87g6765ejasdm8x
And use this regex: [0-9]([a-z]) to group all letters after a number and replace with \1 i will repace all (number)(letter) to (letter) (And if i want to delete the rest and stay only with the letter matched)?...
Converting this text to
ImTr
y
ing
tol
earnregex
How can i replace this text with grouped and delete the rest?
And if i want to delete all but no matched?
In this case, converting the text to:
8I8m8T8r
8y8d
8i8n8g
8t8o8l
9e9a9r1n8r7g5e8x
Can i match all that is not [0-9]([a-z])?
Thanks! :D
You may use the following regex:
(?i-s)[0-9]([a-z])|.
Replace with (?{1}$1:).
To delete all but non-matched, use the (?{1}$0:) replacement with the same regex.
Details:
(?i-s) - an inline modifier turning on case insensitive mode and turning off the DOTALL mode (. does not match a newline)
[0-9]([a-z]) - an ASCII digit and any ASCII letter captured into Group 1 (later referred to with $1 or \1 backreference from the string replacement pattern)
| - or
. - any char but a line break char.
Replacement details
(?{1} - start of the conditional replacement: if Group 1 matched then...
$1 - the contents of Group 1 (or the whole match if $0 backreference is used)
: - else... nothing
) - end of the conditional replacement pattern.
I need to check occurrences where I have put one whitespace after a full-stop, and replace it by 2 spaces. I have the Regex for it, but Atom seems to call in invalid.
(?<=\.|\") {1,}(?=[a-zA-Z])
Conditions:
1 spaces after period.
If period in with a closing double quote, then 1 space after the quote.
The above regex works perfectly for my conditions however Atom is not able to validate it. I need to use it for existing files.
You may use
([."]) ([a-zA-Z])
and replace with $1 $2. See the regex demo and a regex graph:
Details
([."]) - Group 1 (its value is referred to with $1 backreference from the replacement pattern): . or "
- a space (use \s to match any whitespace)
([a-zA-Z]) - Group 2 ($2): an ASCII letter.
If i have a big text, and i'm needind to keep only matched content, how can i do that?
For example, if I have a text like this:
asdas8Isd8m8Td8r
asdia8y8dasd
asd8is88n8gd
asd8t8od8lsdas
as9ea9ad8r1n88r8e87g6765ejasdm8x
And use this regex: [0-9]([a-z]) to group all letters after a number and replace with \1 i will repace all (number)(letter) to (letter) (And if i want to delete the rest and stay only with the letter matched)?...
Converting this text to
ImTr
y
ing
tol
earnregex
How can i replace this text with grouped and delete the rest?
And if i want to delete all but no matched?
In this case, converting the text to:
8I8m8T8r
8y8d
8i8n8g
8t8o8l
9e9a9r1n8r7g5e8x
Can i match all that is not [0-9]([a-z])?
Thanks! :D
You may use the following regex:
(?i-s)[0-9]([a-z])|.
Replace with (?{1}$1:).
To delete all but non-matched, use the (?{1}$0:) replacement with the same regex.
Details:
(?i-s) - an inline modifier turning on case insensitive mode and turning off the DOTALL mode (. does not match a newline)
[0-9]([a-z]) - an ASCII digit and any ASCII letter captured into Group 1 (later referred to with $1 or \1 backreference from the string replacement pattern)
| - or
. - any char but a line break char.
Replacement details
(?{1} - start of the conditional replacement: if Group 1 matched then...
$1 - the contents of Group 1 (or the whole match if $0 backreference is used)
: - else... nothing
) - end of the conditional replacement pattern.