Creating AMI using ec2_ami with Ansible - amazon-web-services

Question

I am trying to create an AMI from an EC2. However, before doing so I would like to check if the AMI with the same name exists. If it does, I would like to deregister it before attempting to create the AMI with the given name.
Issue1: How do I run AMI deregister ONLY if the AMI already exists.
Issue2: When the deregister call has been madem, how do I wait for before creating the AMI with the same name?
Here is what I have so far
- name: Check if AMI with the same name exists
ec2_ami_find:
name: "{{ ami_name }}"
register: ami_find
- name: Deregister AMI if it exists
ec2_ami:
image_id: "{{ ami_find.results[0].ami_id }}"
state: absent
when: ami_find.results[0].state == 'available'
- pause:
minutes: 5
- name: Creating the AMI from of the instance
ec2_ami:
instance_id: "{{ item.id }}"
wait: yes
name: "{{ ami_name }}"
delegate_to: 127.0.0.1
with_items: "{{ ec2.instances }}"
register: image
EDIT:
I am able to deregister the AMI when the state is 'available' and wait for a few minutes before attempting to create the new AMI (which has the same name). However, sometimes I get the following response. In which case I would like to continue with creating AMI.
TASK [createAMI : Check if AMI with the same name exists] **********************
ok: [local] => {"changed": false, "results": []}

Answer 1

First check if the result is not empty and then check the state.
when: ami_find.results | length and ami_find.results[0].state == 'available'

Answer 2

Thanks to the comment above, I managed to add the following to the Deregister task and managed to deal with the empty response.
- name: Check if AMI with the same name exists
ec2_ami_find:
name: "{{ ami_name }}"
register: ami_find
- name: Deregister AMI if it exists
ec2_ami:
image_id: "{{ ami_find.results[0].ami_id }}"
state: absent
when: ami_find.results | length and ami_find.results[0].state == 'available'