How to implement the SimpleMiddleware? - django

Question

I am struggling getting MiddleWare to work. I put this in my settings.py:
MIDDLEWARE_CLASSES = [
'django.middleware.security.SecurityMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware',
'portal.middleware.SimpleMiddleware'
]
and I implemented this class in portal/middleware/MiddleWare.py:
class SimpleMiddleware:
def __init__(self, get_response):
self.get_response = get_response
# One-time configuration and initialization.
def __call__(self, request):
# Code to be executed for each request before
# the view (and later middleware) are called.
response = self.get_response(request)
# Code to be executed for each request/response after
# the view is called.
return response
But when running, I get a TypeError:
TypeError: __init__() takes exactly 2 arguments (1 given)

Answer 1

Since you are writing a new-style middleware, you should use MIDDLEWARE instead of MIDDLEWARE_CLASSES in your settings.
You also need to make sure that your entry in the settings matches the location of the middleware. The entry 'portal.middleware.SimpleMiddleware' suggests a SimpleMiddleware class in portal/middleware.py, which does not match your filename portal/middleware/MiddleWare.py.