QMetaType::Type from template type - c++

Question

Is it possible to determine QMetaType::Type value of a template argument.
I tried this:
template <class T>
class MyClass {
public:
int getType() {
return QMetaType::type(typeid(T).name());
}
};
But this returns always 0 (QMetaType::UnknownType) because Qt uses different type names than the compiler.
It should work like the following:
MyClass<int>().getType(); // 2 (QMetaType::Int)
MyClass<QString>().getType(); // 10 (QMetaType::QString)
MyClass<QRect>().getType(); // 19 (QMetaType::QRect)
MyClass<MyType>().getType(); // 1024 (Set by qRegisterMetaType)

Answer 1

I tested your code on Qt 5.12.4 and it seems to work.
You could also Q_DECLARE_METATYPE to register your custom type and then use qMetaTypeId() to get the metaType id.
Here my test code and example:
#include <QCoreApplication>
#include <QDebug>
#include <QMetaType>
#include <QRect>
#include <QMetaObject>
class MyType
{
public:
int _member;
};
// needed for getType2()
Q_DECLARE_METATYPE(MyType);
// needed for getType()
const int id = qRegisterMetaType<MyType>("MyType");
template <class T>
class MyClass {
public:
int getType() {
return QMetaType::type(typeid(T).name());
}
int getType2() {
return qMetaTypeId<T>();
}
};
int main(int argc, char *argv[])
{
QCoreApplication a(argc, argv);
qDebug() << MyClass<int>().getType();
qDebug() << MyClass<QString>().getType();
qDebug() << MyClass<QRect>().getType();
qDebug() << MyClass<MyType>().getType();
qDebug() << MyClass<int>().getType2();
qDebug() << MyClass<QString>().getType2();
qDebug() << MyClass<QRect>().getType2();
qDebug() << MyClass<MyType>().getType2();
return a.exec();
}
this outputs:
2
10
19
1024
2
10
19
1024