Trouble returning an array value - c++

Question

I keep getting an error code saying jeb has redefined itself and changing int to float or double doesn't work. This is meant to be a random number generator and my array is messing up.
#include "stdafx.h"
#include <iostream>
#include <random>
using std::cout;
using std::endl;
using std::cin;
int generate();
int numb();
int main()
{
int num = numb();
cout << num << endl;
cout << endl;
int gen = generate();
cout << gen << endl;
cout << endl;
system("Pause");
return 0;
}
int generate(float *jeb[])
{
int jeb [20] = {};
for (int i = 0; i < 20; i++) {
int rng = rand() % numb() + 1;
jeb[i] = rng;
return jeb;
}
}
int numb()
{
int choice;
cout << "Enter maximum number: ";
cin >> choice;
return choice;
}

Answer 1

There are several problems here:
int generate(int *jeb[])
{
int jeb [20] = {};
//...
}
Now you have two things called jeb.
Let's assume you just want one.
You could send in a pointer and fill it up
int generate(int *jeb)
{
//.. fill it up in a for loop
}
BUT this says it returns an int...
Instead of pointers, try using an array - you seem to know in advance you have 20 elements:
#include <array>
std::array<int, 20> generate()
{
std::array<int, 20> jeb;
for (int i = 0; i < 20; i++) {
int rng = rand() % numb() + 1;
jeb[i] = rng;
return jeb; //Really, wait - we haven't done the whole loop yet
}
}
Another issue might now be obvious: you are returning in the middle of the for loop. Wait until you've finished generating what you need.
std::array<int, 20> generate()
{
std::array<int, 20> jeb;
for (int i = 0; i < 20; i++) {
int rng = rand() % numb() + 1;
jeb[i] = rng;
}
return jeb; // loop now done
}