I want to create a small app that creates a kind off receipt record in to a db table, from two other tables. very much like a receipt from a grocery store where a cashier makes a sell and the ticket contains multiple items, calculates a total and subtotal and return values to the database. I currently have 3 tables: the Ticket table where i would like to insert the values of all calculations and ticket info, the services table that acts like an inventory of services available. this has the service name and price for each service and my responsible table that has a list of "cashiers" or people that will make the sale and their percentage for their commissions, i have the views to create , edit and delete cashier's and services.
What I don't have is a way to create the ticket. I am completely lost. can you guys point me in to the correct path on what to look for. i am learning to program son i don't have a lot of knowledge in this if its even possible. i don't need the system to print i just want to have all record stored this way later on i can expand on it and create reports of sold items and who sold them and how much commissions each seller has won.
You need to create relationships to two other models (tables) from the Ticket model (table). Luckily you don't have to create the relations in the database tables itself. Use django model's Foreign key fields to accomplish this. Here is the documentation link:
Django Models
You may need to read it several times to get the concepts thoroughly.
Related
I am new to python Django. I have a scenario where I want to filter out data of slots from the slot table of a specific customer. Tables are connected using third table appointments. In the appointment table, I am storing the customer id and slot id associated with that customer. How to filter out customers all slots associated with it?
This is a diagram of tables and their relation with each other. Please help me out to solve it. I know by using join in SQL I get data. But I want to filter data in python Django so how I can apply joins in Django to filter data. I googled a lot but didn't get any proper answer. Please Provide a proper explanation with your answer.
As I understand, You want to list out all slot for the particular customer.
Say example cust_id = 1 then there are slot_id 1,2,3 associated with that customer in appointment table.
I would do something like this,
# Retreive all slot id for the customer with id = 1
slot_ids = Appointment.objects.filter(cust_id=1).values('id')
# Get all slots related to the customer
slots = Slot.objects.filter(id__in=slot_ids)
Remember you should use values() and retrieve specific column for id__in to work with.
Check here for more info https://docs.djangoproject.com/en/2.0/ref/models/querysets/
A little background. I've been developing the core code of an application in python, and now I want to implement it as a website for the user, so I've been learning Django and have come across a problem and not sure where to go with it. I also have little experience dealing with databases
Each user would be able to populate their own list, each with the same attributes. What seems to be the solution is to create a single model defining the attributes etc..., and then the user save records to this, and at the same time very frequently changing the values of the attributes of the records they have added (maybe every 5~10 seconds or so), using filters to filter down to their user ID. Each user would add on average 4000 records to this model, so say just for 1000 users, this table would have 4 million rows, 10,000 users we get 40million rows. To me this seems it would impact the speed of content delivery a lot?
To me a faster solution would be to define the model, and then for each user to have their own instance of this table of 4000ish records. From what I'm learning this would use more memory and disk-space, but I'd rather get a faster user experience as my primary end point.
Is it just my thinking because I don't have experience with databases? Or are my concerns warranted and I should find a solution as to how to be able to do the latter?
This post asked the same question I believe, but no solution on how to achieve it. How to create one Model (table) for each user on django?
Using ForeignKey relationships, I want to be able to copy data and store it in another model. For example, think of how you would handle past Invoices and billed Services.
The Invoice would have one or more Services associated with it and with prices for the Services. This prices for a Service can / will change over time - but the Service price recorded with the Invoice should remain as it was when the Invoice was created.
My first thought was to create a pdf from the resulting data and store it. But this would make the data somewhat inaccessible.
Is there somehow a way to copy the data and keep them accessible?
This is a pretty broad problem with multiple solutions. I dont think that what you're aiming to is the correct one.
One rule for saving invoices is, that invoices never change. You should never update an invoice. So not only your 'copies' of invoices should remain the same, but the original too.
Also, you should have a InvoiceItem (or InvoiceRow) model which are the items on your invoice. Don't bind Products to a Invoice directly.
Here are 2 solutions I've used:
Solution 1
You can normalize the data on your invoice(items). So, don't use foreignkeys, but normalize all data about the product, so product info (incl. price) is saved within the invoice(item).
Solution 2
Give your products revision numbers. So everytime a product is updated (name or price change for example), a new product is created in the database. Now you can link the InvoiceItem to a Product with a Foreign Key, and it will will be historically accurate.
Im sure there are some guides/best practices for creating Invoice backends. Language or Framework is not important. Invoicing is really important, so do alot of research before starting to build something. That's just my two pennies
I have a project that looks like a simple shopping site that sells different kinds of products. For example, I have 4 models: Brand, Product, Consignment. Consignment is linked to Product, and Product is linked to Brand. To reduce count of queries to databases, I want to save current state of these models(or at least some of them). I want to do it, because I show a sidebar with brands and products. So every time when user opens some page, it will execute the query to database to get those brands and products.
But when admin add some new product or brand, I want to handle database changing and resave it. How to implement it?
Your answer is by using Cache. Cache is a method to store your objects in memory/other app like redis temporarily so that you do not need send queries to database. You can read the full description here.
Or, you can use this third party library that helps you to cache Django ORM Model. Here are the example.
Brand.objects.filter(name='stackoverlow').cache()
After doing an update to the model, you need to clear or invalidate the cache.
invalidate_model(Brand)
I have a website which features famous people (each person is a row in the table People). For each famous person I would like to list related websites. I thought about creating a table called Websites and define it in the models.py module as follows:
class Websites(models.Model):
website_url = models.CharField(max_length=200)
related_person = models.ForeignKey(Person)
Then when I load a person's page I will run a wesbsites_set() query to fetch all related website.
However, won't that kind of query "cost" in load time? Isn't there a better solution to design this problem so I won't have to run a query against the Websites table on each person's page load? The table itself will contain many rows!
Thanks,
Meir
that's the SQL way to do it. The foreygn key will create a key to the People's table and as such the query will rely on the table indexes to be faster. Go for it :)