I am trying to implement canonical correlation analysis in C++ using the Eigen linear algebra library.
Part of the algorithm involves QR decomposition using the column pivot method. For that piece I am using the ColPivHouseholderQR class. This class contains an object of type HouseholderSequenceType which I would like to use to extract only the first N columns of the matrix rather than the entire Q matrix.
The full Q matrix has as many columns as rows and quickly fills memory for even modest dataset sizes. Furthermore, I don't need the full matrix, but just a subset of the first N columns.
How can I extract only the first N columns from this object?
My code:
// Set up the class and compute the QR decomposition
Eigen::ColPivHouseholderQR< Eigen::MatrixXd > qr;
qr.setThreshold(threshold);
qr.compute(mat);
int rk = qr.rank();
Eigen::ColPivHouseholderQR< Eigen::MatrixXd >::HouseholderSequenceType seq = qr.householderQ();
seq.setLength(rk);
// return the matrix
return (Eigen::MatrixXd) seq;
Related
Assume that I have 2 matrix: image, filter; with size MxM and NxN.
My regular convolution looks like this and produces matrix output size (M-N+1)x(M-N+1). Basically it places the top-left corner of a filter on a pixel, convolute, then assign the sum onto that pixel:
for (int i=0; i<M-N; i++)
for (int j=0; j<M-N; j++)
{
float sum = 0;
for (int u=0; u<N; u++)
for (int v=0; v<N; v++)
sum += image[i+u][j+v] * filter[u][v];
output[i][j] = sum;
}
Next, to perform FFT:
Apply zero-padding to both image, filter to the right and bottom (that is, adding more zero columns to the right, zero rows to the bottom). Now both have size (M+N)x(M+N); the original image is at
image[0->M-1][0-M-1].
(Do the same for both matrix) Calculate the FFT of each row into a new matrix, then calculate the FFT of each column of that new matrix.
Now, I have 2 matrices imageFreq and filterFreq, both size (M+N)x(M+N), which is the FFT-ed form of the image and the filter.
But how can I get the convolution values that I need (as described in the sample code) from them?
convolution between A,B using FFT is done by per element multiplication in the frequency domain so in 1D something like this:
convert A,B by FFT
assuming the sizes are N,M of A[N],B[M] first zero pad to common size Q which is a power of 2 and at least M+N in size and then apply FFT:
Q = exp2(ceil(log2(M+N)));
zeropad(A,Q);
zeropad(B,Q);
a = FFT(A);
b = FFT(B);
convolute
in frequency domain use just element wise multiplication:
for (i=0;i<Q;i++) a[i]*=b[i];
reconstruct result
simply apply IFFT (inverse of FFT)...
AB = IFFT(a); // crop to first N (real) elements
and use only the first N element (unless algorithm used need more depends on what you are doing...)
For 2D you can either convolute directly in 2D (using 2 nested for loops) or convolve each axis separately. Beware that separating axises need also to normalize the result by some constant (which depends on dimensionality, resolution and kernel used)
So when put together (also assuming the same resolution NxN and MxM) first zero pad to (QxQ) and then:
Q = exp2(ceil(log2(M+N)));
zeropad(A,Q,Q);
zeropad(B,Q,Q);
a = FFT(A);
b = FFT(B);
for (i=0;i<Q;i++)
for (j=0;j<Q;j++) a[i][j]*=b[i][j];
AB = IFFT(a); // crop to first NxN (real) elements
And again crop to AB to NxN size (unless ...) for more info see:
How to compute Discrete Fourier Transform?
and all sublinks there... Also here at the end is 1D convolution example using NTT (its a special form of FFT) to compute bignum multiplication:
Modular arithmetics and NTT (finite field DFT) optimizations
Also if you want real result then just use only the real parts of the result (ignore imaginary part).
Using Armadillo, how do I reshape a matrix when I only specify one dimension size?
In Matlab documentation, there is this example of such functionality:
Reshape a 6-by-6 magic square matrix into a matrix that has only 3
columns. Specify [] for the first dimension size to let reshape
automatically calculate the appropriate number of rows.
A = magic(6);
B = reshape(A,[],3);
The result is a 12-by-3 matrix, which maintains the same number of
elements (36) as the original 6-by-6 matrix. The elements in B also
maintain their columnwise order from A.
How can that be accomplished with Armadillo?
You can use .size() to get the total number of elements of your matrix and calculate the dimensions yourself.
Example:
B = reshape(A, A.size()/3, 3);
In the case of multiple of same matrix matA, like
matA.transpose()*matA,
You don't have to compute all result product, because the result matrix is symmetric(so only if the m>n), in my specific case is always symmetric! square.
So its enough the compute only for. ex. lower triangular part and rest only copy..... because the results of the multiple 2nd and 3rd row, resp.col, is the same like 3rd and 2nd.....And etc....
So my question is , exist way how to tell Eigen, to compute only lower part. and optionally save to only lower trinaguler part the product?
DATA = SparseMatrix<double>((SparseMatrix<double>(matA.transpose()) * matA).pruned()).toDense();
According to the documentation, you can evaluate the lower triangle of a matrix with:
m1.triangularView<Eigen::Lower>() = m2 + m3;
or in your case:
m1.triangularView<Eigen::Lower>() = matA.transpose()*matA;
(where it says "Writing to a specific triangular part: (only the referenced triangular part is evaluated)"). Otherwise, in the line you've written
Eigen will calculate the entire sparse matrix matA.transpose()*matA.
Regarding saving the resulting m1 matrix, it is the same as saving whatever type of matrix it is (Eigen::MatrixXt or Eigen::SparseMatrix<t>). If m1 is sparse, then it will be only half the size of a straightforward matA.transpose()*matA. If m1 is dense, then it will be the full square matrix.
https://eigen.tuxfamily.org/dox/classEigen_1_1SparseSelfAdjointView.html
The symmetric rank update is defined as:
B = B + alpha * A * A^T
where alpha is a scalar. In your case, you are doing A^T * A, so you should pass the transposed matrix instead. The resulting matrix will only store the upper or lower portion of the matrix, whichever you prefer. For example:
SparseMatrix<double> B;
B.selfadjointView<Lower>().rankUpdate(A.transpose());
I am porting some code from Matlab to Armadillo and am stuck at a simple step. I am finding all the indices of a vector res on the basis of a condition and then want to store all the rows of a matrix Pts corresponding to the condition.
So what it is in matlab
ifAny = find(res < lim);
Pts = Pts(ifAny,:);
In Armadillo -
arma::uvec ifAny = arma::find(res < lim);
// elem gives only the single column
// Pts = Pts.elem(ifAny);
According to the Submatrix view section of Armadillo's API documentation, the X.rows(vector_of_row_indices) would extract the selected set of non-contiguous rows in the provided vector_of_row_indices from the matrix X.
Thus in your case, to obtain a result equivalent to Pts = Pts(ifAny,:) of Matlab, you can use :
Pts = Pts.rows(ifAny);
I have performed block SVD decomposition over image and I stored results.
Now, I need to make reconstruction from this results. I found few examples all written in Matlab, which is a mystery for me.
I only need formula from which I can reconstruct my picture, or example written in C language.
Matrix A is equal U*S*V'. How will look formula, e.g. for calculating first five singular values (product of which rows and columns)? Please provide formula with indexes in C like style. U and V' are matrices and S is vector (not matrix).
Not sure if I get your question right, but if you just need to know singular values, they are the diagonal values of the middle matrix S. S in general is a diagonal matrix, which is stored here as a vector. I mean, only the diagonal is stored, you should imagine it as a matrix if you're thinking in matrix calculations.
Those diagonal values are your singular values, if you need the first biggest singular values, just take the 5 biggest values of the vector S.
Quoting from Wikipedia:
The diagonal entries Σi,i of Σ are known as the singular values of M.
The m columns of U and the n columns of V are called the left-singular
vectors and right-singular vectors of M, respectively.
In the above quote, sigma is your S, and M is the original matrix.
You have asked for C code, yet my hope is that pseudocode will suffice (it's late, I'm tired). The target matrix A has m rows, c columns and rank rho. The variable p = min(m,n).
One strategy is to first form the the intermediate matrix product B = US. This is trivial due to the diagonal-like nature of the matrix of singular values. Assume you have rho ( = 5 ) singular values. You must enforce rho <= p.
Replace column vector u1 with s1u1.
Replace column vector u2 with s2u2.
...
Replace column vector urho with srhourho.
Replace column vector urho+1 with a zero vector of length m.
Replace column vector urho+2 with a zero vector of length m.
...
Replace column vector up with a zero vector of length m.
Next form the new image matrix A = BVT. The matrix element in row r and column c is the dot product of the rth row vector (length rho) of B with the cth column vector (length rho) of VT.
Another strategy is to jump to the form where the matrix elements of A in row r and column c are
ar,c = sum ( skur,kvc,k, { k, 1, rho } )
The row counter r runs from 1 to m; the column counter c runs from 1 to n.