How to build a Vector of strings (Containing Spaces)? - c++

Question

I was trying to build a vector of strings.
Some of the strings also contain Spaces.
That's why I was using getline(cin,string_name).
My code looks like
for(int i=0;i<n;++i)
{
getline(cin, s);
vec.push_back(s);
}
When I was taking input
ADAM BOB JOHNSON
It stopped after taking two input words, and the vector contents displayed are
(HERE SPACE IS DISPLAYED)ADAM BOB
What does it mean.Is it taking NULL string as input for the first string ?
It will be really helpful if someone tells me how to take the strings and display it.Thanks.

Answer 1

Abhijit,
Your information is, obviously, not enough. Assuming that your code is written on C++, I made this test cpp:
#include <iostream>
#include <string>
#include <vector>
int main()
{
std::vector<std::string> vec;
std::string s;
int n = 1;
for(int i = 0; i < n; ++i)
{
getline(std::cin, s);
vec.push_back(s);
std::cout << vec.at(i) << std::endl;
}
return 0;
}
Compiled with g++ and fed it with "ADAM BOB JOHNSON" string on input. Everything worked as it planned and it output was exact same as input. So I can see no error in here.
Sorry, cannot make it a comment due to insufficient reputation so far.
UPD: Found the issue. getline first gets '\n', we left after '3' (which is needed for std::cin >> n;) hence, you just need to ignore one string. The code:
#include <iostream>
#include <vector>
#include <string>
int main()
{
int n;
std::cin >> n;
std::vector<std::string> vec;
std::string s;
std::getline(std::cin, s);
for(int i = 0; i < n; ++i)
{
std::getline(std::cin, s);
vec.push_back(s);
// std::cout << vec.at(i) << std::endl;
}
for(int i=0;i<n;++i){
std::cout << vec[i] <<" " << std::endl;
}
return 0;
}
works fine for me.
And yep, #pmaxim98 made it first, sorry, was editing the reply and haven't seen your comment.