I'm trying to do a find and replace on a file to get rid of line breaks using Adobe Brackets. However, when I enter \n in the search field, even with Regular Expression turned on, it says No results. Is there a way to find newlines within Brackets?
You could try this:
(\r\n|\r|\n)
Related
I have written a program that searches for 'opens' without matching 'closes' in a target file. It produces an output like this:
open
close
open
open
close
In this example here the second 'open' is not immediately followed by a matching 'close', so I consider that an error. My text-editor (editpad) has a regular-expression search/replace feature, which I would like to use to get rid of all correct pairs, so I can notice easily the incorrect situations. I tried replacing the following
open\r\nclose
I thought that this would match the two words and the line-break between them (I'm using Windows). This did not work.
Does anyone have an idea why it didn't?
If you select the Regex mode, your regex will work, but I also suggest making \r optional by appending ? after it to support LF endings, too:
open\r?\nclose
See the screenshot with settings and proof it works in EditPad:
I have been trying to get this to work using different tools and sites such as regexr.com but haven't been able to figure it out.
I have a massive block of text somewhere in the text is:
javascript:device_popup(256, 3409)
I am trying to get the 256 sometimes there will be multiple of the above but the number for the comma will always be the same for each block of text.
I have tried variations of the following
/\[(.*?)\]/g
/javascript:device_popup\[(.*?)\]/g
/javascript:device_popup\(\.(*?),)/
Your first attempt matches everything between square brackets. The second attempt does the same only if preceded by "javascript:device_popup". In the third attempt, your syntax is incorrect.
You can modify your regular expression as follows:
/javascript:device_popup\((\d+)/
I am looking for some regex help.
I have a textfile, nothing super important but I would like to delete every second line from it - I have tried following this guide: Delete every other line in notepad++
However I just can't get it to work, is the regex I am using ok? I am noob with regex
Find:
([^\n]*\n)[^\n]*\n
Replace with:
$1
No matter what I try (mouse position at the beginning, ctrl+a and Replace All) I just can't get it to work. I appreciate any help.
I've put the regex into here: http://regexpal.com/ and if I remove the final \n it highlights the individual rows.
Make sure you select regular expression for the search mode...
Also, you may want to make that final newline optional. In the case that there are an even number of lines and you do not have a trailing newline, it won't remove the last line.
([^\n]*\n)[^\n]*\n?
Update:
See how Windows handle new lines with \r\n instead of just \n. Try updating the expression to take this into account:
([^\r\n]*[\r\n]+)[^\r\n]*[\r\n]*
Final Update:
Thanks to #zx81, I now know that N++ uses PCRE so \R can be used for unicode newline characters. However [^\R] won't work (this looks for anything except R literally), so you will need to keep [^\r\n]. This can be simplified as:
([^\r\n]*\R)[^\r\n]*\R?
I'm trying to replace parts within my code that looks like this
Class.Method<>("SomeKeyHere"]
Notice the square bracket at the ending - that's what I want to replace with the correct bracket.
My RegEx to find it looks like this:
Class\.Method\<\>\("{[^"]+}"\]
This RegEx seems to find the occurences pretty well.
My RegEx I want to use to replace (with the correct bracket at the end) is this:
Class\.Method\<\>\("(\1)"\)
However, VS is finding everything using Quickfind or Quickreplace's Find button but it won't replace it, telling me it hasn't found any occurences
The Problem was, that Visual Studio seems not to understand, that the "Replace with"-Part contained RegEx.
The Regex that worked was:
Class.Method<>(\"\1\")
Simpler, than I thought. Seems like VisualStudio only understands the \1, \2,.. Parts within the "Replace with" field.
I have been fighting this problem with the help of a RegEx cheat sheet, trying to figure out how to do this, but I give up... I have this lengthy file open in Notepad++ and would like to remove all lines that do not start with a digit (0..9). I would use the Find/Replace functionality of N++. I am only mentioning this as I am not sure what Regex implementation is N++ using... Thank you
Example. From the following text:
1hello
foo
2world
bar
3!
I would like to extract
1hello
2world
3!
not:
1hello
2world
3!
by doing a find/replace on a regular expression.
You can clear up those line with ^[^0-9].* but it will leave blank lines.
Notepad++ use scintilla, and also using its regex engine to match those.
\r and \n are never matched because in
Scintilla, regular expression searches
are made line per line (stripped of
end-of-line chars).
http://www.scintilla.org/SciTERegEx.html
To clear up those blank lines, only way is choose extended mode, and replace \n\n to \n, If you are in windows mode change \r\n\r\n to \r\n
[^0-9] is a regular expression that matches pretty much anything, except digits. If you say ^[^0-9] you "anchor" it to the start of the line, in most regular expression systems. If you want to include the rest of the line, use ^[^0-9].+.
^[^\d].* marks a whole line whose first character is not a digit. Check if there are really no whitespaces in front of the digits. Otherwise you'd have to use a different expression.
UPDATE:
You will have to do ot in two steps. First empty the lines that do not start with a digit. Then remove the empty lines in extended mode.
One could also use the technique of bookmarking in Notepad++. I started benefiting from this feature (long time present but only more recently made somewhat more visible in the UI) not very long ago.
Simply bring up the find dialogue, type regex for lines not starting with digit ^\D.*$ and select Mark All. This will place blue circles, like marbles, in the left gutter - these are line bookmarks. Then just select from main menu Search -> Bookmark -> Remove bookmarked lines.
Bookmarks are cool, you could extract these lines by simply selecting to copy bookmarked lines, opening new document and pasting lines there. I sometimes use this technique when reviewing log files.
I'm not sure what you are asking. but the reg exp for finding the lines with a digit at the beginning would be
^\d.*
you can remove all the lines that match the above or alternatly keep all the lines that match this expression:
^[^\d].*