Can't put class with main function? - c++

Question

Something I am working on is making a code that focuses on making a class that reverses an order of numbers. This will then get put into the main code that will eliminate any trailing zeroes. I can't seem to wrap my head around how classes work and where I am going wrong. Here is my code:
Numbers.h
#pragma once
#include <iostream>
class Numbers
{
public:
int digit
private:
void Numbers::reverse();
};
Numbers.cpp
#include "Numbers.h
#include <iostream>
using namespace std;
void Numbers::reverse(){
int n, reversedNumber = 0, remainder;
cout << "Enter the number you would like to manipulate! " << endl;
cin >> n;
while (n !=0)
{
remainder = n % 10;
reversedNumber = reversed Number * 10 + remainder;
n /= 10;
}
//return *this;
}
Main.cpp
#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <string>
#include "Numbers.h"
using namespace std;
int main()
{
Numbers.reverse;
system("pause");
return 0;
}
I can't seem to make the reverse function in my Numbers.cpp work in the main function. I am new to C++ and am not sure where I am going wrong. Any help would be appreciated!

Answer 1

OK, there are a lot of mistakes or learning errors in your code. Your header file should look something like:
#pragma once
class Numbers
{
public:
Numbers();
~Numbers();
int Reverse(int input); // Function is 'public'.
};
Your CPP file will then be (parts taken from S.O. post here):
#include "Numbers.h"
Numbers::Numbers()
{
}
Numbers::~Numbers()
{
}
// No need to store the value in 'digit' since this
// is just an algorithm which can return the result.
int Numbers::Reverse(int input)
{
int ret = 0;
while(input > 0)
{
ret = ret * 10 + (input % 10);
input = input / 10;
}
return ret; // Return the reversed number and let the user decide what to do.
}
Then you can use your class as follows:
#include "Numbers.h"
#include <iostream>
using namespace std;
int main()
{
int num;
cout << "Enter a number to reverse: ";
cin >> num;
Numbers numClass;
cout << "Reversed number is: " << numClass.Reverse(num) << endl;
return 0;
}