Multi Taxonomy URL rewrite not wokring - regex

I am trying to rewrite WP URL and here is the URL:
http://example.com/?job_listing_region=california&job_listing_category=wordpress
I want to change it as http://example.com/california/wordpress
I tried this:
add_rewrite_rule('([^/]*)/([^/]*)/?','job_listing_region=$matches[1]&job_listing_category=$matches[2]','top');
But its not working. Sorry I am not good at regex it might be a small one but I am not able to find a solution. Thanks in advance

Code
See regex in use here
Regex
\??\w+=([^&]+)&?
Replacement
$1/
Results
Input
http://example.com/?job_listing_region=california&job_listing_category=alcohol-abuse-programs
Output
http://example.com/california/alcohol-abuse-programs/
Explanation
Regex
\?? Match between zero and one of the ? character literally
\w+= Match any word character one or more times, followed by the = character literally (\w can be replaced with [a-zA-Z0-9_] if preferred/doesn't work in your regex flavour)
([^&]+) Capture into capture group 1 any character except the & character literally one or more times
&? Match between zero and one & character literally
Replacement
$1/ Matches the same text as most recently matched by the 1st capturing group, followed by a / literally

Using http://example.com/{job_listing_region}/{job_listing_category}/ is too broad - it would affect every single URL on your website, such as /wp-admin.
I'd recommend using http://example.com/jobs/{job_listing_region}/{job_listing_category}/ as your URL structure, in which case the rewrite rule would be set as follows:
add_rewrite_rule('^jobs/([^/]*)/([^/]*)/?','index.php?page_id=1234&job_listing_region=$matches[1]&job_listing_region=$matches[2]','top');
page_id should be set to the page ID of the page/post you'd like to route this to.
It's important to note that the rewrite might not be available until you view/save the Settings -> Permalinks page in the back end.

Thanks for the above answer, they helped me to get an solution finally.
So while passing url strings to wordpress we need to register the variables in functions.php and then instead of using php get we need to use wordpress var queries to get the urls.
As suggested by #athms above, I changed url structure.
Now "wordpress" is a wordpress page in which the query variables are captured.
So my URL is http://example.com/wordpress/?job_listing_region=california
In functions.php I registered these variables:
function custom_query_vars_filter($vars) {
$vars[] = 'job_listing_region';
return $vars;
}
add_filter( 'query_vars', 'custom_query_vars_filter' );
function custom_rewrite_tag1() {
add_rewrite_tag('%job_listing_region%', '([^&]+)');
}
add_action('init', 'custom_rewrite_tag1', 10, 0);
Rewrite Rule in functions.php:
function custom_rewrite_rule3() {
add_rewrite_rule('^wordpress/([^/]*)/?','index.php?page_id=35349&state=$matches[1]','top');
}
add_action('init', 'custom_rewrite_rule3', 10, 0);
Here page id is the id of page I created i.e "wordpress"
And in the page template for "wordpress" I captured the region using:
$region = get_query_var('job_listing_region');
Now you can pass this variable to your query.
So now you can start using this pretty URL:
http://example.com/wordpress/california
The end of URL california is taken as query string and can be used in our template.

Related

GA Regex Filter - Filter PPC traffic and replace it with "PPC"

1) www.mysite.site/product/brand?card_type=all
2) www.mysite.site/product/brand?card_type=all&cp=randomID&keyword=randomKeyword&network=randomNetwork&v3=sometype&v4=MM
So I have these 2 types of URLs being reported on my Analytics being:
Traffic that went on that page organically
Traffic that went on that page via Paid Traffic
I need to basically find all the links that have a "&" followed by (cp|keyword|v1|v2|v3|v5) after the value for “card_type” and replace it with “ppc-traffic” - so ideally would have :
www.mysite.site/product/brand?card_type=all
www.mysite.site/product/brand/ppctraffic or just mysite.site/ppctraffic
What I attempted:
Search String
Request URI
^(https?:\/\/\S+\/[^?]*)(.*?)&(cp|keyword|v1|v2|v3|v5)
Replace String:
/ppctraffic
(I’ve also tried $1/ppctraffic and $2/ppctraffic)
When testing the regex online it seems to work so not sure what Im doing wrong.
Any help deeply appreciated
One way is to capture in a group upon /brand matching not a question mark [^?]+ and match ?card_type=all& afterwards followed by any character until the end of the string.
As your links do not start with https:// you could make that part optional (?:https?:\/\/)?.
^((?:https?:\/\/)?www\.[^?]+)\?card_type=all&(?:cp|keyword|v[1235]).*$
Then in the replacement use $1/ppctraffic
Regex demo
const pattern = /^((?:https?:\/\/)?www\.[^?]+)\?card_type=all&(?:cp|keyword|v[1235]).*$/;
[
"www.mysite.site/product/brand?card_type=all&cp=randomID&v1=randomIDv2=productName&v3=sometype&v4=MM&fbclid=randomID",
"www.mysite.site/product/brand?card_type=all",
"www.mysite.site/product/brand?card_type=all&aa=randomID&v1=randomIDv2=productName&v3=sometype&v4=MM&fbclid=randomID"
].forEach(s => console.log(s.replace(pattern, "$1/ppctraffic")));

JMeter extract link using regular expression pass into next request with blank values

This is how I have Test Plan set up:
HTTP Request -> Regular Expression Extractor to extract multiple links - This is extracting correctly -- But some of the links are Blank
RegularExpressionExtractor --- <a href="(.*)" class="product-link">
BeanShell Sampler - to filter blank or null values -- This works fine
BeanShell Sampler
log.info("Enter Beanshell Sampler");
matches = vars.get("url_matchNr");
log.info(matches);
for (Integer i=1; i < Integer.parseInt(matches); i++)
{
String url = vars.get("url_"+i);
//log.info(url1);
if(url != null #and url.length() > 0)
{
log.info(i+"->" + url);
//return url;
//vars.put("url2", url);
vars.put("url2", url);
//props.put("url2", url);
log.info("URL2:" + vars.get("url2"));
}
}
ForEach Controller
ForEach Controller
Test Plan
The problem I am facing is ForEach Controller runs through all the values including Blank or NULL -- How can I run the loop only for the non null blank values
You should change your regular expression to exclude empty value
Instead of using any value including empty using * sign
<a href="(.*)" class="product-link">
Find only not empty strings using + sign:
<a href="(.+)" class="product-link">
As mentioned earlier, you should change your regex!
you can replace it directly by
<a href="(.+)" class="product-link">
or by something more constraining like this:
<a href="^((https?:\/\/)?([\da-z\.-]+)\.([a-z\.]{2,6})([\/\w \.-]*)*\/?)$" class="product-link">
which is a regex to match only URLs.
https://code.tutsplus.com/tutorials/8-regular-expressions-you-should-know--net-6149
The first capturing group is all option. It allows the URL to begin
with "http://", "https://", or neither of them. I have a question mark
after the s to allow URL's that have http or https. In order to make
this entire group optional, I just added a question mark to the end of
it.
Next is the domain name: one or more numbers, letters, dots, or hypens
followed by another dot then two to six letters or dots. The following
section is the optional files and directories. Inside the group, we
want to match any number of forward slashes, letters, numbers,
underscores, spaces, dots, or hyphens. Then we say that this group can
be matched as many times as we want. Pretty much this allows multiple
directories to be matched along with a file at the end. I have used
the star instead of the question mark because the star says zero or
more, not zero or one. If a question mark was to be used there, only
one file/directory would be able to be matched.
Then a trailing slash is matched, but it can be optional. Finally we
end with the end of the line.
String that matches:
http://net.tutsplus.com/about
String that doesn't match:
http://google.com/some/file!.html (contains an exclamation point)
Good luck!!!
ForEach controller doesn't work with JMeter Properties, you need to change the "Input Variable Prefix" to url_2 and your test should start working as expected.
Also be aware that since JMeter 3.1 it is recommended to use Groovy language for any form of scripting so consider migrating to JSR223 Sampler and Groovy language on next available opportunity.
Groovy has much better performance while Beanshell might become a bottleneck when it comes to immense loads.

RegEx pattern to handle URL with dates

I moved to a new website and it mangled up my URL's. Now blog posts are accessible from multiple URL's and would like to redirect one pattern to the other.
I am trying to redirect the first case to the second case:
~/blogs/johndoe/john-doe/2014/03/14/test-article1 =>
~/blogs/john-doe/2014/03/14/test-article1
~/blogs/jimjones/jim-jones/2014/03/14/test-articleb =>
~/blogs/jim-jones/2014/03/14/test-articleb
How do I create a pattern smart enough to slice out the first "johndoe" and "jimjones"? I am using this for IIS rewrite but I think any RegEx should work. Thanks for any help.
This works:
^~/blogs/\w+/(\w+)-(\w+)/(\d{4})/(\d\d)/(\d\d)/([\w-]+)$
Debuggex Demo
It just discards the non-dash name. It doesn't know if its equal to the dash name or not. And it also assumes that the date numbers are valid. 9899/45/33 would be matched.
Capture groups:
First name
Last name
Year
Month
Day
Article name
I don't know about IIS rewrites, but this should work:
/^~/blogs\/[a-z]+\/ -> ~/blogs/
The regular expression will match the start of a string, following by ~/blogs/, followed by a string of all lowercase characters.
I don't use IIS, but this should be at least close.
Pattern:
^blogs/\w+/(\w+/)
Action
blogs/{R:1}
Handy usage doc

Regex to match anything after /

I'm basically not in the clue about regex but I need a regex statement that will recognise anything after the / in a URL.
Basically, i'm developing a site for someone and a page's URL (Local URL of Course) is say (http://)localhost/sweettemptations/available-sweets. This page is filled with custom post types (It's a WordPress site) which have the URL of (http://)localhost/sweettemptations/sweets/sweet-name.
What I want to do is redirect the URL (http://)localhost/sweettemptations/sweets back to (http://)localhost/sweettemptations/available-sweets which is easy to do, but I also need to redirect any type of sweet back to (http://)localhost/sweettemptations/available-sweets. So say I need to redirect (http://)localhost/sweettemptations/sweets/* back to (http://)localhost/sweettemptations/available-sweets.
If anyone could help by telling me how to write a proper regex statement to match everything after sweets/ in the URL, it would be hugely appreciated.
To do what you ask you need to use groups. In regular expression groups allow you to isolate parts of the whole match.
for example:
input string of: aaaaaaaabbbbcccc
regex: a*(b*)
The parenthesis mark a group in this case it will be group 1 since it is the first in the pattern.
Note: group 0 is implicit and is the complete match.
So the matches in my above case will be:
group 0: aaaaaaaabbbb
group 1: bbbb
In order to achieve what you want with the sweets pattern above, you just need to put a group around the end.
possible solution: /sweets/(.*)
the more precise you are with the pattern before the group the less likely you will have a possible false positive.
If what you really want is to match anything after the last / you can take another approach:
possible other solution: /([^/]*)
The pattern above will find a / with a string of characters that are NOT another / and keep it in group 1. Issue here is that you could match things that do not have sweets in the URL.
Note if you do not mind the / at the beginning then just remove the ( and ) and you do not have to worry about groups.
I like to use http://regexpal.com/ to test my regex.. It will mark in different colors the different matches.
Hope this helps.
I may have misunderstood you requirement in my original post.
if you just want to change any string that matches
(http://)localhost/sweettemptations/sweets/*
into the other one you provided (without adding the part match by your * at the end) I would use a regular expression to match the pattern in the URL but them just blind replace the whole string with the desired one:
(http://)localhost/sweettemptations/available-sweets
So if you want the URL:
http://localhost/sweettemptations/sweets/somethingmore.html
to turn into:
http://localhost/sweettemptations/available-sweets
and not into:
localhost/sweettemptations/available-sweets/somethingmore.html
Then the solution is simpler, no groups required :).
when doing this I would make sure you do not match the "localhost" part. Also I am assuming the (http://) really means an optional http:// in front as (http://) is not a valid protocol prefix.
so if that is what you want then this should match the pattern:
(http://)?[^/]+/sweettemptations/sweets/.*
This regular expression will match the http:// part optionally with a host (be it localhost, an IP or the host name). You could omit the .* at the end if you want.
If that pattern matches just replace the whole URL with the one you want to redirect to.
use this regular expression (?<=://).+

How to rewrite url containing plus and special chracters?

We've got some incoming URLs that needs to be redirected, but we are having trouble with URLs that contains pluses (+).
For example any incoming URL must be redirected to the Homepage of the new site:
/eng/news/2005+01+01.htm
Should be redirected to to the home page of the new site
/en/
Using UrlRewriter.net we've set up a rule which works with 'normal' URLs but does not work for the above
<redirect url="~/eng/(.+)" to="/en/index.aspx" />
However it works fine if i change the incoming URL to
/eng/news/2005-01-01.htm
What's the problem and can anyone help?
I don't know about UrlRewriter.net, and I'm not sure which regex syntax it uses. I give some hint based on Perl regex.
what is the ~ at the beginning? Perhaps you mean ^, i.e. beginning of the string.
(.+) matches any character repeated one or more time; it does not match the + sign as you want
This is one way to write a (Perl) regex matching URLs starting with the string /eng/ and containg a + sign:
^\/eng\/.*\+.*
I hope this helps.