I have some text containing . A....
The regex is [.][\s][\s][!A-Z]
This finds the containing string. The problem is, that I don't know how to replace all of it with \n except the [A-Z]
You can use grouping and back refer to them by \1, \2, etc.
Change your regex to [.][\s][\s]([!A-Z]) and replace it with \n\1
Related
In a regular expression (notepad++), I want to search for:( )|(:)|(_)|(\.), and to insert \ before to, as above, a blank space, colon, under line and ".".
Search example: abcd:1234 jiod.8ufd_adfd
Result: abcd\:1234\ jiod\.8ufd\_adfd
Briefly, how can I refer to what was found in the replace expression?
Note that it is not \1, \2, \3 or \4 in the example, as I need to include what was found, there is no way to know which was found, is there?
You can use a single character class (instead of using the alternation with capturing groups) to match one of the listed
In the replacement use $& to refer to the matched text and prepend a backslash.
Match
[:\h._]
Replace with
\\$&
The character class matches either a colon, horizontal whitespace char, dot or underscore.
Regex demo
There's no such thing as insert, because if you think about it, inserting is just replacing the original with a new string that contains the old text as well.
Try this instead: search for ([ :_.]) (your original regex is pointlessly complicated) and replace with \\$1 (ie, slash followed by the original text).
How to find the text between the second and fourth slashes in a path like /folder/subfolder-1/subfolder-2/subfolder-3? I’m trying to replace this with something like /folder/new-folder/subfolder-3.
The most important for me is to be able to find the part after the n-th slash.
I tried the regex /((.*?)/){3}, but it doesn’t work.
Using Match resetter \K meta-character you are able to do it in a simpler way.
Find:
/.*?/\K(.*?/){2}
Replace with:
new-folder/
One way you could to it is by using this string in the pattern to replace
(/.+?)(/.+?){2}(/\S+)
And use this one in your pattern to replace it with
$1/new-folder$3
From your string:
/folder/subfolder-1/subfolder-2/subfolder-3
(/.+?) will match /folder as $1
(/.+?){2} will match /subfolder-1/subfolder-2 as $2 (not used)
(/\S+) will match everything that isn't a space, in this case/subfolder-3 as $3
Leaving you room to insert your new-folder in-between.
How can I just mark till the slash?
Find what: (/[^/]+/)[^/]+/[^/]+
Replace with: $1new-folder
To find text between second and forth slash you can use the regex ^(/[^/]*/)([^/]*/[^/]*) then you can reference to the text between slashes with \2 when replacing the text.
To keep the text before the slashes you can enter something like \1myNewTextBetweenSlashes2and4.
In notepad++ Find by this:
(/[^/]+)(?:/[^/]+/[^/]+/)(.*)
And Replace by this:
\1\/new-folder/\2
Make sure that: .matches newline is not checked
{2} indicates 2 levels after first level will be repalced by new-folder
Find:
(\/.*?\/)(.*?\/){2}(.*)
Replace:
$1new-folder/$3
Demo: https://regex101.com/r/XIA3IN/3
I have something in a text file that looks like '%r'%XXXX, where the XXXX represents some name at the end. Examples include '%r'%addR or '%r'%removeA. I can match these patterns using regex '%r'%\w+. What I would like to replace this with is '{!r}'.format(XXXX). Note that the name has to stay the same in the replace so I'd get '{!r}.format(addR) or '{!r}.format(removeA). Is there a way to replace parts of the matched string in this way while retaining the unknown variable name pulled out with \w+ in the regex search?
I'm specifically looking for a solution using the find and replace features in Notepad++.
You can use
'%r'%(\w+)
and replace with '{!r}.format\(\1\)
The '%r'%(\w+) pattern contains a pair of unescaped parentheses that create a capturing group. Inside the replacement pattern, we use a \1 backreference to restore that value.
NOTE: The ( and ) in the replacement must be escaped because otherwise they are treated as Boost conditional replacement pattern functional characters.
See more on capturing groups and backreferences.
Search on:
'%r'%(XXXX)
Replace with:
Whatever You like \1
\1 will match the first set of grouping parentheses.
I'm using this regex:
\s[0-9]+ thd
It finds what I want perfectly. I want to remove the white space at the beginning. What should I put in the replace field?
Change the search text to \s([0-9]+ thd) and then the replacement id \1 or $1 depending on the type of regex.
Find:
\s([0-9]+ thd)
Replace:
$1
So if you using Notepad++ everything in parenthesis refers to section build from \ and number in Replace box.
Look at example:
Find: (\s)([0-9]+ thd)
Replace: \1\2
This give you back first \1 and second \2 section - nothing unusual, but when you live only \2 after replace you'll get only part found by ([0-9]+ thd)
Going further if you split your expression to (\s)([0-9]+)(\s)(thd) then you'll get 4 parts
This parts will be represented by \1\2\3\4 and if you need add something more to your output line:
for example added_text_before\1added_text_after in Replace will result merging added text and section found - practice because there is no hidden magic out there.
Remember that using regex in Notepad++ have some limitations (to long expression aren't read).
How to append and prepend a character at start and end of each file line?
I have this file structure:
140","Bosnia
160","Croatia
170","Serbia
180","Montenegro
200","Slovenia
What I need is to add a double quote " at the start and at the end of each file line, using regular expressions in Notepad++ editor.
Thanks!
Just search for
(.*)
and replace with
"\1"
with regular expression option activated. Regular expressions are working only on a row bases, so (.*) matches the complete row and because of the brackets around you can access the match using \1.
Try searching ^(.*)$ and replacing by "$1".
bye ;)
You can match the whole, even an empty line, with
^.*$
You can match a non-empty line with
^.+$
You may match a non-blank line with
^\h*\S.*$
Now, all you need to do to wrap these lines with any text of your choice, you need to use the backreference to the whole match (see Replace with whole match value using Notepad++ regex search and replace):
"$0"
"$&"
"$MATCH"
"${^MATCH}"
If you need to wrap the whole line with parentheses, you will need to escape them since ( and ) are "special" in the Notepad++ replacement pattern, \($&\).
Whenever you need to insert a backslash, make sure you double it, \\$&\\.