How to read data from text file using python2.7? - python-2.7

Question

can anybody try to help me to retrieve numbers in Python and each number to an array:
I have done the following code, it does the job but it reads 10 as two numbers:
with open("test.dat") as infile:
for i, line in enumerate(infile):
if i == 0:
for x in range(0, len(line)):
if(line[x] == ' ' or line[x] == " "):
continue
else:
print(x, " " , line[x], ", ")
initial_state.append(line[x])
---Results:
(0, ' ', '1', ', ')
(2, ' ', '2', ', ')
(4, ' ', '3', ', ')
(6, ' ', '4', ', ')
(8, ' ', '5', ', ')
(10, ' ', '6', ', ')
(12, ' ', '7', ', ')
(14, ' ', '8', ', ')
(16, ' ', '9', ', ')
(18, ' ', '1', ', ')
(19, ' ', '0', ', ')
(21, ' ', '1', ', ')
(22, ' ', '1', ', ')
(24, ' ', '1', ', ')
(25, ' ', '2', ', ')
(27, ' ', '1', ', ')
(28, ' ', '3', ', ')
(30, ' ', '1', ', ')
(31, ' ', '4', ', ')
(33, ' ', '1', ', ')
(34, ' ', '5', ', ')
(36, ' ', '0', ', ')
(37, ' ', '\n', ', ')
index include spaces, please see the line of numbers im trying to add to array
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0

Answer 1

Use .split() to split all fields by looping through, please see the following code, it should do it
with open("test.dat") as infile:
for i, line in enumerate(infile):
if i == 0: # if first line
field = [field.split(" ") for field in line.split(" ")]
for x in range(0, len(field)):
initial_state_arr.append(field[x])

Answer 2

If you are sure each number is separated by a single space why not just split the line and print each element as an array:
with open("test.dat") as infile:
content = infile.read().split()
for index, number in enumerate(content):
print ((index*2, number))
And what is your exact input and expected result? Does the file have multiple spaces between numbers?